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From the following value
[AAMP-PLAYER]aamp pos: [14..187..202..2196879032]
I want to get the last number 2196879032
Some times value will be -1
[AAMP-PLAYER]aamp pos: [14..187..202..-1]
Instead of split method how can i extract last digit using regex method
You could match the last (possibly negative) number at the end of the string, just before the closing ]:
(\-?\d+)\]$
A number is last if it is not followed (following it anywhere, not just immediately) by any other number.
(\-?\d+)(?!.*\d)
We could try using a String#replaceAll option here:
String input = "[AAMP-PLAYER]aamp pos: [14..187..202..2196879032]";
String num = input.replaceAll("^.*\\.\\.(-?\\d+).*$", "$1");
System.out.println(num);
This prints:
2196879032
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Input:
[the, and, land, wander, dreams]
Substring: "and"
Output: 3
I need to find all the occurrences of an array that contain a certain substring but all I found was the word itself. For example, I want it to count the "and" in the word "land" and "wander" as well. I don't know how to do that. Please help!
EDIT: Updated the code.
What about:
int cnt=0;
String[] input = {"the", "and", "land", "wander", "dreams"};
for (String str : input){
if (str.contains("and")){
cnt++;
}
}
System.out.println(cnt);
This code should work for you. But keep in mind following - Exbow is right, next time your question might be considered as useless and will be closed.
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any help with this would be greatly appreciated.
code in Java SE 8.
A string is inputted to represent a table.
if a row in the table contains the word NA it must be removed. ex..
if given String = "id,name,age,score\n1,Tom,NA,20\n17,Susan,25,15"
the table would be displayed as follows;
id name age score
1 Tom NA 20
5 Susan 25 15
As the second row contains 'NA' it needs to be removed. Ps Case matters, so if it says 'na' it doesn't need removed.
I have tried the following:
input = input.replaceAll("NULL,", "");
String lines[] = input.split("\\r?\\n");
for (String line : lines) {
System.out.println(line);
The problem is I need to remove the entire row where there is an occurrence of the word 'NA'
any ideas?
I recommend splitting the String with String.split('\n'); That will return an Array you can work with much easier. With that you can just filter the array for Strings that include NA.
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A little help please. I want to strip-off a portion of my string which is made up of a number in Java.
eg. Have the following Strings - 60067 ; 600567 and 600876 and '600676600'
How do I remove 600 from each of the strings in Java so I remain with
67 ; 567 and 876 and '676600'
As Pavneet said in his comment, this works well:
"60067".substring(3);
Also, if you want to make sure it is the string "600" that you are removing:
"60067".replaceFirst("600", "");
Java Strings have no remove method, so it's common to replace the String with a blank one, "".
try this:
String s = "60067 ; 600567 and 600876";
s = s.replaceAll("600", "");
System.out.println(s);
I got
67 ; 567 and 876
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how can I alter text string fields in java to only contain certain alphabetical characters (f,-)
in this format: 2f5-4, 2f6, 8f9
Only numbers f numbers and
numbers f number - numbers
You could use a regular expression to check, if the String in your text field is valid:
\d+f\d+(?:-\d+)?
Java code sample
Pattern pattern = Pattern.compile("\\d+f\\d+(?:-\\d+)?");
for (String s : new String[] {
"2f6", "2f9", "6f10", "5f9-2", "3f4-9"
}) {
System.out.println("String: \""+s+"\" match: "+pattern.matcher(s).matches());
}
Regex expression =>
(([0-9]+)([f])([0-9]*)|(([-])([0-9]*)))\w+
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I am currently writing a game in Java, where words in a string will have to be all changed to equal 5 characters a word.
eg. I am writing in Java
Iamwr iting inJav a
I wonder if anyone knows how I would do this?
First remove spaces between words.
Then split that resulting String to length with 5.
Add a space after every 5 character.