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I have this xml file from where I'm reading this string,
http://localhost:8080/sdpapi/request/10/notes/611/
My question is how can I get just the 611, which is of variable, can be 100000, for example, from this string?
Split the string
String input = "http://localhost:8080/sdpapi/request/10/notes/611/";
String output = input.split("notes/")[1].split("/")[0];
output is the value you need
What language?
Anyway, in most cases it's a syntax like:
String.substring(begin, length);
... where 'begin' is the number of the letter in the string-1. For extracting http from the above string you would write
substring(0, 4);
In case you always need the last string between the last two '/'s, you can retrieve the position of the slashes with index-functions (as stated in the answer of #Liran for example).
// EDIT: In Java the second parameter of substring is not length, but endIndex:
String s = "http://localhost:8080/sdpapi/request/10/notes/611/";
s.substring(46, s.lastIndexOf('/'));
It depends on programming language you use, but Regular Expressions should be the same in most of them:
/(\d+)\/$/
well, it depend in what language are you writing... in c# for example
string s = #"http://localhost:8080/sdpapi/request/10/notes/611/";
s.SubString(s.LastIndexOf('/'));
or
Path.GetFileName(s);
for java
new File(s).getName();
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I want to detect the file structure in a string.
e.g
if I have a string as /name/test/testme/2 I should be able to store it in a arraylist as different elements like {[name],[test],[testme],[2]}
String[] elements = "/name/test/testme/2".split("/");
More info can be found in the String.split() Javadoc
As Lukas pointed out, (please give him some upvoting) you should use the split method.
String[] elements = "/name/test/testme/2".split("/");
The regular expressions are not used to split strings in sections. Regular expressions are used for matching the target string with a specific generic format. In this case a boolean value indicating if the strings match is returned.
Hope I helped!
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Given a string "Hello". I only want all the letters after the first letter to be in my new string.
E.g.: "ello"
How could this be done?
Tried pattern matching but cant get it to work :(
Try this:
String s = "Hello";
String newS = s.substring(1); // newS is "ello"
The above will create a new string containing all the characters of the original, except the first one. See the documentation for more details.
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here is the non-oop way of doing it:
When someone presses a day on a calendar, we need to find out the day, and path. Here is the non-oop way of storing that information:
A string was created with a "-" delimiter between each piece of info we need, like this:
12-c:\files\john_doe.png
Then it was stored in an array. However, to retrieve the data, we then use the "split" function like this.
for (int t = 0;t < day_and_path.length;t++)
{
String[] day_from_db = day_and_path[t].split("-");
String day_db = day_from_db[0];
String path_db = day_from_db[1];
However the OOP way is, make a class with properties: day, path. Then store them into an array of objects.
Which way is better and why?
If you use String#split, you'll be dealing with an array of strings. If all you do is assign the strings to local variables, then there is no point in making a class for that.
If you want to hold on to the string parts and pass them around to other methods, then it begins to make sense to have an object which will conveniently encapsulate those strings.
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For this string, 16.82080560, 96.13055810 I want to get
"String one = 16.82080560"
and
"String two = 96.13055810"
in android.
Admin that I suck in string manipulation and regex.
Please let me know how can I get such two value from a string.
String[] components = original.split(",");
If the Strings are always separated by a comma you can use String.split
For a better regex pattern see the comment from #npinti:
Minor side note, it might be better to do \\s*,\\s* instead of just ,.
Just , might cause problems should the OP wish to cast these to
floats, since the extra white space at the beginning of the second
number will most likely not be recognized as a proper number.
Another option:
String str = "16.82080560, 96.13055810";
StringTokenizer st = new StringTokenizer(str,", ");
String one = st.nextToken();
String two = st.nextToken();
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I am currently trying to make use of the java string function someString.replaceAll() to find commonly used words (and, the, by, of, etc) and replace them with " ". Based on the answers to the question at Whitespace Matching Regex - Java, I produced this function call:
data.replaceAll("(?i)\\sthe\\s", " ")
However, it isnt working and I'm really not sure why. Nothing about it looks wrong based on what I've found. Please help me!
Strings are immutable!
data = data.replaceAll("(?i)\\sthe\\s", " ");