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How do I get the after last two semicolon's occurrences of a string ?
Example:
Mobiles;Students;Test;Yes;1234
The output should be
Yes;1234
Using a regex replacement, we can try:
String input = "Mobiles;Students;Test;Yes;1234";
String output = input.replaceAll("^.*;([^;]+;[^;]+)$", "$1");
System.out.println(output); // Yes;1234
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I want to mask the string before the first white space
Eg. "123 test1" mask to xxtest1
"12/6786 test2" mask to xxtest2
Using string replace all with regex
I tried this ^.*?[^\s]*\s and it seems to be working to your case.
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Can anyone help me to write code that find how many characters string has.
All you need is - int len = yourString.length();
StringUtils should provide you with something that you are looking for:
int count = StringUtils.countMatches("haahaahaa", "a");
System.out.println(count);
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I am currently writing a game in Java, where words in a string will have to be all changed to equal 5 characters a word.
eg. I am writing in Java
Iamwr iting inJav a
I wonder if anyone knows how I would do this?
First remove spaces between words.
Then split that resulting String to length with 5.
Add a space after every 5 character.
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I'm struggling to declare vowel values in my program, We need to remove the from the users input.
vowels = 'a';
vowels = "A";
it all compiles until i attempt to add a second value!
To remove all the vowels from a String s:
String withoutVowels = s.replaceAll("[aeiouAEIOU]", "");
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I have this text:
1 A Maths
And i would like to get only Maths.
I donĀ“t know about regular expressions.
Can any one help me, please?
Thanks
Why don't you split the string ?
String chain="A Maths";
String[] array=chain.split(" ");
String number=array[0];
String course=array[1];
...
How to split a string in Java