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Java - SimpleDateFormat parse from String issue

I'm trying to parse the following string to a Date object:
String str = "04/15/2014 10:30:24"
I'm using SimpleDateFormat :
SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");
java.util.Date orderDate = sdf.parse(str);
java.sql.Date orderSqlDate = new java.sql.Date(orderDate.getTime());
but orderSqlDate always returned: 04/15/2014 00:00:00
how to use SimpleDateFormat in java exactly?

The java.sql.Date javadoc states
To conform with the definition of SQL DATE, the millisecond values
wrapped by a java.sql.Date instance must be 'normalized' by setting
the hours, minutes, seconds, and milliseconds to zero in the
particular time zone with which the instance is associated.
If you're going to use java.sql.Date, there's no way around this.

You are also doing correct.
But to get the result in the format you want, you need to use .format("/your format/") method after parsing the string.
String date = "15/12/2014 10:42:24";
SimpleDateFormat dateParser = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");
SimpleDateFormat formatter = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss");
Date parseDate = dateParser.parse(date);
formatter.format(parseDate) // this will change format of date as you want.

I don't think the way you parse is wrong. Are you sure you print orderDate right ?
The following code demonstrates both parsing and formatting (printing).
public static void main(String[] args) {
String format = "MM/dd/yyyy HH:mm:ss";
try {
SimpleDateFormat sdf = new SimpleDateFormat(format);
Date orderDate = new SimpleDateFormat(format).parse("04/15/2014 10:30:24");
System.out.println(sdf.format(orderDate));
} catch (Exception e) {
e.printStackTrace();
}
}

Provide Locale in the SimpleDateFormat constructor, otherwise parsing might be dependant on your local settings:
SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss", Locale.ROOT);

convert a date object to Oracle timestamp type string

I want to convert a date object, ex: new Date(), to a string which has a format like Oracle's time stamp type, ex: 21-OCT-13 11.08.13.858000000 AM. I know I could just get each piece of information in the date object like day, month, year, hour, minute, ... to form the Oracle format string but I really want to know is there a utility to do that instead?

Using SimpleDateFormat#format() you would print a Date as
SimpleDateFormat sdf = new SimpleDateFormat("dd-MMM-yy hh.mm.ss.SSSSSSSSS a");
System.out.println(sdf.format(new Date()).toUpperCase());
Output :
21-OCT-13 10.01.38.000000614 AM
See JavaDocs for Date and Time patterns.

Try taking a look at SimpleDateFormats - That would be your best bet and easiest way of doing it.
Eg:
Date date = new Date();
SimpleDateFormat dateFormat = new SimpleDateFormat("hh:mm:ss"); //Hours:Minutes:Seconds
String strDate = dateFormat.format(date);

Use SimpleDateFormat.
Date date = new Date();
SimpleDateFormat sdf = new SimpleDateFormat("your_format_here"); // dd/MM/yy h:mm:ss a
String formattedDate = sdf.format(date);
System.out.println(formattedDate);

How to format this string do a proper date format?

I'm very new to Java programming and I have string like this:
2013-03-15T07:23:13Z
I wish I could convert this into date format like:
15-03-2013
is that possible?
Thanks in advance.

Take the reference to this link
How can I change the date format in Java?
See the answer given by Mr. Christopher Parker
It has explained all your needs and it will provide you the easiest solution which is logically correct

Try this :
try {
DateFormat sourceDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
DateFormat targetFormat = new SimpleDateFormat("dd-MM-yyyy");
String strSourceDate = "2013-03-15T07:23:13Z";
Date targetDate = (Date) sourceDateFormat.parseObject(strSourceDate);
String strTargetDate = targetFormat.format(targetDate);
System.out.println(strTargetDate);
} catch (ParseException e) {
e.printStackTrace();
}

If the format of the input string is fixed, the simplest and the most expedient way of doing this would be with string manipulation:
String s = "2013-03-15T07:23:13Z";
String res = s.substring(8, 10)+"-"+s.substring(5, 7)+"-"+s.substring(0, 4);
It would spare you dealing with dates and calendars. Here is a demo on ideone.

java.text.SimpleDateFormat is what you need: SimpleDateFormat JavaDoc
You'll need one format to convert your input String into a Date using the parse() method, and then another to convert that Date into a String in your desired format using format().
If your application could be used internationally, don't forget to think about correctly localizing the output of the second function though. 03-11-2013 is March 11th in some countries, November 3rd in others.

Try this:
Date dNow = new Date( );
SimpleDateFormat ft =
new SimpleDateFormat ("dd.MM.yyyy");
System.out.println("Current Date: " + ft.format(dNow));
It's output
Current Date: 15.03.2013

Using SimpleDateFormat
String strDate = "2013-03-15T07:23:13Z";
SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MM-yyyy");
String date = dateFormat.format(strDate);
System.out.println("Today in dd-MM-yyyy format : " + date);
Hope it help you...

Java change date format from custom date to MM dd yyyy

I am trying to convert a String value that is stored in a database,for example "2012-01-20", to be in the format January 20, 2012.
I have seen some examples, but they are using Date which works with SimpleDateFormat.
As an example here is one way I tried but the "try" always fails and the result is null
DateFormat df = new SimpleDateFormat("MM/dd/yyyy");
Date convertedDate=null;
try {
convertedDate = df.parse(datePlayed);
} catch(ParseException e){
e.printStackTrace();
}

In short, you're not using the right format for parsing. You need to use two DateFormat instances; one for parsing and one for formatting.
DateFormat parser = new SimpleDateFormat("yyyy-MM-dd");
DateFormat formatter = new SimpleDateFormat("MMM dd, yyyy");
Date convertedDate = parser.parse(datePlayed);
String output = formatter.format(convertedDate);

Date da = new Date();
SimpleDateFormat ft = new SimpleDateFormat("E, dd/MM/yyyy !");
System.out.println("Update : " + ft.format(da));
You can change your date style do you want at: E, dd/MM/yyyy !
Good luck !

If the Date is read from a Database, then store it as a java.sql.Date. You can then use SimpleDateFormat on it, maybe after converting to java.util.Date. From the ResultSet object, you can extract Dates.
If what you meant is that you are given a date in text that was extracted from a DB by someone else and you are stuck with it. Try using:
DateFormat df = new SimpleDateFormat("yyyy-MM-dd");
df.setLenient(true);
convertedDate = df.parse(datePlayed.trim() );
Also try displaying the text you are parsing before you parse to make sure the datePlayed value is what you expect.
With parseInt, an extra space before or after the data will cause an error, so calling trim() removes extra spaces.

Parse A Java Date

How can I parse the following date in Java from its string representation to a java.util.Date?
2011-07-12T16:45:56
I tried the following:
private Date getDateTime(String aDateString) {
Date result = new java.util.Date();
SimpleDateFormat sf = new SimpleDateFormat("yyyy/MM/dd hh:mm:ss");
try
{
result = sf.parse(aDateString);
}
catch (Exception ex)
{
Log.e(this.getClass().getName(), "Unable to parse date: " + aDateString);
}
return result;
}

You are not using the right date format pattern. The year/month/day separators are clearly wrong, and you need a literal 'T'. Try this:
SimpleDateFormat sf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
For the record, this is an ISO 8601 combined date and time format.

Your date format pattern is incorrect. It should be yyyy-MM-dd'T'HH:mm:ss .
To parse a date like "2011-07-12T16:45:56" you need to use:-
SimpleDateFormat sf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");

Check the pattern you are feeding your SimpleDateFormat against the string you are feeding in.
See any potential discrepancies? I see 3.