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How to read all the files in a folder through Java? It doesn't matter which API.
public void listFilesForFolder(final File folder) {
for (final File fileEntry : folder.listFiles()) {
if (fileEntry.isDirectory()) {
listFilesForFolder(fileEntry);
} else {
System.out.println(fileEntry.getName());
}
}
}
final File folder = new File("/home/you/Desktop");
listFilesForFolder(folder);
Files.walk API is available from Java 8.
try (Stream<Path> paths = Files.walk(Paths.get("/home/you/Desktop"))) {
paths
.filter(Files::isRegularFile)
.forEach(System.out::println);
}
The example uses try-with-resources pattern recommended in API guide. It ensures that no matter circumstances the stream will be closed.
File folder = new File("/Users/you/folder/");
File[] listOfFiles = folder.listFiles();
for (File file : listOfFiles) {
if (file.isFile()) {
System.out.println(file.getName());
}
}
In Java 8 you can do this
Files.walk(Paths.get("/path/to/folder"))
.filter(Files::isRegularFile)
.forEach(System.out::println);
which will print all files in a folder while excluding all directories. If you need a list, the following will do:
Files.walk(Paths.get("/path/to/folder"))
.filter(Files::isRegularFile)
.collect(Collectors.toList())
If you want to return List<File> instead of List<Path> just map it:
List<File> filesInFolder = Files.walk(Paths.get("/path/to/folder"))
.filter(Files::isRegularFile)
.map(Path::toFile)
.collect(Collectors.toList());
You also need to make sure to close the stream! Otherwise you might run into an exception telling you that too many files are open. Read here for more information.
All of the answers on this topic that make use of the new Java 8 functions are neglecting to close the stream. The example in the accepted answer should be:
try (Stream<Path> filePathStream=Files.walk(Paths.get("/home/you/Desktop"))) {
filePathStream.forEach(filePath -> {
if (Files.isRegularFile(filePath)) {
System.out.println(filePath);
}
});
}
From the javadoc of the Files.walk method:
The returned stream encapsulates one or more DirectoryStreams. If
timely disposal of file system resources is required, the
try-with-resources construct should be used to ensure that the
stream's close method is invoked after the stream operations are completed.
One remark according to get all files in the directory.
The method Files.walk(path) will return all files by walking the file tree rooted at the given started file.
For instance, there is the next file tree:
\---folder
| file1.txt
| file2.txt
|
\---subfolder
file3.txt
file4.txt
Using the java.nio.file.Files.walk(Path):
Files.walk(Paths.get("folder"))
.filter(Files::isRegularFile)
.forEach(System.out::println);
Gives the following result:
folder\file1.txt
folder\file2.txt
folder\subfolder\file3.txt
folder\subfolder\file4.txt
To get all files only in the current directory use the java.nio.file.Files.list(Path):
Files.list(Paths.get("folder"))
.filter(Files::isRegularFile)
.forEach(System.out::println);
Result:
folder\file1.txt
folder\file2.txt
import java.io.File;
public class ReadFilesFromFolder {
public static File folder = new File("C:/Documents and Settings/My Documents/Downloads");
static String temp = "";
public static void main(String[] args) {
// TODO Auto-generated method stub
System.out.println("Reading files under the folder "+ folder.getAbsolutePath());
listFilesForFolder(folder);
}
public static void listFilesForFolder(final File folder) {
for (final File fileEntry : folder.listFiles()) {
if (fileEntry.isDirectory()) {
// System.out.println("Reading files under the folder "+folder.getAbsolutePath());
listFilesForFolder(fileEntry);
} else {
if (fileEntry.isFile()) {
temp = fileEntry.getName();
if ((temp.substring(temp.lastIndexOf('.') + 1, temp.length()).toLowerCase()).equals("txt"))
System.out.println("File= " + folder.getAbsolutePath()+ "\\" + fileEntry.getName());
}
}
}
}
}
In Java 7 and higher you can use listdir
Path dir = ...;
try (DirectoryStream<Path> stream = Files.newDirectoryStream(dir)) {
for (Path file: stream) {
System.out.println(file.getFileName());
}
} catch (IOException | DirectoryIteratorException x) {
// IOException can never be thrown by the iteration.
// In this snippet, it can only be thrown by newDirectoryStream.
System.err.println(x);
}
You can also create a filter that can then be passed into the newDirectoryStream method above
DirectoryStream.Filter<Path> filter = new DirectoryStream.Filter<Path>() {
public boolean accept(Path file) throws IOException {
try {
return (Files.isRegularFile(path));
} catch (IOException x) {
// Failed to determine if it's a file.
System.err.println(x);
return false;
}
}
};
For other filtering examples, [see documentation].(http://docs.oracle.com/javase/tutorial/essential/io/dirs.html#glob)
private static final String ROOT_FILE_PATH="/";
File f=new File(ROOT_FILE_PATH);
File[] allSubFiles=f.listFiles();
for (File file : allSubFiles) {
if(file.isDirectory())
{
System.out.println(file.getAbsolutePath()+" is directory");
//Steps for directory
}
else
{
System.out.println(file.getAbsolutePath()+" is file");
//steps for files
}
}
Just walk through all Files using Files.walkFileTree (Java 7)
Files.walkFileTree(Paths.get(dir), new SimpleFileVisitor<Path>() {
#Override
public FileVisitResult visitFile(Path file, BasicFileAttributes attrs) throws IOException {
System.out.println("file: " + file);
return FileVisitResult.CONTINUE;
}
});
If you want more options, you can use this function which aims to populate an arraylist of files present in a folder. Options are : recursivility and pattern to match.
public static ArrayList<File> listFilesForFolder(final File folder,
final boolean recursivity,
final String patternFileFilter) {
// Inputs
boolean filteredFile = false;
// Ouput
final ArrayList<File> output = new ArrayList<File> ();
// Foreach elements
for (final File fileEntry : folder.listFiles()) {
// If this element is a directory, do it recursivly
if (fileEntry.isDirectory()) {
if (recursivity) {
output.addAll(listFilesForFolder(fileEntry, recursivity, patternFileFilter));
}
}
else {
// If there is no pattern, the file is correct
if (patternFileFilter.length() == 0) {
filteredFile = true;
}
// Otherwise we need to filter by pattern
else {
filteredFile = Pattern.matches(patternFileFilter, fileEntry.getName());
}
// If the file has a name which match with the pattern, then add it to the list
if (filteredFile) {
output.add(fileEntry);
}
}
}
return output;
}
Best, Adrien
File directory = new File("/user/folder");
File[] myarray;
myarray=new File[10];
myarray=directory.listFiles();
for (int j = 0; j < myarray.length; j++)
{
File path=myarray[j];
FileReader fr = new FileReader(path);
BufferedReader br = new BufferedReader(fr);
String s = "";
while (br.ready()) {
s += br.readLine() + "\n";
}
}
nice usage of java.io.FileFilter as seen on https://stackoverflow.com/a/286001/146745
File fl = new File(dir);
File[] files = fl.listFiles(new FileFilter() {
public boolean accept(File file) {
return file.isFile();
}
});
static File mainFolder = new File("Folder");
public static void main(String[] args) {
lf.getFiles(lf.mainFolder);
}
public void getFiles(File f) {
File files[];
if (f.isFile()) {
String name=f.getName();
} else {
files = f.listFiles();
for (int i = 0; i < files.length; i++) {
getFiles(files[i]);
}
}
}
I think this is good way to read all the files in a folder and sub folder's
private static void addfiles (File input,ArrayList<File> files)
{
if(input.isDirectory())
{
ArrayList <File> path = new ArrayList<File>(Arrays.asList(input.listFiles()));
for(int i=0 ; i<path.size();++i)
{
if(path.get(i).isDirectory())
{
addfiles(path.get(i),files);
}
if(path.get(i).isFile())
{
files.add(path.get(i));
}
}
}
if(input.isFile())
{
files.add(input);
}
}
Simple example that works with Java 1.7 to recursively list files in directories specified on the command-line:
import java.io.File;
public class List {
public static void main(String[] args) {
for (String f : args) {
listDir(f);
}
}
private static void listDir(String dir) {
File f = new File(dir);
File[] list = f.listFiles();
if (list == null) {
return;
}
for (File entry : list) {
System.out.println(entry.getName());
if (entry.isDirectory()) {
listDir(entry.getAbsolutePath());
}
}
}
}
While I do agree with Rich, Orian and the rest for using:
final File keysFileFolder = new File(<path>);
File[] fileslist = keysFileFolder.listFiles();
if(fileslist != null)
{
//Do your thing here...
}
for some reason all the examples here uses absolute path (i.e. all the way from root, or, say, drive letter (C:\) for windows..)
I'd like to add that it is possible to use relative path as-well.
So, if you're pwd (current directory/folder) is folder1 and you want to parse folder1/subfolder, you simply write (in the code above instead of ):
final File keysFileFolder = new File("subfolder");
Java 8 Files.walk(..) is good when you are soore it will not throw Avoid Java 8 Files.walk(..) termination cause of ( java.nio.file.AccessDeniedException ) .
Here is a safe solution , not though so elegant as Java 8Files.walk(..) :
int[] count = {0};
try {
Files.walkFileTree(Paths.get(dir.getPath()), new HashSet<FileVisitOption>(Arrays.asList(FileVisitOption.FOLLOW_LINKS)),
Integer.MAX_VALUE, new SimpleFileVisitor<Path>() {
#Override
public FileVisitResult visitFile(Path file , BasicFileAttributes attrs) throws IOException {
System.out.printf("Visiting file %s\n", file);
++count[0];
return FileVisitResult.CONTINUE;
}
#Override
public FileVisitResult visitFileFailed(Path file , IOException e) throws IOException {
System.err.printf("Visiting failed for %s\n", file);
return FileVisitResult.SKIP_SUBTREE;
}
#Override
public FileVisitResult preVisitDirectory(Path dir , BasicFileAttributes attrs) throws IOException {
System.out.printf("About to visit directory %s\n", dir);
return FileVisitResult.CONTINUE;
}
});
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
void getFiles(){
String dirPath = "E:/folder_name";
File dir = new File(dirPath);
String[] files = dir.list();
if (files.length == 0) {
System.out.println("The directory is empty");
} else {
for (String aFile : files) {
System.out.println(aFile);
}
}
}
package com;
import java.io.File;
/**
*
* #author ?Mukesh
*/
public class ListFiles {
static File mainFolder = new File("D:\\Movies");
public static void main(String[] args)
{
ListFiles lf = new ListFiles();
lf.getFiles(lf.mainFolder);
long fileSize = mainFolder.length();
System.out.println("mainFolder size in bytes is: " + fileSize);
System.out.println("File size in KB is : " + (double)fileSize/1024);
System.out.println("File size in MB is :" + (double)fileSize/(1024*1024));
}
public void getFiles(File f){
File files[];
if(f.isFile())
System.out.println(f.getAbsolutePath());
else{
files = f.listFiles();
for (int i = 0; i < files.length; i++) {
getFiles(files[i]);
}
}
}
}
Just to expand on the accepted answer I store the filenames to an ArrayList (instead of just dumping them to System.out.println) I created a helper class "MyFileUtils" so it could be imported by other projects:
class MyFileUtils {
public static void loadFilesForFolder(final File folder, List<String> fileList){
for (final File fileEntry : folder.listFiles()) {
if (fileEntry.isDirectory()) {
loadFilesForFolder(fileEntry, fileList);
} else {
fileList.add( fileEntry.getParent() + File.separator + fileEntry.getName() );
}
}
}
}
I added the full path to the file name.
You would use it like this:
import MyFileUtils;
List<String> fileList = new ArrayList<String>();
final File folder = new File("/home/you/Desktop");
MyFileUtils.loadFilesForFolder(folder, fileList);
// Dump file list values
for (String fileName : fileList){
System.out.println(fileName);
}
The ArrayList is passed by "value", but the value is used to point to the same ArrayList object living in the JVM Heap. In this way, each recursion call adds filenames to the same ArrayList (we are NOT creating a new ArrayList on each recursive call).
There are many good answers above, here's a different approach: In a maven project, everything you put in the resources folder is copied by default in the target/classes folder. To see what is available at runtime
ClassLoader contextClassLoader =
Thread.currentThread().getContextClassLoader();
URL resource = contextClassLoader.getResource("");
File file = new File(resource.toURI());
File[] files = file.listFiles();
for (File f : files) {
System.out.println(f.getName());
}
Now to get the files from a specific folder, let's say you have a folder called 'res' in your resources folder, just replace:
URL resource = contextClassLoader.getResource("res");
If you want to have access in your com.companyName package then:
contextClassLoader.getResource("com.companyName");
You can put the file path to argument and create a list with all the filepaths and not put it the list manually. Then use a for loop and a reader. Example for txt files:
public static void main(String[] args) throws IOException{
File[] files = new File(args[0].replace("\\", "\\\\")).listFiles(new FilenameFilter() { #Override public boolean accept(File dir, String name) { return name.endsWith(".txt"); } });
ArrayList<String> filedir = new ArrayList<String>();
String FILE_TEST = null;
for (i=0; i<files.length; i++){
filedir.add(files[i].toString());
CSV_FILE_TEST=filedir.get(i)
try(Reader testreader = Files.newBufferedReader(Paths.get(FILE_TEST));
){
//write your stuff
}}}
package com.commandline.folder;
import java.io.File;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.util.stream.Stream;
public class FolderReadingDemo {
public static void main(String[] args) {
String str = args[0];
final File folder = new File(str);
// listFilesForFolder(folder);
listFilesForFolder(str);
}
public static void listFilesForFolder(String str) {
try (Stream<Path> paths = Files.walk(Paths.get(str))) {
paths.filter(Files::isRegularFile).forEach(System.out::println);
} catch (Exception e) {
e.printStackTrace();
}
}
public static void listFilesForFolder(final File folder) {
for (final File fileEntry : folder.listFiles()) {
if (fileEntry.isDirectory()) {
listFilesForFolder(fileEntry);
} else {
System.out.println(fileEntry.getName());
}
}
}
}
We can use org.apache.commons.io.FileUtils, use listFiles() mehtod to read all the files in a given folder.
eg:
FileUtils.listFiles(directory, new String[] {"ext1", "ext2"}, true)
This read all the files in the given directory with given extensions, we can pass multiple extensions in the array and read recursively within the folder(true parameter).
public static List<File> files(String dirname) {
if (dirname == null) {
return Collections.emptyList();
}
File dir = new File(dirname);
if (!dir.exists()) {
return Collections.emptyList();
}
if (!dir.isDirectory()) {
return Collections.singletonList(file(dirname));
}
return Arrays.stream(Objects.requireNonNull(dir.listFiles()))
.collect(Collectors.toList());
}
import java.io.File;
import java.util.ArrayList;
import java.util.List;
public class AvoidNullExp {
public static void main(String[] args) {
List<File> fileList =new ArrayList<>();
final File folder = new File("g:/master");
new AvoidNullExp().listFilesForFolder(folder, fileList);
}
public void listFilesForFolder(final File folder,List<File> fileList) {
File[] filesInFolder = folder.listFiles();
if (filesInFolder != null) {
for (final File fileEntry : filesInFolder) {
if (fileEntry.isDirectory()) {
System.out.println("DIR : "+fileEntry.getName());
listFilesForFolder(fileEntry,fileList);
} else {
System.out.println("FILE : "+fileEntry.getName());
fileList.add(fileEntry);
}
}
}
}
}
list down files from Test folder present inside class path
import java.io.File;
import java.io.IOException;
public class Hello {
public static void main(final String[] args) throws IOException {
System.out.println("List down all the files present on the server directory");
File file1 = new File("/prog/FileTest/src/Test");
File[] files = file1.listFiles();
if (null != files) {
for (int fileIntList = 0; fileIntList < files.length; fileIntList++) {
String ss = files[fileIntList].toString();
if (null != ss && ss.length() > 0) {
System.out.println("File: " + (fileIntList + 1) + " :" + ss.substring(ss.lastIndexOf("\\") + 1, ss.length()));
}
}
}
}
}
/**
* Function to read all mp3 files from sdcard and store the details in an
* ArrayList
*/
public ArrayList<HashMap<String, String>> getPlayList()
{
ArrayList<HashMap<String, String>> songsList=new ArrayList<>();
File home = new File(MEDIA_PATH);
if (home.listFiles(new FileExtensionFilter()).length > 0) {
for (File file : home.listFiles(new FileExtensionFilter())) {
HashMap<String, String> song = new HashMap<String, String>();
song.put(
"songTitle",
file.getName().substring(0,
(file.getName().length() - 4)));
song.put("songPath", file.getPath());
// Adding each song to SongList
songsList.add(song);
}
}
// return songs list array
return songsList;
}
/**
* Class to filter files which have a .mp3 extension
* */
class FileExtensionFilter implements FilenameFilter
{
#Override
public boolean accept(File dir, String name) {
return (name.endsWith(".mp3") || name.endsWith(".MP3"));
}
}
You can filter any textfiles or any other extension ..just replace it with .MP3
This will Read Specified file extension files in given path(looks sub folders also)
public static Map<String,List<File>> getFileNames(String
dirName,Map<String,List<File>> filesContainer,final String fileExt){
String dirPath = dirName;
List<File>files = new ArrayList<>();
Map<String,List<File>> completeFiles = filesContainer;
if(completeFiles == null) {
completeFiles = new HashMap<>();
}
File file = new File(dirName);
FileFilter fileFilter = new FileFilter() {
#Override
public boolean accept(File file) {
boolean acceptFile = false;
if(file.isDirectory()) {
acceptFile = true;
}else if (file.getName().toLowerCase().endsWith(fileExt))
{
acceptFile = true;
}
return acceptFile;
}
};
for(File dirfile : file.listFiles(fileFilter)) {
if(dirfile.isFile() &&
dirfile.getName().toLowerCase().endsWith(fileExt)) {
files.add(dirfile);
}else if(dirfile.isDirectory()) {
if(!files.isEmpty()) {
completeFiles.put(dirPath, files);
}
getFileNames(dirfile.getAbsolutePath(),completeFiles,fileExt);
}
}
if(!files.isEmpty()) {
completeFiles.put(dirPath, files);
}
return completeFiles;
}
This will work fine:
private static void addfiles(File inputValVal, ArrayList<File> files)
{
if(inputVal.isDirectory())
{
ArrayList <File> path = new ArrayList<File>(Arrays.asList(inputVal.listFiles()));
for(int i=0; i<path.size(); ++i)
{
if(path.get(i).isDirectory())
{
addfiles(path.get(i),files);
}
if(path.get(i).isFile())
{
files.add(path.get(i));
}
}
/* Optional : if you need to have the counts of all the folders and files you can create 2 global arrays
and store the results of the above 2 if loops inside these arrays */
}
if(inputVal.isFile())
{
files.add(inputVal);
}
}
I have a program that should process the files in the directory and if the file size is more than 50 bytes delete it. Otherwise, if the file size is less then 50 bytes program should rename the args[1] file to the allFilesContent.txt(same directory), and write all the files to this file, separated by "n" (110 ASCII code). But instead the program just creates another file and writes to the very first args[1] file. What's the problem?
public class Solution
{
public static void main(String [] args) throws IOException
{
File path = new File(args[0]);
File resultFileAbsolutePath = new File(args[1]);
ArrayList<File> allFiles = new ArrayList<>();
boolean isRenamed = false;
for(File file : path.listFiles())
{
if(file.length() > 50)
{
FileUtils.deleteFile(file);
}
else if(file.length() <= 50)
{
if(!isRenamed)
{
FileUtils.renameFile(resultFileAbsolutePath, new File(resultFileAbsolutePath.getParent()+"\\allFilesContent.txt"));
isRenamed = true;
}
if(!file.getName().equals(resultFileAbsolutePath.getName()))
{
allFiles.add(file);
}
}
}
Collections.sort(allFiles, new Comparator<File>()
{
#Override
public int compare(File o1, File o2)
{
return o1.getName().compareTo(o2.getName());
}
});
FileOutputStream fileOutputStream = new FileOutputStream(resultFileAbsolutePath, true);
for (File file : allFiles)
{
try(FileInputStream fileInputStream = new FileInputStream(file))
{
if(allFiles.indexOf(file) != 0) fileOutputStream.write(110);
int data;
while(fileInputStream.available() > 0)
{
data = fileInputStream.read();
fileOutputStream.write(data);
}
}
}
fileOutputStream.close();
}
public static void deleteFile(File file)
{
if (!file.delete())
{
System.out.println("Can not delete file with name " + file.getName());
}
}
}
And FileUtils class
import java.io.File;
public class FileUtils
{
public static void deleteFile(File file)
{
if (!file.delete())
{
System.out.println("Can not delete file with name " + file.getName());
}
}
public static void renameFile(File source, File destination)
{
if (!source.renameTo(destination))
{
System.out.println("Can not rename file with name " + source.getName());
}
}
}
You have following statement: "FileOutputStream fileOutputStream = new FileOutputStream(resultFileAbsolutePath, true);"
Instead of "true" put "false". It should work.
I am not able delete file that is stored in cache. I am using the cache for several purposes. I am reading and writing but not able to delete. Can someone please help me with this?
//write
public static void writeObject(Context context, String key, Object object)
throws IOException {
Log.d("Cache", "WRITE: context");
FileOutputStream fos = context.openFileOutput(key, Context.MODE_PRIVATE);
ObjectOutputStream oos = new ObjectOutputStream(fos);
oos.writeObject(object);
oos.close();
fos.close();
}
//read
public static Object readObject(Context context, String key) throws IOException,
ClassNotFoundException {
FileInputStream fis = context.openFileInput(key);
ObjectInputStream ois = new ObjectInputStream(fis);
Object object = ois.readObject();
return object;
}
//delete
public static void clearCahe(String key) throws IOException,ClassNotFoundException {
File file = new File(key);
file.delete();
}
context.openFileOutput(key writes the file to internal memory. The path you can find with getFilesDir() and looks like /data/data/<yourpackagename>/files.
So if you want to delete the file 'key' you have to set up the path for File file = new File(path) as String path = getFilesDir().getAbsolutePath() + "/" + key;.
And use file.exists() to check if the file exists!
use this to clear application data.
public void clearApplicationData()
{
File cache = getCacheDir();
File appDir = new File(cache.getParent());
if (appDir.exists()) {
String[] children = appDir.list();
for (String s : children) {
if (!s.equals("lib")) {
deleteDir(new File(appDir, s));Log.i("TAG", "**************** File /data/data/APP_PACKAGE/" + s + " DELETED *******************");
}
}
}
}
public static boolean deleteDir(File dir)
{
if (dir != null && dir.isDirectory()) {
String[] children = dir.list();
for (int i = 0; i < children.length; i++) {
boolean success = deleteDir(new File(dir, children[i]));
if (!success) {
return false;
}
}
}
return dir.delete();
}
Files
Like the cache directory, your app also has an app-specific directory for holding files. Files in this directory will exist until the app explicitly deletes them or the app is uninstalled. You typically access this directory with Context.getFilesDir(). This can show up as various things on the app info screen, but in your screenshot this is "USB Storage Data".
NOTE: If you want to explicitly place on external media (typically SD card), you can use Context.getExternalFilesDir(String type).
Simple cache manager:
public class CacheManager {
private static final long MAX_SIZE = 5242880L; // 5MB
private CacheManager() {
}
public static void cacheData(Context context, byte[] data, String name) throws IOException {
File cacheDir = context.getCacheDir();
long size = getDirSize(cacheDir);
long newSize = data.length + size;
if (newSize > MAX_SIZE) {
cleanDir(cacheDir, newSize - MAX_SIZE);
}
File file = new File(cacheDir, name);
FileOutputStream os = new FileOutputStream(file);
try {
os.write(data);
}
finally {
os.flush();
os.close();
}
}
public static byte[] retrieveData(Context context, String name) throws IOException {
File cacheDir = context.getCacheDir();
File file = new File(cacheDir, name);
if (!file.exists()) {
// Data doesn't exist
return null;
}
byte[] data = new byte[(int) file.length()];
FileInputStream is = new FileInputStream(file);
try {
is.read(data);
}
finally {
is.close();
}
return data;
}
private static void cleanDir(File dir, long bytes) {
long bytesDeleted = 0;
File[] files = dir.listFiles();
for (File file : files) {
bytesDeleted += file.length();
file.delete();
if (bytesDeleted >= bytes) {
break;
}
}
}
private static long getDirSize(File dir) {
long size = 0;
File[] files = dir.listFiles();
for (File file : files) {
if (file.isFile()) {
size += file.length();
}
}
return size;
}
}
NOTE: The purpose of the cache is to cut down on network activity,
long processes, and provide a responsive UI in your app.
Reference: When to clear the cache dir in Android?.
I want to copy a file from one location to another location in Java. What is the best way to do this?
Here is what I have so far:
import java.io.File;
import java.io.FilenameFilter;
import java.util.ArrayList;
import java.util.List;
public class TestArrayList {
public static void main(String[] args) {
File f = new File(
"D:\\CBSE_Demo\\Demo_original\\fscommand\\contentplayer\\config");
List<String>temp=new ArrayList<String>();
temp.add(0, "N33");
temp.add(1, "N1417");
temp.add(2, "N331");
File[] matchingFiles = null;
for(final String temp1: temp){
matchingFiles = f.listFiles(new FilenameFilter() {
public boolean accept(File dir, String name) {
return name.startsWith(temp1);
}
});
System.out.println("size>>--"+matchingFiles.length);
}
}
}
This does not copy the file, what is the best way to do this?
You can use this (or any variant):
Files.copy(src, dst, StandardCopyOption.REPLACE_EXISTING);
Also, I'd recommend using File.separator or / instead of \\ to make it compliant across multiple OS, question/answer on this available here.
Since you're not sure how to temporarily store files, take a look at ArrayList:
List<File> files = new ArrayList();
files.add(foundFile);
To move a List of files into a single directory:
List<File> files = ...;
String path = "C:/destination/";
for(File file : files) {
Files.copy(file.toPath(),
(new File(path + file.getName())).toPath(),
StandardCopyOption.REPLACE_EXISTING);
}
Update:
see also
https://stackoverflow.com/a/67179064/1847899
Using Stream
private static void copyFileUsingStream(File source, File dest) throws IOException {
InputStream is = null;
OutputStream os = null;
try {
is = new FileInputStream(source);
os = new FileOutputStream(dest);
byte[] buffer = new byte[1024];
int length;
while ((length = is.read(buffer)) > 0) {
os.write(buffer, 0, length);
}
} finally {
is.close();
os.close();
}
}
Using Channel
private static void copyFileUsingChannel(File source, File dest) throws IOException {
FileChannel sourceChannel = null;
FileChannel destChannel = null;
try {
sourceChannel = new FileInputStream(source).getChannel();
destChannel = new FileOutputStream(dest).getChannel();
destChannel.transferFrom(sourceChannel, 0, sourceChannel.size());
}finally{
sourceChannel.close();
destChannel.close();
}
}
Using Apache Commons IO lib:
private static void copyFileUsingApacheCommonsIO(File source, File dest) throws IOException {
FileUtils.copyFile(source, dest);
}
Using Java SE 7 Files class:
private static void copyFileUsingJava7Files(File source, File dest) throws IOException {
Files.copy(source.toPath(), dest.toPath());
}
Or try Googles Guava :
https://github.com/google/guava
docs:
https://guava.dev/releases/snapshot-jre/api/docs/com/google/common/io/Files.html
Use the New Java File classes in Java >=7.
Create the below method and import the necessary libs.
public static void copyFile( File from, File to ) throws IOException {
Files.copy( from.toPath(), to.toPath() );
}
Use the created method as below within main:
File dirFrom = new File(fileFrom);
File dirTo = new File(fileTo);
try {
copyFile(dirFrom, dirTo);
} catch (IOException ex) {
Logger.getLogger(TestJava8.class.getName()).log(Level.SEVERE, null, ex);
}
NB:- fileFrom is the file that you want to copy to a new file fileTo in a different folder.
Credits - #Scott: Standard concise way to copy a file in Java?
public static void copyFile(File oldLocation, File newLocation) throws IOException {
if ( oldLocation.exists( )) {
BufferedInputStream reader = new BufferedInputStream( new FileInputStream(oldLocation) );
BufferedOutputStream writer = new BufferedOutputStream( new FileOutputStream(newLocation, false));
try {
byte[] buff = new byte[8192];
int numChars;
while ( (numChars = reader.read( buff, 0, buff.length ) ) != -1) {
writer.write( buff, 0, numChars );
}
} catch( IOException ex ) {
throw new IOException("IOException when transferring " + oldLocation.getPath() + " to " + newLocation.getPath());
} finally {
try {
if ( reader != null ){
writer.close();
reader.close();
}
} catch( IOException ex ){
Log.e(TAG, "Error closing files when transferring " + oldLocation.getPath() + " to " + newLocation.getPath() );
}
}
} else {
throw new IOException("Old location does not exist when transferring " + oldLocation.getPath() + " to " + newLocation.getPath() );
}
}
Copy a file from one location to another location means,need to copy the whole content to another location.Files.copy(Path source, Path target, CopyOption... options) throws IOException this method expects source location which is original file location and target location which is a new folder location with destination same type file(as original).
Either Target location needs to exist in our system otherwise we need to create a folder location and then in that folder location we need to create a file with the same name as original filename.Then using copy function we can easily copy a file from one location to other.
public static void main(String[] args) throws IOException {
String destFolderPath = "D:/TestFile/abc";
String fileName = "pqr.xlsx";
String sourceFilePath= "D:/TestFile/xyz.xlsx";
File f = new File(destFolderPath);
if(f.mkdir()){
System.out.println("Directory created!!!!");
}
else {
System.out.println("Directory Exists!!!!");
}
f= new File(destFolderPath,fileName);
if(f.createNewFile()) {
System.out.println("File Created!!!!");
} else {
System.out.println("File exists!!!!");
}
Files.copy(Paths.get(sourceFilePath), Paths.get(destFolderPath, fileName),REPLACE_EXISTING);
System.out.println("Copy done!!!!!!!!!!!!!!");
}
You can do it with the Java 8 Streaming API, PrintWriter and the Files API
try (PrintWriter pw = new PrintWriter(new File("destination-path"), StandardCharsets.UTF_8)) {
Files.readAllLines(Path.of("src/test/resources/source-file.something"), StandardCharsets.UTF_8)
.forEach(pw::println);
}
If you want to modify the content on-the-fly while copying, check out this link for the extended example https://overflowed.dev/blog/copy-file-and-modify-with-java-streams/
I modified one of the answers to make it a bit more efficient.
public void copy(){
InputStream in = null;
try {
in = new FileInputStream(Files);
} catch (FileNotFoundException e) {
e.printStackTrace();
}
try {
OutputStream out = new FileOutputStream();
try {
// Transfer bytes from in to out
byte[] buf = new byte[1024];
while (true) {
int len = 0;
try {
if (!((len = in.read(buf)) > 0)) break;
} catch (IOException e) {
e.printStackTrace();
}
try {
out.write(buf, 0, len);
} catch (IOException e) {
e.printStackTrace();
}
}
} finally {
try {
out.close();
} catch (IOException e) {
e.printStackTrace();
}
}
} finally {
try {
in.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
private void moveFile() {
copy();
File dir = getFilesDir();
File file = new File(dir, "my_filename");
boolean deleted = file.delete();
}
Files.exists()
Files.createDirectory()
Files.copy()
Overwriting Existing Files:
Files.move()
Files.delete()
Files.walkFileTree()
enter link description here
You can use
FileUtils.copy(sourceFile, destinationFile);
https://commons.apache.org/proper/commons-io/apidocs/org/apache/commons/io/FileUtils.html
Suppose I have the following directory structure.
D:\reports\january\
Inside january there are suppose two excel files say A.xls and B.xls. There are many places where it has been written about how to zip files using java.util.zip. But I want to zip the january folder itself inside reports folder so that both january and january.zip will be present inside reports. (That means when I unzip the january.zip file I should get the january folder).
Can anyone please provide me the code to do this using java.util.zip. Please let me know whether this can be more easily done by using other libraries.
Thanks a lot...
Have you tried Zeroturnaround Zip library? It's really neat! Zip a folder is just a one liner:
ZipUtil.pack(new File("D:\\reports\\january\\"), new File("D:\\reports\\january.zip"));
(thanks to Oleg Šelajev for the example)
Here is the Java 8+ example:
public static void pack(String sourceDirPath, String zipFilePath) throws IOException {
Path p = Files.createFile(Paths.get(zipFilePath));
try (ZipOutputStream zs = new ZipOutputStream(Files.newOutputStream(p))) {
Path pp = Paths.get(sourceDirPath);
Files.walk(pp)
.filter(path -> !Files.isDirectory(path))
.forEach(path -> {
ZipEntry zipEntry = new ZipEntry(pp.relativize(path).toString());
try {
zs.putNextEntry(zipEntry);
Files.copy(path, zs);
zs.closeEntry();
} catch (IOException e) {
System.err.println(e);
}
});
}
}
It can be easily solved by package java.util.Zip no need any extra Jar files
Just copy the following code and run it with your IDE
//Import all needed packages
package general;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class ZipUtils {
private List <String> fileList;
private static final String OUTPUT_ZIP_FILE = "Folder.zip";
private static final String SOURCE_FOLDER = "D:\\Reports"; // SourceFolder path
public ZipUtils() {
fileList = new ArrayList < String > ();
}
public static void main(String[] args) {
ZipUtils appZip = new ZipUtils();
appZip.generateFileList(new File(SOURCE_FOLDER));
appZip.zipIt(OUTPUT_ZIP_FILE);
}
public void zipIt(String zipFile) {
byte[] buffer = new byte[1024];
String source = new File(SOURCE_FOLDER).getName();
FileOutputStream fos = null;
ZipOutputStream zos = null;
try {
fos = new FileOutputStream(zipFile);
zos = new ZipOutputStream(fos);
System.out.println("Output to Zip : " + zipFile);
FileInputStream in = null;
for (String file: this.fileList) {
System.out.println("File Added : " + file);
ZipEntry ze = new ZipEntry(source + File.separator + file);
zos.putNextEntry(ze);
try {
in = new FileInputStream(SOURCE_FOLDER + File.separator + file);
int len;
while ((len = in .read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
} finally {
in.close();
}
}
zos.closeEntry();
System.out.println("Folder successfully compressed");
} catch (IOException ex) {
ex.printStackTrace();
} finally {
try {
zos.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
public void generateFileList(File node) {
// add file only
if (node.isFile()) {
fileList.add(generateZipEntry(node.toString()));
}
if (node.isDirectory()) {
String[] subNote = node.list();
for (String filename: subNote) {
generateFileList(new File(node, filename));
}
}
}
private String generateZipEntry(String file) {
return file.substring(SOURCE_FOLDER.length() + 1, file.length());
}
}
Refer mkyong..I changed the code for the requirement of current question
Here's a pretty terse Java 7+ solution which relies purely on vanilla JDK classes, no third party libraries required:
public static void pack(final Path folder, final Path zipFilePath) throws IOException {
try (
FileOutputStream fos = new FileOutputStream(zipFilePath.toFile());
ZipOutputStream zos = new ZipOutputStream(fos)
) {
Files.walkFileTree(folder, new SimpleFileVisitor<Path>() {
public FileVisitResult visitFile(Path file, BasicFileAttributes attrs) throws IOException {
zos.putNextEntry(new ZipEntry(folder.relativize(file).toString()));
Files.copy(file, zos);
zos.closeEntry();
return FileVisitResult.CONTINUE;
}
public FileVisitResult preVisitDirectory(Path dir, BasicFileAttributes attrs) throws IOException {
zos.putNextEntry(new ZipEntry(folder.relativize(dir).toString() + "/"));
zos.closeEntry();
return FileVisitResult.CONTINUE;
}
});
}
}
It copies all files in folder, including empty directories, and creates a zip archive at zipFilePath.
Java 7+, commons.io
public final class ZipUtils {
public static void zipFolder(final File folder, final File zipFile) throws IOException {
zipFolder(folder, new FileOutputStream(zipFile));
}
public static void zipFolder(final File folder, final OutputStream outputStream) throws IOException {
try (ZipOutputStream zipOutputStream = new ZipOutputStream(outputStream)) {
processFolder(folder, zipOutputStream, folder.getPath().length() + 1);
}
}
private static void processFolder(final File folder, final ZipOutputStream zipOutputStream, final int prefixLength)
throws IOException {
for (final File file : folder.listFiles()) {
if (file.isFile()) {
final ZipEntry zipEntry = new ZipEntry(file.getPath().substring(prefixLength));
zipOutputStream.putNextEntry(zipEntry);
try (FileInputStream inputStream = new FileInputStream(file)) {
IOUtils.copy(inputStream, zipOutputStream);
}
zipOutputStream.closeEntry();
} else if (file.isDirectory()) {
processFolder(file, zipOutputStream, prefixLength);
}
}
}
}
I usually use a helper class I once wrote for this task:
import java.util.zip.*;
import java.io.*;
public class ZipExample {
public static void main(String[] args){
ZipHelper zippy = new ZipHelper();
try {
zippy.zipDir("folderName","test.zip");
} catch(IOException e2) {
System.err.println(e2);
}
}
}
class ZipHelper
{
public void zipDir(String dirName, String nameZipFile) throws IOException {
ZipOutputStream zip = null;
FileOutputStream fW = null;
fW = new FileOutputStream(nameZipFile);
zip = new ZipOutputStream(fW);
addFolderToZip("", dirName, zip);
zip.close();
fW.close();
}
private void addFolderToZip(String path, String srcFolder, ZipOutputStream zip) throws IOException {
File folder = new File(srcFolder);
if (folder.list().length == 0) {
addFileToZip(path , srcFolder, zip, true);
}
else {
for (String fileName : folder.list()) {
if (path.equals("")) {
addFileToZip(folder.getName(), srcFolder + "/" + fileName, zip, false);
}
else {
addFileToZip(path + "/" + folder.getName(), srcFolder + "/" + fileName, zip, false);
}
}
}
}
private void addFileToZip(String path, String srcFile, ZipOutputStream zip, boolean flag) throws IOException {
File folder = new File(srcFile);
if (flag) {
zip.putNextEntry(new ZipEntry(path + "/" +folder.getName() + "/"));
}
else {
if (folder.isDirectory()) {
addFolderToZip(path, srcFile, zip);
}
else {
byte[] buf = new byte[1024];
int len;
FileInputStream in = new FileInputStream(srcFile);
zip.putNextEntry(new ZipEntry(path + "/" + folder.getName()));
while ((len = in.read(buf)) > 0) {
zip.write(buf, 0, len);
}
}
}
}
}
Enhanced Java 8+ example (Forked from Nikita Koksharov's answer)
public static void pack(String sourceDirPath, String zipFilePath) throws IOException {
Path p = Files.createFile(Paths.get(zipFilePath));
Path pp = Paths.get(sourceDirPath);
try (ZipOutputStream zs = new ZipOutputStream(Files.newOutputStream(p));
Stream<Path> paths = Files.walk(pp)) {
paths
.filter(path -> !Files.isDirectory(path))
.forEach(path -> {
ZipEntry zipEntry = new ZipEntry(pp.relativize(path).toString());
try {
zs.putNextEntry(zipEntry);
Files.copy(path, zs);
zs.closeEntry();
} catch (IOException e) {
System.err.println(e);
}
});
}
}
Files.walk has been wrapped in try with resources block so that stream can be closed. This resolves blocker issue identified by SonarQube.
Thanks #Matt Harrison for pointing this.
I would use Apache Ant, which has an API to call tasks from Java code rather than from an XML build file.
Project p = new Project();
p.init();
Zip zip = new Zip();
zip.setProject(p);
zip.setDestFile(zipFile); // a java.io.File for the zip you want to create
zip.setBasedir(new File("D:\\reports"));
zip.setIncludes("january/**");
zip.perform();
Here I'm telling it to start from the base directory D:\reports and zip up the january folder and everything inside it. The paths in the resulting zip file will be the same as the original paths relative to D:\reports, so they will include the january prefix.
Using zip4j you can simply do this
ZipFile zipfile = new ZipFile(new File("D:\\reports\\january\\filename.zip"));
zipfile.addFolder(new File("D:\\reports\\january\\"));
It will archive your folder and everything in it.
Use the .extractAll method to get it all out:
zipfile.extractAll("D:\\destination_directory");
Try this:
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class Zip {
public static void main(String[] a) throws Exception {
zipFolder("D:\\reports\\january", "D:\\reports\\january.zip");
}
static public void zipFolder(String srcFolder, String destZipFile) throws Exception {
ZipOutputStream zip = null;
FileOutputStream fileWriter = null;
fileWriter = new FileOutputStream(destZipFile);
zip = new ZipOutputStream(fileWriter);
addFolderToZip("", srcFolder, zip);
zip.flush();
zip.close();
}
static private void addFileToZip(String path, String srcFile, ZipOutputStream zip)
throws Exception {
File folder = new File(srcFile);
if (folder.isDirectory()) {
addFolderToZip(path, srcFile, zip);
} else {
byte[] buf = new byte[1024];
int len;
FileInputStream in = new FileInputStream(srcFile);
zip.putNextEntry(new ZipEntry(path + "/" + folder.getName()));
while ((len = in.read(buf)) > 0) {
zip.write(buf, 0, len);
}
}
}
static private void addFolderToZip(String path, String srcFolder, ZipOutputStream zip)
throws Exception {
File folder = new File(srcFolder);
for (String fileName : folder.list()) {
if (path.equals("")) {
addFileToZip(folder.getName(), srcFolder + "/" + fileName, zip);
} else {
addFileToZip(path + "/" + folder.getName(), srcFolder + "/" + fileName, zip);
}
}
}
}
Java 6 +
import java.io.*;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class Zip {
private static final FileFilter FOLDER_FILTER = new FileFilter() {
#Override
public boolean accept(File pathname) {
return pathname.isDirectory();
}
};
private static final FileFilter FILE_FILTER = new FileFilter() {
#Override
public boolean accept(File pathname) {
return pathname.isFile();
}
};
private static void compress(File file, ZipOutputStream outputStream, String path) throws IOException {
if (file.isDirectory()) {
File[] subFiles = file.listFiles(FILE_FILTER);
if (subFiles != null) {
for (File subFile : subFiles) {
compress(subFile, outputStream, new File(path, subFile.getName()).getAbsolutePath());
}
}
File[] subDirs = file.listFiles(FOLDER_FILTER);
if (subDirs != null) {
for (File subDir : subDirs) {
compress(subDir, outputStream, new File(path, subDir.getName()).getAbsolutePath());
}
}
} else if (file.exists()) {
outputStream.putNextEntry(new ZipEntry(path));
FileInputStream inputStream = new FileInputStream(file);
byte[] buffer = new byte[1024];
int len;
while ((len = inputStream.read(buffer)) >= 0) {
outputStream.write(buffer, 0, len);
}
outputStream.closeEntry();
}
}
public static void compress(String dirPath, String zipFilePath) throws IOException {
File file = new File(dirPath);
final ZipOutputStream outputStream = new ZipOutputStream(new FileOutputStream(zipFilePath));
compress(file, outputStream, "/");
outputStream.close();
}
}
I found this solution worked perfectly fine for me. Doesn't require any third party apis
'test' is actually a folder will lots of file inside.
String folderPath= "C:\Users\Desktop\test";
String zipPath = "C:\Users\Desktop\test1.zip";
private boolean zipDirectory(String folderPath, String zipPath) throws IOException{
byte[] buffer = new byte[1024];
FileInputStream fis = null;
ZipOutputStream zos = null;
try{
zos = new ZipOutputStream(new FileOutputStream(zipPath));
updateSourceFolder(new File(folderPath));
if (sourceFolder == null) {
zos.close();
return false;
}
generateFileAndFolderList(new File(folderPath));
for (String unzippedFile: fileList) {
System.out.println(sourceFolder + unzippedFile);
ZipEntry entry = new ZipEntry(unzippedFile);
zos.putNextEntry(entry);
if ((unzippedFile.substring(unzippedFile.length()-1)).equals(File.separator))
continue;
try{
fis = new FileInputStream(sourceFolder + unzippedFile);
int len=0;
while ((len = fis.read(buffer))>0) {
zos.write(buffer,0,len);
}
} catch(IOException e) {
return false;
} finally {
if (fis != null)
fis.close();
}
}
zos.closeEntry();
} catch(IOException e) {
return false;
} finally {
zos.close();
fileList = null;
sourceFolder = null;
}
return true;
}
private void generateFileAndFolderList(File node) {
if (node.isFile()) {
fileList.add(generateZipEntry(node.getAbsoluteFile().toString()));
}
if (node.isDirectory()) {
String dir = node.getAbsoluteFile().toString();
fileList.add(dir.substring(sourceFolder.length(), dir.length()) + File.separator);
String[] subNode = node.list();
for (String fileOrFolderName : subNode) {
generateFileAndFolderList(new File(node, fileOrFolderName));
}
}
}
private void updateSourceFolder(File node) {
if (node.isFile() || node.isDirectory()) {
String sf = node.getAbsoluteFile().toString();
sourceFolder = sf.substring(0, (sf.lastIndexOf("/") > 0 ? sf.lastIndexOf("/") : sf.lastIndexOf("\\")));
sourceFolder += File.separator;
} else
sourceFolder = null;
}
private String generateZipEntry(String file) {
return file.substring(sourceFolder.length(), file.length());
}
This method zips a folder and adds all of the child files & folders (including empty folders) into the zip file.
void zipFolder(Path sourceDir, Path targetFile) throws IOException {
ZipDirectoryVisitor zipVisitor = new ZipDirectoryVisitor(sourceDir);
Files.walkFileTree(sourceDir, zipVisitor);
FileOutputStream fos = new FileOutputStream(targetFile.toString());
ZipOutputStream zos = new ZipOutputStream(fos);
byte[] buffer = new byte[1024];
for (ZipEntry entry : zipVisitor.getZipEntries()) {
zos.putNextEntry(entry);
Path curFile = Paths.get(sourceDir.getParent().toString(), entry.toString());
if (!curFile.toFile().isDirectory()) {
FileInputStream in = new FileInputStream(Paths.get(sourceDir.getParent().toString(), entry.toString()).toString());
int len;
while ((len = in.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
in.close();
}
zos.closeEntry();
}
zos.close();
}
And here is the ZipDirectoryVisitor implementation:
class ZipDirectoryVisitor extends SimpleFileVisitor<Path> {
private Path dirToZip;
private List<ZipEntry> zipEntries; // files and folders inside source folder as zip entries
public ZipDirectoryVisitor(Path dirToZip) throws IOException {
this.dirToZip = dirToZip;
zipEntries = new ArrayList<>();
}
#Override
public FileVisitResult visitFile(Path path, BasicFileAttributes basicFileAttributes) throws IOException {
// According to zip standard backslashes
// should not be used in zip entries
String zipFile = dirToZip.getParent().relativize(path).toString().replace("\\", "/");
ZipEntry entry = new ZipEntry(zipFile);
zipEntries.add(entry);
return FileVisitResult.CONTINUE;
}
#Override
public FileVisitResult preVisitDirectory(Path path, BasicFileAttributes basicFileAttributes) throws IOException {
String zipDir = dirToZip.getParent().relativize(path).toString().replace("\\", "/");
// Zip directory entries should end with a forward slash
ZipEntry entry = new ZipEntry(zipDir + "/");
zipEntries.add(entry);
return FileVisitResult.CONTINUE;
}
#Override
public FileVisitResult visitFileFailed(Path path, IOException e) throws IOException {
System.err.format("Could not visit file %s while creating a file list from file tree", path);
return FileVisitResult.TERMINATE;
}
public List<ZipEntry> getZipEntries() {
return zipEntries;
}
}
I have modified the above solutions and replaced Files.walk with Files.list. This also assumes the directory you are zipping only contains file and not any sub directories.
private void zipDirectory(Path dirPath) throws IOException {
String zipFilePathStr = dirPath.toString() + ".zip";
Path zipFilePath = Files.createFile(Paths.get(zipFilePathStr));
try (ZipOutputStream zs = new ZipOutputStream(Files.newOutputStream(zipFilePath))) {
Files.list(dirPath)
.filter(filePath-> !Files.isDirectory(filePath))
.forEach(filePath-> {
ZipEntry zipEntry = new ZipEntry(dirPath.relativize(filePath).toString());
try {
zs.putNextEntry(zipEntry);
Files.copy(filePath, zs);
zs.closeEntry();
}
catch (IOException e) {
System.err.println(e);
}
});
}
}
Improving #Nikita Koksharov's code had problems packing empty directories.
private void zipDirectory(OutputStream outputStream, Path directoryPath) throws IOException {
try (ZipOutputStream zs = new ZipOutputStream(outputStream)) {
Path pp = directoryPath;
Files.walk(pp)
.forEach(path -> {
try {
if (Files.isDirectory(path)) {
zs.putNextEntry(new ZipEntry(pp.relativize(path).toString() + "/"));
} else {
ZipEntry zipEntry = new ZipEntry(pp.relativize(path).toString());
zs.putNextEntry(zipEntry);
Files.copy(path, zs);
zs.closeEntry();
}
} catch (IOException e) {
System.err.println(e);
}
});
}
}
Test usage
FileOutputStream zipOutput = new FileOutputStream("path_to_file.zip");
Path pathOutput = Path.of("path_directory_fid");
zipDirectory(outputStream, pathOutput);
try this zip("C:\testFolder", "D:\testZip.zip")
public void zip( String sourcDirPath, String zipPath) throws IOException {
Path zipFile = Files.createFile(Paths.get(zipPath));
Path sourceDirPath = Paths.get(sourcDirPath);
try (ZipOutputStream zipOutputStream = new ZipOutputStream(Files.newOutputStream(zipFile));
Stream<Path> paths = Files.walk(sourceDirPath)) {
paths
.filter(path -> !Files.isDirectory(path))
.forEach(path -> {
ZipEntry zipEntry = new ZipEntry(sourceDirPath.relativize(path).toString());
try {
zipOutputStream.putNextEntry(zipEntry);
Files.copy(path, zipOutputStream);
zipOutputStream.closeEntry();
} catch (IOException e) {
System.err.println(e);
}
});
}
System.out.println("Zip is created at : "+zipFile);
}