This question already has answers here:
SimpleDateFormat ignoring month when parsing
(4 answers)
Closed 9 years ago.
I am facing the problem while converting the date:
Current format is:Thu Sep 05 12:07:46 IST 2013(dow mon dd hh:mm:ss zzz yyyy)
I need to convert in to:09/04/2013 11:38 PM PDT(mm/dd/yyyy hh:mm a zzz)
But i am not able to convert.
Try using SimpleDateFormatter. You have to tell it the input/output format, you can do that based on this description (you can also find a few common examples there).
The code will be something like this:
try {
String input = "Thu Sep 05 12:07:46 IST 2013";
DateFormat formatter = new SimpleDateFormat("I leave this to you :-)))");
System.out.println(formatter.parse(input));
} catch (ParseException e) {
e.printStackTrace();
}
Hope that helps.
You can do this
TimeZone tz = TimeZone.getTimeZone("PST8PDT"); // example
// required format. Remember M is for month, m for miniute
DateFormat df = new SimpleDateFormat("MM/dd/yyyy hh:mm a zzz");
df.setTimeZone(tz);
String text = df.format(new Date());// current time
System.out.println(text);
Also please check this TimeZones in Java
You try to convert dateformat and timeZone as well, so you need to convert the timezone in your code.
SimpleDateFormat sf = new SimpleDateFormat("dow mon dd hh:mm:ss zzz yyyy");
isoFormat.setTimeZone(TimeZone.getTimeZone("PDT"));
Date date = isoFormat.parse("mm/dd/yyyy hh:mm a zzz");
this may help you.
try {
DateFormat dffrom = new SimpleDateFormat("E MMM dd hh:mm:ss zzz yyyy");
DateFormat dfto = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss a zzz");
Date date = dffrom.parse("Thu Sep 05 12:07:46 IST 2013");
String s = dfto.format(date);
System.out.println(s);
} catch (ParseException e) {
}
OutPut
09/05/2013 00:07:46 AM IST
update
try {
DateFormat dffrom = new SimpleDateFormat("E MMM dd hh:mm:ss zzz yyyy");
DateFormat dfto = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss a zzz");
TimeZone zone = TimeZone.getTimeZone("America/Los_Angeles");
dfto.setTimeZone(zone);
Date date = dffrom.parse("Thu Sep 05 12:07:46 IST 2013");
String s = dfto.format(date);
System.out.println(s);
} catch (ParseException e) {
}
output
09/04/2013 11:37:46 AM PDT
Related
This question already has answers here:
Java - Unparseable date
(3 answers)
Getting error java.text.ParseException: Unparseable date: (at offset 0) even if the Simple date format and string value are identical
(4 answers)
Date format parse exception - "EEE MMM dd HH:mm:ss Z yyyy" [duplicate]
(3 answers)
Closed 3 years ago.
So I get this String ("Tue Nov 26 12:05:19 CET 2019") from a txt fiel and I want to parse it into a Date like this:
SimpleDateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy");
Date date = null;
try {
date = format.parse(dateAsString);
} catch (ParseException e) {
e.printStackTrace();
}
And I still get this Exception:
java.text.ParseException: Unparseable date: "Tue Nov 26 12:05:19 CET 2019"
But the format/patter should be ok. So my question is how I parse the string into a date.
You are most likely not using English locale so Tue and Nov are not parsing. Specify the locale with the formatter and don't use obsolete date classes:
DateTimeFormatter fmt = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss zzz yyyy", Locale.US);
ZonedDateTime time = ZonedDateTime.parse("Tue Nov 26 12:05:19 CET 2019", fmt);
System.out.println(time); // 2019-11-26T12:05:19+01:00[Europe/Paris]
you can set language as English here
SimpleDateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy", Locale.ENGLISH);
Date date = null;
try {
date = format.parse("Tue Nov 26 12:05:19 CET 2019");
} catch (ParseException e) {
e.printStackTrace();
}
System.out.println(date);
This worked for me:
SimpleDateFormat format =
new SimpleDateFormat("E MMM dd HH:mm:ss zzz yyyy", new Locale("en", "EN"));
Consider the snippet:
String dateStr = "Mon Jan 32 00:00:00 IST 2015"; // 32 Jan 2015
DateFormat formatter = new SimpleDateFormat("E MMM dd HH:mm:ss Z yyyy");
DateFormat ddMMyyyy = new SimpleDateFormat("dd.MM.yyyy");
System.out.println(ddMMyyyy.format(formatter.parse(dateStr)));
gives me the output as
01.02.2015 // Ist February 2015
I wish to prevent this to make the user aware on the UI that is an invalid date?
Any suggestions?
The option setLenient() of your SimpleDateFormat is what you are looking for.
After you set isLenient to false, it will only accept correctly formatted dates anymore, and throw a ParseException in other cases.
String dateStr = "Mon Jan 32 00:00:00 IST 2015"; // 32 Jan 2015
DateFormat formatter = new SimpleDateFormat("E MMM dd HH:mm:ss Z yyyy");
formatter.setLenient(false);
DateFormat ddMMyyyy = new SimpleDateFormat("dd.MM.yyyy");
try {
System.out.println(ddMMyyyy.format(formatter.parse(dateStr)));
} catch (ParseException e) {
// Your date is invalid
}
You can use DateFormat.setLenient(boolean) to (from the Javadoc) with strict parsing, inputs must match this object's format.
DateFormat ddMMyyyy = new SimpleDateFormat("dd.MM.yyyy");
ddMMyyyy.setLenient(false);
Set the date formatter not to be lenient...
DateFormat formatter = new SimpleDateFormat("E MMM dd HH:mm:ss Z yyyy");
formatter.setLenient(false);
I am trying to convert String to Date to compare from current Date and it throws parse Exception
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", Locale.US);
try {
java.util.Date cookiedate = format.parse("Tue Apr 29 11:40:55 GMT+04:00 2014");
Calendar currentDate = Calendar.getInstance();
String dateNow = format.format(currentDate.getTime());
java.util.Date currDate = format.parse(dateNow);
if (currDate.getTime() > cookiedate.getTime()) {
return true;
}
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
In your format, "yyyy-MM-dd HH:mm:ss" will match date string like "2013-03-30 15:57:00", so you get a ParseException.
If you want to parse "Tue Apr 29 11:40:55 GMT+04:00 2014", you should use "EEE MMM dd HH:mm:ss z yyyy" Change your code to
SimpleDateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy", Locale.US);
At first, you should parse the string date to Date object using EEE MMM dd HH:mm:ss Z yyyy format then convert that Date to yyyy-MM-dd HH:mm:ss format as follows...
SimpleDateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss Z yyyy");
try {
Date cookiedate = format.parse("Tue Apr 29 11:40:55 GMT+04:00 2014");
Calendar currentDate = Calendar.getInstance();
format = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", Locale.US);
cookiedate = format.parse(format.parse(cookiedate));
String dateNow = format.format(currentDate.getTime());
Date currDate = format.parse(dateNow);
if (currDate.getTime() > cookiedate.getTime()) {
return true;
}
} catch (ParseException e) {
e.printStackTrace();
}
I think it is pretty obvious that formatted date "Tue Apr 29 11:40:55 GMT+04:00 2014" does not match format "yyyy-MM-dd HH:mm:ss".
If you are using format "yyyy-MM-dd HH:mm:ss" you should parse strings like 2014-03-30 10"59:23.
If you want to parse string like "Tue Apr 29 11:40:55 GMT+04:00 2014" you should use format like EEE MMM dd HH:mm:ss z yyyy. (I am not sure about z, probably it should be Z).
This question already has answers here:
How to parse a date? [duplicate]
(5 answers)
Closed 9 years ago.
I have a
String dateString = "Fri Feb 14 00:00:00 IST 2014";
I need output in Date datatype like 2014-02-14.
Here is the code which is throwing Parse exception.
Need help in this.
public static void main(String args[]){
DateFormat df = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
String dateString = "Fri Feb 14 00:00:00 IST 2014";
Date convertedDate = null;
try {
convertedDate = df.parse(dateString);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println(convertedDate);
}
Base point is - Input string should match with date pattern
Raised parse exception as becasue wrong pattern, use this date pattern - EEE MMM dd hh:mm:ss z yyyy
DateFormat df = new SimpleDateFormat("EEE MMM dd hh:mm:ss z yyyy");
You have to convert dateString to matching Date format and then you can format that Date what ever the format you want.
Try this
DateFormat df1 = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
DateFormat df2 = new SimpleDateFormat("EEE MMM dd hh:mm:ss z yyyy");
String dateString = "Fri Feb 14 00:00:00 IST 2014";
Date date=df2.parse(dateString); // convert stringDate to matching Date format
System.out.println(df1.format(date));
Out put:
2014-02-14 12:00:00
Try this:
public static void main(String[] args) {
DateFormat df = new SimpleDateFormat("EEE MMM dd hh:mm:ss z yyyy");
String dateString = "Fri Feb 14 00:00:00 IST 2014";
Date convertedDate = null;
try {
convertedDate = df.parse(dateString);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println(convertedDate);
}
I'm parsing a UTC Date string with SimpleDateFormat and it is parsed as the previous date.
DateFormat df = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss z");
This string "Fri, 06 Apr 2012 04:00:00 GMT" is being parsed as 4/5/2012. Why? Thanks.
Below is example of date conversion...
For your program, do changes accordingly and let me know what output you are getting.
String dateStr = "Thu Jan 19 2012 01:00 PM";
DateFormat readFormat = new SimpleDateFormat( "EEE MMM dd yyyy hh:mm aaa");
DateFormat writeFormat = new SimpleDateFormat( "yyyy-MM-dd HH:mm:ss");
Date date = null;
try {
date = readFormat.parse( dateStr );
} catch ( ParseException e ) {
e.printStackTrace();
}
String formattedDate = "";
if( date != null ) {
formattedDate = writeFormat.format( date );
}
System.out.println(formattedDate);
Output is 2012-01-19 13:00:00
Do the changes as per output you are expecting.
Beware of JDK 1.5.0_22 (linux). Produces incorrect date. Switched to JDK 1.6 problem gone.