This question already has answers here:
How to get date from date time in java
(6 answers)
Why can't this SimpleDateFormat parse this date string?
(4 answers)
how to parse output of new Date().toString()
(4 answers)
Java - Unparseable date
(3 answers)
Closed 3 years ago.
I have a date that looks like that:
Sun Dec 29 00:24:09 CET 2019
I have a little utility method that parses a string date from a format to another:
public String formatDate(String date, String fromFormat, String toFormat) throws Exception {
SimpleDateFormat from = new SimpleDateFormat(fromFormat);
SimpleDateFormat to = new SimpleDateFormat(toFormat);
return to.format(from.parse(date));
}
However, with above date format, I do not find the correct date pattern to indicate to my method.
According to SimpleDateFormat patterns documentation, it should be (if I am not mistaken), the following (for Sun Dec 29 00:24:09 CET 2019):
"E M d HH:mm:ss z yyyy"
However, it throws the following exception:
java.text.ParseException: Unparseable date: "Sun Dec 29 00:24:09 CET 2019"
at java.text.DateFormat.parse(DateFormat.java:366)
at com.aptar.simulator.Utils.formatDate(Utils.java:60)
The method is called like this:
formatDate(exDate, "E M d HH:mm:ss z yyyy", "dd-MM-yyyy HH:mm:ss");
Where
exDate = "Sun Dec 29 00:24:09 CET 2019"
Try below solution -
formatDate("Sun Dec 29 00:24:09 CET 2019","EEE MMM d HH:mm:ss z yyyy","dd-MM-yyyy HH:mm:ss");
Format should be - "EEE MMM d HH:mm:ss z yyyy"
You should use EEE for Sun and MMM for Dec
hope this helps.
Date format should be
EEE MMM dd HH:mm:ss z yyyy
Your code works fine using this format.
using java.time API
LocalDate.parse(datestr, DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss z yyyy")).format("TO DATE PATTERN");
Further details at Using java.time package to format date
Please find the code snippet below to solve your problem. The issue was the letter codes were correct, but there was character count mismatch , hence causing the issue. E.g.:Sun has three chars, but you were using a single E in your formatter.
public class Examp167 {
public static String formatDate(String date, String fromFormat, String toFormat) throws Exception {
SimpleDateFormat from = new SimpleDateFormat(fromFormat);
SimpleDateFormat to = new SimpleDateFormat(toFormat);
return to.format(from.parse(date));
}
public static void main(String[] args) throws Exception{
String exDate = "Sun Dec 29 00:24:09 CET 2019";
System.out.println( formatDate(exDate, "EEE MMM dd HH:mm:ss zzz yyyy", "dd-MM-yyyy HH:mm:ss"));
}
}
Firs use DateTimeFormatter instead of an old outdated class, then you should set the Locale since the day and month names are in English and last the in format needs to be MMM instead of M for the month
public static String formatDate(String date, String fromFormat, String toFormat) throws Exception {
DateTimeFormatter inFormatter = DateTimeFormatter.ofPattern(fromFormat, Locale.US);
DateTimeFormatter outFormatter = DateTimeFormatter.ofPattern(toFormat, Locale.US);
return outFormatter.format(inFormatter.parse(date));
}
Example:
String exDate = "Sun Dec 29 00:24:09 CET 2019";
String out = formatDate(exDate, "E MMM d HH:mm:ss z yyyy", "dd-MM-yyyy HH:mm:ss");
System.out.println(out);
29-12-2019 00:24:09
Related
This question already has answers here:
How can I parse/format dates with LocalDateTime? (Java 8)
(11 answers)
Closed 4 years ago.
I am using the below code to convert a date in String :
String strDate="Thu Aug 09 16:01:46 IST 2018";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SSS");
LocalDateTime dateTime = LocalDateTime.parse(strDate,formatter);
I am getting the below exception :
java.time.format.DateTimeParseException: Text 'Thu Aug 09 16:01:46 IST 2018' could not be parsed at index 0
The format in the variable 'strDate' will be same and cannot be modified as i will be getting that from a different application
The date format for your input string would be : E MMM dd HH:mm:ss z yyyy. Below code should work without any error
public static void main(String[] args) throws IOException {
String strDate = "Thu Aug 09 16:01:46 IST 2018";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("E MMM dd HH:mm:ss z yyyy");
LocalDateTime dateTime = LocalDateTime.parse(strDate, formatter);
}
This question already has answers here:
How can I convert Date.toString back to Date?
(5 answers)
Closed 4 years ago.
Unparseable date: "Tue Jul 03 16:59:51 IST 2018" Exception
String date="Tue Jul 03 16:59:51 IST 2018";
i want to parse it.
My code is
SimpleDateFormat newformat=SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ")
Date d=newformat.parse(date);
You are using old and quite problematic classes, especially Date.
For your example, perhaps consider using LocalDateTime
String date = "Tue Jul 03 16:59:51 IST 2018";
DateTimeFormatter format = DateTimeFormatter
.ofPattern("EEE MMM dd HH:mm:ss z yyyy");
LocalDateTime dateTime = LocalDateTime.parse(date, format);
Since your pattern has to match the string you want to parse you need to adjust the pattern as following:
EEE MMM dd HH:mm:ss z yyyy
Infos gathered from the docs.
You should also use the new java.time API introduced with Java 8.
String s = "Tue Jul 03 16:59:51 IST 2018";
//Java 7 way
SimpleDateFormat newformat = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy");
Date d = newformat.parse(s);
//Java 8 way
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss z yyyy");
LocalDateTime dateTime = LocalDateTime.parse(s, formatter);
This question already has answers here:
Java - Unparseable date
(3 answers)
Closed 5 years ago.
I'm trying to convert a date from String to a Date object:
String dateString = "Mon, 04 Sep 2017 18:30:28";
String dateFormat = "EEE, dd MMM yyyy HH:mm:ss";
Results in the following exception:
java.text.ParseException: Unparseable date: "Mon, 04 Sep 2017 18:30:28"
I tried different strings and formats and the problems seems to be the name of week ('EEE'). Without it works perfectly.
Also this works perfectly:
String dateString = "04 Sep 2017 18:30:28, Mon";
String dateFormat = "dd MMM yyyy HH:mm:ss, EEE";
Month and weekdays are abbreviated text. The text is language dependent and if you don't provide a specific Locale when instantiating the SimpleDateFormatter the system's Locale is used instead. The reason why your parsing fails with the weekday and not the month can be that the abbreviated name of the month in your system's default language is coincidentally the same as in English.
Here is some code how you should parse a date with text:
SimpleDateFormat formatter = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss", Locale.ENGLISH);
formatter.setLenient(false);
ParsePosition pos = new ParsePosition(0);
return formatter.parse(toParse, pos);
with toParse being a string containing your date as text.
You haven't added the locale which must have caused parse exception while parsing text(s) for Day Of Week & Month
public static void main(String[] args) throws ParseException {
String dateString = "Mon, 04 Sep 2017 18:30:28";
SimpleDateFormat dateFormat = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss", Locale.ENGLISH);
System.out.println(dateFormat.parse(dateString));
}
Produces the following output
Mon Sep 04 18:30:28 IST 2017
This question already has answers here:
How to convert date in to yyyy-MM-dd Format?
(6 answers)
How can I convert Date.toString back to Date?
(5 answers)
Java - Unparseable date
(3 answers)
Closed 5 years ago.
I got problem with date parse example date:
SimpleDateFormat parserSDF=new SimpleDateFormat("EEE MMM dd HH:mm:ss zzzz yyyy", Locale.getDefault());
parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
got exception
Exacly I want parse this format date to yyyy-MM-dd
I try:
SimpleDateFormat parserSDF = new SimpleDateFormat("yyyy-MM-dd", Locale.ENGLISH);
Date date = parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
take :
java.text.ParseException: Unparseable date: "Wed Oct 16 00:00:00 CEST 2013"
OK I change to and works :
SimpleDateFormat parserSDF = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzzz yyyy", Locale.ENGLISH);
Date date = parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
I'm going to assume that Locale.getDefault() for you is pl-PL since you seem to be in Poland.
English words in date strings therefore cause an unparseable date.
An appropriate Polish date String would be something like
"Wt paź 16 00:00:00 -0500 2013"
Otherwise, change your Locale to Locale.ENGLISH so that the SimpleDateFormat object can parse String dates with English words.
Instead of using Locale.default that you and others often don't know which default, you can decide by using locale.ENGLISH because I see your string date is format in English. If you are at other countries, the format will be different.
Here is my example code:
public static void main(String[] args) {
try {
SimpleDateFormat parserSDF = new SimpleDateFormat("EEE MMM dd HH:mm:ss Z yyyy", Locale.ENGLISH);
Date date = parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
System.out.println("date: " + date.toString());
} catch (ParseException ex) {
ex.printStackTrace();
}
}
The result will be : date: Wed Oct 16 05:00:00 ICT 2013. Or you can decide which part of this date to be printed, by using its fields.
Hope this help :)
I think the original Exception is due to Z in your format.
Per documentation:
Z Time zone RFC 822 time zone -0800
most likely you meant to use lower case z
This question already has answers here:
Java string to date conversion
(17 answers)
Closed 7 years ago.
How do I parse the date string below into a Date object?
String target = "Thu Sep 28 20:29:30 JST 2000";
DateFormat df = new SimpleDateFormat("E MM dd kk:mm:ss z yyyy");
Date result = df.parse(target);
Throws exception...
java.text.ParseException: Unparseable date: "Thu Sep 28 20:29:30 JST 2000"
at java.text.DateFormat.parse(DateFormat.java:337)
The pattern is wrong. You have a 3-letter day abbreviation, so it must be EEE. You have a 3-letter month abbreviation, so it must be MMM. As those day and month abbreviations are locale sensitive, you'd like to explicitly specify the SimpleDateFormat locale to English as well, otherwise it will use the platform default locale which may not be English per se.
public static void main(String[] args) throws Exception {
String target = "Thu Sep 28 20:29:30 JST 2000";
DateFormat df = new SimpleDateFormat("EEE MMM dd kk:mm:ss z yyyy", Locale.ENGLISH);
Date result = df.parse(target);
System.out.println(result);
}
This prints here
Thu Sep 28 07:29:30 BOT 2000
which is correct as per my timezone.
I would also reconsider if you wouldn't rather like to use HH instead of kk. Read the javadoc for details about valid patterns.
Here is a working example:
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.text.DateFormat;
import java.util.Date;
public class j4496359 {
public static void main(String[] args) {
try {
String target = "Thu Sep 28 20:29:30 JST 2000";
DateFormat df = new SimpleDateFormat("EEE MMM dd kk:mm:ss zzz yyyy");
Date result = df.parse(target);
System.out.println(result);
} catch (ParseException pe) {
pe.printStackTrace();
}
}
}
Will print:
Thu Sep 28 13:29:30 CEST 2000
String target = "27-09-1991 20:29:30";
DateFormat df = new SimpleDateFormat("dd MM yyyy HH:mm:ss");
Date result = df.parse(target);
System.out.println(result);
This works fine?
new SimpleDateFormat("EEE MMM dd kk:mm:ss ZZZ yyyy");
and
new SimpleDateFormat("EEE MMM dd kk:mm:ss Z yyyy");
still runs. However, if your code throws an exception it is because your tool or jdk or any other reason. Because I got same error in my IDE but please check these http://ideone.com/Y2cRr (online ide) with ZZZ and with Z
output is : Thu Sep 28 11:29:30 GMT 2000
I had this issue, and I set the Locale to US, then it work.
static DateFormat visitTimeFormat = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy",Locale.US);
for String "Sun Jul 08 00:06:30 UTC 2012"
A parse exception is a checked exception, so you must catch it with a try-catch when working with parsing Strings to Dates, as #miku suggested...