This question already has answers here:
Java - Unparseable date
(3 answers)
Closed 5 years ago.
I'm trying to convert a date from String to a Date object:
String dateString = "Mon, 04 Sep 2017 18:30:28";
String dateFormat = "EEE, dd MMM yyyy HH:mm:ss";
Results in the following exception:
java.text.ParseException: Unparseable date: "Mon, 04 Sep 2017 18:30:28"
I tried different strings and formats and the problems seems to be the name of week ('EEE'). Without it works perfectly.
Also this works perfectly:
String dateString = "04 Sep 2017 18:30:28, Mon";
String dateFormat = "dd MMM yyyy HH:mm:ss, EEE";
Month and weekdays are abbreviated text. The text is language dependent and if you don't provide a specific Locale when instantiating the SimpleDateFormatter the system's Locale is used instead. The reason why your parsing fails with the weekday and not the month can be that the abbreviated name of the month in your system's default language is coincidentally the same as in English.
Here is some code how you should parse a date with text:
SimpleDateFormat formatter = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss", Locale.ENGLISH);
formatter.setLenient(false);
ParsePosition pos = new ParsePosition(0);
return formatter.parse(toParse, pos);
with toParse being a string containing your date as text.
You haven't added the locale which must have caused parse exception while parsing text(s) for Day Of Week & Month
public static void main(String[] args) throws ParseException {
String dateString = "Mon, 04 Sep 2017 18:30:28";
SimpleDateFormat dateFormat = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss", Locale.ENGLISH);
System.out.println(dateFormat.parse(dateString));
}
Produces the following output
Mon Sep 04 18:30:28 IST 2017
Related
I am trying to parse this (and many similar) dateString - "Wed Aug 26 2020 11:03:30 GMT-0500"
Looking at the SimpleDateFormat documentation, I was assuming that a pattern like this should work:
String dateFormat = "EEE MMM d yyyy HH:mm:ss z";
However, it doesn't. But the following format is able to parse
String dateFormat = "EEE MMM d yyyy HH:mm:ss 'GMT'z";
But when I print the parsed date, I get the time with an hour added and offset reduced by an hour - Wed Aug 26 12:03:30 GMT-04:00 2020
What can I do to prevent this offset change?
Here is the sample code:
String dateStr = "Wed Aug 26 2020 11:03:30 GMT-0500";
String dateFormat = "EEE MMM d yyyy HH:mm:ss 'GMT'z";
Date date = new SimpleDateFormat(dateFormat).parse(dateStr);
System.out.println("Original Date String : "+dateStr);
System.out.println("Original Date Object : "+date);
Output:
Original Date String : Wed Aug 26 2020 11:03:30 GMT-0500
Original Date Object : Wed Aug 26 12:03:30 GMT-04:00 2020
Use java.time.OffsetDateTime here because there is no zone in that String, just an offset and the classes you are using are outdated for good reasons... Get rid of java.util.Date and java.text.SimpleDateFormat.
See this example:
public static void main(String[] args) {
// provide the String to be parsed
String dateStr = "Wed Aug 26 2020 11:03:30 GMT-0500";
// provide a matching pattern
String dateFormat = "EEE MMM d yyyy HH:mm:ss 'GMT'Z";
// create a formatter with this pattern and a suitable locale for unit names
DateTimeFormatter dtf = DateTimeFormatter.ofPattern(dateFormat, Locale.ENGLISH);
// parse the String to an OffsetDateTime using the formatter
OffsetDateTime odt = OffsetDateTime.parse(dateStr, dtf);
// print the result in the default format
System.out.println("Default/ISO format:\t" + odt);
// and print it in your custom format
System.out.println("Custom format:\t\t" + odt.format(dtf));
}
Output:
Default/ISO format: 2020-08-26T11:03:30-05:00
Custom format: Wed Aug 26 2020 11:03:30 GMT-0500
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Java - Unparseable date
(3 answers)
Closed 3 years ago.
I have a date that looks like that:
Sun Dec 29 00:24:09 CET 2019
I have a little utility method that parses a string date from a format to another:
public String formatDate(String date, String fromFormat, String toFormat) throws Exception {
SimpleDateFormat from = new SimpleDateFormat(fromFormat);
SimpleDateFormat to = new SimpleDateFormat(toFormat);
return to.format(from.parse(date));
}
However, with above date format, I do not find the correct date pattern to indicate to my method.
According to SimpleDateFormat patterns documentation, it should be (if I am not mistaken), the following (for Sun Dec 29 00:24:09 CET 2019):
"E M d HH:mm:ss z yyyy"
However, it throws the following exception:
java.text.ParseException: Unparseable date: "Sun Dec 29 00:24:09 CET 2019"
at java.text.DateFormat.parse(DateFormat.java:366)
at com.aptar.simulator.Utils.formatDate(Utils.java:60)
The method is called like this:
formatDate(exDate, "E M d HH:mm:ss z yyyy", "dd-MM-yyyy HH:mm:ss");
Where
exDate = "Sun Dec 29 00:24:09 CET 2019"
Try below solution -
formatDate("Sun Dec 29 00:24:09 CET 2019","EEE MMM d HH:mm:ss z yyyy","dd-MM-yyyy HH:mm:ss");
Format should be - "EEE MMM d HH:mm:ss z yyyy"
You should use EEE for Sun and MMM for Dec
hope this helps.
Date format should be
EEE MMM dd HH:mm:ss z yyyy
Your code works fine using this format.
using java.time API
LocalDate.parse(datestr, DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss z yyyy")).format("TO DATE PATTERN");
Further details at Using java.time package to format date
Please find the code snippet below to solve your problem. The issue was the letter codes were correct, but there was character count mismatch , hence causing the issue. E.g.:Sun has three chars, but you were using a single E in your formatter.
public class Examp167 {
public static String formatDate(String date, String fromFormat, String toFormat) throws Exception {
SimpleDateFormat from = new SimpleDateFormat(fromFormat);
SimpleDateFormat to = new SimpleDateFormat(toFormat);
return to.format(from.parse(date));
}
public static void main(String[] args) throws Exception{
String exDate = "Sun Dec 29 00:24:09 CET 2019";
System.out.println( formatDate(exDate, "EEE MMM dd HH:mm:ss zzz yyyy", "dd-MM-yyyy HH:mm:ss"));
}
}
Firs use DateTimeFormatter instead of an old outdated class, then you should set the Locale since the day and month names are in English and last the in format needs to be MMM instead of M for the month
public static String formatDate(String date, String fromFormat, String toFormat) throws Exception {
DateTimeFormatter inFormatter = DateTimeFormatter.ofPattern(fromFormat, Locale.US);
DateTimeFormatter outFormatter = DateTimeFormatter.ofPattern(toFormat, Locale.US);
return outFormatter.format(inFormatter.parse(date));
}
Example:
String exDate = "Sun Dec 29 00:24:09 CET 2019";
String out = formatDate(exDate, "E MMM d HH:mm:ss z yyyy", "dd-MM-yyyy HH:mm:ss");
System.out.println(out);
29-12-2019 00:24:09
This question already has answers here:
How can I parse/format dates with LocalDateTime? (Java 8)
(11 answers)
Closed 4 years ago.
I am using the below code to convert a date in String :
String strDate="Thu Aug 09 16:01:46 IST 2018";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SSS");
LocalDateTime dateTime = LocalDateTime.parse(strDate,formatter);
I am getting the below exception :
java.time.format.DateTimeParseException: Text 'Thu Aug 09 16:01:46 IST 2018' could not be parsed at index 0
The format in the variable 'strDate' will be same and cannot be modified as i will be getting that from a different application
The date format for your input string would be : E MMM dd HH:mm:ss z yyyy. Below code should work without any error
public static void main(String[] args) throws IOException {
String strDate = "Thu Aug 09 16:01:46 IST 2018";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("E MMM dd HH:mm:ss z yyyy");
LocalDateTime dateTime = LocalDateTime.parse(strDate, formatter);
}
This question already has answers here:
Parsing Java String into GMT Date
(5 answers)
Illegal pattern character 'T' when parsing a date string to java.util.Date
(4 answers)
Java - unparseable date, need format to match "GMT-0400"
(2 answers)
Closed 5 years ago.
I have a date in string format like this. It is coming from some other souce in the below format and I cannot change that:
2025-08-08T15%3A41%3A46
I have to convert above string date in this format now:
Fri Aug 08 15:41:46 GMT-07:00 2025
So below is what I have tried:
String decodedDate = URLDecoder.decode("2025-08-08T15%3A41%3A46", "UTF-8");
SimpleDateFormat dateParser = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss", Locale.US);
Date date = dateParser.parse(decodedDate);
System.out.println(date);
And this is what it prints out on the console. It prints out PDT instead of GMT-07:00. How can I get that?
Fri Aug 08 15:41:46 PDT 2025
Also I am working with Java 7 and I can use joda-time library as well. This conversion method can be called by multiple threads.
In the desired output it is printing out GMT-07:00 so how can I get the timezone also in my code?
Update:-
How about doing this way?
SimpleDateFormat dateParser = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss", Locale.US);
TimeZone.setDefault(TimeZone.getTimeZone("GMT-07:00"));
String decodedDate = URLDecoder.decode("2025-08-08T15%3A41%3A46", "UTF-8");
Date date = dateParser.parse(decodedDate);
System.out.println(date.toString());
SimpleDateFormat dateParser = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss", Locale.US);
String decodedDate = URLDecoder.decode("2025-08-08T15%3A41%3A46", "UTF-8");
Date date = dateParser.parse(decodedDate);
//Decode the given date and convert to Date object
SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd hh:mm:ss z-07:00 yyyy", Locale.US);
sdf.setTimeZone(TimeZone.getTimeZone("GMT"));
System.out.println(sdf.format(date)); // set the timezone and print in the desired format
Output:
Fri Aug 08 07:41:46 GMT-07:00 2025
Update: As suggected by KevinO, a better way to do is
SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd hh:mm:ss z yyyy", Locale.US);
sdf.setTimeZone(TimeZone.getTimeZone("GMT-0700"));
This question already has answers here:
How to convert date in to yyyy-MM-dd Format?
(6 answers)
How can I convert Date.toString back to Date?
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Java - Unparseable date
(3 answers)
Closed 5 years ago.
I got problem with date parse example date:
SimpleDateFormat parserSDF=new SimpleDateFormat("EEE MMM dd HH:mm:ss zzzz yyyy", Locale.getDefault());
parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
got exception
Exacly I want parse this format date to yyyy-MM-dd
I try:
SimpleDateFormat parserSDF = new SimpleDateFormat("yyyy-MM-dd", Locale.ENGLISH);
Date date = parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
take :
java.text.ParseException: Unparseable date: "Wed Oct 16 00:00:00 CEST 2013"
OK I change to and works :
SimpleDateFormat parserSDF = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzzz yyyy", Locale.ENGLISH);
Date date = parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
I'm going to assume that Locale.getDefault() for you is pl-PL since you seem to be in Poland.
English words in date strings therefore cause an unparseable date.
An appropriate Polish date String would be something like
"Wt paź 16 00:00:00 -0500 2013"
Otherwise, change your Locale to Locale.ENGLISH so that the SimpleDateFormat object can parse String dates with English words.
Instead of using Locale.default that you and others often don't know which default, you can decide by using locale.ENGLISH because I see your string date is format in English. If you are at other countries, the format will be different.
Here is my example code:
public static void main(String[] args) {
try {
SimpleDateFormat parserSDF = new SimpleDateFormat("EEE MMM dd HH:mm:ss Z yyyy", Locale.ENGLISH);
Date date = parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
System.out.println("date: " + date.toString());
} catch (ParseException ex) {
ex.printStackTrace();
}
}
The result will be : date: Wed Oct 16 05:00:00 ICT 2013. Or you can decide which part of this date to be printed, by using its fields.
Hope this help :)
I think the original Exception is due to Z in your format.
Per documentation:
Z Time zone RFC 822 time zone -0800
most likely you meant to use lower case z