This question already has answers here:
How can I parse/format dates with LocalDateTime? (Java 8)
(11 answers)
Closed 4 years ago.
I am using the below code to convert a date in String :
String strDate="Thu Aug 09 16:01:46 IST 2018";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SSS");
LocalDateTime dateTime = LocalDateTime.parse(strDate,formatter);
I am getting the below exception :
java.time.format.DateTimeParseException: Text 'Thu Aug 09 16:01:46 IST 2018' could not be parsed at index 0
The format in the variable 'strDate' will be same and cannot be modified as i will be getting that from a different application
The date format for your input string would be : E MMM dd HH:mm:ss z yyyy. Below code should work without any error
public static void main(String[] args) throws IOException {
String strDate = "Thu Aug 09 16:01:46 IST 2018";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("E MMM dd HH:mm:ss z yyyy");
LocalDateTime dateTime = LocalDateTime.parse(strDate, formatter);
}
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Java - Unparseable date
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Closed 3 years ago.
I have a date that looks like that:
Sun Dec 29 00:24:09 CET 2019
I have a little utility method that parses a string date from a format to another:
public String formatDate(String date, String fromFormat, String toFormat) throws Exception {
SimpleDateFormat from = new SimpleDateFormat(fromFormat);
SimpleDateFormat to = new SimpleDateFormat(toFormat);
return to.format(from.parse(date));
}
However, with above date format, I do not find the correct date pattern to indicate to my method.
According to SimpleDateFormat patterns documentation, it should be (if I am not mistaken), the following (for Sun Dec 29 00:24:09 CET 2019):
"E M d HH:mm:ss z yyyy"
However, it throws the following exception:
java.text.ParseException: Unparseable date: "Sun Dec 29 00:24:09 CET 2019"
at java.text.DateFormat.parse(DateFormat.java:366)
at com.aptar.simulator.Utils.formatDate(Utils.java:60)
The method is called like this:
formatDate(exDate, "E M d HH:mm:ss z yyyy", "dd-MM-yyyy HH:mm:ss");
Where
exDate = "Sun Dec 29 00:24:09 CET 2019"
Try below solution -
formatDate("Sun Dec 29 00:24:09 CET 2019","EEE MMM d HH:mm:ss z yyyy","dd-MM-yyyy HH:mm:ss");
Format should be - "EEE MMM d HH:mm:ss z yyyy"
You should use EEE for Sun and MMM for Dec
hope this helps.
Date format should be
EEE MMM dd HH:mm:ss z yyyy
Your code works fine using this format.
using java.time API
LocalDate.parse(datestr, DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss z yyyy")).format("TO DATE PATTERN");
Further details at Using java.time package to format date
Please find the code snippet below to solve your problem. The issue was the letter codes were correct, but there was character count mismatch , hence causing the issue. E.g.:Sun has three chars, but you were using a single E in your formatter.
public class Examp167 {
public static String formatDate(String date, String fromFormat, String toFormat) throws Exception {
SimpleDateFormat from = new SimpleDateFormat(fromFormat);
SimpleDateFormat to = new SimpleDateFormat(toFormat);
return to.format(from.parse(date));
}
public static void main(String[] args) throws Exception{
String exDate = "Sun Dec 29 00:24:09 CET 2019";
System.out.println( formatDate(exDate, "EEE MMM dd HH:mm:ss zzz yyyy", "dd-MM-yyyy HH:mm:ss"));
}
}
Firs use DateTimeFormatter instead of an old outdated class, then you should set the Locale since the day and month names are in English and last the in format needs to be MMM instead of M for the month
public static String formatDate(String date, String fromFormat, String toFormat) throws Exception {
DateTimeFormatter inFormatter = DateTimeFormatter.ofPattern(fromFormat, Locale.US);
DateTimeFormatter outFormatter = DateTimeFormatter.ofPattern(toFormat, Locale.US);
return outFormatter.format(inFormatter.parse(date));
}
Example:
String exDate = "Sun Dec 29 00:24:09 CET 2019";
String out = formatDate(exDate, "E MMM d HH:mm:ss z yyyy", "dd-MM-yyyy HH:mm:ss");
System.out.println(out);
29-12-2019 00:24:09
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Java: How to convert string with month name to DateTime?
(1 answer)
How to get current moment in ISO 8601 format with date, hour, and minute?
(23 answers)
Closed 3 years ago.
How do I parse this date "Wednesday, 12 June 2019 14:23:39" which comes as a String to a date format like this "2019-03-05T11:56:13Z" in JAVA?
You should use the java.time API for this:
DateTimeFormatter dateTimeFormatter = DateTimeFormatter.ofPattern("EEEE, dd MMMM yyyy HH:mm:ss", Locale.ENGLISH);
LocalDateTime localDateTime = LocalDateTime.parse("Wednesday, 12 June 2019 14:23:39", dateTimeFormatter);
String isoDateTime = localDateTime.format(DateTimeFormatter.ISO_DATE_TIME);
System.out.println(isoDateTime);
which results in:
2019-06-12T14:23:39
attached example of how you can parsar your date
greetings
public static void main(String[] args) throws ParseException {
String date_s = "2011-01-18 00:00:00.0";
// *** note that it's "yyyy-MM-dd hh:mm:ss" not "yyyy-mm-dd hh:mm:ss"
SimpleDateFormat dt = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
Date date = dt.parse(date_s);
// *** same for the format String below
SimpleDateFormat dt1 = new SimpleDateFormat("E, dd MMM yyyy hh:mm:ss");
System.out.println(dt1.format(date));
}
enter image description here
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Change date format in a Java string
(22 answers)
Closed 3 years ago.
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("EEE MMM dd yyyy HH:mm:ss");
OR
java.text.DateFormat dateFormat = new java.text.SimpleDateFormat("EEE MMM dd yyyy HH:mm:ss");
I have the format of time in data bases tables and I have to convert them into yyyy-MM-dd HH:mm:ss or MM/dd/YYYY HH:mm:ss
Input : Mon Jan 21 2019 20:06:48 GMT-0400 (EDT)
Expected output : 01/21/2019 20:06:48
21 January, 2019 is a Monday not a Thursay, Java'll throws an error when parsing
You need an formatter to parse your string, and a formatter to print the date like you want
if your system use by default Locale.ENGLISH you can remove it) :
String input = "Mon Jan 21 2019 20:06:48 GMT-0400 (EDT)";
DateTimeFormatter inFormatter = DateTimeFormatter.ofPattern("EE MMM dd yyyy HH:mm:ss 'GMT'xx (z)");
DateTimeFormatter outFormatter = DateTimeFormatter.ofPattern("MM/dd/yy HH:mm:ss");
OffsetDateTime od = OffsetDateTime.parse(input, inFormatter);
System.out.println(od); // 2019-01-21T20:06:48-04:00
System.out.println(od.format(outFormatter)); // 01/21/19 20:06:48
This question already has answers here:
How can I convert Date.toString back to Date?
(5 answers)
Closed 4 years ago.
Unparseable date: "Tue Jul 03 16:59:51 IST 2018" Exception
String date="Tue Jul 03 16:59:51 IST 2018";
i want to parse it.
My code is
SimpleDateFormat newformat=SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ")
Date d=newformat.parse(date);
You are using old and quite problematic classes, especially Date.
For your example, perhaps consider using LocalDateTime
String date = "Tue Jul 03 16:59:51 IST 2018";
DateTimeFormatter format = DateTimeFormatter
.ofPattern("EEE MMM dd HH:mm:ss z yyyy");
LocalDateTime dateTime = LocalDateTime.parse(date, format);
Since your pattern has to match the string you want to parse you need to adjust the pattern as following:
EEE MMM dd HH:mm:ss z yyyy
Infos gathered from the docs.
You should also use the new java.time API introduced with Java 8.
String s = "Tue Jul 03 16:59:51 IST 2018";
//Java 7 way
SimpleDateFormat newformat = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy");
Date d = newformat.parse(s);
//Java 8 way
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss z yyyy");
LocalDateTime dateTime = LocalDateTime.parse(s, formatter);
This question already has answers here:
Java - Unparseable date
(3 answers)
Closed 5 years ago.
I'm trying to convert a date from String to a Date object:
String dateString = "Mon, 04 Sep 2017 18:30:28";
String dateFormat = "EEE, dd MMM yyyy HH:mm:ss";
Results in the following exception:
java.text.ParseException: Unparseable date: "Mon, 04 Sep 2017 18:30:28"
I tried different strings and formats and the problems seems to be the name of week ('EEE'). Without it works perfectly.
Also this works perfectly:
String dateString = "04 Sep 2017 18:30:28, Mon";
String dateFormat = "dd MMM yyyy HH:mm:ss, EEE";
Month and weekdays are abbreviated text. The text is language dependent and if you don't provide a specific Locale when instantiating the SimpleDateFormatter the system's Locale is used instead. The reason why your parsing fails with the weekday and not the month can be that the abbreviated name of the month in your system's default language is coincidentally the same as in English.
Here is some code how you should parse a date with text:
SimpleDateFormat formatter = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss", Locale.ENGLISH);
formatter.setLenient(false);
ParsePosition pos = new ParsePosition(0);
return formatter.parse(toParse, pos);
with toParse being a string containing your date as text.
You haven't added the locale which must have caused parse exception while parsing text(s) for Day Of Week & Month
public static void main(String[] args) throws ParseException {
String dateString = "Mon, 04 Sep 2017 18:30:28";
SimpleDateFormat dateFormat = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss", Locale.ENGLISH);
System.out.println(dateFormat.parse(dateString));
}
Produces the following output
Mon Sep 04 18:30:28 IST 2017