I have a date coming in. So for example 02/16/2012. What I need to do in order to work with my database format is convert it to 2012-02-16. I figured this would be pretty straightforward. But I can't work it. Here is my date parser.
String endDateString = "02/16/2012"
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-mm-dd");
endDate = dateFormat.parse(endDateString)
Any suggestions? Thanks.
What you want to do is parse the incoming format to a Date object
final SimpleDateFormat idf = new SimpleDateFormat("MM/dd/yyyy");
final Date indate = idf.parse("02/16/2012");
then reformat the Date object to the format you desire
final SimpleDateFormat odf = new SimpleDateFormat("yyyy-MM-dd");
final String s = odf.format(indate);
You should parse it FROM one correct format, then convert TO string with another correct format. What are you doing -- is trying to interpret date in MM/dd/yyyy format with yyyy-MM-dd format, i.e. incorrect.
SAMPLE
public static void main(String[] args) throws ParseException {
SimpleDateFormat sourceFormat = new SimpleDateFormat("MM/dd/yyyy");
SimpleDateFormat destinationFormat = new SimpleDateFormat("yyyy-MM-dd");
String sourceDateString = "02/16/2012";
String destinationDateString;
Date dat; // this object stores "perfect" date object
// interpreting string with input format and converting it to date
dat = sourceFormat.parse(sourceDateString);
// expressing date object as string in destination format
destinationDateString = destinationFormat.format(dat);
System.out.format("Done from %s to %s\n", sourceDateString, destinationDateString));
}
The date-format you specify has to match the date-format of your input like so:
SimpleDateFormat dateFormat = new SimpleDateFormat("MM/dd/yyyy");
This snippet can tell you how to get it done.
SimpleDateFormat inputDateFormat = new SimpleDateFormat("MM/dd/yyyy");
SimpleDateFormat outputDateFormat = new SimpleDateFormat("yyyy-MM-dd");
String endDateString = "02/16/2012";
String endDate = outputDateFormat.format(inputDateFormat.parse(endDateString));
Reference: SimpleDateFormat
You can also convert a date at the database level. For example MySQL has a function STR_TO_DATE. In your case it would be STR_TO_DATE('02/16/2012','%m/%d/%Y')
You are parsing with wrong format
new SimpleDateFormat("MM/dd/yyyy");
Related
I want to change date format which I received reading from excel cell file is "30-mar-2016" to 03/30/2016. I have tried below
String inputDate = "30-mar-2016";
DateFormat df = new SimpleDateFormat("mm/dd/yyyy");
Date startDate;
startDate = df.parse(inputDate);
It gave me- java.text.ParseException: Unparseable date: "30-mar-2016"
.
I also tried below code
String inputDate = "30-mar-2016";
DateFormat df = new SimpleDateFormat("mm/dd/yyyy");
String startDate;
startDate = df.format(inputDate);
getting -- java.lang.IllegalArgumentException: Cannot format given Object as a Date
Can anyone help me .
Your input string 30-mar-2016 is in the format dd-MMM-yyyy. Your output format is MM/dd/yyyy. So you need two DateForamts. One for parsing original input string, one for formatting output string.
DateFormat df1 = new SimpleDateFormat("dd-MMM-yyyy"); // for parsing input
DateFormat df2 = new SimpleDateFormat("MM/dd/yyyy"); // for formatting output
String inputDate = "30-mar-2016";
Date d = df1.parse(inputDate);
String outputDate = df2.format(d); // => "03/30/2016"
I have resolved using below
SimpleDateFormat sdf = new SimpleDateFormat("dd-MMM-yyyy");
Date date = sdf.parse("30-mar-2016");
sdf.applyPattern("MM/dd/yyyy");
System.out.println(sdf.format(date));//got 03/30/2016
Thanks everyone for your quick response
i building a kml file and there is a line of timestamp:
<gx:TimeStamp>
<when>2002-07-09T19:00:00-08:00</when>
</gx:TimeStamp>
i need convert time like: "1430477311" to "2002-07-09T19:00:00-08:00" format
how ?
(java code)
tnx a lot
You are wanting to convert from your timeformat to XML Date Format (ISO-8601) -
long timeStamp = 1430477311L;
java.util.Date yourDate = new java.util.Date(timeStamp*1000); //ms
SimpleDateFormat yyyyMMddTHHmmssSDF = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssX");
String date = yyyyMMddTHHmmssSDF.format(yourDate);
Simple Date Format reference.
Simply pass the timestamp to a Date type:
Timestamp stamp = new Timestamp(inputTimestamp);
Date date = new Date(stamp.getTime());
//change the to the format that you need
DateFormat df = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");
String timeStr = df.format(date);
I'm trying to parse the following string to a Date object:
String str = "04/15/2014 10:30:24"
I'm using SimpleDateFormat :
SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");
java.util.Date orderDate = sdf.parse(str);
java.sql.Date orderSqlDate = new java.sql.Date(orderDate.getTime());
but orderSqlDate always returned: 04/15/2014 00:00:00
how to use SimpleDateFormat in java exactly?
The java.sql.Date javadoc states
To conform with the definition of SQL DATE, the millisecond values
wrapped by a java.sql.Date instance must be 'normalized' by setting
the hours, minutes, seconds, and milliseconds to zero in the
particular time zone with which the instance is associated.
If you're going to use java.sql.Date, there's no way around this.
You are also doing correct.
But to get the result in the format you want, you need to use .format("/your format/") method after parsing the string.
String date = "15/12/2014 10:42:24";
SimpleDateFormat dateParser = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");
SimpleDateFormat formatter = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss");
Date parseDate = dateParser.parse(date);
formatter.format(parseDate) // this will change format of date as you want.
I don't think the way you parse is wrong. Are you sure you print orderDate right ?
The following code demonstrates both parsing and formatting (printing).
public static void main(String[] args) {
String format = "MM/dd/yyyy HH:mm:ss";
try {
SimpleDateFormat sdf = new SimpleDateFormat(format);
Date orderDate = new SimpleDateFormat(format).parse("04/15/2014 10:30:24");
System.out.println(sdf.format(orderDate));
} catch (Exception e) {
e.printStackTrace();
}
}
Provide Locale in the SimpleDateFormat constructor, otherwise parsing might be dependant on your local settings:
SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss", Locale.ROOT);
I'm trying to use this code:
private static Date getTimeStamp() {
return new Timestamp(new Date().getTime());
}
What I'm getting is 2013-03-13 12:46:22.011
But what I need is that the timestamp should be in the format of mm-dd-yyyy hh:mm.
java.sql.Timestamp objects (just like java.util.Date and java.sql.Date) do not have a format by themselves, so you cannot "have a Timestamp in the format [whatever]".
A format only is applicable when you convert the object to a string for display. You can use SimpleDateFormat to convert a Timestamp to a string, using the format you want.
Timestamp timestamp = new Timestamp(System.currentTimeMillis());
DateFormat dateFormat = new SimpleDateFormat("MM-dd-yyyy HH:mm");
String text = dateFormat.format(timestamp);
System.out.println(text);
Hope this helps
String date1="2013-03-13 12:46:22.011";
DateFormat userDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:SS");
DateFormat dateFormatNeeded = new SimpleDateFormat("MM/dd/yyyy HH:mm");
Date date = userDateFormat.parse(date1);
String finaldate = dateFormatNeeded.format(date);
You can use SimpleDateFormat http://docs.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html to achieve your goal.
For Example:
new SimpleDateFormat("MM-dd-yyyy HH:mm").format(timestamp));
I was trying to format a string into date.
For this I have written a code:-
Calendar cal = Calendar.getInstance();
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
System.out.println(sdf.format( cal.getTime() ));
This is fine..
But now I want to convert a string into a date formatted like above..
For example
String dt="2010-10-22";
And the output should be like this:-
2010-10-22T00:00:00
How do I do this?
String dt = "2010-10-22";
SimpleDateFormat sdfIn = new SimpleDateFormat("yyyy-MM-dd");
ParsePosition ps = new ParsePosition(0)
Date date = sdfIn.parse(dt, pos)
SimpleDateFormat sdfOut = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
System.out.println(sdfOut.format( date ));
This should do it for you, remember to wrap it in a try-catch block just in case.
DateFormat dt = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
try
{
Date today = dt.parse("2010-10-22T00:00:00");
System.out.println("Your Date = " + dt.format(today));
} catch (ParseException e)
{
//This parse operation may not be successful, in which case you should handle the ParseException that gets thrown.
//Black Magic Goes Here
}
If your input is going to be ISO, you could also look at using the Joda Time API, like so:
LocalDateTime localDateTime = new LocalDateTime("2010-10-22");
System.out.println("Formatted time: " + localDateTime.toString());
The same class you use for output formatting of dates can also be used to parse dates on input.
SimpleDateFormat reference
To use your example, to parse the sample date:
String dt = "2010-10-22";
SimpleDateFormat dateFormatter = new SimpleDateFormat("yyyy-MM-dd");
System.out.println(dateFormatter.parse(dt));
The fields that are not specified (ie. hour, minutes, etc) will be 0. So your same code can be used to format the date on output.
Date Format Example
Containing the Conversion of String Date object from one format to another