This question already has answers here:
Java - Unparseable date
(3 answers)
Getting error java.text.ParseException: Unparseable date: (at offset 0) even if the Simple date format and string value are identical
(4 answers)
Date format parse exception - "EEE MMM dd HH:mm:ss Z yyyy" [duplicate]
(3 answers)
Closed 3 years ago.
So I get this String ("Tue Nov 26 12:05:19 CET 2019") from a txt fiel and I want to parse it into a Date like this:
SimpleDateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy");
Date date = null;
try {
date = format.parse(dateAsString);
} catch (ParseException e) {
e.printStackTrace();
}
And I still get this Exception:
java.text.ParseException: Unparseable date: "Tue Nov 26 12:05:19 CET 2019"
But the format/patter should be ok. So my question is how I parse the string into a date.
You are most likely not using English locale so Tue and Nov are not parsing. Specify the locale with the formatter and don't use obsolete date classes:
DateTimeFormatter fmt = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss zzz yyyy", Locale.US);
ZonedDateTime time = ZonedDateTime.parse("Tue Nov 26 12:05:19 CET 2019", fmt);
System.out.println(time); // 2019-11-26T12:05:19+01:00[Europe/Paris]
you can set language as English here
SimpleDateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy", Locale.ENGLISH);
Date date = null;
try {
date = format.parse("Tue Nov 26 12:05:19 CET 2019");
} catch (ParseException e) {
e.printStackTrace();
}
System.out.println(date);
This worked for me:
SimpleDateFormat format =
new SimpleDateFormat("E MMM dd HH:mm:ss zzz yyyy", new Locale("en", "EN"));
Related
This question already has answers here:
Java - Unparseable date
(3 answers)
How to Convert RFC-1123 date-time formatter, to local time
(1 answer)
Closed 4 years ago.
I'm trying to parse this date
Thu, 15 Nov 2018 16:56:49 +0000
With this code:
Date date = null;
try {
SimpleDateFormat parser = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss Z");
date = parser.parse(xmlPullParser.nextText());
} catch (ParseException e) {
e.printStackTrace();
date = new Date(); //This is just a temporary workaround
}
java.text.ParseException: Unparseable date: "Thu, 15 Nov 2018 16:56:49
+0000"
I've already try this formats too
EEE, dd MMM yyyy HH:mm:ss sssZ
EEE, d MMM yyyy HH:mm:ss sssZ
EEE, d MMM yyyy HH:mm:ss Z
But obviously it doesn't work
You forgot to set the Locale of SimpleDateFormat. Since you try to read a date in a english form, I would initialize this way:
SimpleDateFormat parser = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss Z", Locale.US);
When you don't specify any Locale, it uses the Locale of your system which is obviously not US or UK.
Can anyone point out what seems to be the problem here?
try {
Date date = new SimpleDateFormat("Mon, 02 Nov 2015 15:13:00 EET").parse("EEE, dd MMM yyyy hh:mm:ss z");
} catch (ParseException e) {
e.printStackTrace();
}
and the stacktrace:
java.text.ParseException: Unparseable date: "Mon, 02 Nov 2015 15:13:00 EET" (at offset 26)
I'm suspecting something with the locale that I'm using but I can't be sure. Seems that "z" for timezone not working.
Edit:
Sorry the exception was funny earlier, I changed it but forgot to update here.
try {
Date date = new SimpleDateFormat("EEE, dd MMM yyyy hh:mm:ss z", Locale.US).parse("Mon, 02 Nov 2015 15:13:00 EET");
} catch (ParseException e) {
e.printStackTrace();
}
After looking at javadoc for SimpleDateFormat, you are using "hh" for hour, which is assumed to be a 12-hour time. Use HH for 24-hour time. Your example as 15 for the hour.
I think you're missing 'z' here.
Try:
Date date = new SimpleDateFormat("Mon, 02 Nov 2015 15:13:00 EET").
parse("EEE, dd MMM yyyy hh:mm:ss zzz")
Since your timezone is with three characters.
Such an exception can come from parsing a date with the wrong Locale. For example this date formatter :
SimpleDateFormat df = new SimpleDateFormat("EEE, dd MMM yyyy hh:mm:ss z", Locale.US);
will successfully parse the example date :
Date date = df.parse("Mon, 02 Nov 2015 15:13:00 EET");
But the following will give the exception you are getting
SimpleDateFormat df = new SimpleDateFormat("EEE, dd MMM yyyy hh:mm:ss z", Locale.FRENCH);
I would expect the Locale in Android to be chosen according to the language set by the user.
This question already has answers here:
Java - Unparseable date
(3 answers)
Closed 7 years ago.
I try to convert string to date format, but the following does't work.
String stringdate = "Fri Mar 27 17:14:27 EET 2015";
DateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy");
try {
Date newdate = format.parse(stringdate);
} catch (ParseException e) {
e.printStackTrace();
}
the output is
java.text.ParseException: Unparseable date: "Fri Mar 27 17:14:27 EET
2015"
SimpleDateFormat is locale-sensitive, so your default locale may be the reason why the exception is thrown. Try setting the locale to US.
DateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy", Locale.US);
This question already has answers here:
How to parse a date? [duplicate]
(5 answers)
Closed 9 years ago.
How to parse the following string to date
Mon Oct 22 03:00:26 +0000 2012
I tried MMM dd HH:mm:ss yyyy, but it is not working. I know I am missing something but couldn't find out that.
String b="Mon Oct 22 03:00:26 +0000 2012";
DateFormat a = new SimpleDateFormat("MMM dd HH:mm:ss yyyy");
Date d=(Date)a.parse(b)
I'd recommend EEE MMM dd HH:mm:ss Z yyyy instead of HH:mm:ss yyyy.
Edit:
Specifically, your code would be:
String b="Mon Oct 22 03:00:26 +0000 2012";
DateFormat a = new SimpleDateFormat("MMM dd HH:mm:ss Z yyyy");
Date d=(Date)a.parse(b)
Edit after comment:
String b="Mon Oct 22 03:00:26 +0000 2012";
DateFormat a = new SimpleDateFormat("MMM dd HH:mm:ss Z yyyy", Locale.getDefault());
Date d=(Date)a.parse(b)
Try to do something like this:
SimpleDateFormat formatter = new SimpleDateFormat("EEEE, MMM dd, yyyy HH:mm:ss a");
String dateInString = "Friday, Jun 7, 2013 12:10:56 PM";
try {
Date date = formatter.parse(dateInString);
System.out.println(date);
System.out.println(formatter.format(date));
} catch (ParseException e) {
e.printStackTrace();
}
Ref: How to Convert String to Date in Java
This question already has answers here:
SimpleDateFormat ignoring month when parsing
(4 answers)
Closed 9 years ago.
I am facing the problem while converting the date:
Current format is:Thu Sep 05 12:07:46 IST 2013(dow mon dd hh:mm:ss zzz yyyy)
I need to convert in to:09/04/2013 11:38 PM PDT(mm/dd/yyyy hh:mm a zzz)
But i am not able to convert.
Try using SimpleDateFormatter. You have to tell it the input/output format, you can do that based on this description (you can also find a few common examples there).
The code will be something like this:
try {
String input = "Thu Sep 05 12:07:46 IST 2013";
DateFormat formatter = new SimpleDateFormat("I leave this to you :-)))");
System.out.println(formatter.parse(input));
} catch (ParseException e) {
e.printStackTrace();
}
Hope that helps.
You can do this
TimeZone tz = TimeZone.getTimeZone("PST8PDT"); // example
// required format. Remember M is for month, m for miniute
DateFormat df = new SimpleDateFormat("MM/dd/yyyy hh:mm a zzz");
df.setTimeZone(tz);
String text = df.format(new Date());// current time
System.out.println(text);
Also please check this TimeZones in Java
You try to convert dateformat and timeZone as well, so you need to convert the timezone in your code.
SimpleDateFormat sf = new SimpleDateFormat("dow mon dd hh:mm:ss zzz yyyy");
isoFormat.setTimeZone(TimeZone.getTimeZone("PDT"));
Date date = isoFormat.parse("mm/dd/yyyy hh:mm a zzz");
this may help you.
try {
DateFormat dffrom = new SimpleDateFormat("E MMM dd hh:mm:ss zzz yyyy");
DateFormat dfto = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss a zzz");
Date date = dffrom.parse("Thu Sep 05 12:07:46 IST 2013");
String s = dfto.format(date);
System.out.println(s);
} catch (ParseException e) {
}
OutPut
09/05/2013 00:07:46 AM IST
update
try {
DateFormat dffrom = new SimpleDateFormat("E MMM dd hh:mm:ss zzz yyyy");
DateFormat dfto = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss a zzz");
TimeZone zone = TimeZone.getTimeZone("America/Los_Angeles");
dfto.setTimeZone(zone);
Date date = dffrom.parse("Thu Sep 05 12:07:46 IST 2013");
String s = dfto.format(date);
System.out.println(s);
} catch (ParseException e) {
}
output
09/04/2013 11:37:46 AM PDT