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Any ideas how to effeciently convert the String "TDMaturityReinvestOnNotSelected" to "TD Maturity Reinvest On Not Selected" using a java function?
Cheers
Shaun
This brilliant answer to RegEx to split camelCase or TitleCase (advanced) should work nicely.
Below is an excerpt from that answer:
final String pattern = "(?<!(^|[A-Z]))(?=[A-Z])|(?<!^)(?=[A-Z][a-z])";
for (String w : "TDMaturityReinvestOnNotSelected".split(pattern))
{
System.out.println(w);
}
And the ouput to show it running:
Edit: You'll need to reassemble the split words with spaces, but that should be trivial to work out.
Related
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How to match a fully qualified class name like com.mycompany.models.Friend using regex and strip away the package name so the result would be Friend for the example given?
You can simply do:
System.out.println(s.substring(s.lastIndexOf(".") + 1));
This will print Friend
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I want to detect the file structure in a string.
e.g
if I have a string as /name/test/testme/2 I should be able to store it in a arraylist as different elements like {[name],[test],[testme],[2]}
String[] elements = "/name/test/testme/2".split("/");
More info can be found in the String.split() Javadoc
As Lukas pointed out, (please give him some upvoting) you should use the split method.
String[] elements = "/name/test/testme/2".split("/");
The regular expressions are not used to split strings in sections. Regular expressions are used for matching the target string with a specific generic format. In this case a boolean value indicating if the strings match is returned.
Hope I helped!
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Given a string "Hello". I only want all the letters after the first letter to be in my new string.
E.g.: "ello"
How could this be done?
Tried pattern matching but cant get it to work :(
Try this:
String s = "Hello";
String newS = s.substring(1); // newS is "ello"
The above will create a new string containing all the characters of the original, except the first one. See the documentation for more details.
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I have this xml file from where I'm reading this string,
http://localhost:8080/sdpapi/request/10/notes/611/
My question is how can I get just the 611, which is of variable, can be 100000, for example, from this string?
Split the string
String input = "http://localhost:8080/sdpapi/request/10/notes/611/";
String output = input.split("notes/")[1].split("/")[0];
output is the value you need
What language?
Anyway, in most cases it's a syntax like:
String.substring(begin, length);
... where 'begin' is the number of the letter in the string-1. For extracting http from the above string you would write
substring(0, 4);
In case you always need the last string between the last two '/'s, you can retrieve the position of the slashes with index-functions (as stated in the answer of #Liran for example).
// EDIT: In Java the second parameter of substring is not length, but endIndex:
String s = "http://localhost:8080/sdpapi/request/10/notes/611/";
s.substring(46, s.lastIndexOf('/'));
It depends on programming language you use, but Regular Expressions should be the same in most of them:
/(\d+)\/$/
well, it depend in what language are you writing... in c# for example
string s = #"http://localhost:8080/sdpapi/request/10/notes/611/";
s.SubString(s.LastIndexOf('/'));
or
Path.GetFileName(s);
for java
new File(s).getName();
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I am currently trying to make use of the java string function someString.replaceAll() to find commonly used words (and, the, by, of, etc) and replace them with " ". Based on the answers to the question at Whitespace Matching Regex - Java, I produced this function call:
data.replaceAll("(?i)\\sthe\\s", " ")
However, it isnt working and I'm really not sure why. Nothing about it looks wrong based on what I've found. Please help me!
Strings are immutable!
data = data.replaceAll("(?i)\\sthe\\s", " ");