Remove Known Part of String Java [closed] - java

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A little help please. I want to strip-off a portion of my string which is made up of a number in Java.
eg. Have the following Strings - 60067 ; 600567 and 600876 and '600676600'
How do I remove 600 from each of the strings in Java so I remain with
67 ; 567 and 876 and '676600'

As Pavneet said in his comment, this works well:
"60067".substring(3);
Also, if you want to make sure it is the string "600" that you are removing:
"60067".replaceFirst("600", "");
Java Strings have no remove method, so it's common to replace the String with a blank one, "".

try this:
String s = "60067 ; 600567 and 600876";
s = s.replaceAll("600", "");
System.out.println(s);
I got
67 ; 567 and 876

Related

last two occurance of semicolon(;) in given String using Java [closed]

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How do I get the after last two semicolon's occurrences of a string ?
Example:
Mobiles;Students;Test;Yes;1234
The output should be
Yes;1234
Using a regex replacement, we can try:
String input = "Mobiles;Students;Test;Yes;1234";
String output = input.replaceAll("^.*;([^;]+;[^;]+)$", "$1");
System.out.println(output); // Yes;1234

Regex to get the last value [closed]

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From the following value
[AAMP-PLAYER]aamp pos: [14..187..202..2196879032]
I want to get the last number 2196879032
Some times value will be -1
[AAMP-PLAYER]aamp pos: [14..187..202..-1]
Instead of split method how can i extract last digit using regex method
You could match the last (possibly negative) number at the end of the string, just before the closing ]:
(\-?\d+)\]$
A number is last if it is not followed (following it anywhere, not just immediately) by any other number.
(\-?\d+)(?!.*\d)
We could try using a String#replaceAll option here:
String input = "[AAMP-PLAYER]aamp pos: [14..187..202..2196879032]";
String num = input.replaceAll("^.*\\.\\.(-?\\d+).*$", "$1");
System.out.println(num);
This prints:
2196879032

How could I cut string strings by words according to a length? [closed]

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How can I cut a string string by words according to a length
String text = "Hello world welcome";
The maximum size of a row must be 15 characters, if you used the substring method I would stay like this
Hello wordl wel
come
and it should not be like that, it should be like that
Hello wordl
welcome
Use Apache Commons Text WordUtils.wrap() method:
String out = WordUtils.wrap("Hello world welcome", 15);
System.out.println(out);
will output:
Hello world
welcome

Changing the Lengths of Words in a String - Java [closed]

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I am currently writing a game in Java, where words in a string will have to be all changed to equal 5 characters a word.
eg. I am writing in Java
Iamwr iting inJav a
I wonder if anyone knows how I would do this?
First remove spaces between words.
Then split that resulting String to length with 5.
Add a space after every 5 character.

Regular expression, to get text after blank space [closed]

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I have this text:
1 A Maths
And i would like to get only Maths.
I donĀ“t know about regular expressions.
Can any one help me, please?
Thanks
Why don't you split the string ?
String chain="A Maths";
String[] array=chain.split(" ");
String number=array[0];
String course=array[1];
...
How to split a string in Java

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