Display the value of swing timer - java

Currently I am printing my values for my swing worker timer in a label
.setText(days + " Days :" + hours + " Hours :" + mins + " Minutes : " + seconds + " Seconds elapsed")
I was wondering if it were possible to format this in a slightly neater way?

I've got a program that I'm working on now that uses String.format(...) and a format String for this:
// in the constants section
private static final String DISPLAY_FORMAT_STR = "%02d:%02d:%02d:%01d";
private void showTimeLeft() {
int oldMin = min;
hours = (int) (deltaTime / (MS_PER_SEC * SEC_PER_MIN * MIN_PER_HR));
min = (int) (deltaTime / (MS_PER_SEC * SEC_PER_MIN) % MIN_PER_HR);
sec = (int) (deltaTime / (MS_PER_SEC) % SEC_PER_MIN);
msec = (int) (deltaTime % MS_PER_SEC);
String displayString = String.format(DISPLAY_FORMAT_STR, hours, min, sec,
msec / 100);
displayField.setText(displayString);
// ... etc...
Otherwise if you're dealing with a Date object (I'm not), you could use a SimpleDateFormat object to better format your output.

How about String.format()?
http://docs.oracle.com/javase/6/docs/api/java/util/Formatter.html#syntax

One of ways, how do you can calculating elapsed time
long start = System.currentTimeMillis();
// some code executed
long end = System.currentTimeMillis();
long elapsed = end - start;
long seconds = elapsed / 1000;
rest for calculating days / hours / minutes / seconds

Related

Java - Adding a 0 in the minutes of the current time (GMT) [duplicate]

This question already has answers here:
How can I pad an integer with zeros on the left?
(18 answers)
Closed 6 years ago.
when I output the following code (taken from dr. Liang Introduction to Java, 10th ed., chapter 03 - selections)
/*
(Current time) Listing 2.7, ShowCurrentTime.java, gives a program that displays
the current time in GMT. Revise the program so that it prompts the user to enter
the time zone offset to GMT and displays the time in the specified time zone.
*/
import java.util.Scanner;
public class Ex_03_08 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter the time zone (GMT): ");
int gmt = input.nextInt();
long totalMilliseconds = System.currentTimeMillis();
long totalSeconds = totalMilliseconds / 1000;
long currentSecond = totalSeconds % 60;
long totalMinutes = totalSeconds / 60;
long currentMinute = totalMinutes % 60;
long totalHours = totalMinutes / 60;
long currentHour = totalHours % 24;
currentHour = currentHour + gmt;
System.out.println("The current time is " + currentHour + ":"
+ currentMinute + ":" + currentSecond);
input.close();
}
}
the output is
Enter the time zone (GMT): 1
The current time is 11:2:31
How can I let display instead 11:02:31?
Thank you.
You can do something like this,
String currentMinuteStr=""+currentMinute ;
if(currentMinuteStr.length()==1){
currentMinuteStr="0"+currentMinuteStr;
}
I have just converted the minutes variable to string and then checked whether the length of the string is 1 that is whether it is a one digit minute and then i have appended the existing minutes to 0 and then you can display it as before like this,
System.out.println("The current time is " + currentHour + ":"
+ currentMinuteStr+ ":" + currentSecond);
You can format your input in C style printf using format method.
class NumericFormat
{
public static void main(String[] args) {
System.out.format("%02d%n",3);
//you can use \n too but %n is preferrable for format method
}
}
Get a better understanding at Java Docs
If link fails, here are some of the formatters.
On a side Note, to format and use Date and Time, Java 8 has clean inbuilt API. Get a look at this Oracle tutorial - Date Time Parsing and Formatting
long totalMilliseconds = System.currentTimeMillis();
long totalSeconds = totalMilliseconds / 1000;
long currentSecond = totalSeconds % 60;
long totalMinutes = totalSeconds / 60;
long currentMinute = totalMinutes % 60;
long totalHours = totalMinutes / 60;
long currentHour = totalHours % 24;
currentHour = currentHour + gmt;
String strTime = "" + (currentHour < 10 ? "0" + currentHour : currentHour) +
(currentMinute < 10 ? "0" + currentMinute : currentMinute) +
(currentSecond < 10 ? "0" + currentSecond : currentSecond);
System.out.println("The current time is : " + strTime);

How to update time every second in Java emulator? [duplicate]

This question already has answers here:
Update time every second
(3 answers)
Closed 8 years ago.
I have been working on a code for an app but I cannot get the time to update in the emulator when I run the code. The code works in the compiler but not the emulator.
Any helpful suggestions would be greatly appreciated. The timer is a countdown to Christmas day.
Here is my code:
Calendar today = Calendar.getInstance();
Calendar thatDay = Calendar.getInstance();
thatDay.set(Calendar.DAY_OF_MONTH, 25);
thatDay.set(Calendar.MONTH, 11); // 0-11 so 1 less
thatDay.set(Calendar.YEAR, 2014);
thatDay.set(Calendar.HOUR, 0);
thatDay.set(Calendar.MINUTE, 0);
thatDay.set(Calendar.SECOND, 0);
thatDay.set(Calendar.AM_PM, 0);
System.out.println(thatDay.getTime());
ScheduledExecutorService scheduledExecutorService=
Executors.newScheduledThreadPool(1);
scheduledExecutorService.scheduleAtFixedRate(new ReadThisPeriod(thatDay), 0, 1,
TimeUnit.SECONDS);
long diff = (thatDay.getTimeInMillis() - today.getTimeInMillis()) / 1000;
long days = diff / (60 * 60 * 24);
long hours = diff / (60 * 60) % 24;
long minutes = diff / 60 % 60;
long seconds = diff % 60;
TextView daysBox = (TextView) findViewById(R.id.s1Days);
daysBox.setText(" + "" + days + "" + hours + "" + minutes + " " + seconds + " ");
Keeping things very simple, I'd remove all Executors stuff and do something like:
TextView daysBox = (TextView) findViewById(R.id.s1Days);
// We create a runnable that will re-call itself each second to update time
Runnable printDaysToXmas=new Runnable() {
#Override
public void run() {
Calendar today = Calendar.getInstance();
long diff = (thatDay.getTimeInMillis() - today.getTimeInMillis()) / 1000;
long days = diff / (60 * 60 * 24);
long hours = diff / (60 * 60) % 24;
long minutes = diff / 60 % 60;
long seconds = diff % 60;
daysBox.setText(" + "" + days + "" + hours + "" + minutes + " " + seconds + " ");
// we call this runnable again in 1000ms (1 sec)
daysBox.postDelayed(printDaysToXmas, 1000); // all views have a Handler you can use ;P
}
};
... and to start the process just do
printDaysToXmas.run();
... and to stop it, you can do
daysBox.removeCallbacks(printDaysToXmas);
Also some little add to rupps answer. You can use
DateUtils.getRelativeTimeSpanString(long time, long now, long minResolution);
to simplify math and give more user readable string for user.

Issue converting to seconds

Can anyone assist me as to why my seconds are not printing out correctly? The hours and minutes are both correct, but it is not printing out anything for the secs variable. The items in my arraylist are in System.currentTimeMillis(), which is why I have to convert them.
//divides 'logoutTimeTotal' by 'loginTimeTotal' to get 'totalTimeLoggedIn'
long totalTimeLoggedIn = (((totalTimeArray.get(1) - totalTimeArray.get(0)) / 1000) / 60);
//creates 2 variables that convert time logged in to hours and minutes
long hr = totalTimeLoggedIn / 60;
long min = totalTimeLoggedIn - (hr * 60);
long secs = totalTimeLoggedIn;
//creates String variable with hours and minutes logged in
String timeLoggedStr = hr + " Hours " + min + " Minutes " + secs + " Seconds";
Thanks
You problem is when you getting the totalTimeLoggedIn, you do:
long totalTimeLoggedIn = (((totalTimeArray.get(1) - totalTimeArray.get(0)) / 1000) / 60);
If you want to get the total time in second that generating using System.currentTimeMillis(), then you have to divide just on 1000,since the 1 second is 1000 milliseconds, so you need to do:
long totalTimeLoggedIn = (((totalTimeArray.get(1) - totalTimeArray.get(0)) / 1000));
It is probably caused by rounding.
Instead of long, using float is better.

How to measure the a time-span in seconds using System.currentTimeMillis()?

How to convert System.currentTimeMillis(); to seconds?
long start6=System.currentTimeMillis();
System.out.println(counter.countPrimes(100000000)+" for "+start6);
The console shows me 5761455 for 1307816001290.
I can't read how many seconds that is.
Any help?
TimeUnit
Use the TimeUnit enum built into Java 5 and later.
long timeMillis = System.currentTimeMillis();
long timeSeconds = TimeUnit.MILLISECONDS.toSeconds(timeMillis);
long start = System.currentTimeMillis();
counter.countPrimes(1000000);
long end = System.currentTimeMillis();
System.out.println("Took : " + ((end - start) / 1000));
UPDATE
An even more accurate solution would be:
final long start = System.nanoTime();
counter.countPrimes(1000000);
final long end = System.nanoTime();
System.out.println("Took: " + ((end - start) / 1000000) + "ms");
System.out.println("Took: " + (end - start)/ 1000000000 + " seconds");
like so:
(int)(milliseconds / 1000)
Java 8 now provides the most concise method to get current Unix Timestamp:
Instant.now().getEpochSecond();
From your code it would appear that you are trying to measure how long a computation took (as opposed to trying to figure out what the current time is).
In that case, you need to call currentTimeMillis before and after the computation, take the difference, and divide the result by 1000 to convert milliseconds to seconds.
I have written the following code in my last assignment, it may help you:
// A method that converts the nano-seconds to Seconds-Minutes-Hours form
private static String formatTime(long nanoSeconds)
{
int hours, minutes, remainder, totalSecondsNoFraction;
double totalSeconds, seconds;
// Calculating hours, minutes and seconds
totalSeconds = (double) nanoSeconds / 1000000000.0;
String s = Double.toString(totalSeconds);
String [] arr = s.split("\\.");
totalSecondsNoFraction = Integer.parseInt(arr[0]);
hours = totalSecondsNoFraction / 3600;
remainder = totalSecondsNoFraction % 3600;
minutes = remainder / 60;
seconds = remainder % 60;
if(arr[1].contains("E")) seconds = Double.parseDouble("." + arr[1]);
else seconds += Double.parseDouble("." + arr[1]);
// Formatting the string that conatins hours, minutes and seconds
StringBuilder result = new StringBuilder(".");
String sep = "", nextSep = " and ";
if(seconds > 0)
{
result.insert(0, " seconds").insert(0, seconds);
sep = nextSep;
nextSep = ", ";
}
if(minutes > 0)
{
if(minutes > 1) result.insert(0, sep).insert(0, " minutes").insert(0, minutes);
else result.insert(0, sep).insert(0, " minute").insert(0, minutes);
sep = nextSep;
nextSep = ", ";
}
if(hours > 0)
{
if(hours > 1) result.insert(0, sep).insert(0, " hours").insert(0, hours);
else result.insert(0, sep).insert(0, " hour").insert(0, hours);
}
return result.toString();
}
Just convert nano-seconds to milli-seconds.
TimeUnit.SECONDS.convert(start6, TimeUnit.MILLISECONDS);
For conversion of milliseconds to seconds, since 1 second = 10³ milliseconds:
//here m will be in seconds
long m = System.currentTimeMillis()/1000;
//here m will be in minutes
long m = System.currentTimeMillis()/1000/60; //this will give in mins
// Convert millis to seconds. This can be simplified a bit,
// but I left it in this form for clarity.
long m = System.currentTimeMillis(); // that's our input
int s = Math.max(
.18 * (Math.toRadians(m)/Math.PI),
Math.pow( Math.E, Math.log(m)-Math.log(1000) )
);
System.out.println( "seconds: "+s );

How to convert Milliseconds to "X mins, x seconds" in Java?

I want to record the time using System.currentTimeMillis() when a user begins something in my program. When he finishes, I will subtract the current System.currentTimeMillis() from the start variable, and I want to show them the time elapsed using a human readable format such as "XX hours, XX mins, XX seconds" or even "XX mins, XX seconds" because its not likely to take someone an hour.
What's the best way to do this?
Use the java.util.concurrent.TimeUnit class:
String.format("%d min, %d sec",
TimeUnit.MILLISECONDS.toMinutes(millis),
TimeUnit.MILLISECONDS.toSeconds(millis) -
TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis))
);
Note: TimeUnit is part of the Java 1.5 specification, but toMinutes was added as of Java 1.6.
To add a leading zero for values 0-9, just do:
String.format("%02d min, %02d sec",
TimeUnit.MILLISECONDS.toMinutes(millis),
TimeUnit.MILLISECONDS.toSeconds(millis) -
TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis))
);
If TimeUnit or toMinutes are unsupported (such as on Android before API version 9), use the following equations:
int seconds = (int) (milliseconds / 1000) % 60 ;
int minutes = (int) ((milliseconds / (1000*60)) % 60);
int hours = (int) ((milliseconds / (1000*60*60)) % 24);
//etc...
Based on #siddhadev's answer, I wrote a function which converts milliseconds to a formatted string:
/**
* Convert a millisecond duration to a string format
*
* #param millis A duration to convert to a string form
* #return A string of the form "X Days Y Hours Z Minutes A Seconds".
*/
public static String getDurationBreakdown(long millis) {
if(millis < 0) {
throw new IllegalArgumentException("Duration must be greater than zero!");
}
long days = TimeUnit.MILLISECONDS.toDays(millis);
millis -= TimeUnit.DAYS.toMillis(days);
long hours = TimeUnit.MILLISECONDS.toHours(millis);
millis -= TimeUnit.HOURS.toMillis(hours);
long minutes = TimeUnit.MILLISECONDS.toMinutes(millis);
millis -= TimeUnit.MINUTES.toMillis(minutes);
long seconds = TimeUnit.MILLISECONDS.toSeconds(millis);
StringBuilder sb = new StringBuilder(64);
sb.append(days);
sb.append(" Days ");
sb.append(hours);
sb.append(" Hours ");
sb.append(minutes);
sb.append(" Minutes ");
sb.append(seconds);
sb.append(" Seconds");
return(sb.toString());
}
long time = 1536259;
return (new SimpleDateFormat("mm:ss:SSS")).format(new Date(time));
Prints:
25:36:259
Using the java.time package in Java 8:
Instant start = Instant.now();
Thread.sleep(63553);
Instant end = Instant.now();
System.out.println(Duration.between(start, end));
Output is in ISO 8601 Duration format: PT1M3.553S (1 minute and 3.553 seconds).
Uhm... how many milliseconds are in a second? And in a minute? Division is not that hard.
int seconds = (int) ((milliseconds / 1000) % 60);
int minutes = (int) ((milliseconds / 1000) / 60);
Continue like that for hours, days, weeks, months, year, decades, whatever.
I would not pull in the extra dependency just for that (division is not that hard, after all), but if you are using Commons Lang anyway, there are the DurationFormatUtils.
Example Usage (adapted from here):
import org.apache.commons.lang3.time.DurationFormatUtils
public String getAge(long value) {
long currentTime = System.currentTimeMillis();
long age = currentTime - value;
String ageString = DurationFormatUtils.formatDuration(age, "d") + "d";
if ("0d".equals(ageString)) {
ageString = DurationFormatUtils.formatDuration(age, "H") + "h";
if ("0h".equals(ageString)) {
ageString = DurationFormatUtils.formatDuration(age, "m") + "m";
if ("0m".equals(ageString)) {
ageString = DurationFormatUtils.formatDuration(age, "s") + "s";
if ("0s".equals(ageString)) {
ageString = age + "ms";
}
}
}
}
return ageString;
}
Example:
long lastTime = System.currentTimeMillis() - 2000;
System.out.println("Elapsed time: " + getAge(lastTime));
//Output: 2s
Note: To get millis from two LocalDateTime objects you can use:
long age = ChronoUnit.MILLIS.between(initTime, LocalDateTime.now())
Either hand divisions, or use the SimpleDateFormat API.
long start = System.currentTimeMillis();
// do your work...
long elapsed = System.currentTimeMillis() - start;
DateFormat df = new SimpleDateFormat("HH 'hours', mm 'mins,' ss 'seconds'");
df.setTimeZone(TimeZone.getTimeZone("GMT+0"));
System.out.println(df.format(new Date(elapsed)));
Edit by Bombe: It has been shown in the comments that this approach only works for smaller durations (i.e. less than a day).
Just to add more info
if you want to format like: HH:mm:ss
0 <= HH <= infinite
0 <= mm < 60
0 <= ss < 60
use this:
int h = (int) ((startTimeInMillis / 1000) / 3600);
int m = (int) (((startTimeInMillis / 1000) / 60) % 60);
int s = (int) ((startTimeInMillis / 1000) % 60);
I just had this issue now and figured this out
Shortest solution:
Here's probably the shortest which also deals with time zones.
System.out.printf("%tT", millis-TimeZone.getDefault().getRawOffset());
Which outputs for example:
00:18:32
Explanation:
%tT is the time formatted for the 24-hour clock as %tH:%tM:%tS.
%tT also accepts longs as input, so no need to create a Date. printf() will simply print the time specified in milliseconds, but in the current time zone therefore we have to subtract the raw offset of the current time zone so that 0 milliseconds will be 0 hours and not the time offset value of the current time zone.
Note #1: If you need the result as a String, you can get it like this:
String t = String.format("%tT", millis-TimeZone.getDefault().getRawOffset());
Note #2: This only gives correct result if millis is less than a day because the day part is not included in the output.
I think the best way is:
String.format("%d min, %d sec",
TimeUnit.MILLISECONDS.toSeconds(length)/60,
TimeUnit.MILLISECONDS.toSeconds(length) % 60 );
Revisiting #brent-nash contribution, we could use modulus function instead of subtractions and use String.format method for the result string:
/**
* Convert a millisecond duration to a string format
*
* #param millis A duration to convert to a string form
* #return A string of the form "X Days Y Hours Z Minutes A Seconds B Milliseconds".
*/
public static String getDurationBreakdown(long millis) {
if (millis < 0) {
throw new IllegalArgumentException("Duration must be greater than zero!");
}
long days = TimeUnit.MILLISECONDS.toDays(millis);
long hours = TimeUnit.MILLISECONDS.toHours(millis) % 24;
long minutes = TimeUnit.MILLISECONDS.toMinutes(millis) % 60;
long seconds = TimeUnit.MILLISECONDS.toSeconds(millis) % 60;
long milliseconds = millis % 1000;
return String.format("%d Days %d Hours %d Minutes %d Seconds %d Milliseconds",
days, hours, minutes, seconds, milliseconds);
}
Joda-Time
Using Joda-Time:
DateTime startTime = new DateTime();
// do something
DateTime endTime = new DateTime();
Duration duration = new Duration(startTime, endTime);
Period period = duration.toPeriod().normalizedStandard(PeriodType.time());
System.out.println(PeriodFormat.getDefault().print(period));
For those who looking for Kotlin code:
fun converter(millis: Long): String =
String.format(
"%02d : %02d : %02d",
TimeUnit.MILLISECONDS.toHours(millis),
TimeUnit.MILLISECONDS.toMinutes(millis) - TimeUnit.HOURS.toMinutes(
TimeUnit.MILLISECONDS.toHours(millis)
),
TimeUnit.MILLISECONDS.toSeconds(millis) - TimeUnit.MINUTES.toSeconds(
TimeUnit.MILLISECONDS.toMinutes(millis)
)
)
Sample output: 09 : 10 : 26
My simple calculation:
String millisecToTime(int millisec) {
int sec = millisec/1000;
int second = sec % 60;
int minute = sec / 60;
if (minute >= 60) {
int hour = minute / 60;
minute %= 60;
return hour + ":" + (minute < 10 ? "0" + minute : minute) + ":" + (second < 10 ? "0" + second : second);
}
return minute + ":" + (second < 10 ? "0" + second : second);
}
Happy coding :)
Firstly, System.currentTimeMillis() and Instant.now() are not ideal for timing. They both report the wall-clock time, which the computer doesn't know precisely, and which can move erratically, including going backwards if for example the NTP daemon corrects the system time. If your timing happens on a single machine then you should instead use System.nanoTime().
Secondly, from Java 8 onwards java.time.Duration is the best way to represent a duration:
long start = System.nanoTime();
// do things...
long end = System.nanoTime();
Duration duration = Duration.ofNanos(end - start);
System.out.println(duration); // Prints "PT18M19.511627776S"
System.out.printf("%d Hours %d Minutes %d Seconds%n",
duration.toHours(), duration.toMinutes() % 60, duration.getSeconds() % 60);
// prints "0 Hours 18 Minutes 19 Seconds"
for Android below API 9
(String.format("%d hr %d min, %d sec", millis/(1000*60*60), (millis%(1000*60*60))/(1000*60), ((millis%(1000*60*60))%(1000*60))/1000))
For small times, less than an hour, I prefer:
long millis = ...
System.out.printf("%1$TM:%1$TS", millis);
// or
String str = String.format("%1$TM:%1$TS", millis);
for longer intervalls:
private static final long HOUR = TimeUnit.HOURS.toMillis(1);
...
if (millis < HOUR) {
System.out.printf("%1$TM:%1$TS%n", millis);
} else {
System.out.printf("%d:%2$TM:%2$TS%n", millis / HOUR, millis % HOUR);
}
Here is an answer based on Brent Nash answer, Hope that helps !
public static String getDurationBreakdown(long millis)
{
String[] units = {" Days ", " Hours ", " Minutes ", " Seconds "};
Long[] values = new Long[units.length];
if(millis < 0)
{
throw new IllegalArgumentException("Duration must be greater than zero!");
}
values[0] = TimeUnit.MILLISECONDS.toDays(millis);
millis -= TimeUnit.DAYS.toMillis(values[0]);
values[1] = TimeUnit.MILLISECONDS.toHours(millis);
millis -= TimeUnit.HOURS.toMillis(values[1]);
values[2] = TimeUnit.MILLISECONDS.toMinutes(millis);
millis -= TimeUnit.MINUTES.toMillis(values[2]);
values[3] = TimeUnit.MILLISECONDS.toSeconds(millis);
StringBuilder sb = new StringBuilder(64);
boolean startPrinting = false;
for(int i = 0; i < units.length; i++){
if( !startPrinting && values[i] != 0)
startPrinting = true;
if(startPrinting){
sb.append(values[i]);
sb.append(units[i]);
}
}
return(sb.toString());
}
long startTime = System.currentTimeMillis();
// do your work...
long endTime=System.currentTimeMillis();
long diff=endTime-startTime;
long hours=TimeUnit.MILLISECONDS.toHours(diff);
diff=diff-(hours*60*60*1000);
long min=TimeUnit.MILLISECONDS.toMinutes(diff);
diff=diff-(min*60*1000);
long seconds=TimeUnit.MILLISECONDS.toSeconds(diff);
//hour, min and seconds variables contains the time elapsed on your work
This is easier in Java 9:
Duration elapsedTime = Duration.ofMillis(millisDiff );
String humanReadableElapsedTime = String.format(
"%d hours, %d mins, %d seconds",
elapsedTime.toHours(),
elapsedTime.toMinutesPart(),
elapsedTime.toSecondsPart());
This produces a string like 0 hours, 39 mins, 9 seconds.
If you want to round to whole seconds before formatting:
elapsedTime = elapsedTime.plusMillis(500).truncatedTo(ChronoUnit.SECONDS);
To leave out the hours if they are 0:
long hours = elapsedTime.toHours();
String humanReadableElapsedTime;
if (hours == 0) {
humanReadableElapsedTime = String.format(
"%d mins, %d seconds",
elapsedTime.toMinutesPart(),
elapsedTime.toSecondsPart());
} else {
humanReadableElapsedTime = String.format(
"%d hours, %d mins, %d seconds",
hours,
elapsedTime.toMinutesPart(),
elapsedTime.toSecondsPart());
}
Now we can have for example 39 mins, 9 seconds.
To print minutes and seconds with leading zero to make them always two digits, just insert 02 into the relevant format specifiers, thus:
String humanReadableElapsedTime = String.format(
"%d hours, %02d mins, %02d seconds",
elapsedTime.toHours(),
elapsedTime.toMinutesPart(),
elapsedTime.toSecondsPart());
Now we can have for example 0 hours, 39 mins, 09 seconds.
for correct strings ("1hour, 3sec", "3 min" but not "0 hour, 0 min, 3 sec") i write this code:
int seconds = (int)(millis / 1000) % 60 ;
int minutes = (int)((millis / (1000*60)) % 60);
int hours = (int)((millis / (1000*60*60)) % 24);
int days = (int)((millis / (1000*60*60*24)) % 365);
int years = (int)(millis / 1000*60*60*24*365);
ArrayList<String> timeArray = new ArrayList<String>();
if(years > 0)
timeArray.add(String.valueOf(years) + "y");
if(days > 0)
timeArray.add(String.valueOf(days) + "d");
if(hours>0)
timeArray.add(String.valueOf(hours) + "h");
if(minutes>0)
timeArray.add(String.valueOf(minutes) + "min");
if(seconds>0)
timeArray.add(String.valueOf(seconds) + "sec");
String time = "";
for (int i = 0; i < timeArray.size(); i++)
{
time = time + timeArray.get(i);
if (i != timeArray.size() - 1)
time = time + ", ";
}
if (time == "")
time = "0 sec";
If you know the time difference would be less than an hour, then you can use following code:
Calendar c1 = Calendar.getInstance();
Calendar c2 = Calendar.getInstance();
c2.add(Calendar.MINUTE, 51);
long diff = c2.getTimeInMillis() - c1.getTimeInMillis();
c2.set(Calendar.MINUTE, 0);
c2.set(Calendar.HOUR, 0);
c2.set(Calendar.SECOND, 0);
DateFormat df = new SimpleDateFormat("mm:ss");
long diff1 = c2.getTimeInMillis() + diff;
System.out.println(df.format(new Date(diff1)));
It will result to: 51:00
This answer is similar to some answers above. However, I feel that it would be beneficial because, unlike other answers, this will remove any extra commas or whitespace and handles abbreviation.
/**
* Converts milliseconds to "x days, x hours, x mins, x secs"
*
* #param millis
* The milliseconds
* #param longFormat
* {#code true} to use "seconds" and "minutes" instead of "secs" and "mins"
* #return A string representing how long in days/hours/minutes/seconds millis is.
*/
public static String millisToString(long millis, boolean longFormat) {
if (millis < 1000) {
return String.format("0 %s", longFormat ? "seconds" : "secs");
}
String[] units = {
"day", "hour", longFormat ? "minute" : "min", longFormat ? "second" : "sec"
};
long[] times = new long[4];
times[0] = TimeUnit.DAYS.convert(millis, TimeUnit.MILLISECONDS);
millis -= TimeUnit.MILLISECONDS.convert(times[0], TimeUnit.DAYS);
times[1] = TimeUnit.HOURS.convert(millis, TimeUnit.MILLISECONDS);
millis -= TimeUnit.MILLISECONDS.convert(times[1], TimeUnit.HOURS);
times[2] = TimeUnit.MINUTES.convert(millis, TimeUnit.MILLISECONDS);
millis -= TimeUnit.MILLISECONDS.convert(times[2], TimeUnit.MINUTES);
times[3] = TimeUnit.SECONDS.convert(millis, TimeUnit.MILLISECONDS);
StringBuilder s = new StringBuilder();
for (int i = 0; i < 4; i++) {
if (times[i] > 0) {
s.append(String.format("%d %s%s, ", times[i], units[i], times[i] == 1 ? "" : "s"));
}
}
return s.toString().substring(0, s.length() - 2);
}
/**
* Converts milliseconds to "x days, x hours, x mins, x secs"
*
* #param millis
* The milliseconds
* #return A string representing how long in days/hours/mins/secs millis is.
*/
public static String millisToString(long millis) {
return millisToString(millis, false);
}
There is a problem. When milliseconds is 59999, actually it is 1 minute but it will be computed as 59 seconds and 999 milliseconds is lost.
Here is a modified version based on previous answers, which can solve this loss:
public static String formatTime(long millis) {
long seconds = Math.round((double) millis / 1000);
long hours = TimeUnit.SECONDS.toHours(seconds);
if (hours > 0)
seconds -= TimeUnit.HOURS.toSeconds(hours);
long minutes = seconds > 0 ? TimeUnit.SECONDS.toMinutes(seconds) : 0;
if (minutes > 0)
seconds -= TimeUnit.MINUTES.toSeconds(minutes);
return hours > 0 ? String.format("%02d:%02d:%02d", hours, minutes, seconds) : String.format("%02d:%02d", minutes, seconds);
}
I have covered this in another answer but you can do:
public static Map<TimeUnit,Long> computeDiff(Date date1, Date date2) {
long diffInMillies = date2.getTime() - date1.getTime();
List<TimeUnit> units = new ArrayList<TimeUnit>(EnumSet.allOf(TimeUnit.class));
Collections.reverse(units);
Map<TimeUnit,Long> result = new LinkedHashMap<TimeUnit,Long>();
long milliesRest = diffInMillies;
for ( TimeUnit unit : units ) {
long diff = unit.convert(milliesRest,TimeUnit.MILLISECONDS);
long diffInMilliesForUnit = unit.toMillis(diff);
milliesRest = milliesRest - diffInMilliesForUnit;
result.put(unit,diff);
}
return result;
}
The output is something like Map:{DAYS=1, HOURS=3, MINUTES=46, SECONDS=40, MILLISECONDS=0, MICROSECONDS=0, NANOSECONDS=0}, with the units ordered.
It's up to you to figure out how to internationalize this data according to the target locale.
DurationFormatUtils.formatDurationHMS(long)
I modified #MyKuLLSKI 's answer and added plurlization support. I took out seconds because I didn't need them, though feel free to re-add it if you need it.
public static String intervalToHumanReadableTime(int intervalMins) {
if(intervalMins <= 0) {
return "0";
} else {
long intervalMs = intervalMins * 60 * 1000;
long days = TimeUnit.MILLISECONDS.toDays(intervalMs);
intervalMs -= TimeUnit.DAYS.toMillis(days);
long hours = TimeUnit.MILLISECONDS.toHours(intervalMs);
intervalMs -= TimeUnit.HOURS.toMillis(hours);
long minutes = TimeUnit.MILLISECONDS.toMinutes(intervalMs);
StringBuilder sb = new StringBuilder(12);
if (days >= 1) {
sb.append(days).append(" day").append(pluralize(days)).append(", ");
}
if (hours >= 1) {
sb.append(hours).append(" hour").append(pluralize(hours)).append(", ");
}
if (minutes >= 1) {
sb.append(minutes).append(" minute").append(pluralize(minutes));
} else {
sb.delete(sb.length()-2, sb.length()-1);
}
return(sb.toString());
}
}
public static String pluralize(long val) {
return (Math.round(val) > 1 ? "s" : "");
}
Use java.util.concurrent.TimeUnit, and use this simple method:
private static long timeDiff(Date date, Date date2, TimeUnit unit) {
long milliDiff=date2.getTime()-date.getTime();
long unitDiff = unit.convert(milliDiff, TimeUnit.MILLISECONDS);
return unitDiff;
}
For example:
SimpleDateFormat sdf = new SimpleDateFormat("yy/MM/dd HH:mm:ss");
Date firstDate = sdf.parse("06/24/2017 04:30:00");
Date secondDate = sdf.parse("07/24/2017 05:00:15");
Date thirdDate = sdf.parse("06/24/2017 06:00:15");
System.out.println("days difference: "+timeDiff(firstDate,secondDate,TimeUnit.DAYS));
System.out.println("hours difference: "+timeDiff(firstDate,thirdDate,TimeUnit.HOURS));
System.out.println("minutes difference: "+timeDiff(firstDate,thirdDate,TimeUnit.MINUTES));
System.out.println("seconds difference: "+timeDiff(firstDate,thirdDate,TimeUnit.SECONDS));
This topic has been well covered, I just wanted to share my functions perhaps you can make use of these rather than importing an entire library.
public long getSeconds(ms) {
return (ms/1000%60);
}
public long getMinutes(ms) {
return (ms/(1000*60)%60);
}
public long getHours(ms) {
return ((ms/(1000*60*60))%24);
}

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