How would I convert a String date in the form of 24/04/2012 to a date variable in the format of 24-Apr-12, which can later be passed into my Oracle database.
I have tried this but it says the string date is unparsable:
DateFormat format = new SimpleDateFormat("dd-MMM-yy");
Date newDate = (Date) format.parse(date);
I think you are confusing parsing and formatting, try this:
String old_date = "24/04/2012";
DateFormat old_format = new SimpleDateFormat("dd/MM/yyyy");
Date newDate = (Date) old_format.parse(old_date);
DateFormat new_format = new SimpleDateFormat("dd-MMM-yy");
String date = new_format.format(newDate);
System.out.println(date);
You are doing this backwards:
DateFormat format = new SimpleDateFormat("dd/MM/yyyy");
Date newDate = format.parse(date);
DateFormat formatOutput = new SimpleDateFormat("dd-MMM-yyyy");
String output = formatOutput.format(newDate);
But if what you are doing is passing the date to Oracle, you should really use a PreparedStatement
Your date format should be "dd/MM/yyyy"
SimpleDateFormat sdf= new SimpleDateFormat("dd-MM-yy");
DateTime newDate = sdf.format(date);
Try DateFormat format = new SimpleDateFormat("dd/MM/yyyy")
Why don't you try using java.sql.Date.
For example:
Date newDate = new java.sql.Date(date.getTime());
So you can just give an generic sql object for date.
The Date class of Java is quite difficult to use in many cases. I recommend the use of the much better Joda Time classes:
DateTimeFormatter oldFormat = DateTimeFormat.forPattern("dd/mm/yyyy");
DateTimeFormatter newFormat = DateTimeFormat.forPattern("dd-MMM-yy");
DateTime dateTime = oldFormat.parseDateTime("24/04/2012");
String newDate = newFormat.print(dateTime);
Related
i have a common doubt for a long while. During date formation if the input date in the format like "2019/05/22 02:00:23" then with the help following line we can format the date,
String inputDate = "2019/05/22 02:00:23";
SimpleDateFormat dateFormatter = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss");
Date toDate = dateFormatter.parse(inputDate);
I can see both input format and the required format is same. Suppose if i change the input date like below, it is showing the java.text.ParseException: Unparseable date: exception.
String inputDate = "31.12.9999";
SimpleDateFormat dateFormatter = new SimpleDateFormat("yyyy.MM.dd HH:mm:ss");
Date toDate = dateFormatter.parse(inputDate);
Please suggest how to achieve this.
Please try below i mentioned date format code,I hope it will help you,
From this,
String inputDate = "31.12.9999";
SimpleDateFormat dateFormatter = new SimpleDateFormat("yyyy.MM.dd HH:mm:ss");
Date toDate = dateFormatter.parse(inputDate);
To Change:
Date date = new SimpleDateFormat("dd.MM.yyyy").parse("31.12.9999");
String formattedDate = new SimpleDateFormat("yyyy.MM.dd HH:mm:ss").format(date);
System.out.println("formattedDate :: " + formattedDate);
Thanks,.
I am trying to format the following input date: "2019-02-12 18:00:40""
to the following format "dd-MM-yyyy". However, I am experiencing mixed results with the date formatter method I created below and the output is as follows
"Wed Aug 11 00:00:00 GMT+02:00 17"
private String formatDate(String dateT) throws ParseException
{
SimpleDateFormat formatter = new SimpleDateFormat("dd-MM-yyyy");
Date date = formatter.parse(dateT);
return date.toString();
}
As mentioned, you'll need two formats to get your desired result.
If you can use Java8+, I suggest using LocalDateTime and DateTimeFormatter (instead of SimpleDateFormat):
String stamp = "2019-02-12 18:00:40";
LocalDateTime ldt = LocalDateTime.parse(stamp, DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss"));
System.out.println(ldt.format(DateTimeFormatter.ofPattern("dd-MM-yyyy")));
Output:
12-02-2019
Edit:
If you really must use the outdated classes, you can apply the same principle with SimpleDateFormat:
String stamp = "2019-02-12 18:00:40";
SimpleDateFormat dt1 = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date date = dt1.parse(stamp);
SimpleDateFormat dt2 = new SimpleDateFormat("dd-MM-yyyy");
System.out.println(dt2.format(date));
As suggested by #Robert. This was the solution I ended up using with two simpledateformatters.
private String formatDate(String date) throws ParseException {
SimpleDateFormat inputDate = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date currentDate = inputDate.parse(date);
SimpleDateFormat formatter = new SimpleDateFormat("dd-MM-yyyy");
String formattedDate = formatter.format(currentDate);
return formattedDate;
}
I want to convert a date object, ex: new Date(), to a string which has a format like Oracle's time stamp type, ex: 21-OCT-13 11.08.13.858000000 AM. I know I could just get each piece of information in the date object like day, month, year, hour, minute, ... to form the Oracle format string but I really want to know is there a utility to do that instead?
Using SimpleDateFormat#format() you would print a Date as
SimpleDateFormat sdf = new SimpleDateFormat("dd-MMM-yy hh.mm.ss.SSSSSSSSS a");
System.out.println(sdf.format(new Date()).toUpperCase());
Output :
21-OCT-13 10.01.38.000000614 AM
See JavaDocs for Date and Time patterns.
Try taking a look at SimpleDateFormats - That would be your best bet and easiest way of doing it.
Eg:
Date date = new Date();
SimpleDateFormat dateFormat = new SimpleDateFormat("hh:mm:ss"); //Hours:Minutes:Seconds
String strDate = dateFormat.format(date);
Use SimpleDateFormat.
Date date = new Date();
SimpleDateFormat sdf = new SimpleDateFormat("your_format_here"); // dd/MM/yy h:mm:ss a
String formattedDate = sdf.format(date);
System.out.println(formattedDate);
String str2="April 30, 2013";
simpleDateFormat s= new simpleDateFormat();
SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
SimpleDateFormat formatter2 = new SimpleDateFormat("yyyy-MM-dd");
Date dateObject = null;
I have string like "April 30,2013", I am getting this as string from form. I want to convert this into date object as 04/30/2013. Is there any way to do it?
I tried with simpleDateFormat() but I didn't found proper output.
Use MMMMM dd, yyyy to parse and MM/dd/yyyy to format
Use the following code.
String str2="April 30, 2013";
SimpleDateFormat input = new SimpleDateFormat("MMMM dd, yyyy");
SimpleDateFormat output = new SimpleDateFormat("MM/dd/yyyy");
Date date = input.parse(str2);
System.out.println(output.format(date));
This is how you can convert it String date to Date object:
SimpleDateFormat dateFormat = new SimpleDateFormat("MMMM d,yyyy");
SimpleDateFormat yourNewDateFormat = new SimpleDateFormat("MM/dd/yyyy");
Date date = dateFormat.parse("April 30,2013");
System.out.println(yourNewDateFormat.format(date));
I'm trying to use this code:
private static Date getTimeStamp() {
return new Timestamp(new Date().getTime());
}
What I'm getting is 2013-03-13 12:46:22.011
But what I need is that the timestamp should be in the format of mm-dd-yyyy hh:mm.
java.sql.Timestamp objects (just like java.util.Date and java.sql.Date) do not have a format by themselves, so you cannot "have a Timestamp in the format [whatever]".
A format only is applicable when you convert the object to a string for display. You can use SimpleDateFormat to convert a Timestamp to a string, using the format you want.
Timestamp timestamp = new Timestamp(System.currentTimeMillis());
DateFormat dateFormat = new SimpleDateFormat("MM-dd-yyyy HH:mm");
String text = dateFormat.format(timestamp);
System.out.println(text);
Hope this helps
String date1="2013-03-13 12:46:22.011";
DateFormat userDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:SS");
DateFormat dateFormatNeeded = new SimpleDateFormat("MM/dd/yyyy HH:mm");
Date date = userDateFormat.parse(date1);
String finaldate = dateFormatNeeded.format(date);
You can use SimpleDateFormat http://docs.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html to achieve your goal.
For Example:
new SimpleDateFormat("MM-dd-yyyy HH:mm").format(timestamp));