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I want to mask the string before the first white space
Eg. "123 test1" mask to xxtest1
"12/6786 test2" mask to xxtest2
Using string replace all with regex
I tried this ^.*?[^\s]*\s and it seems to be working to your case.
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How do I get the after last two semicolon's occurrences of a string ?
Example:
Mobiles;Students;Test;Yes;1234
The output should be
Yes;1234
Using a regex replacement, we can try:
String input = "Mobiles;Students;Test;Yes;1234";
String output = input.replaceAll("^.*;([^;]+;[^;]+)$", "$1");
System.out.println(output); // Yes;1234
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Inputs ={6,7,8,9,10}
Outputs ={42,56,72,90}
Multiplication needs to be done
// arr[ ] = {6*7,7*8,8*9,9*10}
for i--> input.length
Outputs[i] = input[i]*input[i+1]
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I want to write a regex for this below pattern.
of John at /roger/adam/sam
here John is a value(can be alphanumeric) and /roger/adam/sam is an XPath with can change.
I want to replace all such instances with
of $value at $XPath
You can use the following to match
(of\s*)[a-zA-Z\d:-]+(\s*at\s*).*?(?=\s)
and replace with $1$value$2$XPath
See DEMO
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I am currently writing a game in Java, where words in a string will have to be all changed to equal 5 characters a word.
eg. I am writing in Java
Iamwr iting inJav a
I wonder if anyone knows how I would do this?
First remove spaces between words.
Then split that resulting String to length with 5.
Add a space after every 5 character.
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I have this text:
1 A Maths
And i would like to get only Maths.
I donĀ“t know about regular expressions.
Can any one help me, please?
Thanks
Why don't you split the string ?
String chain="A Maths";
String[] array=chain.split(" ");
String number=array[0];
String course=array[1];
...
How to split a string in Java