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I'm struggling to declare vowel values in my program, We need to remove the from the users input.
vowels = 'a';
vowels = "A";
it all compiles until i attempt to add a second value!
To remove all the vowels from a String s:
String withoutVowels = s.replaceAll("[aeiouAEIOU]", "");
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How do I get the after last two semicolon's occurrences of a string ?
Example:
Mobiles;Students;Test;Yes;1234
The output should be
Yes;1234
Using a regex replacement, we can try:
String input = "Mobiles;Students;Test;Yes;1234";
String output = input.replaceAll("^.*;([^;]+;[^;]+)$", "$1");
System.out.println(output); // Yes;1234
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My Friend ask me this question and i am posting it here, if you have better approach please share
String getRandomMobileNumber() {
double random = Math.random();
Double randomten = random*1000000000.0;
return "0"+Math.round(randomten);
}
You can use this, see javadoc:
String phoneNumber = "0" + ThreadLocalRandom.current().nextInt(10000000, 99999999);
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String mobiles="1234567890,0987654321,1234567890,1122334455"
I need output as
mobiles = "1234567890,0987654321,1122334455";
int count = 3;
I am coding in java.
Answer by #YSF_L is correct
String mobiles = Arrays.stream(mmobiles.split(",")) .distinct() .collect(Collectors.joining(","));
String[] mcounts = mobiles.split(",");
int Count = mcounts.length;
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Can anyone help me to write code that find how many characters string has.
All you need is - int len = yourString.length();
StringUtils should provide you with something that you are looking for:
int count = StringUtils.countMatches("haahaahaa", "a");
System.out.println(count);
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I have
String[] country={"USA","ks a","UK","France"};
I have a variable String z.
I want to say
if(z.equals(any element of my array (USA or ks or France)
but randomly:
if(z.equals(country[i]){
Doing action any code
}
Can anybody help me?
you can use
if ( Arrays.asList(country).contains(z)) {
// your code
}