How can convert a hexdecimal IP string into IP4 dotted string... [closed] - java

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Closed 8 years ago.
This question appears to be off-topic because it lacks sufficient information to diagnose the problem. Describe your problem in more detail or include a minimal example in the question itself.
Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist
Improve this question
I want to convert a hexadecimal string into IP4 string , I googled but didn't get any good way. Could anybody suggest me a simple way.
Thanks .

Please try this method.
String hexValue = "Hex IP";
String ip = "";
for(int i = 0; i < hexValue.length(); i = i + 2) {
ip = ip + Integer.valueOf(hexValue.subString(i, i+2), 16) + ".";
}
System.out.println("Ip = " + ip);

In this post the author gave a method for printing out an int into hexadecimal.

Related

Format a string containing no spaces using java [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question appears to be off-topic because it lacks sufficient information to diagnose the problem. Describe your problem in more detail or include a minimal example in the question itself.
Closed 8 years ago.
Improve this question
Any ideas how to effeciently convert the String "TDMaturityReinvestOnNotSelected" to "TD Maturity Reinvest On Not Selected" using a java function?
Cheers
Shaun
This brilliant answer to RegEx to split camelCase or TitleCase (advanced) should work nicely.
Below is an excerpt from that answer:
final String pattern = "(?<!(^|[A-Z]))(?=[A-Z])|(?<!^)(?=[A-Z][a-z])";
for (String w : "TDMaturityReinvestOnNotSelected".split(pattern))
{
System.out.println(w);
}
And the ouput to show it running:
Edit: You'll need to reassemble the split words with spaces, but that should be trivial to work out.

Java convert bytes (in the form of a string) into a string [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist
Closed 9 years ago.
Improve this question
I'm receiving a string of bytes from my server like so:
60,104,101,97,100,62,60,115,99,114,105,112
How can i convert this into a readable string?
This is what I've tried to do:
String s = new String(json.get("msg").toString());
System.out.println("Text Decryted : " + s);
But this just gives me:
60,104,101,97,100,62,60,115,99,114,105,112
Any ideas how to accomplish this?
Parse a byte array from it:
String byteString = "60,104,101,97,100,62,60,115,99,114,105,112";
String[] byteStrings = byteString.split(",");
byte[] bytes = new byte[byteStrings.length];
for (int i = 0; i < bytes.length; i++) {
bytes[i] = (byte)Integer.parseInt(byteStrings[i]);
}
Then interpret the bytes as a string in a particular character set. Find out which character set you're actually using, to avoid future problems.
String string = new String(bytes, java.nio.charset.StandardCharsets.UTF_8);
The above is not very efficient by the way. Since you're already sending a string from the server, it would make more sense just to send the actual string. If you can't send the string as-is, you should ask about that problem.

String of bytes to byte array [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist
Closed 9 years ago.
Improve this question
I am reading an array of bytes from a page as a String. Example: "80 75 7 8 0 0".
I would like to convert this String into a byte array in Java. Can anyone help me/tell me what method I can possibly use?
Thank you.
Try:
String[] bytesString = originalString.split(" ");
byte[] bytes = new byte[bytesString.length];
for(int i = 0 ; i < bytes.length ; ++i) {
bytes[i] = Byte.parseByte(bytesString[i]);
}

Regex to remove all "#[x]" [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist
Closed 9 years ago.
Improve this question
I am looking for a regular expression to remove all #[x] present in a string
Where x can be any string.
For example #[title]
#\[[^\]]*\]?
As in:
String s = "asda #[asdagf] dsgfdg";
System.out.println(s.replaceAll("#\\[[^\\]]*\\]",""));
will print out:
asda dsgfdg
String original = "Hello #[world]!";
String replaced = original.replaceAll("#\\[.*?\\]", "");
// replaced = "Hello !"`enter code here`

How to insert multiple tabs string in java? [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist
Closed 9 years ago.
Improve this question
How to insert multiple tabs string in Java?
This example:
getName() + '\t' + '\t' + getLastName(), does not work.
Your example should work; however there's no reason to append each tab character individually. This works, too:
getName() + "\t\t" + getLastName();
The errors you are getting are not related to the tab characters.
Your syntax is screwy. Try this.
String whatever0 = "firstname"+"\t"+"\t"+"lastname";
String whatever1 = "firstname"+"\t"+"\t"+"\t"+"lastname";
System.out.println(whatever0);
System.out.println(whatever1);
You'll see that they give different results.

Categories

Resources