Regex to remove all "#[x]" [closed] - java

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I am looking for a regular expression to remove all #[x] present in a string
Where x can be any string.
For example #[title]

#\[[^\]]*\]?
As in:
String s = "asda #[asdagf] dsgfdg";
System.out.println(s.replaceAll("#\\[[^\\]]*\\]",""));
will print out:
asda dsgfdg

String original = "Hello #[world]!";
String replaced = original.replaceAll("#\\[.*?\\]", "");
// replaced = "Hello !"`enter code here`

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how to nest if statements in HashSet? [duplicate]

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I'm trying to find the lentgh of a set from a preference.
I tired set.length, but it doesnt work. Anyone know another way to find a length of a set?
set = prefs.getStringSet("key", null);
int X = set.length; //it doesn't like length....
I believe instead of set.length, you'll want to call set.size()
Your set is a Set<String>, not a String[]. So you have to call:
int x = set.size();

Setting the text field using setText(..) method with a double value. Java GUI [closed]

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I'm trying to use setText(..) and sending a double value to it but it says
setText(java.lang.String) in javax.swing.text.JTextComponent cannot be applied to (double)
You need to convert your double to a String and then pass that String as an argument to the setText(String) method. This is how you convert a double to a String:
double d = 3.14;
String s = String.valueOf(d);
// s is now "3.14"

Remove the first letter from a string in Java [closed]

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Given a string "Hello". I only want all the letters after the first letter to be in my new string.
E.g.: "ello"
How could this be done?
Tried pattern matching but cant get it to work :(
Try this:
String s = "Hello";
String newS = s.substring(1); // newS is "ello"
The above will create a new string containing all the characters of the original, except the first one. See the documentation for more details.

How to insert multiple tabs string in java? [closed]

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How to insert multiple tabs string in Java?
This example:
getName() + '\t' + '\t' + getLastName(), does not work.
Your example should work; however there's no reason to append each tab character individually. This works, too:
getName() + "\t\t" + getLastName();
The errors you are getting are not related to the tab characters.
Your syntax is screwy. Try this.
String whatever0 = "firstname"+"\t"+"\t"+"lastname";
String whatever1 = "firstname"+"\t"+"\t"+"\t"+"lastname";
System.out.println(whatever0);
System.out.println(whatever1);
You'll see that they give different results.

Whitespace matching regex in Java [closed]

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Closed 8 years ago.
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I am currently trying to make use of the java string function someString.replaceAll() to find commonly used words (and, the, by, of, etc) and replace them with " ". Based on the answers to the question at Whitespace Matching Regex - Java, I produced this function call:
data.replaceAll("(?i)\\sthe\\s", " ")
However, it isnt working and I'm really not sure why. Nothing about it looks wrong based on what I've found. Please help me!
Strings are immutable!
data = data.replaceAll("(?i)\\sthe\\s", " ");

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