Parameterless methods/static

Parameterless methods/static - java

As my name suggests, I am a .NET developer but I have a growing interest in Java, and I am interested in learning more about other languages as this helps me to learn more about programming generally.
Anyway, my question is this: Methods which don't take parameters/work with state (which is just parameters in the method, correct me if I am wrong) are recommended to be made static. What is the relationship/link between static and parameterless methods? Not working with state means if you pass a Person object into the method, and you don't edit that object's state (Eg its properties) - this is my understanding.
I don't mind any Java specific answers.
Thanks

"What is the relationship/link between static and parameterless methods? "
None.
"Methods which don't take parameters/work with state... are recommended to be made static"
Really? By whom? Can you provide a link or quote?
Static means that the method belongs to the class -- as a whole -- not any specific object of that class. Therefore, static methods can only deal with static variables, not instance variables.
Parameterless doesn't mean anything. It may be that the method deals only with instance variables or only with static variables. Or it returns a constant. Or it has some calculation which is private to that method. It could, for example, create a socket, do a read using HTTP, and destroy the socket. No parameters; no instance variables.

There is no relationship between static and parameterless methods.
A static method is one which does not access instance state in the receiving class (and therefore does not need to be associated with a particular instance). It can easily take parameters:
public class Calculator
{
public static int Add(int a, int b) { return a + b; } // does not need any Calculator state
}
A static method can access its parameters (and can therefore modify their state if they allow it):
public class Officialdom
{
public static void Rename(Person person) { person.Name = "Bob"; } // does not need any Officialdom state
}
Conversely, a parameterless method might well need to access receiver state, and therefore be an instance (non-static) method:
public class Spline
{
private bool _isReticulated;
public void Reticulate()
{
_isReticulated = true; // does need Spline state
}
}
(I've posted code samples in C# because this is language-independent; the same notions and distinctions apply in Java, possibly with a few keyword changes.)

there is no connection between static methods and what they do with parameters passed into them. static methods are CLASS level methods and not INSTANCE level in Java. static methods are associated with the Class they are declared in and not instances of those classes.

There's a general principle that methods should not have access to more data than they need. This is one of the reasons why member variables are usually private and OO uses encapsulation to hide data and code from other parts of the system.
When you have a function which does not require access to the variables in that class, some people recommend making the method static.
Whether or not a function has parameters does not affect whether it has access to instance methods.

Related

What's the benefit of using class name to access static methods and static variables in java instead of creating objects and calling them? [duplicate]

I am wondering when to use static methods? Say if I have a class with a few getters and setters, a method or two, and I want those methods only to be invokable on an instance object of the class. Does this mean I should use a static method?
Example:
Obj x = new Obj();
x.someMethod();
...or:
Obj.someMethod(); // Is this the static way?
I'm rather confused!

One rule-of-thumb: ask yourself "Does it make sense to call this method, even if no object has been constructed yet?" If so, it should definitely be static.
So in a class Car you might have a method:
double convertMpgToKpl(double mpg)
...which would be static, because one might want to know what 35mpg converts to, even if nobody has ever built a Car. But this method (which sets the efficiency of one particular Car):
void setMileage(double mpg)
...can't be static since it's inconceivable to call the method before any Car has been constructed.
(By the way, the converse isn't always true: you might sometimes have a method which involves two Car objects, and still want it to be static. E.g.:
Car theMoreEfficientOf(Car c1, Car c2)
Although this could be converted to a non-static version, some would argue that since there isn't a "privileged" choice of which Car is more important, you shouldn't force a caller to choose one Car as the object you'll invoke the method on. This situation accounts for a fairly small fraction of all static methods, though.

Define static methods in the following scenarios only:
If you are writing utility classes and they are not supposed to be changed.
If the method is not using any instance variable.
If any operation is not dependent on instance creation.
If there is some code that can easily be shared by all the instance methods, extract that code into a static method.
If you are sure that the definition of the method will never be changed or overridden. As static methods can not be overridden.

There are some valid reasons to use static methods:
Performance: if you want some code to be run, and don't want to instantiate an extra object to do so, shove it into a static method. The JVM also can optimize static methods a lot (I think I've once read James Gosling declaring that you don't need custom instructions in the JVM, since static methods will be just as fast, but couldn't find the source - thus it could be completely false). Yes, it is micro-optimization, and probably unneeded. And we programmers never do unneeded things just because they are cool, right?
Practicality: instead of calling new Util().method(arg), call Util.method(arg), or method(arg) with static imports. Easier, shorter.
Adding methods: you really wanted the class String to have a removeSpecialChars() instance method, but it's not there (and it shouldn't, since your project's special characters may be different from the other project's), and you can't add it (since Java is somewhat sane), so you create an utility class, and call removeSpecialChars(s) instead of s.removeSpecialChars(). Sweet.
Purity: taking some precautions, your static method will be a pure function, that is, the only thing it depends on is its parameters. Data in, data out. This is easier to read and debug, since you don't have inheritance quirks to worry about. You can do it with instance methods too, but the compiler will help you a little more with static methods (by not allowing references to instance attributes, overriding methods, etc.).
You'll also have to create a static method if you want to make a singleton, but... don't. I mean, think twice.
Now, more importantly, why you wouldn't want to create a static method? Basically, polymorphism goes out of the window. You'll not be able to override the method, nor declare it in an interface (pre-Java 8). It takes a lot of flexibility out from your design. Also, if you need state, you'll end up with lots of concurrency bugs and/or bottlenecks if you are not careful.

After reading Misko's articles I believe that static methods are bad from a testing point of view. You should have factories instead(maybe using a dependency injection tool like Guice).
how do I ensure that I only have one of something
only have one of something
The problem of “how do I ensure that I
only have one of something” is nicely
sidestepped. You instantiate only a
single ApplicationFactory in your
main, and as a result, you only
instantiate a single instance of all
of your singletons.
The basic issue with static methods is they are procedural code
The basic issue with static methods is
they are procedural code. I have no
idea how to unit-test procedural code.
Unit-testing assumes that I can
instantiate a piece of my application
in isolation. During the instantiation
I wire the dependencies with
mocks/friendlies which replace the
real dependencies. With procedural
programing there is nothing to "wire"
since there are no objects, the code
and data are separate.

A static method is one type of method which doesn't need any object to be initialized for it to be called. Have you noticed static is used in the main function in Java? Program execution begins from there without an object being created.
Consider the following example:
class Languages
{
public static void main(String[] args)
{
display();
}
static void display()
{
System.out.println("Java is my favorite programming language.");
}
}

Static methods in java belong to the class (not an instance of it). They use no instance variables and will usually take input from the parameters, perform actions on it, then return some result. Instances methods are associated with objects and, as the name implies, can use instance variables.

No, static methods aren't associated with an instance; they belong to the class. Static methods are your second example; instance methods are the first.

If you apply static keyword with any method, it is known as static method.
A static method belongs to the class rather than object of a class.
A static method invoked without the need for creating an instance of a class.
static method can access static data member and can change the value of it.
A static method can be accessed just using the name of a class dot static name . . . example : Student9.change();
If you want to use non-static fields of a class, you must use a non-static method.
//Program of changing the common property of all objects(static field).
class Student9{
int rollno;
String name;
static String college = "ITS";
static void change(){
college = "BBDIT";
}
Student9(int r, String n){
rollno = r;
name = n;
}
void display (){System.out.println(rollno+" "+name+" "+college);}
public static void main(String args[]){
Student9.change();
Student9 s1 = new Student9 (111,"Indian");
Student9 s2 = new Student9 (222,"American");
Student9 s3 = new Student9 (333,"China");
s1.display();
s2.display();
s3.display();
} }
O/P: 111 Indian BBDIT
222 American BBDIT
333 China BBDIT

Static methods are not associated with an instance, so they can not access any non-static fields in the class.
You would use a static method if the method does not use any fields (or only static fields) of a class.
If any non-static fields of a class are used you must use a non-static method.

Static methods should be called on the Class, Instance methods should be called on the Instances of the Class. But what does that mean in reality? Here is a useful example:
A car class might have an instance method called Accelerate(). You can only Accelerate a car, if the car actually exists (has been constructed) and therefore this would be an instance method.
A car class might also have a count method called GetCarCount(). This would return the total number of cars created (or constructed). If no cars have been constructed, this method would return 0, but it should still be able to be called, and therefore it would have to be a static method.

Use a static method when you want to be able to access the method without an instance of the class.

Actually, we use static properties and methods in a class, when we want to use some part of our program should exists there until our program is running. And we know that, to manipulate static properties, we need static methods as they are not a part of instance variable. And without static methods, to manipulate static properties is time consuming.

Static:
Obj.someMethod
Use static when you want to provide class level access to a method, i.e. where the method should be callable without an instance of the class.

Static methods don't need to be invoked on the object and that is when you use it. Example: your Main() is a static and you don't create an object to call it.

Static methods and variables are controlled version of 'Global' functions and variables in Java. In which methods can be accessed as classname.methodName() or classInstanceName.methodName(), i.e. static methods and variables can be accessed using class name as well as instances of the class.
Class can't be declared as static(because it makes no sense. if a class is declared public, it can be accessed from anywhere), inner classes can be declared static.

Static methods can be used if
One does not want to perform an action on an instance (utility methods)
As mentioned in few of above answers in this post, converting miles to kilometers, or calculating temperature from Fahrenheit to Celsius and vice-versa. With these examples using static method, it does not need to instantiate whole new object in heap memory. Consider below
1. new ABCClass(double farenheit).convertFarenheitToCelcium()
2. ABCClass.convertFarenheitToCelcium(double farenheit)
the former creates a new class footprint for every method invoke, Performance, Practical. Examples are Math and Apache-Commons library StringUtils class below:
Math.random()
Math.sqrt(double)
Math.min(int, int)
StringUtils.isEmpty(String)
StringUtils.isBlank(String)
One wants to use as a simple function. Inputs are explictly passed, and getting the result data as return value. Inheritence, object instanciation does not come into picture. Concise, Readable.
NOTE:
Few folks argue against testability of static methods, but static methods can be tested too! With jMockit, one can mock static methods. Testability. Example below:
new MockUp<ClassName>() {
#Mock
public int doSomething(Input input1, Input input2){
return returnValue;
}
};

I found a nice description, when to use static methods:
There is no hard and fast, well written rules, to decide when to make a method static or not, But there are few observations based upon experience, which not only help to make a method static but also teaches when to use static method in Java. You should consider making a method static in Java :
If a method doesn't modify state of object, or not using any instance variables.
You want to call method without creating instance of that class.
A method is good candidate of being static, if it only work on arguments provided to it e.g. public int factorial(int number){}, this method only operate on number provided as argument.
Utility methods are also good candidate of being static e.g. StringUtils.isEmpty(String text), this a utility method to check if a String is empty or not.
If function of method will remain static across class hierarchy e.g. equals() method is not a good candidate of making static because every Class can redefine equality.
Source is here

Static methods are the methods in Java that can be called without creating an object of class. It is belong to the class.
We use static method when we no need to be invoked method using instance.

A static method has two main purposes:
For utility or helper methods that don't require any object state.
Since there is no need to access instance variables, having static
methods eliminates the need for the caller to instantiate the object
just to call the method.
For the state that is shared by all
instances of the class, like a counter. All instance must share the
same state. Methods that merely use that state should be static as
well.

You should use static methods whenever,
The code in the method is not dependent on instance creation and is
not using any instance variable.
A particular piece of code is to be shared by all the instance methods.
The definition of the method should not be changed or overridden.
you are writing utility classes that should not be changed.
https://www.tutorialspoint.com/When-to-use-static-methods-in-Java

In eclipse you can enable a warning which helps you detect potential static methods. (Above the highlighted line is another one I forgot to highlight)

I am wondering when to use static methods?
A common use for static methods is to access static fields.
But you can have static methods, without referencing static variables. Helper methods without referring static variable can be found in some java classes like java.lang.Math
public static int min(int a, int b) {
return (a <= b) ? a : b;
}
The other use case, I can think of these methods combined with synchronized method is implementation of class level locking in multi threaded environment.
Say if I have a class with a few getters and setters, a method or two, and I want those methods only to be invokable on an instance object of the class. Does this mean I should use a static method?
If you need to access method on an instance object of the class, your method should should be non static.
Oracle documentation page provides more details.
Not all combinations of instance and class variables and methods are allowed:
Instance methods can access instance variables and instance methods directly.
Instance methods can access class variables and class methods directly.
Class methods can access class variables and class methods directly.
Class methods cannot access instance variables or instance methods directly—they must use an object reference. Also, class methods cannot use the this keyword as there is no instance for this to refer to.

Whenever you do not want to create an object to call a method in your code just declare that method as static. Since the static method does not need an instance to be called with but the catch here is not all static methods are called by JVM automatically. This privilege is enjoyed only by the main() "public static void main[String... args]" method in java because at Runtime this is the method Signature public "static" void main[] sought by JVM as an entry point to start execution of the code.
Example:
public class Demo
{
public static void main(String... args)
{
Demo d = new Demo();
System.out.println("This static method is executed by JVM");
//Now to call the static method Displ() you can use the below methods:
Displ(); //By method name itself
Demo.Displ(); //By using class name//Recommended
d.Displ(); //By using instance //Not recommended
}
public static void Displ()
{
System.out.println("This static method needs to be called explicitly");
}
}
Output:-
This static method is executed by JVM
This static method needs to be called explicitly
This static method needs to be called explicitly
This static method needs to be called explicitly

The only reasonable place to use static methods are probably Math functions, and of course main() must be static, and maybe small factory-methods. But logic should not be kept in static methods.

Running a class method concurrently in multiple threads [duplicate]

I am wondering when to use static methods? Say if I have a class with a few getters and setters, a method or two, and I want those methods only to be invokable on an instance object of the class. Does this mean I should use a static method?
Example:
Obj x = new Obj();
x.someMethod();
...or:
Obj.someMethod(); // Is this the static way?
I'm rather confused!

One rule-of-thumb: ask yourself "Does it make sense to call this method, even if no object has been constructed yet?" If so, it should definitely be static.
So in a class Car you might have a method:
double convertMpgToKpl(double mpg)
...which would be static, because one might want to know what 35mpg converts to, even if nobody has ever built a Car. But this method (which sets the efficiency of one particular Car):
void setMileage(double mpg)
...can't be static since it's inconceivable to call the method before any Car has been constructed.
(By the way, the converse isn't always true: you might sometimes have a method which involves two Car objects, and still want it to be static. E.g.:
Car theMoreEfficientOf(Car c1, Car c2)
Although this could be converted to a non-static version, some would argue that since there isn't a "privileged" choice of which Car is more important, you shouldn't force a caller to choose one Car as the object you'll invoke the method on. This situation accounts for a fairly small fraction of all static methods, though.

Define static methods in the following scenarios only:
If you are writing utility classes and they are not supposed to be changed.
If the method is not using any instance variable.
If any operation is not dependent on instance creation.
If there is some code that can easily be shared by all the instance methods, extract that code into a static method.
If you are sure that the definition of the method will never be changed or overridden. As static methods can not be overridden.

There are some valid reasons to use static methods:
Performance: if you want some code to be run, and don't want to instantiate an extra object to do so, shove it into a static method. The JVM also can optimize static methods a lot (I think I've once read James Gosling declaring that you don't need custom instructions in the JVM, since static methods will be just as fast, but couldn't find the source - thus it could be completely false). Yes, it is micro-optimization, and probably unneeded. And we programmers never do unneeded things just because they are cool, right?
Practicality: instead of calling new Util().method(arg), call Util.method(arg), or method(arg) with static imports. Easier, shorter.
Adding methods: you really wanted the class String to have a removeSpecialChars() instance method, but it's not there (and it shouldn't, since your project's special characters may be different from the other project's), and you can't add it (since Java is somewhat sane), so you create an utility class, and call removeSpecialChars(s) instead of s.removeSpecialChars(). Sweet.
Purity: taking some precautions, your static method will be a pure function, that is, the only thing it depends on is its parameters. Data in, data out. This is easier to read and debug, since you don't have inheritance quirks to worry about. You can do it with instance methods too, but the compiler will help you a little more with static methods (by not allowing references to instance attributes, overriding methods, etc.).
You'll also have to create a static method if you want to make a singleton, but... don't. I mean, think twice.
Now, more importantly, why you wouldn't want to create a static method? Basically, polymorphism goes out of the window. You'll not be able to override the method, nor declare it in an interface (pre-Java 8). It takes a lot of flexibility out from your design. Also, if you need state, you'll end up with lots of concurrency bugs and/or bottlenecks if you are not careful.

After reading Misko's articles I believe that static methods are bad from a testing point of view. You should have factories instead(maybe using a dependency injection tool like Guice).
how do I ensure that I only have one of something
only have one of something
The problem of “how do I ensure that I
only have one of something” is nicely
sidestepped. You instantiate only a
single ApplicationFactory in your
main, and as a result, you only
instantiate a single instance of all
of your singletons.
The basic issue with static methods is they are procedural code
The basic issue with static methods is
they are procedural code. I have no
idea how to unit-test procedural code.
Unit-testing assumes that I can
instantiate a piece of my application
in isolation. During the instantiation
I wire the dependencies with
mocks/friendlies which replace the
real dependencies. With procedural
programing there is nothing to "wire"
since there are no objects, the code
and data are separate.

A static method is one type of method which doesn't need any object to be initialized for it to be called. Have you noticed static is used in the main function in Java? Program execution begins from there without an object being created.
Consider the following example:
class Languages
{
public static void main(String[] args)
{
display();
}
static void display()
{
System.out.println("Java is my favorite programming language.");
}
}

Static methods in java belong to the class (not an instance of it). They use no instance variables and will usually take input from the parameters, perform actions on it, then return some result. Instances methods are associated with objects and, as the name implies, can use instance variables.

No, static methods aren't associated with an instance; they belong to the class. Static methods are your second example; instance methods are the first.

If you apply static keyword with any method, it is known as static method.
A static method belongs to the class rather than object of a class.
A static method invoked without the need for creating an instance of a class.
static method can access static data member and can change the value of it.
A static method can be accessed just using the name of a class dot static name . . . example : Student9.change();
If you want to use non-static fields of a class, you must use a non-static method.
//Program of changing the common property of all objects(static field).
class Student9{
int rollno;
String name;
static String college = "ITS";
static void change(){
college = "BBDIT";
}
Student9(int r, String n){
rollno = r;
name = n;
}
void display (){System.out.println(rollno+" "+name+" "+college);}
public static void main(String args[]){
Student9.change();
Student9 s1 = new Student9 (111,"Indian");
Student9 s2 = new Student9 (222,"American");
Student9 s3 = new Student9 (333,"China");
s1.display();
s2.display();
s3.display();
} }
O/P: 111 Indian BBDIT
222 American BBDIT
333 China BBDIT

Static methods are not associated with an instance, so they can not access any non-static fields in the class.
You would use a static method if the method does not use any fields (or only static fields) of a class.
If any non-static fields of a class are used you must use a non-static method.

Static methods should be called on the Class, Instance methods should be called on the Instances of the Class. But what does that mean in reality? Here is a useful example:
A car class might have an instance method called Accelerate(). You can only Accelerate a car, if the car actually exists (has been constructed) and therefore this would be an instance method.
A car class might also have a count method called GetCarCount(). This would return the total number of cars created (or constructed). If no cars have been constructed, this method would return 0, but it should still be able to be called, and therefore it would have to be a static method.

Use a static method when you want to be able to access the method without an instance of the class.

Actually, we use static properties and methods in a class, when we want to use some part of our program should exists there until our program is running. And we know that, to manipulate static properties, we need static methods as they are not a part of instance variable. And without static methods, to manipulate static properties is time consuming.

Static:
Obj.someMethod
Use static when you want to provide class level access to a method, i.e. where the method should be callable without an instance of the class.

Static methods don't need to be invoked on the object and that is when you use it. Example: your Main() is a static and you don't create an object to call it.

Static methods and variables are controlled version of 'Global' functions and variables in Java. In which methods can be accessed as classname.methodName() or classInstanceName.methodName(), i.e. static methods and variables can be accessed using class name as well as instances of the class.
Class can't be declared as static(because it makes no sense. if a class is declared public, it can be accessed from anywhere), inner classes can be declared static.

Static methods can be used if
One does not want to perform an action on an instance (utility methods)
As mentioned in few of above answers in this post, converting miles to kilometers, or calculating temperature from Fahrenheit to Celsius and vice-versa. With these examples using static method, it does not need to instantiate whole new object in heap memory. Consider below
1. new ABCClass(double farenheit).convertFarenheitToCelcium()
2. ABCClass.convertFarenheitToCelcium(double farenheit)
the former creates a new class footprint for every method invoke, Performance, Practical. Examples are Math and Apache-Commons library StringUtils class below:
Math.random()
Math.sqrt(double)
Math.min(int, int)
StringUtils.isEmpty(String)
StringUtils.isBlank(String)
One wants to use as a simple function. Inputs are explictly passed, and getting the result data as return value. Inheritence, object instanciation does not come into picture. Concise, Readable.
NOTE:
Few folks argue against testability of static methods, but static methods can be tested too! With jMockit, one can mock static methods. Testability. Example below:
new MockUp<ClassName>() {
#Mock
public int doSomething(Input input1, Input input2){
return returnValue;
}
};

I found a nice description, when to use static methods:
There is no hard and fast, well written rules, to decide when to make a method static or not, But there are few observations based upon experience, which not only help to make a method static but also teaches when to use static method in Java. You should consider making a method static in Java :
If a method doesn't modify state of object, or not using any instance variables.
You want to call method without creating instance of that class.
A method is good candidate of being static, if it only work on arguments provided to it e.g. public int factorial(int number){}, this method only operate on number provided as argument.
Utility methods are also good candidate of being static e.g. StringUtils.isEmpty(String text), this a utility method to check if a String is empty or not.
If function of method will remain static across class hierarchy e.g. equals() method is not a good candidate of making static because every Class can redefine equality.
Source is here

Static methods are the methods in Java that can be called without creating an object of class. It is belong to the class.
We use static method when we no need to be invoked method using instance.

A static method has two main purposes:
For utility or helper methods that don't require any object state.
Since there is no need to access instance variables, having static
methods eliminates the need for the caller to instantiate the object
just to call the method.
For the state that is shared by all
instances of the class, like a counter. All instance must share the
same state. Methods that merely use that state should be static as
well.

You should use static methods whenever,
The code in the method is not dependent on instance creation and is
not using any instance variable.
A particular piece of code is to be shared by all the instance methods.
The definition of the method should not be changed or overridden.
you are writing utility classes that should not be changed.
https://www.tutorialspoint.com/When-to-use-static-methods-in-Java

In eclipse you can enable a warning which helps you detect potential static methods. (Above the highlighted line is another one I forgot to highlight)

I am wondering when to use static methods?
A common use for static methods is to access static fields.
But you can have static methods, without referencing static variables. Helper methods without referring static variable can be found in some java classes like java.lang.Math
public static int min(int a, int b) {
return (a <= b) ? a : b;
}
The other use case, I can think of these methods combined with synchronized method is implementation of class level locking in multi threaded environment.
Say if I have a class with a few getters and setters, a method or two, and I want those methods only to be invokable on an instance object of the class. Does this mean I should use a static method?
If you need to access method on an instance object of the class, your method should should be non static.
Oracle documentation page provides more details.
Not all combinations of instance and class variables and methods are allowed:
Instance methods can access instance variables and instance methods directly.
Instance methods can access class variables and class methods directly.
Class methods can access class variables and class methods directly.
Class methods cannot access instance variables or instance methods directly—they must use an object reference. Also, class methods cannot use the this keyword as there is no instance for this to refer to.

Whenever you do not want to create an object to call a method in your code just declare that method as static. Since the static method does not need an instance to be called with but the catch here is not all static methods are called by JVM automatically. This privilege is enjoyed only by the main() "public static void main[String... args]" method in java because at Runtime this is the method Signature public "static" void main[] sought by JVM as an entry point to start execution of the code.
Example:
public class Demo
{
public static void main(String... args)
{
Demo d = new Demo();
System.out.println("This static method is executed by JVM");
//Now to call the static method Displ() you can use the below methods:
Displ(); //By method name itself
Demo.Displ(); //By using class name//Recommended
d.Displ(); //By using instance //Not recommended
}
public static void Displ()
{
System.out.println("This static method needs to be called explicitly");
}
}
Output:-
This static method is executed by JVM
This static method needs to be called explicitly
This static method needs to be called explicitly
This static method needs to be called explicitly

The only reasonable place to use static methods are probably Math functions, and of course main() must be static, and maybe small factory-methods. But logic should not be kept in static methods.

Generics, static Methods and Extension [duplicate]

Why is it not possible to override static methods?
If possible, please use an example.

Overriding depends on having an instance of a class. The point of polymorphism is that you can subclass a class and the objects implementing those subclasses will have different behaviors for the same methods defined in the superclass (and overridden in the subclasses). A static method is not associated with any instance of a class so the concept is not applicable.
There were two considerations driving Java's design that impacted this. One was a concern with performance: there had been a lot of criticism of Smalltalk about it being too slow (garbage collection and polymorphic calls being part of that) and Java's creators were determined to avoid that. Another was the decision that the target audience for Java was C++ developers. Making static methods work the way they do had the benefit of familiarity for C++ programmers and was also very fast, because there's no need to wait until runtime to figure out which method to call.

Personally I think this is a flaw in the design of Java. Yes, yes, I understand that non-static methods are attached to an instance while static methods are attached to a class, etc etc. Still, consider the following code:
public class RegularEmployee {
private BigDecimal salary;
public void setSalary(BigDecimal salary) {
this.salary = salary;
}
public static BigDecimal getBonusMultiplier() {
return new BigDecimal(".02");
}
public BigDecimal calculateBonus() {
return salary.multiply(getBonusMultiplier());
}
/* ... presumably lots of other code ... */
}
public class SpecialEmployee extends RegularEmployee {
public static BigDecimal getBonusMultiplier() {
return new BigDecimal(".03");
}
}
This code will not work as you might expect. Namely, SpecialEmployee's get a 2% bonus just like regular employees. But if you remove the "static"s, then SpecialEmployee's get a 3% bonus.
(Admittedly, this example is poor coding style in that in real life you would likely want the bonus multiplier to be in a database somewhere rather than hard-coded. But that's just because I didn't want to bog down the example with a lot of code irrelevant to the point.)
It seems quite plausible to me that you might want to make getBonusMultiplier static. Perhaps you want to be able to display the bonus multiplier for all the categories of employees, without needing to have an instance of an employee in each category. What would be the point of searching for such example instances? What if we are creating a new category of employee and don't have any employees assigned to it yet? This is quite logically a static function.
But it doesn't work.
And yes, yes, I can think of any number of ways to rewrite the above code to make it work. My point is not that it creates an unsolvable problem, but that it creates a trap for the unwary programmer, because the language does not behave as I think a reasonable person would expect.
Perhaps if I tried to write a compiler for an OOP language, I would quickly see why implementing it so that static functions can be overriden would be difficult or impossible.
Or perhaps there is some good reason why Java behaves this way. Can anyone point out an advantage to this behavior, some category of problem that is made easier by this? I mean, don't just point me to the Java language spec and say "see, this is documented how it behaves". I know that. But is there a good reason why it SHOULD behave this way? (Besides the obvious "making it work right was too hard"...)
Update
#VicKirk: If you mean that this is "bad design" because it doesn't fit how Java handles statics, my reply is, "Well, duh, of course." As I said in my original post, it doesn't work. But if you mean that it is bad design in the sense that there would be something fundamentally wrong with a language where this worked, i.e. where statics could be overridden just like virtual functions, that this would somehow introduce an ambiguity or it would be impossible to implement efficiently or some such, I reply, "Why? What's wrong with the concept?"
I think the example I give is a very natural thing to want to do. I have a class that has a function that does not depend on any instance data, and which I might very reasonably want to call independent of an instance, as well as wanting to call from within an instance method. Why should this not work? I've run into this situation a fair number of times over the years. In practice I get around it by making the function virtual, and then creating a static method whose only purpose in life is to be a static method that passes the call on to the virtual method with a dummy instance. That seems like a very roundabout way to get there.

The short answer is: it is entirely possible, but Java doesn't do it.
Here is some code which illustrates the current state of affairs in Java:
File Base.java:
package sp.trial;
public class Base {
static void printValue() {
System.out.println(" Called static Base method.");
}
void nonStatPrintValue() {
System.out.println(" Called non-static Base method.");
}
void nonLocalIndirectStatMethod() {
System.out.println(" Non-static calls overridden(?) static:");
System.out.print(" ");
this.printValue();
}
}
File Child.java:
package sp.trial;
public class Child extends Base {
static void printValue() {
System.out.println(" Called static Child method.");
}
void nonStatPrintValue() {
System.out.println(" Called non-static Child method.");
}
void localIndirectStatMethod() {
System.out.println(" Non-static calls own static:");
System.out.print(" ");
printValue();
}
public static void main(String[] args) {
System.out.println("Object: static type Base; runtime type Child:");
Base base = new Child();
base.printValue();
base.nonStatPrintValue();
System.out.println("Object: static type Child; runtime type Child:");
Child child = new Child();
child.printValue();
child.nonStatPrintValue();
System.out.println("Class: Child static call:");
Child.printValue();
System.out.println("Class: Base static call:");
Base.printValue();
System.out.println("Object: static/runtime type Child -- call static from non-static method of Child:");
child.localIndirectStatMethod();
System.out.println("Object: static/runtime type Child -- call static from non-static method of Base:");
child.nonLocalIndirectStatMethod();
}
}
If you run this (I did it on a Mac, from Eclipse, using Java 1.6) you get:
Object: static type Base; runtime type Child.
Called static Base method.
Called non-static Child method.
Object: static type Child; runtime type Child.
Called static Child method.
Called non-static Child method.
Class: Child static call.
Called static Child method.
Class: Base static call.
Called static Base method.
Object: static/runtime type Child -- call static from non-static method of Child.
Non-static calls own static.
Called static Child method.
Object: static/runtime type Child -- call static from non-static method of Base.
Non-static calls overridden(?) static.
Called static Base method.
Here, the only cases which might be a surprise (and which the question is about) appear to be the first case:
"The run-time type is not used to determine which static methods are called, even when called with an object instance (obj.staticMethod())."
and the last case:
"When calling a static method from within an object method of a class, the static method chosen is the one accessible from the class itself and not from the class defining the run-time type of the object."
Calling with an object instance
The static call is resolved at compile-time, whereas a non-static method call is resolved at run-time. Notice that although static methods are inherited (from parent) they are not overridden (by child). This could be a surprise if you expected otherwise.
Calling from within an object method
Object method calls are resolved using the run-time type, but static (class) method calls are resolved using the compile-time (declared) type.
Changing the rules
To change these rules, so that the last call in the example called Child.printValue(), static calls would have to be provided with a type at run-time, rather than the compiler resolving the call at compile-time with the declared class of the object (or context). Static calls could then use the (dynamic) type hierarchy to resolve the call, just as object method calls do today.
This would easily be doable (if we changed Java :-O), and is not at all unreasonable, however, it has some interesting considerations.
The main consideration is that we need to decide which static method calls should do this.
At the moment, Java has this "quirk" in the language whereby obj.staticMethod() calls are replaced by ObjectClass.staticMethod() calls (normally with a warning). [Note: ObjectClass is the compile-time type of obj.] These would be good candidates for overriding in this way, taking the run-time type of obj.
If we did it would make method bodies harder to read: static calls in a parent class could potentially be dynamically "re-routed". To avoid this we would have to call the static method with a class name -- and this makes the calls more obviously resolved with the compile-time type hierarchy (as now).
The other ways of invoking a static method are more tricky: this.staticMethod() should mean the same as obj.staticMethod(), taking the run-time type of this. However, this might cause some headaches with existing programs, which call (apparently local) static methods without decoration (which is arguably equivalent to this.method()).
So what about unadorned calls staticMethod()? I suggest they do the same as today, and use the local class context to decide what to do. Otherwise great confusion would ensue. Of course it means that method() would mean this.method() if method was a non-static method, and ThisClass.method() if method were a static method. This is another source of confusion.
Other considerations
If we changed this behaviour (and made static calls potentially dynamically non-local), we would probably want to revisit the meaning of final, private and protected as qualifiers on static methods of a class. We would then all have to get used to the fact that private static and public final methods are not overridden, and can therefore be safely resolved at compile-time, and are "safe" to read as local references.

Actually we were wrong.
Despite Java doesn't allow you to override static methods by default, if you look thoroughly through documentation of Class and Method classes in Java, you can still find a way to emulate static methods overriding by following workaround:
import java.lang.reflect.InvocationTargetException;
import java.math.BigDecimal;
class RegularEmployee {
private BigDecimal salary = BigDecimal.ONE;
public void setSalary(BigDecimal salary) {
this.salary = salary;
}
public static BigDecimal getBonusMultiplier() {
return new BigDecimal(".02");
}
public BigDecimal calculateBonus() {
return salary.multiply(this.getBonusMultiplier());
}
public BigDecimal calculateOverridenBonus() {
try {
// System.out.println(this.getClass().getDeclaredMethod(
// "getBonusMultiplier").toString());
try {
return salary.multiply((BigDecimal) this.getClass()
.getDeclaredMethod("getBonusMultiplier").invoke(this));
} catch (IllegalAccessException e) {
e.printStackTrace();
} catch (IllegalArgumentException e) {
e.printStackTrace();
} catch (InvocationTargetException e) {
e.printStackTrace();
}
} catch (NoSuchMethodException e) {
e.printStackTrace();
} catch (SecurityException e) {
e.printStackTrace();
}
return null;
}
// ... presumably lots of other code ...
}
final class SpecialEmployee extends RegularEmployee {
public static BigDecimal getBonusMultiplier() {
return new BigDecimal(".03");
}
}
public class StaticTestCoolMain {
static public void main(String[] args) {
RegularEmployee Alan = new RegularEmployee();
System.out.println(Alan.calculateBonus());
System.out.println(Alan.calculateOverridenBonus());
SpecialEmployee Bob = new SpecialEmployee();
System.out.println(Bob.calculateBonus());
System.out.println(Bob.calculateOverridenBonus());
}
}
Resulting output:
0.02
0.02
0.02
0.03
what we were trying to achieve :)
Even if we declare third variable Carl as RegularEmployee and assign to it instance of SpecialEmployee, we will still have call of RegularEmployee method in first case and call of SpecialEmployee method in second case
RegularEmployee Carl = new SpecialEmployee();
System.out.println(Carl.calculateBonus());
System.out.println(Carl.calculateOverridenBonus());
just look at output console:
0.02
0.03
;)

Static methods are treated as global by the JVM, there are not bound to an object instance at all.
It could conceptually be possible if you could call static methods from class objects (like in languages like Smalltalk) but it's not the case in Java.
EDIT
You can overload static method, that's ok. But you can not override a static method, because class are no first-class object. You can use reflection to get the class of an object at run-time, but the object that you get does not parallel the class hierarchy.
class MyClass { ... }
class MySubClass extends MyClass { ... }
MyClass obj1 = new MyClass();
MySubClass obj2 = new MySubClass();
ob2 instanceof MyClass --> true
Class clazz1 = obj1.getClass();
Class clazz2 = obj2.getClass();
clazz2 instanceof clazz1 --> false
You can reflect over the classes, but it stops there. You don't invoke a static method by using clazz1.staticMethod(), but using MyClass.staticMethod(). A static method is not bound to an object and there is hence no notion of this nor super in a static method. A static method is a global function; as a consequence there is also no notion of polymorphism and, therefore, method overriding makes no sense.
But this could be possible if MyClass was an object at run-time on which you invoke a method, as in Smalltalk (or maybe JRuby as one comment suggest, but I know nothing of JRuby).
Oh yeah... one more thing. You can invoke a static method through an object obj1.staticMethod() but that really syntactic sugar for MyClass.staticMethod() and should be avoided. It usually raises a warning in modern IDE. I don't know why they ever allowed this shortcut.

Method overriding is made possible by dynamic dispatching, meaning that the declared type of an object doesn't determine its behavior, but rather its runtime type:
Animal lassie = new Dog();
lassie.speak(); // outputs "woof!"
Animal kermit = new Frog();
kermit.speak(); // outputs "ribbit!"
Even though both lassie and kermit are declared as objects of type Animal, their behavior (method .speak()) varies because dynamic dispatching will only bind the method call .speak() to an implementation at run time - not at compile time.
Now, here's where the static keyword starts to make sense: the word "static" is an antonym for "dynamic". So the reason why you can't override static methods is because there is no dynamic dispatching on static members - because static literally means "not dynamic". If they dispatched dynamically (and thus could be overriden) the static keyword just wouldn't make sense anymore.

Yes. Practically Java allows overriding static method, and No theoretically if you Override a static method in Java then it will compile and run smoothly but it will lose Polymorphism which is the basic property of Java. You will Read Everywhere that it is not possible to try yourself compiling and running. you will get your answer. e.g. If you Have Class Animal and a static method eat() and you Override that static method in its Subclass lets called it Dog. Then when wherever you Assign a Dog object to an Animal Reference and call eat() according to Java Dog's eat() should have been called but in static Overriding Animals' eat() will Be Called.
class Animal {
public static void eat() {
System.out.println("Animal Eating");
}
}
class Dog extends Animal{
public static void eat() {
System.out.println("Dog Eating");
}
}
class Test {
public static void main(String args[]) {
Animal obj= new Dog();//Dog object in animal
obj.eat(); //should call dog's eat but it didn't
}
}
Output Animal Eating
According to Polymorphism Principle of Java, the Output Should be Dog Eating.
But the result was different because to support Polymorphism Java uses Late Binding that means methods are called only at the run-time but not in the case of static methods. In static methods compiler calls methods at the compile time rather than the run-time, so we get methods according to the reference and not according to the object a reference a containing that's why You can say Practically it supports static overring but theoretically, it doesn't.

In Java (and many OOP languages, but I cannot speak for all; and some do not have static at all) all methods have a fixed signature - the parameters and types. In a virtual method, the first parameter is implied: a reference to the object itself and when called from within the object, the compiler automatically adds this.
There is no difference for static methods - they still have a fixed signature. However, by declaring the method static you have explicitly stated that the compiler must not include the implied object parameter at the beginning of that signature. Therefore, any other code that calls this must must not attempt to put a reference to an object on the stack. If it did do that, then the method execution would not work since the parameters would be in the wrong place - shifted by one - on the stack.
Because of this difference between the two; virtual methods always have a reference to the context object (i.e. this) so then it is possible to reference anything within the heap that belong to that instance of the object. But with static methods, since there is no reference passed, that method cannot access any object variables and methods since the context is not known.
If you wish that Java would change the definition so that a object context is passed in for every method, static or virtual, then you would in essence have only virtual methods.
As someone asked in a comment to the op - what is your reason and purpose for wanting this feature?
I do not know Ruby much, as this was mentioned by the OP, I did some research. I see that in Ruby classes are really a special kind of object and one can create (even dynamically) new methods. Classes are full class objects in Ruby, they are not in Java. This is just something you will have to accept when working with Java (or C#). These are not dynamic languages, though C# is adding some forms of dynamic. In reality, Ruby does not have "static" methods as far as I could find - in that case these are methods on the singleton class object. You can then override this singleton with a new class and the methods in the previous class object will call those defined in the new class (correct?). So if you called a method in the context of the original class it still would only execute the original statics, but calling a method in the derived class, would call methods either from the parent or sub-class. Interesting and I can see some value in that. It takes a different thought pattern.
Since you are working in Java, you will need to adjust to that way of doing things. Why they did this? Well, probably to improve performance at the time based on the technology and understanding that was available. Computer languages are constantly evolving. Go back far enough and there is no such thing as OOP. In the future, there will be other new ideas.
EDIT: One other comment. Now that I see the differences and as I Java/C# developer myself, I can understand why the answers you get from Java developers may be confusing if you are coming from a language like Ruby. Java static methods are not the same as Ruby class methods. Java developers will have a hard time understanding this, as will conversely those who work mostly with a language like Ruby/Smalltalk. I can see how this would also be greatly confusing by the fact that Java also uses "class method" as another way to talk about static methods but this same term is used differently by Ruby. Java does not have Ruby style class methods (sorry); Ruby does not have Java style static methods which are really just old procedural style functions, as found in C.
By the way - thanks for the question! I learned something new for me today about class methods (Ruby style).

Well... the answer is NO if you think from the perspective of how an overriden method should behave in Java. But, you don't get any compiler error if you try to override a static method. That means, if you try to override, Java doesn't stop you doing that; but you certainly don't get the same effect as you get for non-static methods. Overriding in Java simply means that the particular method would be called based on the run time type of the object and not on the compile time type of it (which is the case with overriden static methods). Okay... any guesses for the reason why do they behave strangely? Because they are class methods and hence access to them is always resolved during compile time only using the compile time type information. Accessing them using object references is just an extra liberty given by the designers of Java and we should certainly not think of stopping that practice only when they restrict it :-)
Example: let's try to see what happens if we try overriding a static method:-
class SuperClass {
// ......
public static void staticMethod() {
System.out.println("SuperClass: inside staticMethod");
}
// ......
}
public class SubClass extends SuperClass {
// ......
// overriding the static method
public static void staticMethod() {
System.out.println("SubClass: inside staticMethod");
}
// ......
public static void main(String[] args) {
// ......
SuperClass superClassWithSuperCons = new SuperClass();
SuperClass superClassWithSubCons = new SubClass();
SubClass subClassWithSubCons = new SubClass();
superClassWithSuperCons.staticMethod();
superClassWithSubCons.staticMethod();
subClassWithSubCons.staticMethod();
// ...
}
}
Output:-
SuperClass: inside staticMethod
SuperClass: inside staticMethod
SubClass: inside staticMethod
Notice the second line of the output. Had the staticMethod been overriden this line should have been identical to the third line as we're invoking the 'staticMethod()' on an object of Runtime Type as 'SubClass' and not as 'SuperClass'. This confirms that the static methods are always resolved using their compile time type information only.

I like and double Jay's comment (https://stackoverflow.com/a/2223803/1517187).
I agree that this is the bad design of Java.
Many other languages support overriding static methods, as we see in previous comments.
I feel Jay has also come to Java from Delphi like me.
Delphi (Object Pascal) was one of the languages implementing OOP before Java and one of the first languages used for commercial application development.
It is obvious that many people had experience with that language since it was in the past the only language to write commercial GUI products. And - yes, we could in Delphi override static methods. Actually, static methods in Delphi are called "class methods", while Delphi had the different concept of "Delphi static methods" which were methods with early binding. To override methods you had to use late binding, declare "virtual" directive. So it was very convenient and intuitive and I would expect this in Java.

In general it doesn't make sense to allow 'overriding' of static methods as there would be no good way to determine which one to call at runtime. Taking the Employee example, if we call RegularEmployee.getBonusMultiplier() - which method is supposed to be executed?
In the case of Java, one could imagine a language definition where it is possible to 'override' static methods as long as they are called through an object instance. However, all this would do is to re-implement regular class methods, adding redundancy to the language without really adding any benefit.

overriding is reserved for instance members to support polymorphic behaviour. static class members do not belong to a particular instance. instead, static members belong to the class and as a result overriding is not supported because subclasses only inherit protected and public instance members and not static members. You may want to define an inerface and research factory and/or strategy design patterns to evaluate an alternate approach.

By overriding we can create a polymorphic nature depending on the object type. Static method has no relation with object. So java can not support static method overriding.

By overriding, you achieve dynamic polymorphism.
When you say overriding static methods, the words you are trying to use are contradictory.
Static says - compile time, overriding is used for dynamic polymorphism.
Both are opposite in nature, and hence can't be used together.
Dynamic polymorphic behavior comes when a programmer uses an object and accessing an instance method. JRE will map different instance methods of different classes based on what kind of object you are using.
When you say overriding static methods, static methods we will access by using the class name, which will be linked at compile time, so there is no concept of linking methods at runtime with static methods. So the term "overriding" static methods itself doesn't make any meaning.
Note: even if you access a class method with an object, still java compiler is intelligent enough to find it out, and will do static linking.

Overriding in Java simply means that the particular method would be called based on the runtime type
of the object and not on the compile-time type of it (which is the case with overridden static methods). As static methods are class methods they are not instance methods so they have nothing to do with the fact which reference is pointing to which Object or instance, because due to the nature of static method it belongs to a specific class. You can redeclare it in the subclass but that subclass won't know anything about the parent class' static methods because, as I said, it is specific to only that class in which it has been declared. Accessing them using object references is just an extra liberty given by the designers of Java and we should certainly not think of stopping that practice only when they restrict it
more details and example
http://faisalbhagat.blogspot.com/2014/09/method-overriding-and-method-hiding.html

What good will it do to override static methods. You cannot call static methods through an instance.
MyClass.static1()
MySubClass.static1() // If you overrode, you have to call it through MySubClass anyway.
EDIT : It appears that through an unfortunate oversight in language design, you can call static methods through an instance. Generally nobody does that. My bad.

Answer of this question is simple, the method or variable marked as static belongs to the class only, So that static method cannot be inherited in the sub class because they belong to the super class only.

Easy solution: Use singleton instance. It will allow overrides and inheritance.
In my system, I have SingletonsRegistry class, which returns instance for passed Class. If instance is not found, it is created.
Haxe language class:
package rflib.common.utils;
import haxe.ds.ObjectMap;
class SingletonsRegistry
{
public static var instances:Map<Class<Dynamic>, Dynamic>;
static function __init__()
{
StaticsInitializer.addCallback(SingletonsRegistry, function()
{
instances = null;
});
}
public static function getInstance(cls:Class<Dynamic>, ?args:Array<Dynamic>)
{
if (instances == null) {
instances = untyped new ObjectMap<Dynamic, Dynamic>();
}
if (!instances.exists(cls))
{
if (args == null) args = [];
instances.set(cls, Type.createInstance(cls, args));
}
return instances.get(cls);
}
public static function validate(inst:Dynamic, cls:Class<Dynamic>)
{
if (instances == null) return;
var inst2 = instances[cls];
if (inst2 != null && inst != inst2) throw "Can\'t create multiple instances of " + Type.getClassName(cls) + " - it's singleton!";
}
}

A Static method, variable, block or nested class belongs to the entire class rather than an object.
A Method in Java is used to expose the behaviour of an Object / Class. Here, as the method is static (i.e, static method is used to represent the behaviour of a class only.) changing/ overriding the behaviour of entire class will violate the phenomenon of one of the fundamental pillar of Object oriented programming i.e, high cohesion. (remember a constructor is a special kind of method in Java.)
High Cohesion - One class should have only one role. For example: A car class should produce only car objects and not bike, trucks, planes etc. But the Car class may have some features(behaviour) that belongs to itself only.
Therefore, while designing the java programming language. The language designers thought to allow developers to keep some behaviours of a class to itself only by making a method static in nature.
The below piece code tries to override the static method, but will not encounter any compilation error.
public class Vehicle {
static int VIN;
public static int getVehileNumber() {
return VIN;
}}
class Car extends Vehicle {
static int carNumber;
public static int getVehileNumber() {
return carNumber;
}}
This is because, here we are not overriding a method but we are just re-declaring it. Java allows re-declaration of a method (static/non-static).
Removing the static keyword from getVehileNumber() method of Car class will result into compilation error, Since, we are trying to change the functionality of static method which belongs to Vehicle class only.
Also, If the getVehileNumber() is declared as final then the code will not compile, Since the final keyword restricts the programmer from re-declaring the method.
public static final int getVehileNumber() {
return VIN; }
Overall, this is upto software designers for where to use the static methods.
I personally prefer to use static methods to perform some actions without creating any instance of a class. Secondly, to hide the behaviour of a class from outside world.

Here is a simple explanation. A static method is associated with a class while an instance method is associated with a particular object. Overrides allow calling the different implementation of the overridden methods associated with the particular object. So it is counter-intuitive to override static method which is not even associated with objects but the class itself in the first place. So static methods cannot be overridden based on what object is calling it, it will always be associated with the class where it was created.

Now seeing above answers everyone knows that we can't override static methods, but one should not misunderstood about the concept of accessing static methods from subclass.
We can access static methods of super class with subclass reference if this static method has not been hidden by new static method defined in sub class.
For Example, see below code:-
public class StaticMethodsHiding {
public static void main(String[] args) {
SubClass.hello();
}
}
class SuperClass {
static void hello(){
System.out.println("SuperClass saying Hello");
}
}
class SubClass extends SuperClass {
// static void hello() {
// System.out.println("SubClass Hello");
// }
}
Output:-
SuperClass saying Hello
See Java oracle docs and search for What You Can Do in a Subclass for details about hiding of static methods in sub class.
Thanks

The following code shows that it is possible:
class OverridenStaticMeth {
static void printValue() {
System.out.println("Overriden Meth");
}
}
public class OverrideStaticMeth extends OverridenStaticMeth {
static void printValue() {
System.out.println("Overriding Meth");
}
public static void main(String[] args) {
OverridenStaticMeth osm = new OverrideStaticMeth();
osm.printValue();
System.out.println("now, from main");
printValue();
}
}

Why doesn't java provide implicit Method class' invoke? [duplicate]

Why is it not possible to override static methods?
If possible, please use an example.

Overriding depends on having an instance of a class. The point of polymorphism is that you can subclass a class and the objects implementing those subclasses will have different behaviors for the same methods defined in the superclass (and overridden in the subclasses). A static method is not associated with any instance of a class so the concept is not applicable.
There were two considerations driving Java's design that impacted this. One was a concern with performance: there had been a lot of criticism of Smalltalk about it being too slow (garbage collection and polymorphic calls being part of that) and Java's creators were determined to avoid that. Another was the decision that the target audience for Java was C++ developers. Making static methods work the way they do had the benefit of familiarity for C++ programmers and was also very fast, because there's no need to wait until runtime to figure out which method to call.

Personally I think this is a flaw in the design of Java. Yes, yes, I understand that non-static methods are attached to an instance while static methods are attached to a class, etc etc. Still, consider the following code:
public class RegularEmployee {
private BigDecimal salary;
public void setSalary(BigDecimal salary) {
this.salary = salary;
}
public static BigDecimal getBonusMultiplier() {
return new BigDecimal(".02");
}
public BigDecimal calculateBonus() {
return salary.multiply(getBonusMultiplier());
}
/* ... presumably lots of other code ... */
}
public class SpecialEmployee extends RegularEmployee {
public static BigDecimal getBonusMultiplier() {
return new BigDecimal(".03");
}
}
This code will not work as you might expect. Namely, SpecialEmployee's get a 2% bonus just like regular employees. But if you remove the "static"s, then SpecialEmployee's get a 3% bonus.
(Admittedly, this example is poor coding style in that in real life you would likely want the bonus multiplier to be in a database somewhere rather than hard-coded. But that's just because I didn't want to bog down the example with a lot of code irrelevant to the point.)
It seems quite plausible to me that you might want to make getBonusMultiplier static. Perhaps you want to be able to display the bonus multiplier for all the categories of employees, without needing to have an instance of an employee in each category. What would be the point of searching for such example instances? What if we are creating a new category of employee and don't have any employees assigned to it yet? This is quite logically a static function.
But it doesn't work.
And yes, yes, I can think of any number of ways to rewrite the above code to make it work. My point is not that it creates an unsolvable problem, but that it creates a trap for the unwary programmer, because the language does not behave as I think a reasonable person would expect.
Perhaps if I tried to write a compiler for an OOP language, I would quickly see why implementing it so that static functions can be overriden would be difficult or impossible.
Or perhaps there is some good reason why Java behaves this way. Can anyone point out an advantage to this behavior, some category of problem that is made easier by this? I mean, don't just point me to the Java language spec and say "see, this is documented how it behaves". I know that. But is there a good reason why it SHOULD behave this way? (Besides the obvious "making it work right was too hard"...)
Update
#VicKirk: If you mean that this is "bad design" because it doesn't fit how Java handles statics, my reply is, "Well, duh, of course." As I said in my original post, it doesn't work. But if you mean that it is bad design in the sense that there would be something fundamentally wrong with a language where this worked, i.e. where statics could be overridden just like virtual functions, that this would somehow introduce an ambiguity or it would be impossible to implement efficiently or some such, I reply, "Why? What's wrong with the concept?"
I think the example I give is a very natural thing to want to do. I have a class that has a function that does not depend on any instance data, and which I might very reasonably want to call independent of an instance, as well as wanting to call from within an instance method. Why should this not work? I've run into this situation a fair number of times over the years. In practice I get around it by making the function virtual, and then creating a static method whose only purpose in life is to be a static method that passes the call on to the virtual method with a dummy instance. That seems like a very roundabout way to get there.

The short answer is: it is entirely possible, but Java doesn't do it.
Here is some code which illustrates the current state of affairs in Java:
File Base.java:
package sp.trial;
public class Base {
static void printValue() {
System.out.println(" Called static Base method.");
}
void nonStatPrintValue() {
System.out.println(" Called non-static Base method.");
}
void nonLocalIndirectStatMethod() {
System.out.println(" Non-static calls overridden(?) static:");
System.out.print(" ");
this.printValue();
}
}
File Child.java:
package sp.trial;
public class Child extends Base {
static void printValue() {
System.out.println(" Called static Child method.");
}
void nonStatPrintValue() {
System.out.println(" Called non-static Child method.");
}
void localIndirectStatMethod() {
System.out.println(" Non-static calls own static:");
System.out.print(" ");
printValue();
}
public static void main(String[] args) {
System.out.println("Object: static type Base; runtime type Child:");
Base base = new Child();
base.printValue();
base.nonStatPrintValue();
System.out.println("Object: static type Child; runtime type Child:");
Child child = new Child();
child.printValue();
child.nonStatPrintValue();
System.out.println("Class: Child static call:");
Child.printValue();
System.out.println("Class: Base static call:");
Base.printValue();
System.out.println("Object: static/runtime type Child -- call static from non-static method of Child:");
child.localIndirectStatMethod();
System.out.println("Object: static/runtime type Child -- call static from non-static method of Base:");
child.nonLocalIndirectStatMethod();
}
}
If you run this (I did it on a Mac, from Eclipse, using Java 1.6) you get:
Object: static type Base; runtime type Child.
Called static Base method.
Called non-static Child method.
Object: static type Child; runtime type Child.
Called static Child method.
Called non-static Child method.
Class: Child static call.
Called static Child method.
Class: Base static call.
Called static Base method.
Object: static/runtime type Child -- call static from non-static method of Child.
Non-static calls own static.
Called static Child method.
Object: static/runtime type Child -- call static from non-static method of Base.
Non-static calls overridden(?) static.
Called static Base method.
Here, the only cases which might be a surprise (and which the question is about) appear to be the first case:
"The run-time type is not used to determine which static methods are called, even when called with an object instance (obj.staticMethod())."
and the last case:
"When calling a static method from within an object method of a class, the static method chosen is the one accessible from the class itself and not from the class defining the run-time type of the object."
Calling with an object instance
The static call is resolved at compile-time, whereas a non-static method call is resolved at run-time. Notice that although static methods are inherited (from parent) they are not overridden (by child). This could be a surprise if you expected otherwise.
Calling from within an object method
Object method calls are resolved using the run-time type, but static (class) method calls are resolved using the compile-time (declared) type.
Changing the rules
To change these rules, so that the last call in the example called Child.printValue(), static calls would have to be provided with a type at run-time, rather than the compiler resolving the call at compile-time with the declared class of the object (or context). Static calls could then use the (dynamic) type hierarchy to resolve the call, just as object method calls do today.
This would easily be doable (if we changed Java :-O), and is not at all unreasonable, however, it has some interesting considerations.
The main consideration is that we need to decide which static method calls should do this.
At the moment, Java has this "quirk" in the language whereby obj.staticMethod() calls are replaced by ObjectClass.staticMethod() calls (normally with a warning). [Note: ObjectClass is the compile-time type of obj.] These would be good candidates for overriding in this way, taking the run-time type of obj.
If we did it would make method bodies harder to read: static calls in a parent class could potentially be dynamically "re-routed". To avoid this we would have to call the static method with a class name -- and this makes the calls more obviously resolved with the compile-time type hierarchy (as now).
The other ways of invoking a static method are more tricky: this.staticMethod() should mean the same as obj.staticMethod(), taking the run-time type of this. However, this might cause some headaches with existing programs, which call (apparently local) static methods without decoration (which is arguably equivalent to this.method()).
So what about unadorned calls staticMethod()? I suggest they do the same as today, and use the local class context to decide what to do. Otherwise great confusion would ensue. Of course it means that method() would mean this.method() if method was a non-static method, and ThisClass.method() if method were a static method. This is another source of confusion.
Other considerations
If we changed this behaviour (and made static calls potentially dynamically non-local), we would probably want to revisit the meaning of final, private and protected as qualifiers on static methods of a class. We would then all have to get used to the fact that private static and public final methods are not overridden, and can therefore be safely resolved at compile-time, and are "safe" to read as local references.

Actually we were wrong.
Despite Java doesn't allow you to override static methods by default, if you look thoroughly through documentation of Class and Method classes in Java, you can still find a way to emulate static methods overriding by following workaround:
import java.lang.reflect.InvocationTargetException;
import java.math.BigDecimal;
class RegularEmployee {
private BigDecimal salary = BigDecimal.ONE;
public void setSalary(BigDecimal salary) {
this.salary = salary;
}
public static BigDecimal getBonusMultiplier() {
return new BigDecimal(".02");
}
public BigDecimal calculateBonus() {
return salary.multiply(this.getBonusMultiplier());
}
public BigDecimal calculateOverridenBonus() {
try {
// System.out.println(this.getClass().getDeclaredMethod(
// "getBonusMultiplier").toString());
try {
return salary.multiply((BigDecimal) this.getClass()
.getDeclaredMethod("getBonusMultiplier").invoke(this));
} catch (IllegalAccessException e) {
e.printStackTrace();
} catch (IllegalArgumentException e) {
e.printStackTrace();
} catch (InvocationTargetException e) {
e.printStackTrace();
}
} catch (NoSuchMethodException e) {
e.printStackTrace();
} catch (SecurityException e) {
e.printStackTrace();
}
return null;
}
// ... presumably lots of other code ...
}
final class SpecialEmployee extends RegularEmployee {
public static BigDecimal getBonusMultiplier() {
return new BigDecimal(".03");
}
}
public class StaticTestCoolMain {
static public void main(String[] args) {
RegularEmployee Alan = new RegularEmployee();
System.out.println(Alan.calculateBonus());
System.out.println(Alan.calculateOverridenBonus());
SpecialEmployee Bob = new SpecialEmployee();
System.out.println(Bob.calculateBonus());
System.out.println(Bob.calculateOverridenBonus());
}
}
Resulting output:
0.02
0.02
0.02
0.03
what we were trying to achieve :)
Even if we declare third variable Carl as RegularEmployee and assign to it instance of SpecialEmployee, we will still have call of RegularEmployee method in first case and call of SpecialEmployee method in second case
RegularEmployee Carl = new SpecialEmployee();
System.out.println(Carl.calculateBonus());
System.out.println(Carl.calculateOverridenBonus());
just look at output console:
0.02
0.03
;)

Static methods are treated as global by the JVM, there are not bound to an object instance at all.
It could conceptually be possible if you could call static methods from class objects (like in languages like Smalltalk) but it's not the case in Java.
EDIT
You can overload static method, that's ok. But you can not override a static method, because class are no first-class object. You can use reflection to get the class of an object at run-time, but the object that you get does not parallel the class hierarchy.
class MyClass { ... }
class MySubClass extends MyClass { ... }
MyClass obj1 = new MyClass();
MySubClass obj2 = new MySubClass();
ob2 instanceof MyClass --> true
Class clazz1 = obj1.getClass();
Class clazz2 = obj2.getClass();
clazz2 instanceof clazz1 --> false
You can reflect over the classes, but it stops there. You don't invoke a static method by using clazz1.staticMethod(), but using MyClass.staticMethod(). A static method is not bound to an object and there is hence no notion of this nor super in a static method. A static method is a global function; as a consequence there is also no notion of polymorphism and, therefore, method overriding makes no sense.
But this could be possible if MyClass was an object at run-time on which you invoke a method, as in Smalltalk (or maybe JRuby as one comment suggest, but I know nothing of JRuby).
Oh yeah... one more thing. You can invoke a static method through an object obj1.staticMethod() but that really syntactic sugar for MyClass.staticMethod() and should be avoided. It usually raises a warning in modern IDE. I don't know why they ever allowed this shortcut.

Method overriding is made possible by dynamic dispatching, meaning that the declared type of an object doesn't determine its behavior, but rather its runtime type:
Animal lassie = new Dog();
lassie.speak(); // outputs "woof!"
Animal kermit = new Frog();
kermit.speak(); // outputs "ribbit!"
Even though both lassie and kermit are declared as objects of type Animal, their behavior (method .speak()) varies because dynamic dispatching will only bind the method call .speak() to an implementation at run time - not at compile time.
Now, here's where the static keyword starts to make sense: the word "static" is an antonym for "dynamic". So the reason why you can't override static methods is because there is no dynamic dispatching on static members - because static literally means "not dynamic". If they dispatched dynamically (and thus could be overriden) the static keyword just wouldn't make sense anymore.

Yes. Practically Java allows overriding static method, and No theoretically if you Override a static method in Java then it will compile and run smoothly but it will lose Polymorphism which is the basic property of Java. You will Read Everywhere that it is not possible to try yourself compiling and running. you will get your answer. e.g. If you Have Class Animal and a static method eat() and you Override that static method in its Subclass lets called it Dog. Then when wherever you Assign a Dog object to an Animal Reference and call eat() according to Java Dog's eat() should have been called but in static Overriding Animals' eat() will Be Called.
class Animal {
public static void eat() {
System.out.println("Animal Eating");
}
}
class Dog extends Animal{
public static void eat() {
System.out.println("Dog Eating");
}
}
class Test {
public static void main(String args[]) {
Animal obj= new Dog();//Dog object in animal
obj.eat(); //should call dog's eat but it didn't
}
}
Output Animal Eating
According to Polymorphism Principle of Java, the Output Should be Dog Eating.
But the result was different because to support Polymorphism Java uses Late Binding that means methods are called only at the run-time but not in the case of static methods. In static methods compiler calls methods at the compile time rather than the run-time, so we get methods according to the reference and not according to the object a reference a containing that's why You can say Practically it supports static overring but theoretically, it doesn't.

In Java (and many OOP languages, but I cannot speak for all; and some do not have static at all) all methods have a fixed signature - the parameters and types. In a virtual method, the first parameter is implied: a reference to the object itself and when called from within the object, the compiler automatically adds this.
There is no difference for static methods - they still have a fixed signature. However, by declaring the method static you have explicitly stated that the compiler must not include the implied object parameter at the beginning of that signature. Therefore, any other code that calls this must must not attempt to put a reference to an object on the stack. If it did do that, then the method execution would not work since the parameters would be in the wrong place - shifted by one - on the stack.
Because of this difference between the two; virtual methods always have a reference to the context object (i.e. this) so then it is possible to reference anything within the heap that belong to that instance of the object. But with static methods, since there is no reference passed, that method cannot access any object variables and methods since the context is not known.
If you wish that Java would change the definition so that a object context is passed in for every method, static or virtual, then you would in essence have only virtual methods.
As someone asked in a comment to the op - what is your reason and purpose for wanting this feature?
I do not know Ruby much, as this was mentioned by the OP, I did some research. I see that in Ruby classes are really a special kind of object and one can create (even dynamically) new methods. Classes are full class objects in Ruby, they are not in Java. This is just something you will have to accept when working with Java (or C#). These are not dynamic languages, though C# is adding some forms of dynamic. In reality, Ruby does not have "static" methods as far as I could find - in that case these are methods on the singleton class object. You can then override this singleton with a new class and the methods in the previous class object will call those defined in the new class (correct?). So if you called a method in the context of the original class it still would only execute the original statics, but calling a method in the derived class, would call methods either from the parent or sub-class. Interesting and I can see some value in that. It takes a different thought pattern.
Since you are working in Java, you will need to adjust to that way of doing things. Why they did this? Well, probably to improve performance at the time based on the technology and understanding that was available. Computer languages are constantly evolving. Go back far enough and there is no such thing as OOP. In the future, there will be other new ideas.
EDIT: One other comment. Now that I see the differences and as I Java/C# developer myself, I can understand why the answers you get from Java developers may be confusing if you are coming from a language like Ruby. Java static methods are not the same as Ruby class methods. Java developers will have a hard time understanding this, as will conversely those who work mostly with a language like Ruby/Smalltalk. I can see how this would also be greatly confusing by the fact that Java also uses "class method" as another way to talk about static methods but this same term is used differently by Ruby. Java does not have Ruby style class methods (sorry); Ruby does not have Java style static methods which are really just old procedural style functions, as found in C.
By the way - thanks for the question! I learned something new for me today about class methods (Ruby style).

Well... the answer is NO if you think from the perspective of how an overriden method should behave in Java. But, you don't get any compiler error if you try to override a static method. That means, if you try to override, Java doesn't stop you doing that; but you certainly don't get the same effect as you get for non-static methods. Overriding in Java simply means that the particular method would be called based on the run time type of the object and not on the compile time type of it (which is the case with overriden static methods). Okay... any guesses for the reason why do they behave strangely? Because they are class methods and hence access to them is always resolved during compile time only using the compile time type information. Accessing them using object references is just an extra liberty given by the designers of Java and we should certainly not think of stopping that practice only when they restrict it :-)
Example: let's try to see what happens if we try overriding a static method:-
class SuperClass {
// ......
public static void staticMethod() {
System.out.println("SuperClass: inside staticMethod");
}
// ......
}
public class SubClass extends SuperClass {
// ......
// overriding the static method
public static void staticMethod() {
System.out.println("SubClass: inside staticMethod");
}
// ......
public static void main(String[] args) {
// ......
SuperClass superClassWithSuperCons = new SuperClass();
SuperClass superClassWithSubCons = new SubClass();
SubClass subClassWithSubCons = new SubClass();
superClassWithSuperCons.staticMethod();
superClassWithSubCons.staticMethod();
subClassWithSubCons.staticMethod();
// ...
}
}
Output:-
SuperClass: inside staticMethod
SuperClass: inside staticMethod
SubClass: inside staticMethod
Notice the second line of the output. Had the staticMethod been overriden this line should have been identical to the third line as we're invoking the 'staticMethod()' on an object of Runtime Type as 'SubClass' and not as 'SuperClass'. This confirms that the static methods are always resolved using their compile time type information only.

I like and double Jay's comment (https://stackoverflow.com/a/2223803/1517187).
I agree that this is the bad design of Java.
Many other languages support overriding static methods, as we see in previous comments.
I feel Jay has also come to Java from Delphi like me.
Delphi (Object Pascal) was one of the languages implementing OOP before Java and one of the first languages used for commercial application development.
It is obvious that many people had experience with that language since it was in the past the only language to write commercial GUI products. And - yes, we could in Delphi override static methods. Actually, static methods in Delphi are called "class methods", while Delphi had the different concept of "Delphi static methods" which were methods with early binding. To override methods you had to use late binding, declare "virtual" directive. So it was very convenient and intuitive and I would expect this in Java.

In general it doesn't make sense to allow 'overriding' of static methods as there would be no good way to determine which one to call at runtime. Taking the Employee example, if we call RegularEmployee.getBonusMultiplier() - which method is supposed to be executed?
In the case of Java, one could imagine a language definition where it is possible to 'override' static methods as long as they are called through an object instance. However, all this would do is to re-implement regular class methods, adding redundancy to the language without really adding any benefit.

overriding is reserved for instance members to support polymorphic behaviour. static class members do not belong to a particular instance. instead, static members belong to the class and as a result overriding is not supported because subclasses only inherit protected and public instance members and not static members. You may want to define an inerface and research factory and/or strategy design patterns to evaluate an alternate approach.

By overriding we can create a polymorphic nature depending on the object type. Static method has no relation with object. So java can not support static method overriding.

By overriding, you achieve dynamic polymorphism.
When you say overriding static methods, the words you are trying to use are contradictory.
Static says - compile time, overriding is used for dynamic polymorphism.
Both are opposite in nature, and hence can't be used together.
Dynamic polymorphic behavior comes when a programmer uses an object and accessing an instance method. JRE will map different instance methods of different classes based on what kind of object you are using.
When you say overriding static methods, static methods we will access by using the class name, which will be linked at compile time, so there is no concept of linking methods at runtime with static methods. So the term "overriding" static methods itself doesn't make any meaning.
Note: even if you access a class method with an object, still java compiler is intelligent enough to find it out, and will do static linking.

Overriding in Java simply means that the particular method would be called based on the runtime type
of the object and not on the compile-time type of it (which is the case with overridden static methods). As static methods are class methods they are not instance methods so they have nothing to do with the fact which reference is pointing to which Object or instance, because due to the nature of static method it belongs to a specific class. You can redeclare it in the subclass but that subclass won't know anything about the parent class' static methods because, as I said, it is specific to only that class in which it has been declared. Accessing them using object references is just an extra liberty given by the designers of Java and we should certainly not think of stopping that practice only when they restrict it
more details and example
http://faisalbhagat.blogspot.com/2014/09/method-overriding-and-method-hiding.html

What good will it do to override static methods. You cannot call static methods through an instance.
MyClass.static1()
MySubClass.static1() // If you overrode, you have to call it through MySubClass anyway.
EDIT : It appears that through an unfortunate oversight in language design, you can call static methods through an instance. Generally nobody does that. My bad.

Answer of this question is simple, the method or variable marked as static belongs to the class only, So that static method cannot be inherited in the sub class because they belong to the super class only.

Easy solution: Use singleton instance. It will allow overrides and inheritance.
In my system, I have SingletonsRegistry class, which returns instance for passed Class. If instance is not found, it is created.
Haxe language class:
package rflib.common.utils;
import haxe.ds.ObjectMap;
class SingletonsRegistry
{
public static var instances:Map<Class<Dynamic>, Dynamic>;
static function __init__()
{
StaticsInitializer.addCallback(SingletonsRegistry, function()
{
instances = null;
});
}
public static function getInstance(cls:Class<Dynamic>, ?args:Array<Dynamic>)
{
if (instances == null) {
instances = untyped new ObjectMap<Dynamic, Dynamic>();
}
if (!instances.exists(cls))
{
if (args == null) args = [];
instances.set(cls, Type.createInstance(cls, args));
}
return instances.get(cls);
}
public static function validate(inst:Dynamic, cls:Class<Dynamic>)
{
if (instances == null) return;
var inst2 = instances[cls];
if (inst2 != null && inst != inst2) throw "Can\'t create multiple instances of " + Type.getClassName(cls) + " - it's singleton!";
}
}

A Static method, variable, block or nested class belongs to the entire class rather than an object.
A Method in Java is used to expose the behaviour of an Object / Class. Here, as the method is static (i.e, static method is used to represent the behaviour of a class only.) changing/ overriding the behaviour of entire class will violate the phenomenon of one of the fundamental pillar of Object oriented programming i.e, high cohesion. (remember a constructor is a special kind of method in Java.)
High Cohesion - One class should have only one role. For example: A car class should produce only car objects and not bike, trucks, planes etc. But the Car class may have some features(behaviour) that belongs to itself only.
Therefore, while designing the java programming language. The language designers thought to allow developers to keep some behaviours of a class to itself only by making a method static in nature.
The below piece code tries to override the static method, but will not encounter any compilation error.
public class Vehicle {
static int VIN;
public static int getVehileNumber() {
return VIN;
}}
class Car extends Vehicle {
static int carNumber;
public static int getVehileNumber() {
return carNumber;
}}
This is because, here we are not overriding a method but we are just re-declaring it. Java allows re-declaration of a method (static/non-static).
Removing the static keyword from getVehileNumber() method of Car class will result into compilation error, Since, we are trying to change the functionality of static method which belongs to Vehicle class only.
Also, If the getVehileNumber() is declared as final then the code will not compile, Since the final keyword restricts the programmer from re-declaring the method.
public static final int getVehileNumber() {
return VIN; }
Overall, this is upto software designers for where to use the static methods.
I personally prefer to use static methods to perform some actions without creating any instance of a class. Secondly, to hide the behaviour of a class from outside world.

Here is a simple explanation. A static method is associated with a class while an instance method is associated with a particular object. Overrides allow calling the different implementation of the overridden methods associated with the particular object. So it is counter-intuitive to override static method which is not even associated with objects but the class itself in the first place. So static methods cannot be overridden based on what object is calling it, it will always be associated with the class where it was created.

Now seeing above answers everyone knows that we can't override static methods, but one should not misunderstood about the concept of accessing static methods from subclass.
We can access static methods of super class with subclass reference if this static method has not been hidden by new static method defined in sub class.
For Example, see below code:-
public class StaticMethodsHiding {
public static void main(String[] args) {
SubClass.hello();
}
}
class SuperClass {
static void hello(){
System.out.println("SuperClass saying Hello");
}
}
class SubClass extends SuperClass {
// static void hello() {
// System.out.println("SubClass Hello");
// }
}
Output:-
SuperClass saying Hello
See Java oracle docs and search for What You Can Do in a Subclass for details about hiding of static methods in sub class.
Thanks

The following code shows that it is possible:
class OverridenStaticMeth {
static void printValue() {
System.out.println("Overriden Meth");
}
}
public class OverrideStaticMeth extends OverridenStaticMeth {
static void printValue() {
System.out.println("Overriding Meth");
}
public static void main(String[] args) {
OverridenStaticMeth osm = new OverrideStaticMeth();
osm.printValue();
System.out.println("now, from main");
printValue();
}
}

What's the equivalent of C's "static" keyword in Java?

I want to know what could be the equivalent keyword in java which could perform same function as "Static keyword in C".. I want to do recursion in java, performing same function that a static keyword in C does...
Please help..

C has two entirely different uses of the static keyword, and C++ adds a third use:
// Use 1: declare a variable or function to be local to a given module
// At global scope:
static int global_var;
static void func();
In this case, the global variable global_var and the function void func() can only be accessed inside the file in which they are declared; they cannot be accessed by any other file.
// Use 2: declare a variable inside a function with global scope
void func(void)
{
static int x;
}
In this case, the variable x is effectively a global variable, in that there is only one instance of it -- multiple calls to func() (including recursive calls) will always access the same variable.
// Use 3 (C++ only): declare a global variable with class scope
class Widget
{
public:
static int var;
};
In this case, this declares the variable Widget::var as a global variable, but its scope is different. Outside of class member functions, it has to be named as Widget::var; inside class member functions, it can be named as just var. It can also be made protected or private to limit its scope even more.
Now, what are the analogs of these 3 uses in Java?
Case 1 has no direct analog; the closest is declaring objects with package scope, which is done by omitting a public, protected, or private:
class Widget // Declare a class with package scope
{
int x; // Declare a member variable with package scope
void func() {} // Declare a member function with package scope
}
In this case, the declared objects are only accessible by classes within the same package; they are not accessible to other packages.
Case 2 also does not have an analog in Java. The closest you can get is by declaring a global variable (that is, a static class variable, since Java doesn't have true global variables in the strictest sense):
class Widget
{
private static int func_x;
public static void func()
{
// use func_x here in place of 'static int x' in the C example
}
}
Case 3 is the only case that has a direct analog in Java. In this case, the static keyword serves exactly the same purpose.

The "static" keyword in C actually serves two functions depending on where it's used. Those functions are visibility and duration (these are my terms based on quite a bit of teaching, the standard, if you're interested in that level of detail, uses different terms which I often find confuses new students, hence my reticence in using them).
When used at file level, it marks an item (variable or function) as non-exported so that a linker cannot see it. This is static as in visibility, duration is the same as the program (i.e., until the program exits). This is useful for encapsulating the item within a single compilation unit (a source file, in its simplest definition). The item is available to the whole compilation unit (assuming it's declared before use).
When used within a function, it controls duration (visibility is limited to within the function). In this case, the item is also created once and endures until the program exits. Non-static variables within a function are created and destroyed on function entry and exit.
I gather what you're after is the first type, basically a global variable since I can't immediately see much of a use for the other variant in recursion..
It can't be done since, in Java, everything must belong to a class. The workaround is to create a class holding the "globals" and either:
pass that object around so you can reference its members; or
construct a singleton item so you can access its members.

Java doesn't have global variables, so there isn't a direct equivalent. However, there's a static keyword in Java that shares the state of a field with all instances of a class, which is a good approximation to what you're describing.
I want to do recursion in java, performing same function that a static keyword in C does...
However, if you're looking to do recursion, are you sure that static variables are what you need? Any special state needed for a recursive function call is almost always passed back to itself, not maintained separately.

The concept of static in Java doesn't adhere with the concept of static in C. However, there is a static keyword in Java as well. But its more like a static in C++ then C, with some differences.

You can simulate a static class in java as follows:
/**
* Utility class: this class contains only static methods and behaves as a static class.
*/
public abstract class Utilities
{
// prevent inheritance
private Utilities()
{
}
// ... all your static methods here
public static Person convert(string) {...}
}
This class cannot be inherited (like final because although abstract it has a private constuctor), cannot be instantiated (like static because abstract) so only static methods in it can be called.

Develop Reference

Java is a programming language and computing platform first released by Sun Microsystems in 1995.

Parameterless methods/static - java

there is no connection between static methods and what they do with parameters passed into them. static methods are CLASS level methods and not INSTANCE level in Java. static methods are associated with the Class they are declared in and not instances of those classes.

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