Can anyone point out what seems to be the problem here?
try {
Date date = new SimpleDateFormat("Mon, 02 Nov 2015 15:13:00 EET").parse("EEE, dd MMM yyyy hh:mm:ss z");
} catch (ParseException e) {
e.printStackTrace();
}
and the stacktrace:
java.text.ParseException: Unparseable date: "Mon, 02 Nov 2015 15:13:00 EET" (at offset 26)
I'm suspecting something with the locale that I'm using but I can't be sure. Seems that "z" for timezone not working.
Edit:
Sorry the exception was funny earlier, I changed it but forgot to update here.
try {
Date date = new SimpleDateFormat("EEE, dd MMM yyyy hh:mm:ss z", Locale.US).parse("Mon, 02 Nov 2015 15:13:00 EET");
} catch (ParseException e) {
e.printStackTrace();
}
After looking at javadoc for SimpleDateFormat, you are using "hh" for hour, which is assumed to be a 12-hour time. Use HH for 24-hour time. Your example as 15 for the hour.
I think you're missing 'z' here.
Try:
Date date = new SimpleDateFormat("Mon, 02 Nov 2015 15:13:00 EET").
parse("EEE, dd MMM yyyy hh:mm:ss zzz")
Since your timezone is with three characters.
Such an exception can come from parsing a date with the wrong Locale. For example this date formatter :
SimpleDateFormat df = new SimpleDateFormat("EEE, dd MMM yyyy hh:mm:ss z", Locale.US);
will successfully parse the example date :
Date date = df.parse("Mon, 02 Nov 2015 15:13:00 EET");
But the following will give the exception you are getting
SimpleDateFormat df = new SimpleDateFormat("EEE, dd MMM yyyy hh:mm:ss z", Locale.FRENCH);
I would expect the Locale in Android to be chosen according to the language set by the user.
Related
This question already has answers here:
Java - Unparseable date
(3 answers)
Getting error java.text.ParseException: Unparseable date: (at offset 0) even if the Simple date format and string value are identical
(4 answers)
Date format parse exception - "EEE MMM dd HH:mm:ss Z yyyy" [duplicate]
(3 answers)
Closed 3 years ago.
So I get this String ("Tue Nov 26 12:05:19 CET 2019") from a txt fiel and I want to parse it into a Date like this:
SimpleDateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy");
Date date = null;
try {
date = format.parse(dateAsString);
} catch (ParseException e) {
e.printStackTrace();
}
And I still get this Exception:
java.text.ParseException: Unparseable date: "Tue Nov 26 12:05:19 CET 2019"
But the format/patter should be ok. So my question is how I parse the string into a date.
You are most likely not using English locale so Tue and Nov are not parsing. Specify the locale with the formatter and don't use obsolete date classes:
DateTimeFormatter fmt = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss zzz yyyy", Locale.US);
ZonedDateTime time = ZonedDateTime.parse("Tue Nov 26 12:05:19 CET 2019", fmt);
System.out.println(time); // 2019-11-26T12:05:19+01:00[Europe/Paris]
you can set language as English here
SimpleDateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy", Locale.ENGLISH);
Date date = null;
try {
date = format.parse("Tue Nov 26 12:05:19 CET 2019");
} catch (ParseException e) {
e.printStackTrace();
}
System.out.println(date);
This worked for me:
SimpleDateFormat format =
new SimpleDateFormat("E MMM dd HH:mm:ss zzz yyyy", new Locale("en", "EN"));
I am trying to convert the following json string: "Mon Apr 04 00:00:00 CEST 2016" to a new date object by a simpleDateFormat. But i dont see why it wont work hope some one can help me.
String date = "Mon Apr 04 00:00:00 CEST 2016";
I get the following error:
(java.text.ParseException) java.text.ParseException: Unparseable
date: "Mon Apr 04 00:00:00 CEST 2016"
public Date parseDate(String date)
{
try
{
SimpleDateFormat formatter = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy");
Date returnDate = formatter.parse(date);
return returnDate;
}
catch (ParseException e)
{
e.printStackTrace();
return null;
}
}
you need to parse with the locale:
SimpleDateFormat formatter = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy", Locale.ENGLISH);
"EEE MMM ddHH:mm:ss z yyyy"
looks you forgot to put the space after dd:
"EEE MMM dd HH:mm:ss z yyyy"
This question already has answers here:
SimpleDateFormat ignoring month when parsing
(4 answers)
Closed 9 years ago.
I am facing the problem while converting the date:
Current format is:Thu Sep 05 12:07:46 IST 2013(dow mon dd hh:mm:ss zzz yyyy)
I need to convert in to:09/04/2013 11:38 PM PDT(mm/dd/yyyy hh:mm a zzz)
But i am not able to convert.
Try using SimpleDateFormatter. You have to tell it the input/output format, you can do that based on this description (you can also find a few common examples there).
The code will be something like this:
try {
String input = "Thu Sep 05 12:07:46 IST 2013";
DateFormat formatter = new SimpleDateFormat("I leave this to you :-)))");
System.out.println(formatter.parse(input));
} catch (ParseException e) {
e.printStackTrace();
}
Hope that helps.
You can do this
TimeZone tz = TimeZone.getTimeZone("PST8PDT"); // example
// required format. Remember M is for month, m for miniute
DateFormat df = new SimpleDateFormat("MM/dd/yyyy hh:mm a zzz");
df.setTimeZone(tz);
String text = df.format(new Date());// current time
System.out.println(text);
Also please check this TimeZones in Java
You try to convert dateformat and timeZone as well, so you need to convert the timezone in your code.
SimpleDateFormat sf = new SimpleDateFormat("dow mon dd hh:mm:ss zzz yyyy");
isoFormat.setTimeZone(TimeZone.getTimeZone("PDT"));
Date date = isoFormat.parse("mm/dd/yyyy hh:mm a zzz");
this may help you.
try {
DateFormat dffrom = new SimpleDateFormat("E MMM dd hh:mm:ss zzz yyyy");
DateFormat dfto = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss a zzz");
Date date = dffrom.parse("Thu Sep 05 12:07:46 IST 2013");
String s = dfto.format(date);
System.out.println(s);
} catch (ParseException e) {
}
OutPut
09/05/2013 00:07:46 AM IST
update
try {
DateFormat dffrom = new SimpleDateFormat("E MMM dd hh:mm:ss zzz yyyy");
DateFormat dfto = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss a zzz");
TimeZone zone = TimeZone.getTimeZone("America/Los_Angeles");
dfto.setTimeZone(zone);
Date date = dffrom.parse("Thu Sep 05 12:07:46 IST 2013");
String s = dfto.format(date);
System.out.println(s);
} catch (ParseException e) {
}
output
09/04/2013 11:37:46 AM PDT
I have the next problem with this date:
java.text.ParseException: Unparseable date: "Wed Jan 11 00:00:00 CET 2012"
I have this:
DateFormat formatter ;
Date dateIn=null;
formatter = new SimpleDateFormat( "EEE MMM dd HH:mm:ss yyyy" );
try {
dateIn = (Date)formatter.parse(dateI);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
What I'm doing bad?. Thanks
Use timezone and also a locale
SimpleDateFormat( "EEE MMM dd HH:mm:ss z yyyy", Locale.US);
to reflect English language in the input string (days and month names).
You need to add z in your format string for including timezone. Try this:
SimpleDateFormat( "EEE MMM dd HH:mm:ss z yyyy" );
I have date strings in this form Thu Aug 02 00:00:00 GMT+00:00 2012
I have tried to use this method to parse these String in a Date object
public Date fromStringToDate(String data) {
Date result;
SimpleDateFormat sdf = new SimpleDateFormat("yyyy MM dd HH:mm:ss");
try {
result = sdf.parse(data);
return result;
} catch (ParseException e) {
e.printStackTrace();
return null;
}
}
But doesn't works and I get this error
java.text.ParseException: Unparseable date: "Thu Aug 02 00:00:00 GMT+00:00 2012"
I suppose that the problem is caused by a wrong SimpleDateFormat, but I don't know the right syntax to fix it.
You need to adjust the date format to the given string:
EEE MMM dd HH:mm:ss Z yyyy
Make sure use the correct placeholders, case sensitive, etc. Take a look to the Date and Time Patterns.
Sorry, I had a mistake with the 'z' pattern, 'Z' is:
SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd HH:mm:ss Z yyyy", Locale.US);
Take a look to Locale.US, it is important to apply because the months and and days are in english.
Use this date formatting:
SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy")