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How can I pad an integer with zeros on the left?
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when I output the following code (taken from dr. Liang Introduction to Java, 10th ed., chapter 03 - selections)
/*
(Current time) Listing 2.7, ShowCurrentTime.java, gives a program that displays
the current time in GMT. Revise the program so that it prompts the user to enter
the time zone offset to GMT and displays the time in the specified time zone.
*/
import java.util.Scanner;
public class Ex_03_08 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter the time zone (GMT): ");
int gmt = input.nextInt();
long totalMilliseconds = System.currentTimeMillis();
long totalSeconds = totalMilliseconds / 1000;
long currentSecond = totalSeconds % 60;
long totalMinutes = totalSeconds / 60;
long currentMinute = totalMinutes % 60;
long totalHours = totalMinutes / 60;
long currentHour = totalHours % 24;
currentHour = currentHour + gmt;
System.out.println("The current time is " + currentHour + ":"
+ currentMinute + ":" + currentSecond);
input.close();
}
}
the output is
Enter the time zone (GMT): 1
The current time is 11:2:31
How can I let display instead 11:02:31?
Thank you.
You can do something like this,
String currentMinuteStr=""+currentMinute ;
if(currentMinuteStr.length()==1){
currentMinuteStr="0"+currentMinuteStr;
}
I have just converted the minutes variable to string and then checked whether the length of the string is 1 that is whether it is a one digit minute and then i have appended the existing minutes to 0 and then you can display it as before like this,
System.out.println("The current time is " + currentHour + ":"
+ currentMinuteStr+ ":" + currentSecond);
You can format your input in C style printf using format method.
class NumericFormat
{
public static void main(String[] args) {
System.out.format("%02d%n",3);
//you can use \n too but %n is preferrable for format method
}
}
Get a better understanding at Java Docs
If link fails, here are some of the formatters.
On a side Note, to format and use Date and Time, Java 8 has clean inbuilt API. Get a look at this Oracle tutorial - Date Time Parsing and Formatting
long totalMilliseconds = System.currentTimeMillis();
long totalSeconds = totalMilliseconds / 1000;
long currentSecond = totalSeconds % 60;
long totalMinutes = totalSeconds / 60;
long currentMinute = totalMinutes % 60;
long totalHours = totalMinutes / 60;
long currentHour = totalHours % 24;
currentHour = currentHour + gmt;
String strTime = "" + (currentHour < 10 ? "0" + currentHour : currentHour) +
(currentMinute < 10 ? "0" + currentMinute : currentMinute) +
(currentSecond < 10 ? "0" + currentSecond : currentSecond);
System.out.println("The current time is : " + strTime);
I have two objects of DateTime, which need to find the duration of their difference,
I have the following code but not sure how to continue it to get to the expected results as following:
Example:
11/03/14 09:30:58
11/03/14 09:33:43
elapsed time is 02 minutes and 45 seconds
-----------------------------------------------------
11/03/14 09:30:58
11/03/15 09:30:58
elapsed time is a day
-----------------------------------------------------
11/03/14 09:30:58
11/03/16 09:30:58
elapsed time is two days
-----------------------------------------------------
11/03/14 09:30:58
11/03/16 09:35:58
elapsed time is two days and 05 minutes
Code:
String dateStart = "11/03/14 09:29:58";
String dateStop = "11/03/14 09:33:43";
Custom date format
SimpleDateFormat format = new SimpleDateFormat("yy/MM/dd HH:mm:ss");
Date d1 = null;
Date d2 = null;
try {
d1 = format.parse(dateStart);
d2 = format.parse(dateStop);
} catch (ParseException e) {
e.printStackTrace();
}
// Get msec from each, and subtract.
long diff = d2.getTime() - d1.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000);
System.out.println("Time in seconds: " + diffSeconds + " seconds.");
System.out.println("Time in minutes: " + diffMinutes + " minutes.");
System.out.println("Time in hours: " + diffHours + " hours.");
The date difference conversion could be handled in a better way using Java built-in class, TimeUnit. It provides utility methods to do that:
Date startDate = // Set start date
Date endDate = // Set end date
long duration = endDate.getTime() - startDate.getTime();
long diffInSeconds = TimeUnit.MILLISECONDS.toSeconds(duration);
long diffInMinutes = TimeUnit.MILLISECONDS.toMinutes(duration);
long diffInHours = TimeUnit.MILLISECONDS.toHours(duration);
long diffInDays = TimeUnit.MILLISECONDS.toDays(duration);
try the following
{
Date dt2 = new DateAndTime().getCurrentDateTime();
long diff = dt2.getTime() - dt1.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000);
int diffInDays = (int) ((dt2.getTime() - dt1.getTime()) / (1000 * 60 * 60 * 24));
if (diffInDays > 1) {
System.err.println("Difference in number of days (2) : " + diffInDays);
return false;
} else if (diffHours > 24) {
System.err.println(">24");
return false;
} else if ((diffHours == 24) && (diffMinutes >= 1)) {
System.err.println("minutes");
return false;
}
return true;
}
Use Joda-Time library
DateTime startTime, endTime;
Period p = new Period(startTime, endTime);
long hours = p.getHours();
long minutes = p.getMinutes();
Joda Time has a concept of time Interval:
Interval interval = new Interval(oldTime, new Instant());
One more example
Date Difference
One more Link
or with Java-8 (which integrated Joda-Time concepts)
Instant start, end;//
Duration dur = Duration.between(start, stop);
long hours = dur.toHours();
long minutes = dur.toMinutes();
Here is how the problem can solved in Java 8 just like the answer by shamimz.
Source : http://docs.oracle.com/javase/tutorial/datetime/iso/period.html
LocalDate today = LocalDate.now();
LocalDate birthday = LocalDate.of(1960, Month.JANUARY, 1);
Period p = Period.between(birthday, today);
long p2 = ChronoUnit.DAYS.between(birthday, today);
System.out.println("You are " + p.getYears() + " years, " + p.getMonths() + " months, and " + p.getDays() + " days old. (" + p2 + " days total)");
The code produces output similar to the following:
You are 53 years, 4 months, and 29 days old. (19508 days total)
We have to use LocalDateTime http://docs.oracle.com/javase/8/docs/api/java/time/LocalDateTime.html to get hour,minute,second differences.
You can create a method like
public long getDaysBetweenDates(Date d1, Date d2){
return TimeUnit.MILLISECONDS.toDays(d1.getTime() - d2.getTime());
}
This method will return the number of days between the 2 days.
Date d2 = new Date();
Date d1 = new Date(1384831803875l);
long diff = d2.getTime() - d1.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000);
int diffInDays = (int) diff / (1000 * 60 * 60 * 24);
System.out.println(diffInDays+" days");
System.out.println(diffHours+" Hour");
System.out.println(diffMinutes+" min");
System.out.println(diffSeconds+" sec");
As Michael Borgwardt writes in his answer here:
int diffInDays = (int)( (newerDate.getTime() - olderDate.getTime())
/ (1000 * 60 * 60 * 24) )
Note that this works with UTC dates, so the difference may be a day
off if you look at local dates. And getting it to work correctly with
local dates requires a completely different approach due to daylight
savings time.
It worked for me can try with this, hope it will be helpful . Let me know if any concern .
Date startDate = java.util.Calendar.getInstance().getTime(); //set your start time
Date endDate = java.util.Calendar.getInstance().getTime(); // set your end time
long duration = endDate.getTime() - startDate.getTime();
long diffInSeconds = TimeUnit.MILLISECONDS.toSeconds(duration);
long diffInMinutes = TimeUnit.MILLISECONDS.toMinutes(duration);
long diffInHours = TimeUnit.MILLISECONDS.toHours(duration);
long diffInDays = TimeUnit.MILLISECONDS.toDays(duration);
Toast.makeText(MainActivity.this, "Diff"
+ duration + diffInDays + diffInHours + diffInMinutes + diffInSeconds, Toast.LENGTH_SHORT).show(); **// Toast message for android .**
System.out.println("Diff" + duration + diffInDays + diffInHours + diffInMinutes + diffInSeconds); **// Print console message for Java .**
In Java 8, you can make of DateTimeFormatter, Duration, and LocalDateTime. Here is an example:
final String dateStart = "11/03/14 09:29:58";
final String dateStop = "11/03/14 09:33:43";
final DateTimeFormatter formatter = new DateTimeFormatterBuilder()
.appendValue(ChronoField.MONTH_OF_YEAR, 2)
.appendLiteral('/')
.appendValue(ChronoField.DAY_OF_MONTH, 2)
.appendLiteral('/')
.appendValueReduced(ChronoField.YEAR, 2, 2, 2000)
.appendLiteral(' ')
.appendValue(ChronoField.HOUR_OF_DAY, 2)
.appendLiteral(':')
.appendValue(ChronoField.MINUTE_OF_HOUR, 2)
.appendLiteral(':')
.appendValue(ChronoField.SECOND_OF_MINUTE, 2)
.toFormatter();
final LocalDateTime start = LocalDateTime.parse(dateStart, formatter);
final LocalDateTime stop = LocalDateTime.parse(dateStop, formatter);
final Duration between = Duration.between(start, stop);
System.out.println(start);
System.out.println(stop);
System.out.println(formatter.format(start));
System.out.println(formatter.format(stop));
System.out.println(between);
System.out.println(between.get(ChronoUnit.SECONDS));
This is the code:
String date1 = "07/15/2013";
String time1 = "11:00:01";
String date2 = "07/16/2013";
String time2 = "22:15:10";
String format = "MM/dd/yyyy HH:mm:ss";
SimpleDateFormat sdf = new SimpleDateFormat(format);
Date fromDate = sdf.parse(date1 + " " + time1);
Date toDate = sdf.parse(date2 + " " + time2);
long diff = toDate.getTime() - fromDate.getTime();
String dateFormat="duration: ";
int diffDays = (int) (diff / (24 * 60 * 60 * 1000));
if(diffDays>0){
dateFormat+=diffDays+" day ";
}
diff -= diffDays * (24 * 60 * 60 * 1000);
int diffhours = (int) (diff / (60 * 60 * 1000));
if(diffhours>0){
dateFormat+=diffhours+" hour ";
}
diff -= diffhours * (60 * 60 * 1000);
int diffmin = (int) (diff / (60 * 1000));
if(diffmin>0){
dateFormat+=diffmin+" min ";
}
diff -= diffmin * (60 * 1000);
int diffsec = (int) (diff / (1000));
if(diffsec>0){
dateFormat+=diffsec+" sec";
}
System.out.println(dateFormat);
and the out is:
duration: 1 day 11 hour 15 min 9 sec
I solved the similar problem using a simple method recently.
public static void main(String[] args) throws IOException, ParseException {
TimeZone utc = TimeZone.getTimeZone("UTC");
Calendar calendar = Calendar.getInstance(utc);
Date until = calendar.getTime();
calendar.add(Calendar.DAY_OF_MONTH, -7);
Date since = calendar.getTime();
long durationInSeconds = TimeUnit.MILLISECONDS.toSeconds(until.getTime() - since.getTime());
long SECONDS_IN_A_MINUTE = 60;
long MINUTES_IN_AN_HOUR = 60;
long HOURS_IN_A_DAY = 24;
long DAYS_IN_A_MONTH = 30;
long MONTHS_IN_A_YEAR = 12;
long sec = (durationInSeconds >= SECONDS_IN_A_MINUTE) ? durationInSeconds % SECONDS_IN_A_MINUTE : durationInSeconds;
long min = (durationInSeconds /= SECONDS_IN_A_MINUTE) >= MINUTES_IN_AN_HOUR ? durationInSeconds%MINUTES_IN_AN_HOUR : durationInSeconds;
long hrs = (durationInSeconds /= MINUTES_IN_AN_HOUR) >= HOURS_IN_A_DAY ? durationInSeconds % HOURS_IN_A_DAY : durationInSeconds;
long days = (durationInSeconds /= HOURS_IN_A_DAY) >= DAYS_IN_A_MONTH ? durationInSeconds % DAYS_IN_A_MONTH : durationInSeconds;
long months = (durationInSeconds /=DAYS_IN_A_MONTH) >= MONTHS_IN_A_YEAR ? durationInSeconds % MONTHS_IN_A_YEAR : durationInSeconds;
long years = (durationInSeconds /= MONTHS_IN_A_YEAR);
String duration = getDuration(sec,min,hrs,days,months,years);
System.out.println(duration);
}
private static String getDuration(long secs, long mins, long hrs, long days, long months, long years) {
StringBuffer sb = new StringBuffer();
String EMPTY_STRING = "";
sb.append(years > 0 ? years + (years > 1 ? " years " : " year "): EMPTY_STRING);
sb.append(months > 0 ? months + (months > 1 ? " months " : " month "): EMPTY_STRING);
sb.append(days > 0 ? days + (days > 1 ? " days " : " day "): EMPTY_STRING);
sb.append(hrs > 0 ? hrs + (hrs > 1 ? " hours " : " hour "): EMPTY_STRING);
sb.append(mins > 0 ? mins + (mins > 1 ? " mins " : " min "): EMPTY_STRING);
sb.append(secs > 0 ? secs + (secs > 1 ? " secs " : " secs "): EMPTY_STRING);
sb.append("ago");
return sb.toString();
}
And as expected it prints: 7 days ago.
with reference to shamim's answer update here is a method that does the task without using any third party library. Just copy the method and use
public static String getDurationTimeStamp(String date) {
String timeDifference = "";
//date formatter as per the coder need
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
//parse the string date-ti
// me to Date object
Date startDate = null;
try {
startDate = sdf.parse(date);
} catch (ParseException e) {
e.printStackTrace();
}
//end date will be the current system time to calculate the lapse time difference
//if needed, coder can add end date to whatever date
Date endDate = new Date();
System.out.println(startDate);
System.out.println(endDate);
//get the time difference in milliseconds
long duration = endDate.getTime() - startDate.getTime();
//now we calculate the differences in different time units
//this long value will be the total time difference in each unit
//i.e; total difference in seconds, total difference in minutes etc...
long diffInSeconds = TimeUnit.MILLISECONDS.toSeconds(duration);
long diffInMinutes = TimeUnit.MILLISECONDS.toMinutes(duration);
long diffInHours = TimeUnit.MILLISECONDS.toHours(duration);
long diffInDays = TimeUnit.MILLISECONDS.toDays(duration);
//now we create the time stamps depending on the value of each unit that we get
//as we do not have the unit in years,
//we will see if the days difference is more that 365 days, as 365 days = 1 year
if (diffInDays > 365) {
//we get the year in integer not in float
//ex- 791/365 = 2.167 in float but it will be 2 years in int
int year = (int) (diffInDays / 365);
timeDifference = year + " years ago";
System.out.println(year + " years ago");
}
//if days are not enough to create year then get the days
else if (diffInDays > 1) {
timeDifference = diffInDays + " days ago";
System.out.println(diffInDays + " days ago");
}
//if days value<1 then get the hours
else if (diffInHours > 1) {
timeDifference = diffInHours + " hours ago";
System.out.println(diffInHours + " hours ago");
}
//if hours value<1 then get the minutes
else if (diffInMinutes > 1) {
timeDifference = diffInMinutes + " minutes ago";
System.out.println(diffInMinutes + " minutes ago");
}
//if minutes value<1 then get the seconds
else if (diffInSeconds > 1) {
timeDifference = diffInSeconds + " seconds ago";
System.out.println(diffInSeconds + " seconds ago");
}
return timeDifference;
// that's all. Happy Coding :)
}
java.time.Duration
I still didn’t feel any of the answers was quite up to date and to the point. So here is the modern answer using Duration from java.time, the modern Java date and time API (the answers by MayurB and mkobit mention the same class, but none of them correctly converts to days, hours, minutes and minutes as asked).
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yy/MM/dd HH:mm:ss");
String dateStart = "11/03/14 09:29:58";
String dateStop = "11/03/14 09:33:43";
ZoneId zone = ZoneId.systemDefault();
ZonedDateTime startDateTime = LocalDateTime.parse(dateStart, formatter).atZone(zone);
ZonedDateTime endDateTime = LocalDateTime.parse(dateStop, formatter).atZone(zone);
Duration diff = Duration.between(startDateTime, endDateTime);
if (diff.isZero()) {
System.out.println("0 minutes");
} else {
long days = diff.toDays();
if (days != 0) {
System.out.print("" + days + " days ");
diff = diff.minusDays(days);
}
long hours = diff.toHours();
if (hours != 0) {
System.out.print("" + hours + " hours ");
diff = diff.minusHours(hours);
}
long minutes = diff.toMinutes();
if (minutes != 0) {
System.out.print("" + minutes + " minutes ");
diff = diff.minusMinutes(minutes);
}
long seconds = diff.getSeconds();
if (seconds != 0) {
System.out.print("" + seconds + " seconds ");
}
System.out.println();
}
Output from this example snippet is:
3 minutes 45 seconds
Note that Duration always counts a day as 24 hours. If you want to treat time anomalies like summer time transistions differently, solutions inlcude (1) use ChronoUnit.DAYS (2) Use Period (3) Use LocalDateTimeinstead ofZonedDateTime` (may be considered a hack).
The code above works with Java 8 and with ThreeTen Backport, that backport of java.time to Java 6 and 7. From Java 9 it may be possible to write it a bit more nicely using the methods toHoursPart, toMinutesPart and toSecondsPart added there.
I will elaborate the explanations further one of the days when I get time, maybe not until next week.
This is a program I wrote, which gets the number of days between 2 dates(no time here).
import java.util.Scanner;
public class HelloWorld {
public static void main(String args[]) {
Scanner s = new Scanner(System.in);
System.out.print("Enter starting date separated by dots: ");
String inp1 = s.nextLine();
System.out.print("Enter ending date separated by dots: ");
String inp2 = s.nextLine();
int[] nodim = {
0,
31,
28,
31,
30,
31,
30,
31,
31,
30,
31,
30,
31
};
String[] inpArr1 = split(inp1);
String[] inpArr2 = split(inp2);
int d1 = Integer.parseInt(inpArr1[0]);
int m1 = Integer.parseInt(inpArr1[1]);
int y1 = Integer.parseInt(inpArr1[2]);
int d2 = Integer.parseInt(inpArr2[0]);
int m2 = Integer.parseInt(inpArr2[1]);
int y2 = Integer.parseInt(inpArr2[2]);
if (y1 % 4 == 0) nodim[2] = 29;
int diff = m1 == m2 && y1 == y2 ? d2 - (d1 - 1) : (nodim[m1] - (d1 - 1));
int mm1 = m1 + 1, mm2 = m2 - 1, yy1 = y1, yy2 = y2;
for (; yy1 <= yy2; yy1++, mm1 = 1) {
mm2 = yy1 == yy2 ? (m2 - 1) : 12;
if (yy1 % 4 == 0) nodim[2] = 29;
else nodim[2] = 28;
if (mm2 == 0) {
mm2 = 12;
yy2 = yy2 - 1;
}
for (; mm1 <= mm2 && yy1 <= yy2; mm1++) diff = diff + nodim[mm1];
}
System.out.print("No. of days from " + inp1 + " to " + inp2 + " is " + diff);
}
public static String[] split(String s) {
String[] retval = {
"",
"",
""
};
s = s + ".";
s = s + " ";
for (int i = 0; i <= 2; i++) {
retval[i] = s.substring(0, s.indexOf("."));
s = s.substring((s.indexOf(".") + 1), s.length());
}
return retval;
}
}
http://pastebin.com/HRsjTtUf
You can get the difference between two DateTime using this
DateTime startDate = DateTime.now();
DateTime endDate = DateTime.now();
Days daysBetween = Days.daysBetween(startDate, endDate);
System.out.println(daysBetween.toStandardSeconds());
The below code will give the difference between two DateTime (Will work in Java 8 and above)
private long countDaysBetween(LocalDateTime startDate, LocalDateTime enddate)
{
if(startDate == null || enddate == null)
{
throw new IllegalArgumentException("No such a date");
}
long daysBetween = ChronoUnit.DAYS.between(startDate, enddate);
return daysBetween;
}
If anyone wants a string with all of them together, this function can be used.
String getTimeDifference(long duration) {
StringBuilder timeRemaining = new StringBuilder();
long days = TimeUnit.MILLISECONDS.toDays(duration);
if (days >= 1) {
timeRemaining.append(days).append((days == 1) ? " day " : " days ");
}
duration -= TimeUnit.DAYS.toMillis(days);
long hours = TimeUnit.MILLISECONDS.toHours(duration);
if (hours >= 1) {
timeRemaining.append(hours).append((hours == 1) ? " hour " : " hours ");
}
duration -= TimeUnit.HOURS.toMillis(hours);
long minutes = TimeUnit.MILLISECONDS.toMinutes(duration);
if (minutes >= 1) {
timeRemaining.append(minutes).append((hours == 1) ? " minute " : " minutes ");
}
return timeRemaining.toString().trim();
}
// calculating the difference b/w startDate and endDate
String startDate = "01-01-2016";
String endDate = simpleDateFormat.format(currentDate);
date1 = simpleDateFormat.parse(startDate);
date2 = simpleDateFormat.parse(endDate);
long getDiff = date2.getTime() - date1.getTime();
// using TimeUnit class from java.util.concurrent package
long getDaysDiff = TimeUnit.MILLISECONDS.toDays(getDiff);
How to calculate difference between two dates in Java
Currently I am printing my values for my swing worker timer in a label
.setText(days + " Days :" + hours + " Hours :" + mins + " Minutes : " + seconds + " Seconds elapsed")
I was wondering if it were possible to format this in a slightly neater way?
I've got a program that I'm working on now that uses String.format(...) and a format String for this:
// in the constants section
private static final String DISPLAY_FORMAT_STR = "%02d:%02d:%02d:%01d";
private void showTimeLeft() {
int oldMin = min;
hours = (int) (deltaTime / (MS_PER_SEC * SEC_PER_MIN * MIN_PER_HR));
min = (int) (deltaTime / (MS_PER_SEC * SEC_PER_MIN) % MIN_PER_HR);
sec = (int) (deltaTime / (MS_PER_SEC) % SEC_PER_MIN);
msec = (int) (deltaTime % MS_PER_SEC);
String displayString = String.format(DISPLAY_FORMAT_STR, hours, min, sec,
msec / 100);
displayField.setText(displayString);
// ... etc...
Otherwise if you're dealing with a Date object (I'm not), you could use a SimpleDateFormat object to better format your output.
How about String.format()?
http://docs.oracle.com/javase/6/docs/api/java/util/Formatter.html#syntax
One of ways, how do you can calculating elapsed time
long start = System.currentTimeMillis();
// some code executed
long end = System.currentTimeMillis();
long elapsed = end - start;
long seconds = elapsed / 1000;
rest for calculating days / hours / minutes / seconds
I've been trying to convert a value of seconds (in a BigDecimal variable) to a string in an editText like "1 hour 22 minutes 33 seconds" or something of the kind.
I've tried this:
String sequenceCaptureTime = "";
BigDecimal roundThreeCalc = new BigDecimal("0");
BigDecimal hours = new BigDecimal("0");
BigDecimal myremainder = new BigDecimal("0");
BigDecimal minutes = new BigDecimal("0");
BigDecimal seconds = new BigDecimal("0");
BigDecimal var3600 = new BigDecimal("3600");
BigDecimal var60 = new BigDecimal("60");
(I have a roundThreeCalc which is the value in seconds so I try to convert it here.)
hours = (roundThreeCalc.divide(var3600));
myremainder = (roundThreeCalc.remainder(var3600));
minutes = (myremainder.divide(var60));
seconds = (myremainder.remainder(var60));
sequenceCaptureTime = hours.toString() + minutes.toString() + seconds.toString();
Then I set the editText to sequnceCaptureTime String.
But that didn't work. It force closed the app every time. I am totally out of my depth here, any help is greatly appreciated.
Is it necessary to use a BigDecimal? If you don't have to, I'd use an int or long for seconds, and it would simplify things a little bit:
hours = totalSecs / 3600;
minutes = (totalSecs % 3600) / 60;
seconds = totalSecs % 60;
timeString = String.format("%02d:%02d:%02d", hours, minutes, seconds);
You might want to pad each to make sure they're two digit values(or whatever) in the string, though.
DateUtils.formatElapsedTime(long), formats an elapsed time in the form "MM:SS" or "H:MM:SS" . It returns the String you are looking for. You can find the documentation here
You should have more luck with
hours = roundThreeCalc.divide(var3600, BigDecimal.ROUND_FLOOR);
myremainder = roundThreeCalc.remainder(var3600);
minutes = myremainder.divide(var60, BigDecimal.ROUND_FLOOR);
seconds = myremainder.remainder(var60);
This will drop the decimal values after each division.
Edit: If that didn't work, try this. (I just wrote and tested it)
public static int[] splitToComponentTimes(BigDecimal biggy)
{
long longVal = biggy.longValue();
int hours = (int) longVal / 3600;
int remainder = (int) longVal - hours * 3600;
int mins = remainder / 60;
remainder = remainder - mins * 60;
int secs = remainder;
int[] ints = {hours , mins , secs};
return ints;
}
Something really helpful in Java 8
import java.time.LocalTime;
private String ConvertSecondToHHMMSSString(int nSecondTime) {
return LocalTime.MIN.plusSeconds(nSecondTime).toString();
}
Here is the working code:
private String getDurationString(int seconds) {
int hours = seconds / 3600;
int minutes = (seconds % 3600) / 60;
seconds = seconds % 60;
return twoDigitString(hours) + " : " + twoDigitString(minutes) + " : " + twoDigitString(seconds);
}
private String twoDigitString(int number) {
if (number == 0) {
return "00";
}
if (number / 10 == 0) {
return "0" + number;
}
return String.valueOf(number);
}
I prefer java's built in TimeUnit library
long seconds = TimeUnit.MINUTES.toSeconds(8);
private String ConvertSecondToHHMMString(int secondtTime)
{
TimeZone tz = TimeZone.getTimeZone("UTC");
SimpleDateFormat df = new SimpleDateFormat("HH:mm:ss");
df.setTimeZone(tz);
String time = df.format(new Date(secondtTime*1000L));
return time;
}
This is my simple solution:
String secToTime(int sec) {
int seconds = sec % 60;
int minutes = sec / 60;
if (minutes >= 60) {
int hours = minutes / 60;
minutes %= 60;
if( hours >= 24) {
int days = hours / 24;
return String.format("%d days %02d:%02d:%02d", days,hours%24, minutes, seconds);
}
return String.format("%02d:%02d:%02d", hours, minutes, seconds);
}
return String.format("00:%02d:%02d", minutes, seconds);
}
Test Results:
Result: 00:00:36 - 36
Result: 01:00:07 - 3607
Result: 6313 days 12:39:05 - 545488745
If you want the units h, min and sec for a duration you can use this:
public static String convertSeconds(int seconds) {
int h = seconds/ 3600;
int m = (seconds % 3600) / 60;
int s = seconds % 60;
String sh = (h > 0 ? String.valueOf(h) + " " + "h" : "");
String sm = (m < 10 && m > 0 && h > 0 ? "0" : "") + (m > 0 ? (h > 0 && s == 0 ? String.valueOf(m) : String.valueOf(m) + " " + "min") : "");
String ss = (s == 0 && (h > 0 || m > 0) ? "" : (s < 10 && (h > 0 || m > 0) ? "0" : "") + String.valueOf(s) + " " + "sec");
return sh + (h > 0 ? " " : "") + sm + (m > 0 ? " " : "") + ss;
}
int seconds = 3661;
String duration = convertSeconds(seconds);
That's a lot of conditional operators. The method will return those strings:
0 -> 0 sec
5 -> 5 sec
60 -> 1 min
65 -> 1 min 05 sec
3600 -> 1 h
3601 -> 1 h 01 sec
3660 -> 1 h 01
3661 -> 1 h 01 min 01 sec
108000 -> 30 h
I like to keep things simple therefore:
int tot_seconds = 5000;
int hours = tot_seconds / 3600;
int minutes = (tot_seconds % 3600) / 60;
int seconds = tot_seconds % 60;
String timeString = String.format("%02d Hour %02d Minutes %02d Seconds ", hours, minutes, seconds);
System.out.println(timeString);
The result will be: 01 Hour 23 Minutes 20 Seconds
Duration from java.time
BigDecimal secondsValue = BigDecimal.valueOf(4953);
if (secondsValue.compareTo(BigDecimal.valueOf(Long.MAX_VALUE)) > 0) {
System.out.println("Seconds value " + secondsValue + " is out of range");
} else {
Duration dur = Duration.ofSeconds(secondsValue.longValueExact());
long hours = dur.toHours();
int minutes = dur.toMinutesPart();
int seconds = dur.toSecondsPart();
System.out.format("%d hours %d minutes %d seconds%n", hours, minutes, seconds);
}
Output from this snippet is:
1 hours 22 minutes 33 seconds
If there had been a non-zero fraction of second in the BigDecimal this code would not have worked as it stands, but you may be able to modify it. The code works in Java 9 and later. In Java 8 the conversion from Duration into hours minutes and seconds is a bit more wordy, see the link at the bottom for how. I am leaving to you to choose the correct singular or plural form of the words (hour or hours, etc.).
Links
Oracle tutorial: Date Time explaining how to use java.time.
Answer by lauhub showing the conversion from a Duration to days, hours, minutes and seconds in Java 8.
This Code Is working Fine :
txtTimer.setText(String.format("%02d:%02d:%02d",(SecondsCounter/3600), ((SecondsCounter % 3600)/60), (SecondsCounter % 60)));
A nice and easy way to do it using GregorianCalendar
Import these into the project:
import java.util.GregorianCalendar;
import java.util.Date;
import java.text.SimpleDateFormat;
import java.util.Scanner;
And then:
Scanner s = new Scanner(System.in);
System.out.println("Seconds: ");
int secs = s.nextInt();
GregorianCalendar cal = new GregorianCalendar(0,0,0,0,0,secs);
Date dNow = cal.getTime();
SimpleDateFormat ft = new SimpleDateFormat("HH 'hours' mm 'minutes' ss 'seconds'");
System.out.println("Your time: " + ft.format(dNow));
for just minutes and seconds use this
String.format("%02d:%02d", (seconds / 3600 * 60 + ((seconds % 3600) / 60)), (seconds % 60))
With Java 8, you can easily achieve time in String format from long seconds like,
LocalTime.ofSecondOfDay(86399L)
Here, given value is max allowed to convert (upto 24 hours) and result will be
23:59:59
Pros : 1) No need to convert manually and to append 0 for single digit
Cons : work only for up to 24 hours
I use this:
public String SEG2HOR( long lnValue) { //OK
String lcStr = "00:00:00";
String lcSign = (lnValue>=0 ? " " : "-");
lnValue = lnValue * (lnValue>=0 ? 1 : -1);
if (lnValue>0) {
long lnHor = (lnValue/3600);
long lnHor1 = (lnValue % 3600);
long lnMin = (lnHor1/60);
long lnSec = (lnHor1 % 60);
lcStr = lcSign + ( lnHor < 10 ? "0": "") + String.valueOf(lnHor) +":"+
( lnMin < 10 ? "0": "") + String.valueOf(lnMin) +":"+
( lnSec < 10 ? "0": "") + String.valueOf(lnSec) ;
}
return lcStr;
}
Here's my function to address the problem:
public static String getConvertedTime(double time){
double h,m,s,mil;
mil = time % 1000;
s = time/1000;
m = s/60;
h = m/60;
s = s % 60;
m = m % 60;
h = h % 24;
return ((int)h < 10 ? "0"+String.valueOf((int)h) : String.valueOf((int)h))+":"+((int)m < 10 ? "0"+String.valueOf((int)m) : String.valueOf((int)m))
+":"+((int)s < 10 ? "0"+String.valueOf((int)s) : String.valueOf((int)s))
+":"+((int)mil > 100 ? String.valueOf((int)mil) : (int)mil > 9 ? "0"+String.valueOf((int)mil) : "00"+String.valueOf((int)mil));
}
I know this is pretty old but in java 8:
LocalTime.MIN.plusSeconds(120).format(DateTimeFormatter.ISO_LOCAL_TIME)
I use this in python to convert a float representing seconds to hours, minutes, seconds, and microseconds. It's reasonably elegant and is handy for converting to a datetime type via strptime to convert. It could also be easily extended to longer intervals (weeks, months, etc.) if needed.
def sectohmsus(seconds):
x = seconds
hmsus = []
for i in [3600, 60, 1]: # seconds in a hour, minute, and second
hmsus.append(int(x / i))
x %= i
hmsus.append(int(round(x * 1000000))) # microseconds
return hmsus # hours, minutes, seconds, microsecond
i have tried the best way and less code but may be it is little bit difficult to understand how i wrote my code but if you good at maths it is so easy
import java.util.Scanner;
class hours {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
double s;
System.out.println("how many second you have ");
s =input.nextInt();
double h=s/3600;
int h2=(int)h;
double h_h2=h-h2;
double m=h_h2*60;
int m1=(int)m;
double m_m1=m-m1;
double m_m1s=m_m1*60;
System.out.println(h2+" hours:"+m1+" Minutes:"+Math.round(m_m1s)+" seconds");
}
}
more over it is accurate !
Tough there are yet many correct answers and an accepted one, if you want a more handmade and systematized way to do this, I suggest something like this:
/**
* Factors for converting seconds in minutes, minutes in hours, etc.
*/
private static int[] FACTORS = new int[] {
60, 60, 24, 7
};
/**
* Names of each time unit.
* The length of this array needs to be FACTORS.length + 1.
* The last one is the name of the remainder after
* obtaining each component.
*/
private static String[] NAMES = new String[] {
"second", "minute", "hour", "day", "week"
};
/**
* Checks if quantity is 1 in order to use or not the plural.
*/
private static String quantityToString(int quantity, String name) {
if (quantity == 1) {
return String.format("%d %s", quantity, name);
}
return String.format("%d %ss", quantity, name);
}
/**
* The seconds to String method.
*/
private static String secondsToString(int seconds) {
List<String> components = new ArrayList<>();
/**
* Obtains each component and stores only if is not 0.
*/
for (int i = 0; i < FACTORS.length; i++) {
int component = seconds % FACTORS[i];
seconds /= FACTORS[i];
if (component != 0) {
components.add(quantityToString(component, NAMES[i]));
}
}
/**
* The remainder is the last component.
*/
if (seconds != 0) {
components.add(quantityToString(seconds, NAMES[FACTORS.length]));
}
/**
* We have the non-0 components in reversed order.
* This could be extracted to another method.
*/
StringBuilder builder = new StringBuilder();
for (int i = components.size() - 1; i >= 0; i--) {
if (i == 0 && components.size() > 1) {
builder.append(" and ");
} else if (builder.length() > 0) {
builder.append(", ");
}
builder.append(components.get(i));
}
return builder.toString();
}
The result is as following:
System.out.println(secondsToString(5_000_000)); // 8 weeks, 1 day, 20 hours, 53 minutes and 20 seconds
System.out.println(secondsToString(500_000)); // 5 days, 18 hours, 53 minutes and 20 seconds
System.out.println(secondsToString(60*60*24)); // 1 day
System.out.println(secondsToString(2*60*60*24 + 3*60)); // 2 days and 3 minutes
System.out.println(secondsToString(60*60*24 + 3 * 60 * 60 + 53)); // 1 day, 3 hours and 53 seconds
You can get this done easily using method overloading.
Here's a code I wrote to convert seconds to hours, minutes and seconds format.
public class SecondsAndMinutes {
public static void main(String[] args) {
String finalOutput = getDurationString(-3666);
System.out.println(finalOutput);
}
public static String getDurationString(int seconds) {
if(seconds <= 0) {
return "Add a value bigger than zero.";
}else {
int hours = seconds / (60*60);
int remainingOneSeconds = seconds % (60*60);
int minutes = remainingOneSeconds / 60;
int remainingSeconds = remainingOneSeconds % 60;
String x = Integer.toString(hours);
return x+"h " + getDurationString(minutes, remainingSeconds);
}
}
public static String getDurationString(int minutes, int seconds) {
if(seconds <= 0 && seconds > 59) {
return "Seconds needs to be within 1 to 59";
}else {
String y = Integer.toString(minutes);
String z = Integer.toString(seconds);
return y+"m "+z+"s";
}
}
}
I want to record the time using System.currentTimeMillis() when a user begins something in my program. When he finishes, I will subtract the current System.currentTimeMillis() from the start variable, and I want to show them the time elapsed using a human readable format such as "XX hours, XX mins, XX seconds" or even "XX mins, XX seconds" because its not likely to take someone an hour.
What's the best way to do this?
Use the java.util.concurrent.TimeUnit class:
String.format("%d min, %d sec",
TimeUnit.MILLISECONDS.toMinutes(millis),
TimeUnit.MILLISECONDS.toSeconds(millis) -
TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis))
);
Note: TimeUnit is part of the Java 1.5 specification, but toMinutes was added as of Java 1.6.
To add a leading zero for values 0-9, just do:
String.format("%02d min, %02d sec",
TimeUnit.MILLISECONDS.toMinutes(millis),
TimeUnit.MILLISECONDS.toSeconds(millis) -
TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis))
);
If TimeUnit or toMinutes are unsupported (such as on Android before API version 9), use the following equations:
int seconds = (int) (milliseconds / 1000) % 60 ;
int minutes = (int) ((milliseconds / (1000*60)) % 60);
int hours = (int) ((milliseconds / (1000*60*60)) % 24);
//etc...
Based on #siddhadev's answer, I wrote a function which converts milliseconds to a formatted string:
/**
* Convert a millisecond duration to a string format
*
* #param millis A duration to convert to a string form
* #return A string of the form "X Days Y Hours Z Minutes A Seconds".
*/
public static String getDurationBreakdown(long millis) {
if(millis < 0) {
throw new IllegalArgumentException("Duration must be greater than zero!");
}
long days = TimeUnit.MILLISECONDS.toDays(millis);
millis -= TimeUnit.DAYS.toMillis(days);
long hours = TimeUnit.MILLISECONDS.toHours(millis);
millis -= TimeUnit.HOURS.toMillis(hours);
long minutes = TimeUnit.MILLISECONDS.toMinutes(millis);
millis -= TimeUnit.MINUTES.toMillis(minutes);
long seconds = TimeUnit.MILLISECONDS.toSeconds(millis);
StringBuilder sb = new StringBuilder(64);
sb.append(days);
sb.append(" Days ");
sb.append(hours);
sb.append(" Hours ");
sb.append(minutes);
sb.append(" Minutes ");
sb.append(seconds);
sb.append(" Seconds");
return(sb.toString());
}
long time = 1536259;
return (new SimpleDateFormat("mm:ss:SSS")).format(new Date(time));
Prints:
25:36:259
Using the java.time package in Java 8:
Instant start = Instant.now();
Thread.sleep(63553);
Instant end = Instant.now();
System.out.println(Duration.between(start, end));
Output is in ISO 8601 Duration format: PT1M3.553S (1 minute and 3.553 seconds).
Uhm... how many milliseconds are in a second? And in a minute? Division is not that hard.
int seconds = (int) ((milliseconds / 1000) % 60);
int minutes = (int) ((milliseconds / 1000) / 60);
Continue like that for hours, days, weeks, months, year, decades, whatever.
I would not pull in the extra dependency just for that (division is not that hard, after all), but if you are using Commons Lang anyway, there are the DurationFormatUtils.
Example Usage (adapted from here):
import org.apache.commons.lang3.time.DurationFormatUtils
public String getAge(long value) {
long currentTime = System.currentTimeMillis();
long age = currentTime - value;
String ageString = DurationFormatUtils.formatDuration(age, "d") + "d";
if ("0d".equals(ageString)) {
ageString = DurationFormatUtils.formatDuration(age, "H") + "h";
if ("0h".equals(ageString)) {
ageString = DurationFormatUtils.formatDuration(age, "m") + "m";
if ("0m".equals(ageString)) {
ageString = DurationFormatUtils.formatDuration(age, "s") + "s";
if ("0s".equals(ageString)) {
ageString = age + "ms";
}
}
}
}
return ageString;
}
Example:
long lastTime = System.currentTimeMillis() - 2000;
System.out.println("Elapsed time: " + getAge(lastTime));
//Output: 2s
Note: To get millis from two LocalDateTime objects you can use:
long age = ChronoUnit.MILLIS.between(initTime, LocalDateTime.now())
Either hand divisions, or use the SimpleDateFormat API.
long start = System.currentTimeMillis();
// do your work...
long elapsed = System.currentTimeMillis() - start;
DateFormat df = new SimpleDateFormat("HH 'hours', mm 'mins,' ss 'seconds'");
df.setTimeZone(TimeZone.getTimeZone("GMT+0"));
System.out.println(df.format(new Date(elapsed)));
Edit by Bombe: It has been shown in the comments that this approach only works for smaller durations (i.e. less than a day).
Just to add more info
if you want to format like: HH:mm:ss
0 <= HH <= infinite
0 <= mm < 60
0 <= ss < 60
use this:
int h = (int) ((startTimeInMillis / 1000) / 3600);
int m = (int) (((startTimeInMillis / 1000) / 60) % 60);
int s = (int) ((startTimeInMillis / 1000) % 60);
I just had this issue now and figured this out
Shortest solution:
Here's probably the shortest which also deals with time zones.
System.out.printf("%tT", millis-TimeZone.getDefault().getRawOffset());
Which outputs for example:
00:18:32
Explanation:
%tT is the time formatted for the 24-hour clock as %tH:%tM:%tS.
%tT also accepts longs as input, so no need to create a Date. printf() will simply print the time specified in milliseconds, but in the current time zone therefore we have to subtract the raw offset of the current time zone so that 0 milliseconds will be 0 hours and not the time offset value of the current time zone.
Note #1: If you need the result as a String, you can get it like this:
String t = String.format("%tT", millis-TimeZone.getDefault().getRawOffset());
Note #2: This only gives correct result if millis is less than a day because the day part is not included in the output.
I think the best way is:
String.format("%d min, %d sec",
TimeUnit.MILLISECONDS.toSeconds(length)/60,
TimeUnit.MILLISECONDS.toSeconds(length) % 60 );
Revisiting #brent-nash contribution, we could use modulus function instead of subtractions and use String.format method for the result string:
/**
* Convert a millisecond duration to a string format
*
* #param millis A duration to convert to a string form
* #return A string of the form "X Days Y Hours Z Minutes A Seconds B Milliseconds".
*/
public static String getDurationBreakdown(long millis) {
if (millis < 0) {
throw new IllegalArgumentException("Duration must be greater than zero!");
}
long days = TimeUnit.MILLISECONDS.toDays(millis);
long hours = TimeUnit.MILLISECONDS.toHours(millis) % 24;
long minutes = TimeUnit.MILLISECONDS.toMinutes(millis) % 60;
long seconds = TimeUnit.MILLISECONDS.toSeconds(millis) % 60;
long milliseconds = millis % 1000;
return String.format("%d Days %d Hours %d Minutes %d Seconds %d Milliseconds",
days, hours, minutes, seconds, milliseconds);
}
Joda-Time
Using Joda-Time:
DateTime startTime = new DateTime();
// do something
DateTime endTime = new DateTime();
Duration duration = new Duration(startTime, endTime);
Period period = duration.toPeriod().normalizedStandard(PeriodType.time());
System.out.println(PeriodFormat.getDefault().print(period));
For those who looking for Kotlin code:
fun converter(millis: Long): String =
String.format(
"%02d : %02d : %02d",
TimeUnit.MILLISECONDS.toHours(millis),
TimeUnit.MILLISECONDS.toMinutes(millis) - TimeUnit.HOURS.toMinutes(
TimeUnit.MILLISECONDS.toHours(millis)
),
TimeUnit.MILLISECONDS.toSeconds(millis) - TimeUnit.MINUTES.toSeconds(
TimeUnit.MILLISECONDS.toMinutes(millis)
)
)
Sample output: 09 : 10 : 26
My simple calculation:
String millisecToTime(int millisec) {
int sec = millisec/1000;
int second = sec % 60;
int minute = sec / 60;
if (minute >= 60) {
int hour = minute / 60;
minute %= 60;
return hour + ":" + (minute < 10 ? "0" + minute : minute) + ":" + (second < 10 ? "0" + second : second);
}
return minute + ":" + (second < 10 ? "0" + second : second);
}
Happy coding :)
Firstly, System.currentTimeMillis() and Instant.now() are not ideal for timing. They both report the wall-clock time, which the computer doesn't know precisely, and which can move erratically, including going backwards if for example the NTP daemon corrects the system time. If your timing happens on a single machine then you should instead use System.nanoTime().
Secondly, from Java 8 onwards java.time.Duration is the best way to represent a duration:
long start = System.nanoTime();
// do things...
long end = System.nanoTime();
Duration duration = Duration.ofNanos(end - start);
System.out.println(duration); // Prints "PT18M19.511627776S"
System.out.printf("%d Hours %d Minutes %d Seconds%n",
duration.toHours(), duration.toMinutes() % 60, duration.getSeconds() % 60);
// prints "0 Hours 18 Minutes 19 Seconds"
for Android below API 9
(String.format("%d hr %d min, %d sec", millis/(1000*60*60), (millis%(1000*60*60))/(1000*60), ((millis%(1000*60*60))%(1000*60))/1000))
For small times, less than an hour, I prefer:
long millis = ...
System.out.printf("%1$TM:%1$TS", millis);
// or
String str = String.format("%1$TM:%1$TS", millis);
for longer intervalls:
private static final long HOUR = TimeUnit.HOURS.toMillis(1);
...
if (millis < HOUR) {
System.out.printf("%1$TM:%1$TS%n", millis);
} else {
System.out.printf("%d:%2$TM:%2$TS%n", millis / HOUR, millis % HOUR);
}
Here is an answer based on Brent Nash answer, Hope that helps !
public static String getDurationBreakdown(long millis)
{
String[] units = {" Days ", " Hours ", " Minutes ", " Seconds "};
Long[] values = new Long[units.length];
if(millis < 0)
{
throw new IllegalArgumentException("Duration must be greater than zero!");
}
values[0] = TimeUnit.MILLISECONDS.toDays(millis);
millis -= TimeUnit.DAYS.toMillis(values[0]);
values[1] = TimeUnit.MILLISECONDS.toHours(millis);
millis -= TimeUnit.HOURS.toMillis(values[1]);
values[2] = TimeUnit.MILLISECONDS.toMinutes(millis);
millis -= TimeUnit.MINUTES.toMillis(values[2]);
values[3] = TimeUnit.MILLISECONDS.toSeconds(millis);
StringBuilder sb = new StringBuilder(64);
boolean startPrinting = false;
for(int i = 0; i < units.length; i++){
if( !startPrinting && values[i] != 0)
startPrinting = true;
if(startPrinting){
sb.append(values[i]);
sb.append(units[i]);
}
}
return(sb.toString());
}
long startTime = System.currentTimeMillis();
// do your work...
long endTime=System.currentTimeMillis();
long diff=endTime-startTime;
long hours=TimeUnit.MILLISECONDS.toHours(diff);
diff=diff-(hours*60*60*1000);
long min=TimeUnit.MILLISECONDS.toMinutes(diff);
diff=diff-(min*60*1000);
long seconds=TimeUnit.MILLISECONDS.toSeconds(diff);
//hour, min and seconds variables contains the time elapsed on your work
This is easier in Java 9:
Duration elapsedTime = Duration.ofMillis(millisDiff );
String humanReadableElapsedTime = String.format(
"%d hours, %d mins, %d seconds",
elapsedTime.toHours(),
elapsedTime.toMinutesPart(),
elapsedTime.toSecondsPart());
This produces a string like 0 hours, 39 mins, 9 seconds.
If you want to round to whole seconds before formatting:
elapsedTime = elapsedTime.plusMillis(500).truncatedTo(ChronoUnit.SECONDS);
To leave out the hours if they are 0:
long hours = elapsedTime.toHours();
String humanReadableElapsedTime;
if (hours == 0) {
humanReadableElapsedTime = String.format(
"%d mins, %d seconds",
elapsedTime.toMinutesPart(),
elapsedTime.toSecondsPart());
} else {
humanReadableElapsedTime = String.format(
"%d hours, %d mins, %d seconds",
hours,
elapsedTime.toMinutesPart(),
elapsedTime.toSecondsPart());
}
Now we can have for example 39 mins, 9 seconds.
To print minutes and seconds with leading zero to make them always two digits, just insert 02 into the relevant format specifiers, thus:
String humanReadableElapsedTime = String.format(
"%d hours, %02d mins, %02d seconds",
elapsedTime.toHours(),
elapsedTime.toMinutesPart(),
elapsedTime.toSecondsPart());
Now we can have for example 0 hours, 39 mins, 09 seconds.
for correct strings ("1hour, 3sec", "3 min" but not "0 hour, 0 min, 3 sec") i write this code:
int seconds = (int)(millis / 1000) % 60 ;
int minutes = (int)((millis / (1000*60)) % 60);
int hours = (int)((millis / (1000*60*60)) % 24);
int days = (int)((millis / (1000*60*60*24)) % 365);
int years = (int)(millis / 1000*60*60*24*365);
ArrayList<String> timeArray = new ArrayList<String>();
if(years > 0)
timeArray.add(String.valueOf(years) + "y");
if(days > 0)
timeArray.add(String.valueOf(days) + "d");
if(hours>0)
timeArray.add(String.valueOf(hours) + "h");
if(minutes>0)
timeArray.add(String.valueOf(minutes) + "min");
if(seconds>0)
timeArray.add(String.valueOf(seconds) + "sec");
String time = "";
for (int i = 0; i < timeArray.size(); i++)
{
time = time + timeArray.get(i);
if (i != timeArray.size() - 1)
time = time + ", ";
}
if (time == "")
time = "0 sec";
If you know the time difference would be less than an hour, then you can use following code:
Calendar c1 = Calendar.getInstance();
Calendar c2 = Calendar.getInstance();
c2.add(Calendar.MINUTE, 51);
long diff = c2.getTimeInMillis() - c1.getTimeInMillis();
c2.set(Calendar.MINUTE, 0);
c2.set(Calendar.HOUR, 0);
c2.set(Calendar.SECOND, 0);
DateFormat df = new SimpleDateFormat("mm:ss");
long diff1 = c2.getTimeInMillis() + diff;
System.out.println(df.format(new Date(diff1)));
It will result to: 51:00
This answer is similar to some answers above. However, I feel that it would be beneficial because, unlike other answers, this will remove any extra commas or whitespace and handles abbreviation.
/**
* Converts milliseconds to "x days, x hours, x mins, x secs"
*
* #param millis
* The milliseconds
* #param longFormat
* {#code true} to use "seconds" and "minutes" instead of "secs" and "mins"
* #return A string representing how long in days/hours/minutes/seconds millis is.
*/
public static String millisToString(long millis, boolean longFormat) {
if (millis < 1000) {
return String.format("0 %s", longFormat ? "seconds" : "secs");
}
String[] units = {
"day", "hour", longFormat ? "minute" : "min", longFormat ? "second" : "sec"
};
long[] times = new long[4];
times[0] = TimeUnit.DAYS.convert(millis, TimeUnit.MILLISECONDS);
millis -= TimeUnit.MILLISECONDS.convert(times[0], TimeUnit.DAYS);
times[1] = TimeUnit.HOURS.convert(millis, TimeUnit.MILLISECONDS);
millis -= TimeUnit.MILLISECONDS.convert(times[1], TimeUnit.HOURS);
times[2] = TimeUnit.MINUTES.convert(millis, TimeUnit.MILLISECONDS);
millis -= TimeUnit.MILLISECONDS.convert(times[2], TimeUnit.MINUTES);
times[3] = TimeUnit.SECONDS.convert(millis, TimeUnit.MILLISECONDS);
StringBuilder s = new StringBuilder();
for (int i = 0; i < 4; i++) {
if (times[i] > 0) {
s.append(String.format("%d %s%s, ", times[i], units[i], times[i] == 1 ? "" : "s"));
}
}
return s.toString().substring(0, s.length() - 2);
}
/**
* Converts milliseconds to "x days, x hours, x mins, x secs"
*
* #param millis
* The milliseconds
* #return A string representing how long in days/hours/mins/secs millis is.
*/
public static String millisToString(long millis) {
return millisToString(millis, false);
}
There is a problem. When milliseconds is 59999, actually it is 1 minute but it will be computed as 59 seconds and 999 milliseconds is lost.
Here is a modified version based on previous answers, which can solve this loss:
public static String formatTime(long millis) {
long seconds = Math.round((double) millis / 1000);
long hours = TimeUnit.SECONDS.toHours(seconds);
if (hours > 0)
seconds -= TimeUnit.HOURS.toSeconds(hours);
long minutes = seconds > 0 ? TimeUnit.SECONDS.toMinutes(seconds) : 0;
if (minutes > 0)
seconds -= TimeUnit.MINUTES.toSeconds(minutes);
return hours > 0 ? String.format("%02d:%02d:%02d", hours, minutes, seconds) : String.format("%02d:%02d", minutes, seconds);
}
I have covered this in another answer but you can do:
public static Map<TimeUnit,Long> computeDiff(Date date1, Date date2) {
long diffInMillies = date2.getTime() - date1.getTime();
List<TimeUnit> units = new ArrayList<TimeUnit>(EnumSet.allOf(TimeUnit.class));
Collections.reverse(units);
Map<TimeUnit,Long> result = new LinkedHashMap<TimeUnit,Long>();
long milliesRest = diffInMillies;
for ( TimeUnit unit : units ) {
long diff = unit.convert(milliesRest,TimeUnit.MILLISECONDS);
long diffInMilliesForUnit = unit.toMillis(diff);
milliesRest = milliesRest - diffInMilliesForUnit;
result.put(unit,diff);
}
return result;
}
The output is something like Map:{DAYS=1, HOURS=3, MINUTES=46, SECONDS=40, MILLISECONDS=0, MICROSECONDS=0, NANOSECONDS=0}, with the units ordered.
It's up to you to figure out how to internationalize this data according to the target locale.
DurationFormatUtils.formatDurationHMS(long)
I modified #MyKuLLSKI 's answer and added plurlization support. I took out seconds because I didn't need them, though feel free to re-add it if you need it.
public static String intervalToHumanReadableTime(int intervalMins) {
if(intervalMins <= 0) {
return "0";
} else {
long intervalMs = intervalMins * 60 * 1000;
long days = TimeUnit.MILLISECONDS.toDays(intervalMs);
intervalMs -= TimeUnit.DAYS.toMillis(days);
long hours = TimeUnit.MILLISECONDS.toHours(intervalMs);
intervalMs -= TimeUnit.HOURS.toMillis(hours);
long minutes = TimeUnit.MILLISECONDS.toMinutes(intervalMs);
StringBuilder sb = new StringBuilder(12);
if (days >= 1) {
sb.append(days).append(" day").append(pluralize(days)).append(", ");
}
if (hours >= 1) {
sb.append(hours).append(" hour").append(pluralize(hours)).append(", ");
}
if (minutes >= 1) {
sb.append(minutes).append(" minute").append(pluralize(minutes));
} else {
sb.delete(sb.length()-2, sb.length()-1);
}
return(sb.toString());
}
}
public static String pluralize(long val) {
return (Math.round(val) > 1 ? "s" : "");
}
Use java.util.concurrent.TimeUnit, and use this simple method:
private static long timeDiff(Date date, Date date2, TimeUnit unit) {
long milliDiff=date2.getTime()-date.getTime();
long unitDiff = unit.convert(milliDiff, TimeUnit.MILLISECONDS);
return unitDiff;
}
For example:
SimpleDateFormat sdf = new SimpleDateFormat("yy/MM/dd HH:mm:ss");
Date firstDate = sdf.parse("06/24/2017 04:30:00");
Date secondDate = sdf.parse("07/24/2017 05:00:15");
Date thirdDate = sdf.parse("06/24/2017 06:00:15");
System.out.println("days difference: "+timeDiff(firstDate,secondDate,TimeUnit.DAYS));
System.out.println("hours difference: "+timeDiff(firstDate,thirdDate,TimeUnit.HOURS));
System.out.println("minutes difference: "+timeDiff(firstDate,thirdDate,TimeUnit.MINUTES));
System.out.println("seconds difference: "+timeDiff(firstDate,thirdDate,TimeUnit.SECONDS));
This topic has been well covered, I just wanted to share my functions perhaps you can make use of these rather than importing an entire library.
public long getSeconds(ms) {
return (ms/1000%60);
}
public long getMinutes(ms) {
return (ms/(1000*60)%60);
}
public long getHours(ms) {
return ((ms/(1000*60*60))%24);
}