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Date format conversion error [duplicate]

This question already has answers here:
SimpleDateFormat ignoring month when parsing
(4 answers)
Closed 9 years ago.
I am facing the problem while converting the date:
Current format is:Thu Sep 05 12:07:46 IST 2013(dow mon dd hh:mm:ss zzz yyyy)
I need to convert in to:09/04/2013 11:38 PM PDT(mm/dd/yyyy hh:mm a zzz)
But i am not able to convert.

Try using SimpleDateFormatter. You have to tell it the input/output format, you can do that based on this description (you can also find a few common examples there).
The code will be something like this:
try {
String input = "Thu Sep 05 12:07:46 IST 2013";
DateFormat formatter = new SimpleDateFormat("I leave this to you :-)))");
System.out.println(formatter.parse(input));
} catch (ParseException e) {
e.printStackTrace();
}
Hope that helps.

You can do this
TimeZone tz = TimeZone.getTimeZone("PST8PDT"); // example
// required format. Remember M is for month, m for miniute
DateFormat df = new SimpleDateFormat("MM/dd/yyyy hh:mm a zzz");
df.setTimeZone(tz);
String text = df.format(new Date());// current time
System.out.println(text);
Also please check this TimeZones in Java

You try to convert dateformat and timeZone as well, so you need to convert the timezone in your code.
SimpleDateFormat sf = new SimpleDateFormat("dow mon dd hh:mm:ss zzz yyyy");
isoFormat.setTimeZone(TimeZone.getTimeZone("PDT"));
Date date = isoFormat.parse("mm/dd/yyyy hh:mm a zzz");
this may help you.

try {
DateFormat dffrom = new SimpleDateFormat("E MMM dd hh:mm:ss zzz yyyy");
DateFormat dfto = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss a zzz");
Date date = dffrom.parse("Thu Sep 05 12:07:46 IST 2013");
String s = dfto.format(date);
System.out.println(s);
} catch (ParseException e) {
}
OutPut
09/05/2013 00:07:46 AM IST
update
try {
DateFormat dffrom = new SimpleDateFormat("E MMM dd hh:mm:ss zzz yyyy");
DateFormat dfto = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss a zzz");
TimeZone zone = TimeZone.getTimeZone("America/Los_Angeles");
dfto.setTimeZone(zone);
Date date = dffrom.parse("Thu Sep 05 12:07:46 IST 2013");
String s = dfto.format(date);
System.out.println(s);
} catch (ParseException e) {
}
output
09/04/2013 11:37:46 AM PDT

Simpledateformat ParseException

I need to change the input date format to my desired format.
String time = "Fri, 02 Nov 2012 11:58 pm CET";
SimpleDateFormat displayFormat =
new SimpleDateFormat("dd.MM.yyyy, HH:mm");
SimpleDateFormat parseFormat =
new SimpleDateFormat("EEE, dd MMM yyyy HH:mm aa z");
Date date = parseFormat.parse(time);
System.out.println("output is " + displayFormat.format(date));
it gives me this error
java.text.ParseException: Unparseable date: "Fri, 02 Nov 2012 11:58 pm CET"
at java.text.DateFormat.parse(Unknown Source)
at Main.main(Main.java:10)
Can anyody help me? Because this code doesn't work.

It appears Android's z does not accept time zones in the format XXX (such as "CET"). (Pulling from the SimpleDateFormat documentation.)
Try this instead:
String time = "Fri, 02 Nov 2012 11:58 pm +0100"; // CET = +1hr = +0100
SimpleDateFormat parseFormat =
new SimpleDateFormat("EEE, dd MMM yyyy hh:mm aa Z"); // Capital Z
Date date = parseFormat.parse(time);
SimpleDateFormat displayFormat =
new SimpleDateFormat("dd.MM.yyyy, HH:mm");
System.out.println("output is " + displayFormat.format(date));
output is 02.11.2012, 22:58
Note: Also, I think you meant hh instead of HH, since you have PM.
Result is shown here. (This uses Java7's SimpleDateFormat, but Android should support RFC 822 timezones (+0100) as well.)
NB: Also, as it appears Android's z accepts full names ("Pacific Standard Time" is the example they give), you could simply specify "Centural European Time" instead of "CET".

Try out the following code:
SimpleDateFormat date_format = new SimpleDateFormat("yyyyMMMdd");
System.out.println(date_format.format(cal.getTime()));
It will work.. If not print the log cat? What erroe is coming?

First of All I must agree with #Eric answer.
You just need to remove "CET" from your string of date.
Here is sample code. Check it.
String time = "Fri, 02 Nov 2012 11:58 pm CET";
time = time.replaceAll("CET", "").trim();
SimpleDateFormat displayFormat =
new SimpleDateFormat("dd.MM.yyyy, HH:mm");
SimpleDateFormat parseFormat =
new SimpleDateFormat("EEE, dd MMM yyyy HH:mm aa");
Date date = null;
try {
date = parseFormat.parse(time);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("output is " + displayFormat.format(date));

I am trying to SimpleDateFormat date in java

I am trying to format a date by parsing it and then formating it but it is not working.
It is showing a parsing exception
public java.util.Date convertFormat(String DateTimeForm)
throws ParseException {
DateTimeForm="2012-06-01 10:00 PM";
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd hh:mm aaa");
java.util.Date FCDate = (java.util.Date) formatter.parse(DateTimeForm);
return (java.util.Date) FCDate;
}

SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd hh:mm aaa");
try {
Date date = formatter.parse("2012-06-01 10:00 PM");
System.out.println(date.toString());
} catch (ParseException e) {
e.printStackTrace();
}
Didn't change anything and yet it works.
Fri Jun 01 22:00:00 CDT 2012

This works fine on my machine. I didn't change anything important.
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd hh:mm aaa");
Date date = null;
try {
date = formatter.parse("2012-06-01 10:00 PM");
} catch (ParseException ex) {
// Intentionally empty. Failed parse causes date == null.
}
System.out.print(date);
prints
Fri Jun 01 22:00:00 EDT 2012
The Java docs say the numerics are all locale-independent, but not the AM/PM. For example the code fails if you specify Locale.JAPAN in the formatter construction. Specify Local.US to guarantee AM/PM will always work.

How to apply applyPattern for SimpleDateFormat in java?

I am trying to add a new pattern to the date display but I am not getting the result that I am expecting:
Here is my code:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.S");
sdf.applyPattern("yyyy-MM-dd");
Date date_out = null;
try {
date_out = sdf.parse(date);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
((TextView) view.findViewById(R.id.date)).setText(date_out.toString());
I want the output to look something like this: 03 Oct 2011
However this is the output tat I am getting: Oct 03 00:00:00 GMT+ 11:00 2011
How do I reach the desired output?
EDIT:
I solved this code by adding this line:
sdf.format(date_out);
instead of setText()

Date.toString(); does always format your String that way. You should a SimpleDateFormat to format the Date object to the String you want.
The JavaDoc of the Date.toString(); method says:
Converts this Date object to a String of the form:
dow mon dd hh:mm:ss zzz yyyy

You have to use two SimpleDateFormat objects. One for parsing the input and an other one for formatting the parsed Date object to String.
final String inputDate = "2011-05-08T11:12:13.0123";
final SimpleDateFormat inputParser = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.S");
Date date_out = null;
try {
date_out = inputParser.parse(inputDate);
} catch (final ParseException e) {
e.printStackTrace();
}
final SimpleDateFormat outputFormatter =
new SimpleDateFormat("dd MMM yyyy", Locale.US);
final String result = outputFormatter.format(date_out);
System.out.println(result);
Output:
08 May 2011

The Date.toString() method formats the string like that (check the api documentation).
You do not actually need to use applyFormat(...) in this case. You want to parse one format and output it in another format.
To parse the date (given the string: 2011-10-03") use can use the format"yyyy-MM-dd"and when you output theDateyou want to use"dd MMM yyyy"`:
public static void main(String[] args) throws ParseException {
SimpleDateFormat inputFormat = new SimpleDateFormat("yyyy-MM-dd");
SimpleDateFormat outputFormat = new SimpleDateFormat("yyyy MMM dd");
Date parsedDate = inputFormat.parse("2011-10-05");
System.out.println(outputFormat.format(parsedDate));
}
Outputs (on US locale):
2011 Oct 05

Read below document :-
http://docs.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html
hope help u above link.

How to convert date format

Can any one help in conversion of date format?
My returned date object is contains "Mon Jul 12 00:00:00 IST 2010"
I'm trying to convert this date format to "MM/dd/yyyy" but I'm getting parse exception. Please help me how to convert it
Code from the OP's comment:
String mydatObj = myDate.toString();
Date formatedDate = getDateFormat(mydatObj);
public static Date getDateFormat(String dateString) {
Date date = null;
SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy");
try {
// set isLenient to false to adhere to the date format.
format.setLenient(false);
date = format.parse(dateString);
} catch (ParseException parseException) {
// ignore
LOG.error(parseException.getMessage(), parseException);
}
return date;
}

Well, you are getting a ParseException since you are trying to parse a date with the wrong format.
Here is a small code snippet which will work with the format you have:
// parse the date
DateFormat f = new SimpleDateFormat("E MMM dd HH:mm:ss zzz yyyy");
Date d = f.parse("Mon Jul 12 00:00:00 IST 2010"); // works
// now print the date
DateFormat out = new SimpleDateFormat("MM/dd/yyyy");
System.out.println(out.format(d));