How can we rotate a Image Clockwise using LibGDX? what i am looking is when a image is loaded,suppose a star, i need to rotate it from beginning of screen to end of the screen horizontally, with star rotating,how can i do that in libgdx?
When you draw the Texture with your SpriteBatch, you can use one of the draw functions that includes rotation. This javadoc has all the draw functions: SpriteBatch
You can keep a variable for position and rotation, and increase the rotation and x component of the position each time you render to make it rotate while moving horizontally.
Libgdx gives you more then one way to do that:
You can use Scene2D and add an Image to your Stage. Image is a subclass of Actor, so you can add Actions to it:
Image myImage = new Image(myTexture);
myImage.addAction(Actions.parallel(Actions.moveTo(endX, endY, duration), Actions.rotateBy(degrees, duration)));
myImage.setPosition(startX, startY);
myImage.setOrigin(sizeX/2, sizeY/2);
stage.add(myImage);
In render you can then call stage.act(), which updates the position, rotation, scale... of all your Actors and then call stage.draw() which will call draw() for all your Actors.
Image allready handles the draw() so you don't need to care about that anymore.
You can also do it without scene2d, by updating everything yourself:
You can store a int rotationSpeed in degrees/sec
You can store a int moveSpeed in units/sec (maybe pixel but i would suggest to use camera or viewport and use your own unit, which is equal on all devices)
Store the float angle, which is the current rotation of your Texture
and store a Vector2 position, which contains the x and y position of your Texture.
If you want to move in x and y direction you can also store a Vector2 direction, which is a normalized Vector, giving the percent of movement in x and y direction, but thats a different story.
Then in your render(float delta) you update everything:
angle+=delta*rotationSpeed;
angl%=360; // Limits the angle to be <= 360
while (angle < 0) // Unfortunally the "modulo" in java gives negative result for negativ values.
angle+=360;
position.x+=direction.x*moveSpeed*delta;
position.y+=direction.y*movSpeed*delta;
spriteBatch.draw(yourTextureRegion, position.x, position.y, sizeX/2, sizeY/2, sizeX, sizeY, scaleX, scaleY, angle);
For clockwise rotation simply use a negative rotationSpeed or replace the angle+= with angle-=.
Hope it helps.
Following is the implementation to rotate any sprite
batch.draw(sprite,(Gdx.graphics.getWidth() - sprite.getRegionWidth()) / 2.0f,(Gdx.graphics.getHeight() - sprite.getRegionHeight()) / 2.0f,sprite.getRegionWidth()/2.0f,sprite.getRegionHeight()/2.0f, sprite.getRegionWidth(), sprite.getRegionHeight(), 1f, 1f,count, false);
if(count < 0.0f)
count = 360.0f;
else
count --;
Initially set counter to
private float count =360.0f;
You can also use the Scene2D actions. I have an example here with asteroid-type thing falling down the screen and rotating.
http://www.netthreads.co.uk/2012/02/09/libgdx-scene2d-demo-with-scene-transitions/
To rotate anticlockwise and horizontally..
create a textureRegion
then
Sprite sprite = new Sprite(textureRegion, 0, 0, 128, 128);
sprite.setPosition(++mX, 0);
angle++;
sprite.setRotation(angle);
sprite.draw(batcher);
You can do it too like this:
on your create method
sprite.setOrigin(sprite.getWitdh() /2f, sprite.getHeight() /2f);
sprite.setPosition( 0, 200 ); //200 it's a example
on your render(float delta)
sprite.setX( sprite.getX() + delta ).setRotation( sprite.getRotation() + delta );
Here is a simple to rotate an actor in libgdx. First you need to set the origin:
img.setOrigin(getWidth/2,getHeight/2);
And then you can rotate clockwise and anticlockwise according to your need:
img.rotate(2f); or img.rotate(-2f);
So the following sample worked for me (infinite rotation)
Method 1: (recommended)
loadingActor.addAction(Actions.repeat(RepeatAction.FOREVER, Actions.rotateBy(360, 1)));
Method 2:
Image loadingActor = new Image(AssetsController.getInstance().getLoading());
loadingActor.setOrigin(Align.center);
final SequenceAction infiniteRotate = Actions.sequence();
infiniteRotate.addAction(Actions.rotateTo(0 , 0f) );
infiniteRotate.addAction(Actions.rotateTo(360 , 1f) );
loadingActor.addAction(Actions.forever(infiniteRotate));
Related
When trying to program a game using Box2D, I ran into a problem with Box2D. I filled in pixel numbers for the lengths of the the textures and sprites to create a box around it. Everything was at the right place, but for some reason everything went very slowly. By looking on the internet I found out that if you didn't convert pixels to meters box2d might handle shapes as very large objects. this seemed to be a logical cause of everything moving slowly.
I found similar questions on this site, but the answers didn't really seem to help out. in most of the cases the solution was to make methods to convert the pixel numbers to meters using a scaling factor. I tried this out, but everything got misplaced and had wrong sizes. this seemed logical to me since the numbers where changed but had the same meaning.
I was wondering if there is a way to make the pixels mean less meters, so everything whould be at the same place with the same (pixel) size, but mean less meters.
If you have a different way which you think might help, I whould also like to hear it..
Here is the code i use to create the camera
width = Gdx.graphics.getWidth() / 5;
height = Gdx.graphics.getHeight() / 5;
camera = new OrthographicCamera(width, height);
camera.setToOrtho(false, 1628, 440);
camera.update();
This is the method I use to create an object:
public void Create(float X, float Y, float Width, float Height, float density, float friction, float restitution, World world){
//Method to create an item
width = Width;
height = Height;
polygonDef = new BodyDef();
polygonDef.type = BodyType.DynamicBody;
polygonDef.position.set(X + (Width / 2f), Y + (Height / 2f));
polygonBody = world.createBody(polygonDef);
polygonShape = new PolygonShape();
polygonShape.setAsBox(Width / 2f, Height / 2f);
polygonFixture = new FixtureDef();
polygonFixture.shape = polygonShape;
polygonFixture.density = density;
polygonFixture.friction = friction;
polygonFixture.restitution = restitution;
polygonBody.createFixture(polygonFixture);
}
To create an item, in this case a table, I use the following:
Table = new Item();
Table.Create(372f, 60f, 152f, 96f, 1.0f, 0.2f, 0.2f, world);
The Sprites are drawn on the item by using the following method:
public void drawSprite(Sprite sprite){
polygonBody.setUserData(sprite);
Utils.batch.begin();
if(polygonBody.getUserData() instanceof Sprite){
Sprite Sprite = (Sprite) polygonBody.getUserData();
Sprite.setPosition(polygonBody.getPosition().x - Sprite.getWidth() / 2, polygonBody.getPosition().y - Sprite.getHeight() / 2);
Sprite.setRotation(polygonBody.getAngle() * MathUtils.radiansToDegrees);
Sprite.draw(Utils.batch);
}
Utils.batch.end();
}
The sprites also have pixel sizes.
Using this methods it displays the images at the right places, but everything moves slowly.
I was wondering how or if I whould have to change this to make the objects move correctly, and / or mean less. Thanks in advance.
Box2D is an entirely independent of the graphics library that you use. It doesn't have any notion of sprites and textures. What you read online is correct, you'll have to convert pixels to metres, as Box2D works with metres(the standard unit for distance).
For example, if you drew a sprite of size 100x100 pixels, that's the size of the sprite that you want the user to see on the screen. In real world the size of the object should be in metres and not in pixels - so if you say 1px = 1m, then that'll map the sprite to a gigantic 100x100 meter object. In Box2D, large world objects will slow down calculations. So what you need to do is map the 100 pixels to a smaller number of meters, say, 1 meter - thus 100x100px sprite will be represented in Box2D world by a 1x1 meter object.
Box2D doesn't work well with very small numbers and very large numbers. So keep it in between, say between 0.5 and 100, to have good performance.
EDIT:
Ok. Now I get your question.
Don't code to pixels. Its as simple as that. I know it'll take some time to understand this(it took for me). But once you get the hang of it, its straight forward.
Instead of pixels, use a unit, say, you call it meter.
So we decide our viewport should be say 6mx5m.
So initialization is
Constants.VIEWPORT_WIDTH = 6;
Constants.VIEWPORT_HEIGHT = 5;
...
void init() {
camera = new OrthographicCamera(Constants.VIEWPORT_WIDTH, Constants.VIEWPORT_HEIGHT);
camera.position.set(Constants.VIEWPORT_WIDTH/2, Constants.VIEWPORT_HEIGHT/2, 0);
camera.update();
}
Once you know the actual width and height, you call the following function in order to maintain aspect ratio:
public void resize(int width, int height) {
camera.viewportHeight = (Constants.VIEWPORT_WIDTH / width) * height;
camera.update();
}
resize() can be called anytime you change your screen size(eg: when you screen orientation changes). resize() takes the actual width and height (320x480 etc), which is the pixel value.
Now you specify you sprite sizes, their positions etc. in this new world of size 6x5. You can forget pixels. The minimum size of the sprite that'll fill the screen will be 6x5.
You can now use the same unit with Box2D. Since the new dimensions will be smaller, it won't be a problem for Box2D. If I remember correctly Box2D doesn't have any unit. We just call it meter for convenience sake.
Now you might ask where you specify the dimensions of the window. It depends on the platform. Following code shows a 320x480 windowed desktop game:
public class Main {
public static void main(String[] args) {
LwjglApplicationConfiguration cfg = new LwjglApplicationConfiguration();
cfg.title = "my-game";
cfg.useGL20 = false;
cfg.width = 480;
cfg.height = 320;
new LwjglApplication(new MyGame(), cfg);
}
}
Our camera will intelligently map the 6x5 viewport to 480x320.
I am trying to turn my screen x and y coordinates to the ones that's used to draw on screen.
So I get my screen X and Y coordinates from MotionEvent thats fired by my touch listener.
I thought it should be as easy as multiplying those by the matrix that's used to draw on canvas so I creatad Matrix instance at creation of view
matrix = new Matrix();
when void onDraw(Canvas canvas) gets called, I set the canvas' matrix to be the matrix I created on the constructor and apply all my transformations to the matrix
matrix.reset();
canvas.setMatrix(matrix);
canvas.translate(getWidth() / 2, getHeight() / 2);
canvas.scale(mScaleFactor, mScaleFactor);
canvas.translate(-getWidth() / 2, -getHeight() / 2);
canvas.translate(-x, -y);
The view looks as it should but when on my touch listener I try to turn my screen coordinates to view coordinates with that matrix using mapPoints(float[] points) the values it gives aren't right, I draw cross on 0, 0 in onDraw
canvas.drawLine(0f, -100f, 0f, 100f, viewportPaint);
canvas.drawLine(-100f, 0f, 100, 0f, viewportPaint);
and when I click where it appears to be after scaling and what not the values I receive aren't even close to 0, 0
float[] array = new float[]{e.getX(), e.getY()};
matrix.mapPoints(array);
Log.v(TAG, "points transformed are " + array[0] + ", " + array[1]);
When I took this picture where I am clearly clicking the 0, 0 mark I received the following logging:
03-09 14:08:48.803: V/XXXX(22181): points transformed are 403.43967, 628.47
Ps. I am not touching matrix anywhere else than in my onDraw code
I had the question in my mind inverted, when I thought about the question again after having a break from it(after 8 hours..) I got it, I had to invert the matrix in order to perform this operation.
Also the matrix wasn't transformed when I was transforming canvas so i had to canvas.get(matrix)
in order to get the same matrix that the canvas was using..
This might help others:
In onDraw()
canvasMatrix.postScale(mScaleFactor, mScaleFactor);
canvasMatrix.postTranslate(-getWidth() / 2, -getHeight() / 2);
canvas.setMatrix(canvasMatrix);
Somewhere else where you need the mapped coordinates:
Matrix m = new Matrix();
canvasMatrix.invert(m);
float[] touch = new float[] { X, Y };
m.mapPoints(touch);
X = touch[0];
Y = touch[1];
there you go.
Few days ago I figured out how to do some scrolling in LibGdx. Now I'm triying to do something related. I want to repeat the background. My scrolling follows a ship (Is an s[ace ship game). In the background there is a space photo loaded as a Texture. When the ship reach the end of the backgorund, It keeps going and there's no background anymore. I have read about wrap but I don't really understand How It works. I did that:
px=new Pixmap(Gdx.files.internal("fondo.jpg"));
background=new Texture(px);
background.setWrap(TextureWrap.Repeat, TextureWrap.Repeat);
And then, in my render method
spriteBatch.begin();
spriteBatch.draw(background,0,0,500,50);
drawShip();
spriteBatch.end();
Of course It doesn't work, It only draws the background once. I don't know how make this wrap method work. Any help?
SOLUTION
I figured It out. It's not a nice code but It works.
First I declare two Textures with the same image
bck1=new Texture(Gdx.files.internal("fondo.jpg"));
bck2=new Texture(Gdx.files.internal("fondo.jpg"));
Also I declare two variables like this to specify the X value of the position of each bck
int posXBck1=0,posXBck2=0;
Then I use that in Render()
public void calculoPosicionFondos(){
posXBck2=posXBck1+ANCHODEFONDO;
if(cam.position.x>=posXBck2+cam.viewportWidth/2){
posXBck1=posXBck2;
}
}
Where:
ANCHODEFONDO is the width of my background
Cam is an OtrhoCam.
So I said that if the cam is in bck2 (wich means that you can't see bck1 anymore) It change positions, giving bck1 de position of bck2 and, in the next render loop, recalculating bck2
Then just paint both bck in your render mode.
Like Teitus said, do not load your texture multiple times, ever! Anyway, you where on the right track with the wrapper:
texture.setWrap(TextureWrap.Repeat, TextureWrap.Repeat);
Now you can just use the draw method with the source location. The source location is the area you choose to draw on the texture.
batch.draw(texture, x, y, srcX, srcY, srcWidth, srcHeight)
To scroll your texture from right to left all you have to do is increase srcX incrementally. So create a int that increments in the update/render method.
int sourceX = 0;
//render() method
//Increment the variable where to draw from on the image.
sourceX += 10;
//Simply draw it using that variable in the srcX.
batch.draw(YourTexture, 0, 0, sourceX, 0, screenWidth, screenHeight);
Because you are wrapping the texture it will wrap/loop and scroll indefinitely. There might be a issue with the sourceX int if the game runs for a very long time because a int can only hold 2147483647. It takes a while but you can fix it by subtracting the image width each time the number goes over the total image width.
Don't to this, please:
bck1=new Texture(Gdx.files.internal("fondo.jpg"));
bck2=new Texture(Gdx.files.internal("fondo.jpg"));
That will load your big background texture twice. That's a complete waste. If you want to keep your solution at least do:
bck1=new Texture(Gdx.files.internal("fondo.jpg"));
bck2=bkg1;
Regarding the texture Wrapping. If your texture is 500px wide, and you draw a 500px sprite, you won't see any repetition. If you want it repeated 2 times, draw it 1000px wide with 0-2 texture coordinates.
I'm not sure how spriteBatch handles the call you posted, you could try that one, or may be use the overload that uses a texture region and set your region manually.
I see this is a pretty old question, but I think there is an easier way to accomplish background scrolling. Just use the Sprite class. Here is a snippet I use for layered background images that scroll from right to left.
public class LevelLayer
{
public float speedScalar = 1;
private List<Sprite> backgroundSprites = new ArrayList<Sprite>();
public LevelLayer()
{
}
public void addSpriteLayer(Texture texture, float startingPointX, float y, int repeats)
{
for (int k = 0; k < repeats; k++)
{
Sprite s = new Sprite(texture);
s.setX(startingPointX + (k*texture.getWidth()));
s.setY(y);
backgroundSprites.add(s);
}
}
public void render(SpriteBatch spriteBatch, float speed)
{
for (Sprite s : backgroundSprites)
{
float delta = s.getX() - (speed * speedScalar);
s.setX(delta);
s.draw(spriteBatch);
}
}
}
Then you can use the same texture or series of textures like so:
someLayer.addSpriteLayer(sideWalkTexture1, 0, 0, 15);
someLayer.addSpriteLayer(sideWalkTexture2, 15 * sideWalkTexture1.getWidth(), 0, 7);
I change background repeating sections randomly in code and make new ones or reset existing sets when they go off screen. All the layers go to a pool and get pulled randomly when a new one is needed.
SOLUTION
I figured It out. It's not a nice code but It works.
First I declare two Textures with the same image
bck1=new Texture(Gdx.files.internal("fondo.jpg"));
bck2=new Texture(Gdx.files.internal("fondo.jpg"));
Also I declare two variables like this to specify the X value of the position of each bck
int posXBck1=0,posXBck2=0;
Then I use that in Render()
public void calculoPosicionFondos(){
posXBck2=posXBck1+ANCHODEFONDO;
if(cam.position.x>=posXBck2+cam.viewportWidth/2){
posXBck1=posXBck2;
}
}
Where:
ANCHODEFONDO is the width of my background
Cam is an OtrhoCam.
So I said that if the cam is in bck2 (wich means that you can't see bck1 anymore) It change positions, giving bck1 de position of bck2 and, in the next render loop, recalculating bck2
Then just draw both bck in your render()
I'm having problem trying to point my "arrow_sprite" to the touch position.
The result I want is that the arrow(the sprite that I want to rotate)will point to the touch position.
How can I acheive this?
You need to calculate the vector between the touch position and the sprite position. To do so you have to unproject the touch position received through your InputProcessor.
public class MyInputProcessor implements InputProcessor {
...
#Override
public boolean touchDown (int x, int y, int pointer, int button) {
Vector3 touchDown = new Vector3(x, y, 0);
camera.unproject(touchDown);
Vector3 spritePosition = new Vector3(yourSpriteX, yourSpriteY, 0);
spritePosition.sub(touchDown);
return false;
}
...
}
Now we have a vector pointing from your sprite to the touch position. From there you just need to calculate the rotation angle. One way would be to use Vector2.angle(), as such creating a Vector2 from the spritePosition Vector3.
If you want to draw in 2D, then you have to set your SpriteBatch to Camera.combined,
something like this : yourBatch.setProjectionMatrix(yourCamera.combined);
Then you must unproject the camera like "batch" said.
After, you must choose if you want to use a vector or 2d coordinate. Basically identycal ending for angle calculation :
First define a float degrees then make it like so in the touchDown method :
degrees = (float) ((Math.atan2 (touchPoint.x - arrowPosition.x, -(touchPoint.y - arrowPosition.y))*180.0d/Math.PI)+90.0f);
assuming you use a Vector3 or 2 for both input and arrow.
then when rendering the Arrow sprite :
Batch.draw(Arrow, x, y, originX, originY, width, height, scaleX, scaleY, degrees);
Hope this will be helpfull.
Just like Psilopat said, we define the degree by :
degrees = (float) ((Math.atan2 (touchPoint.x - arrowPosition.x, -(touchPoint.y - arrowPosition.y))*180.0d/Math.PI)+90.0f);
but if the rotation seems wrong, change the "+90.0f" at the end of line to something else. My arrow is pointing up, so I change it to "-180.0f"
If I have a canvas, on which I draw a Bitmap like this:
canvas.drawBitmap(bmLargeImage, srcRect, destRect, paint);
and I scale the bitmap:
canvas.scale(1.5f, 1.5f, 450, 250);
I want to get the position of the Bitmap after the scale. If the position before scale was (0, 0), after scale there is a offset and I need that offset.. how can I get it?
Thanks and sorry for the simple question, newbie here...
Ok lets try to work out the best formula for this
canvas.scale(scaleX, scaleY, pivotX, pivotY);
if (scaleX >= 1){
objectNewX = objectOldX + (objectOldX - pivotX)*(scaleX - 1);
}else{
objectNewX = objectOldX - (objectOldX - pivotX)*(1 - scaleX);
}
The same for objectNewY. The new width and height of the bitmap would of course be the multiple of the old size and scale.
I believe the cleanest Solution would be to use the underlying transformation Matrix of the Canvas you are manipulating.
In Android there is the canvas.getMatrix(Matrix cmt) method available which will yield it. The transformation matrix will transform any point in world space you throw at into screen coordinates. Just use the matrix.mapPoints(float[] points) and you will be fine.
FYI, you can easily do it the other way around too. If you want to know what screen coordinate maps to which point in world space, e.g. for tapping; the inverse matrix can be used for that. It can be obtained via the matrix.invert(Matrix out) method. Use its mapPoints() for the coordinate mapping then.
Here are the official docs:
mapPoints(), invert(), getMatrix()
If you'd like know the corners of your screen relative to your original canvas, you can use canvas.getClipBounds(). This returns a Rect with edge coordinates relative to your original canvas. For instance, if you start off with a canvas size of 320 x 480 and call
canvas.scale(2, 2, getWidth()/2, getHeight()/2);
and then
canvas.getClipBounds();
you will have a Rect (call this rect) where
rect.top == 120
rect.bottom == 360
rect.left == 80
rect.right == 240