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Java Date TIME Format AM/PM Configuration

I am facing problems some while formatting the date:
Date : 11/06/2020 04:14:20
Date Format:dd/MM/yyyy hh:mm:ss a
Exception:
java.text.ParseException: Unparseable date: "11/06/2020 04:14:20"
Following is the code
Blockquote
public String getFormatDate(String inputDate) {
String strDate = "";
try {
DateFormat outputFormat = new SimpleDateFormat("MMMM dd, yyyy hh:mm:ss a");
DateFormat inputFormat = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss a");
Date date1 = inputFormat.parse(inputDate);
strDate = outputFormat.format(date1);
}catch( Exception exe) {
exe.printStackTrace();
logger.error( "[ERROR] getFormatDate:. ", exe );
}
return strDate;
}
Blockquote
Any help would be greatly appeciated.

You can check this code you have to pass the am/pm part too with the date string value as your format is expecting that.
//String date = "11/06/2020 04:14:20";
String date = "11/06/2020 04:14:20 am";
DateFormat df = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss a");
https://ideone.com/3nibwJ

Use proper date-time objects for your dates and times
For the vast majority of purposes you should not keep your date and time in a string and should not convert your date and time from a string in one format to a string in another format. Keep your date and time in a ZonedDateTime or LocalDateTime object.
When you are required to accept string input, parse that input into a date-time object immediately. I am using and recommending java.time, the modern Java date and time API:
DateTimeFormatter inputFormatter = DateTimeFormatter.ofPattern("dd/MM/uuuu HH:mm:ss");
String input = "11/06/2020 04:14:20";
LocalDateTime dateTime = LocalDateTime.parse(input, inputFormatter);
System.out.println(dateTime);
Output so far is:
2020-06-11T04:14:20
Since there is no AM or PM in your string, I have assumed that 04:14:20 was the time of day from 00:00:00 through 23:59:59. If you intended otherwise, you need to explain how.
Only when you need to give string output, format your date and time back into a string of appropriate format:
DateTimeFormatter outputFormatter = DateTimeFormatter
.ofPattern("MMMM dd, yyyy hh:mm:ss a", Locale.ENGLISH);
String output = dateTime.format(outputFormatter);
System.out.println(output);
June 11, 2020 04:14:20 AM
Do provide a locale for the formatter so Java knows which language to use for the month name and the AM/PM indicator.
What went wrong in your code?
Your string has no AM nor PM: 11/06/2020 04:14:20. Yet your format pattern string requires an AM/PM marker in the end. This is what format pattern letter a signifies. So your string wasn’t in the format that you required. This was the reason for the exception that you observed.
Link
Oracle tutorial: Date Time explaining how to use java.time.

Thanks All for your help:
I have changed the source date "11/06/2020 04:14:20" to "06/11/2020 04:14:20 PM", and then after perform follwoing steps, its working for me:
Blockquote
DateFormat inputFormat = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss a");
inputFormat.setTimeZone( TimeZone.getTimeZone("UTC") );
Date dDate = inputFormat.parse( srcDate );
String strDeDate = formatDateToString( dDate, "dd/MM/yyyy hh:mm:ss a", "IST" );
public String formatDateToString(Date date, String format,String timeZone) {
if (date == null) return null;
SimpleDateFormat sdf = new SimpleDateFormat(format);
if (timeZone == null || "".equalsIgnoreCase(timeZone.trim())) {
timeZone = Calendar.getInstance().getTimeZone().getID();
}
sdf.setTimeZone(TimeZone.getTimeZone(timeZone));
return sdf.format(date);
}
Blockquote

Incorrect UNIX timestamp from String Date

I am trying to convert a date in String format into UNIX timestamp, I am able to convert it but when I check the timestamp it displays incorrect date.
I am using the following code to convert a Date in String to Unix timestamp:
String selected_date = "16/11/2015 1:34 am";
datetime.setText(selected_date);
DateFormat dateFormat = new SimpleDateFormat("MM/dd/yy hh:mm a");
Date date = null;
try {
date = dateFormat.parse(selected_date);
} catch (ParseException e) {
e.printStackTrace();
}
long unixTime = (long)date.getTime()/1000;
The output UNIX timestamp is: 1460309640
But when I convert that timestamp using a web tool it returns: 4/11/2016, 1:34:00 AM

The format
DateFormat dateFormat = new SimpleDateFormat("MM/dd/yy hh:mm a");
is not compatible with the string
String selected_date = "16/11/2015 1:34 am";
16 can't be a month!
2015 is not a year in two digits format
The right format seems to be (not sure if kk or KK depending on hours if 0 based or not)
DateFormat dateFormat = new SimpleDateFormat("dd/MM/yyyy kk:mm a");

Converting string date to date

How would I convert a String date in the form of 24/04/2012 to a date variable in the format of 24-Apr-12, which can later be passed into my Oracle database.
I have tried this but it says the string date is unparsable:
DateFormat format = new SimpleDateFormat("dd-MMM-yy");
Date newDate = (Date) format.parse(date);

I think you are confusing parsing and formatting, try this:
String old_date = "24/04/2012";
DateFormat old_format = new SimpleDateFormat("dd/MM/yyyy");
Date newDate = (Date) old_format.parse(old_date);
DateFormat new_format = new SimpleDateFormat("dd-MMM-yy");
String date = new_format.format(newDate);
System.out.println(date);

You are doing this backwards:
DateFormat format = new SimpleDateFormat("dd/MM/yyyy");
Date newDate = format.parse(date);
DateFormat formatOutput = new SimpleDateFormat("dd-MMM-yyyy");
String output = formatOutput.format(newDate);
But if what you are doing is passing the date to Oracle, you should really use a PreparedStatement

Your date format should be "dd/MM/yyyy"

SimpleDateFormat sdf= new SimpleDateFormat("dd-MM-yy");
DateTime newDate = sdf.format(date);

Try DateFormat format = new SimpleDateFormat("dd/MM/yyyy")

Why don't you try using java.sql.Date.
For example:
Date newDate = new java.sql.Date(date.getTime());
So you can just give an generic sql object for date.

The Date class of Java is quite difficult to use in many cases. I recommend the use of the much better Joda Time classes:
DateTimeFormatter oldFormat = DateTimeFormat.forPattern("dd/mm/yyyy");
DateTimeFormatter newFormat = DateTimeFormat.forPattern("dd-MMM-yy");
DateTime dateTime = oldFormat.parseDateTime("24/04/2012");
String newDate = newFormat.print(dateTime);

Java Date Formatter

I am getting date format as "YYYY-mm-dd hh:mm" as formatter object.
How can I format the input formatter object to get only "YYYY-mm-dd";?

I am getting date format as
"YYYY-mm-dd hh:mm" as formatter
object. How can i format the input
formatter object to get only
"YYYY-mm-dd";
You can not have date as YYYY-mm-dd it should be yyyy-MM-dd. To get date in yyyy-MM-dd following is the code:
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd");
String formattedDate = formatter.format(todaysDate);

Format formatter = new SimpleDateFormat("yyyy-MM-dd hh:mm");
Date date;
try {
date = (Date)((DateFormat) formatter).parse("2011-04-13 05:00");
formatter = new SimpleDateFormat("yyyy-MM-dd");
String s = formatter.format(date);
System.out.println(s);
} catch (ParseException e) {
e.printStackTrace();
}

Use SimpleDateFormat
String myDateString = "2009-04-22 15:51";
SimpleDateFormat inFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm");
SimpleDateFormat outFormat = new SimpleDateFormat("yyyy-MM-dd");
System.out.println(outFormat.format(inFormat.parse(myDateString)));

If you're getting a date in the format "YYYY-mm-dd hh:mm" and you want it as "YYYY-mm-dd" I suggest you just use inputDate.substring(0, 10).
In either way, beware of potential Y10k bugs :)

Following sample formate date as yyyy-MM-dd in Java
Format formatter = new SimpleDateFormat("yyyy-MM-dd");
Calendar now = Calendar.getInstance();
System.out.println("Now: "+formatter.format(now.getTime()) );

Yes, SimpleDateFormat is what you are looking for
http://dlc.sun.com.edgesuite.net/jdk/jdk-api-localizations/jdk-api-zh-cn/builds/latest/html/en/api/java/text/SimpleDateFormat.html

SimpleDateFormat is what you're looking for.

Try this:
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd");
String formattedDate = formatter.format(todaysDate);

Use this code:
Date date=new Date();
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd");
String formattedDate = formatter.format(date);
System.out.println("formatted time==>" + formattedDate);
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");

Other answers such as the one by user2663609 are correct.
As an alternative, the third-part open-source replacement for the java.util.Date/Calendar classes, Joda-Time, includes a built-in format for your needs.
// © 2013 Basil Bourque. This source code may be used freely forever by anyone taking full responsibility for doing so.
// import org.joda.time.*;
// import org.joda.time.format.*;
String stringIn = "2011-04-07";
// Returns a formatter for a full date as four digit year, two digit month of year, and two digit day of month (yyyy-MM-dd).
DateTimeFormatter formatter = ISODateTimeFormat.date().withZone( DateTimeZone.forID( "Europe/London" ) ).withLocale( Locale.UK );
DateTime dateTime = formatter.parseDateTime( stringIn ).withTimeAtStartOfDay();
String stringOut = formatter.print( dateTime );
Dump to console…
System.out.println( "dateTime: " + dateTime.toString() );
System.out.println( "stringOut: " + stringOut );
When run…
dateTime: 2011-04-07T00:00:00.000+01:00
stringOut: 2011-04-07

This question has so many good answers !! , here comes another one more generic solution
public static String getDateInFormate(String oldFormate , String newFormate , String dateToParse){
//old "yyyy-MM-dd hh:mm"
//new yyyy-MM-dd
//dateTopars 2011-04-13 05:00
String formatedDate="";
Format formatter = new SimpleDateFormat();
Date date;
try {
date = (Date)((DateFormat) formatter).parse(dateToParse);
formatter = new SimpleDateFormat(newFormate);
formatedDate = formatter.format(date);
} catch (ParseException e) {
e.printStackTrace();
}
return formatedDate;
}

SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
String strDate = entry_date;
System.out.println("strDate*************"+strDate);
Date date = null;
try {
date = sdf.parse(strDate);
} catch (ParseException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
DateFormat df = new SimpleDateFormat("dd/MM/yyyy");
Date yesterday =subtractDay( date);
String requiredDate = df.format(yesterday);
System.out.println("110 days before*******************"+requiredDate);
public static Date subtractDay(Date date) {
Calendar cal = Calendar.getInstance();
cal.setTime(date);
cal.add(Calendar.DATE, -110);`enter code here`
return cal.getTime();
}

java.time
I recommend that you use java.time, the modern Java date and time API, for your date and time work.
For parsing input define a formatter:
private static final DateTimeFormatter FORMATTER
= DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm", Locale.ROOT);
Parse:
String input = "2019-01-21 23:45";
LocalDateTime dateTime = LocalDateTime.parse(input, FORMATTER);
System.out.println(dateTime);
Output so far:
2019-01-21T23:45
Format output:
String output = dateTime.format(DateTimeFormatter.ISO_LOCAL_DATE);
System.out.println(output);
2019-01-21
Tutorial link
Trail: Date Time (The Java™ Tutorials) explaining how to use java.time.

How to format a date String into desirable Date format

I was trying to format a string into date.
For this I have written a code:-
Calendar cal = Calendar.getInstance();
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
System.out.println(sdf.format( cal.getTime() ));
This is fine..
But now I want to convert a string into a date formatted like above..
For example
String dt="2010-10-22";
And the output should be like this:-
2010-10-22T00:00:00
How do I do this?

String dt = "2010-10-22";
SimpleDateFormat sdfIn = new SimpleDateFormat("yyyy-MM-dd");
ParsePosition ps = new ParsePosition(0)
Date date = sdfIn.parse(dt, pos)
SimpleDateFormat sdfOut = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
System.out.println(sdfOut.format( date ));

This should do it for you, remember to wrap it in a try-catch block just in case.
DateFormat dt = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
try
{
Date today = dt.parse("2010-10-22T00:00:00");
System.out.println("Your Date = " + dt.format(today));
} catch (ParseException e)
{
//This parse operation may not be successful, in which case you should handle the ParseException that gets thrown.
//Black Magic Goes Here
}

If your input is going to be ISO, you could also look at using the Joda Time API, like so:
LocalDateTime localDateTime = new LocalDateTime("2010-10-22");
System.out.println("Formatted time: " + localDateTime.toString());

The same class you use for output formatting of dates can also be used to parse dates on input.
SimpleDateFormat reference
To use your example, to parse the sample date:
String dt = "2010-10-22";
SimpleDateFormat dateFormatter = new SimpleDateFormat("yyyy-MM-dd");
System.out.println(dateFormatter.parse(dt));
The fields that are not specified (ie. hour, minutes, etc) will be 0. So your same code can be used to format the date on output.

Date Format Example
Containing the Conversion of String Date object from one format to another