How to copy file from one location to another location? - java

I want to copy a file from one location to another location in Java. What is the best way to do this?
Here is what I have so far:
import java.io.File;
import java.io.FilenameFilter;
import java.util.ArrayList;
import java.util.List;
public class TestArrayList {
public static void main(String[] args) {
File f = new File(
"D:\\CBSE_Demo\\Demo_original\\fscommand\\contentplayer\\config");
List<String>temp=new ArrayList<String>();
temp.add(0, "N33");
temp.add(1, "N1417");
temp.add(2, "N331");
File[] matchingFiles = null;
for(final String temp1: temp){
matchingFiles = f.listFiles(new FilenameFilter() {
public boolean accept(File dir, String name) {
return name.startsWith(temp1);
}
});
System.out.println("size>>--"+matchingFiles.length);
}
}
}
This does not copy the file, what is the best way to do this?


You can use this (or any variant):
Files.copy(src, dst, StandardCopyOption.REPLACE_EXISTING);
Also, I'd recommend using File.separator or / instead of \\ to make it compliant across multiple OS, question/answer on this available here.
Since you're not sure how to temporarily store files, take a look at ArrayList:
List<File> files = new ArrayList();
files.add(foundFile);
To move a List of files into a single directory:
List<File> files = ...;
String path = "C:/destination/";
for(File file : files) {
Files.copy(file.toPath(),
(new File(path + file.getName())).toPath(),
StandardCopyOption.REPLACE_EXISTING);
}


Update:
see also
https://stackoverflow.com/a/67179064/1847899
Using Stream
private static void copyFileUsingStream(File source, File dest) throws IOException {
InputStream is = null;
OutputStream os = null;
try {
is = new FileInputStream(source);
os = new FileOutputStream(dest);
byte[] buffer = new byte[1024];
int length;
while ((length = is.read(buffer)) > 0) {
os.write(buffer, 0, length);
}
} finally {
is.close();
os.close();
}
}
Using Channel
private static void copyFileUsingChannel(File source, File dest) throws IOException {
FileChannel sourceChannel = null;
FileChannel destChannel = null;
try {
sourceChannel = new FileInputStream(source).getChannel();
destChannel = new FileOutputStream(dest).getChannel();
destChannel.transferFrom(sourceChannel, 0, sourceChannel.size());
}finally{
sourceChannel.close();
destChannel.close();
}
}
Using Apache Commons IO lib:
private static void copyFileUsingApacheCommonsIO(File source, File dest) throws IOException {
FileUtils.copyFile(source, dest);
}
Using Java SE 7 Files class:
private static void copyFileUsingJava7Files(File source, File dest) throws IOException {
Files.copy(source.toPath(), dest.toPath());
}
Or try Googles Guava :
https://github.com/google/guava
docs:
https://guava.dev/releases/snapshot-jre/api/docs/com/google/common/io/Files.html


Use the New Java File classes in Java >=7.
Create the below method and import the necessary libs.
public static void copyFile( File from, File to ) throws IOException {
Files.copy( from.toPath(), to.toPath() );
}
Use the created method as below within main:
File dirFrom = new File(fileFrom);
File dirTo = new File(fileTo);
try {
copyFile(dirFrom, dirTo);
} catch (IOException ex) {
Logger.getLogger(TestJava8.class.getName()).log(Level.SEVERE, null, ex);
}
NB:- fileFrom is the file that you want to copy to a new file fileTo in a different folder.
Credits - #Scott: Standard concise way to copy a file in Java?


public static void copyFile(File oldLocation, File newLocation) throws IOException {
if ( oldLocation.exists( )) {
BufferedInputStream reader = new BufferedInputStream( new FileInputStream(oldLocation) );
BufferedOutputStream writer = new BufferedOutputStream( new FileOutputStream(newLocation, false));
try {
byte[] buff = new byte[8192];
int numChars;
while ( (numChars = reader.read( buff, 0, buff.length ) ) != -1) {
writer.write( buff, 0, numChars );
}
} catch( IOException ex ) {
throw new IOException("IOException when transferring " + oldLocation.getPath() + " to " + newLocation.getPath());
} finally {
try {
if ( reader != null ){
writer.close();
reader.close();
}
} catch( IOException ex ){
Log.e(TAG, "Error closing files when transferring " + oldLocation.getPath() + " to " + newLocation.getPath() );
}
}
} else {
throw new IOException("Old location does not exist when transferring " + oldLocation.getPath() + " to " + newLocation.getPath() );
}
}


Copy a file from one location to another location means,need to copy the whole content to another location.Files.copy(Path source, Path target, CopyOption... options) throws IOException this method expects source location which is original file location and target location which is a new folder location with destination same type file(as original).
Either Target location needs to exist in our system otherwise we need to create a folder location and then in that folder location we need to create a file with the same name as original filename.Then using copy function we can easily copy a file from one location to other.
public static void main(String[] args) throws IOException {
String destFolderPath = "D:/TestFile/abc";
String fileName = "pqr.xlsx";
String sourceFilePath= "D:/TestFile/xyz.xlsx";
File f = new File(destFolderPath);
if(f.mkdir()){
System.out.println("Directory created!!!!");
}
else {
System.out.println("Directory Exists!!!!");
}
f= new File(destFolderPath,fileName);
if(f.createNewFile()) {
System.out.println("File Created!!!!");
} else {
System.out.println("File exists!!!!");
}
Files.copy(Paths.get(sourceFilePath), Paths.get(destFolderPath, fileName),REPLACE_EXISTING);
System.out.println("Copy done!!!!!!!!!!!!!!");
}


You can do it with the Java 8 Streaming API, PrintWriter and the Files API
try (PrintWriter pw = new PrintWriter(new File("destination-path"), StandardCharsets.UTF_8)) {
Files.readAllLines(Path.of("src/test/resources/source-file.something"), StandardCharsets.UTF_8)
.forEach(pw::println);
}
If you want to modify the content on-the-fly while copying, check out this link for the extended example https://overflowed.dev/blog/copy-file-and-modify-with-java-streams/


I modified one of the answers to make it a bit more efficient.
public void copy(){
InputStream in = null;
try {
in = new FileInputStream(Files);
} catch (FileNotFoundException e) {
e.printStackTrace();
}
try {
OutputStream out = new FileOutputStream();
try {
// Transfer bytes from in to out
byte[] buf = new byte[1024];
while (true) {
int len = 0;
try {
if (!((len = in.read(buf)) > 0)) break;
} catch (IOException e) {
e.printStackTrace();
}
try {
out.write(buf, 0, len);
} catch (IOException e) {
e.printStackTrace();
}
}
} finally {
try {
out.close();
} catch (IOException e) {
e.printStackTrace();
}
}
} finally {
try {
in.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
private void moveFile() {
copy();
File dir = getFilesDir();
File file = new File(dir, "my_filename");
boolean deleted = file.delete();
}


Files.exists()
Files.createDirectory()
Files.copy()
Overwriting Existing Files:
Files.move()
Files.delete()
Files.walkFileTree()
enter link description here


You can use
FileUtils.copy(sourceFile, destinationFile);
https://commons.apache.org/proper/commons-io/apidocs/org/apache/commons/io/FileUtils.html

Related

Java File.renamTo not working

I have made the code which renames all the jpg files in a directory from 1 to n (number of files)..
if there were let say 50 jpg files that after running the program all the files are renamed to 1.jpg ,2.jpg and so on till 50.jpg
But i am facing the problem if I manually rename the file let say 50.jpg to aaa.jpg then again running the program doesn't rename that file
I have wasted one day to resove that issue
Kindly help me
Code:
public class Renaming {
private static String path; // string for storing the path
public static void main(String[] args) {
FileReader fileReader = null; // filereader for opening the file
BufferedReader bufferedReader = null; // buffered reader for buffering the data of file
try{
fileReader = new FileReader("input.txt"); // making the filereader object and paasing the file name
bufferedReader = new BufferedReader(fileReader); //making the buffered Reader object
path=bufferedReader.readLine();
fileReader.close();
bufferedReader.close();
}
catch (FileNotFoundException e) { // Exception when file is not found
e.printStackTrace();
}
catch (IOException e) { // IOException
e.printStackTrace();
}
finally {
File directory=new File(path);
File[] files= directory.listFiles(); // Storing the all the files in Array
int file_counter=1;
for(int file_no=0;file_no<files.length;file_no++){
String Extension=getFileExtension(files[file_no]); //getting the filw extension
if (files[file_no].isFile() && (Extension .equals("jpg")|| Extension.equals("JPG"))){ // checking that if file is of jpg type then apply renaming // checking thaat if it is file
File new_file = new File(path+"\\"+files[file_no].getName()); //making the new file
new_file.renameTo(new File(path+"\\"+String.valueOf(file_no+1)+".jpg")); //Renaming the file
System.out.println(new_file.toString());
file_counter++; // incrementing the file counter
}
}
}
}
private static String getFileExtension(File file) { //utility function for getting the file extension
String name = file.getName();
try {
return name.substring(name.lastIndexOf(".") + 1); // gettingf the extension name after .
} catch (Exception e) {
return "";
}
}`

first of all, you should use the path separator / . It's work on Windows, Linux and Mac OS.
This is my version of your problem to rename all files into a folder provide. Hope this will help you. I use last JDK version to speed up and reduce the code.
public class App {
private String path = null;
public static int index = 1;
public App(String path){
if (Files.isDirectory(Paths.get( path ))) {
this.path = path;
}
}
public void rename() throws IOException{
if ( this.path != null){
Files.list(Paths.get( this.path ))
.forEach( f ->
{
String fileName = f.getFileName().toString();
String extension = fileName.replaceAll("^.*\\.([^.]+)$", "$1");
try {
Files.move( f ,Paths.get( this.path + "/" + App.index + "." + extension));
App.index++;
} catch (IOException e) {
e.printStackTrace();
}
}
);
}
}
public static void main(String[] args) throws IOException {
App app = new App("c:/Temp/");
app.rename();
}
}

how to backup file in java?

In reality its just making a copy of a text.txt file. I know how to use file chooser to choose the file but that is as far as my knowledge really goes.
I can do this:
public BasicFile()
{
JFileChooser choose = new JFileChooser(".");
int status = choose.showOpenDialog(null);
try
{
if (status != JFileChooser.APPROVE_OPTION) throw new IOException();
f = choose.getSelectedFile();
if (!f.exists()) throw new FileNotFoundException();
}
catch(FileNotFoundException e)
{
display(1, e.toString(), "File not found ....");
}
catch(IOException e)
{
display(1, e.toString(), "Approve option was not selected");
}
}

Path object is perfect for copying files,
Try this code to copy a file,
Path source = Paths.get("c:\\blabla.txt");
Path target = Paths.get("c:\\blabla2.txt");
try {
Files.copy(source, target);
} catch (IOException e1) {
e1.printStackTrace();
}

If you have to backup a whole folder, you can use this code
public class BackUpFolder {
public void copy(File sourceLocation, File targetLocation) throws IOException {
if (sourceLocation.isDirectory()) {
copyDirectory(sourceLocation, targetLocation);
} else {
copyFile(sourceLocation, targetLocation);
}
}
private void copyDirectory(File source, File target) throws IOException {
if (!target.exists()) {
target.mkdir();
}
for (String f : source.list()) {
copy(new File(source, f), new File(target, f));
}
}
private void copyFile(File source, File target) throws IOException {
try (
InputStream in = new FileInputStream(source);
OutputStream out = new FileOutputStream(target)) {
byte[] buf = new byte[1024];
int length;
while ((length = in.read(buf)) > 0) {
out.write(buf, 0, length);
}
}
}
public static void main(String[] args) {
try {
BackUpFolder backUpFolder = new BackUpFolder();
String location = "./src/edu/abc/locationFiles/daofile"; //File path you are getting from file chooser
String target = "./src"; //target place you want to patse
File locFile = new File(location);
File tarFile = new File(target);
backUpFolder.copyDirectory(locFile, tarFile);
} catch (IOException ex) {
Logger.getLogger(BackUpFolder.class.getName()).log(Level.SEVERE, null, ex);
}
}
}

Start by taking a look at Basic I/O, which explains the basics of Input/OutputStreams and Readers and Writers, which are used to read/write bytes of data from a source to a destination.
If you're using Java 7 or over, you should also take a look at Copying a File or Directory which is part of newer Files and Paths API, which you can find more information about at File I/O (Featuring NIO.2)

how to zip a folder itself using java

Suppose I have the following directory structure.
D:\reports\january\
Inside january there are suppose two excel files say A.xls and B.xls. There are many places where it has been written about how to zip files using java.util.zip. But I want to zip the january folder itself inside reports folder so that both january and january.zip will be present inside reports. (That means when I unzip the january.zip file I should get the january folder).
Can anyone please provide me the code to do this using java.util.zip. Please let me know whether this can be more easily done by using other libraries.
Thanks a lot...

Have you tried Zeroturnaround Zip library? It's really neat! Zip a folder is just a one liner:
ZipUtil.pack(new File("D:\\reports\\january\\"), new File("D:\\reports\\january.zip"));
(thanks to Oleg Šelajev for the example)

Here is the Java 8+ example:
public static void pack(String sourceDirPath, String zipFilePath) throws IOException {
Path p = Files.createFile(Paths.get(zipFilePath));
try (ZipOutputStream zs = new ZipOutputStream(Files.newOutputStream(p))) {
Path pp = Paths.get(sourceDirPath);
Files.walk(pp)
.filter(path -> !Files.isDirectory(path))
.forEach(path -> {
ZipEntry zipEntry = new ZipEntry(pp.relativize(path).toString());
try {
zs.putNextEntry(zipEntry);
Files.copy(path, zs);
zs.closeEntry();
} catch (IOException e) {
System.err.println(e);
}
});
}
}

It can be easily solved by package java.util.Zip no need any extra Jar files
Just copy the following code and run it with your IDE
//Import all needed packages
package general;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class ZipUtils {
private List <String> fileList;
private static final String OUTPUT_ZIP_FILE = "Folder.zip";
private static final String SOURCE_FOLDER = "D:\\Reports"; // SourceFolder path
public ZipUtils() {
fileList = new ArrayList < String > ();
}
public static void main(String[] args) {
ZipUtils appZip = new ZipUtils();
appZip.generateFileList(new File(SOURCE_FOLDER));
appZip.zipIt(OUTPUT_ZIP_FILE);
}
public void zipIt(String zipFile) {
byte[] buffer = new byte[1024];
String source = new File(SOURCE_FOLDER).getName();
FileOutputStream fos = null;
ZipOutputStream zos = null;
try {
fos = new FileOutputStream(zipFile);
zos = new ZipOutputStream(fos);
System.out.println("Output to Zip : " + zipFile);
FileInputStream in = null;
for (String file: this.fileList) {
System.out.println("File Added : " + file);
ZipEntry ze = new ZipEntry(source + File.separator + file);
zos.putNextEntry(ze);
try {
in = new FileInputStream(SOURCE_FOLDER + File.separator + file);
int len;
while ((len = in .read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
} finally {
in.close();
}
}
zos.closeEntry();
System.out.println("Folder successfully compressed");
} catch (IOException ex) {
ex.printStackTrace();
} finally {
try {
zos.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
public void generateFileList(File node) {
// add file only
if (node.isFile()) {
fileList.add(generateZipEntry(node.toString()));
}
if (node.isDirectory()) {
String[] subNote = node.list();
for (String filename: subNote) {
generateFileList(new File(node, filename));
}
}
}
private String generateZipEntry(String file) {
return file.substring(SOURCE_FOLDER.length() + 1, file.length());
}
}
Refer mkyong..I changed the code for the requirement of current question

Here's a pretty terse Java 7+ solution which relies purely on vanilla JDK classes, no third party libraries required:
public static void pack(final Path folder, final Path zipFilePath) throws IOException {
try (
FileOutputStream fos = new FileOutputStream(zipFilePath.toFile());
ZipOutputStream zos = new ZipOutputStream(fos)
) {
Files.walkFileTree(folder, new SimpleFileVisitor<Path>() {
public FileVisitResult visitFile(Path file, BasicFileAttributes attrs) throws IOException {
zos.putNextEntry(new ZipEntry(folder.relativize(file).toString()));
Files.copy(file, zos);
zos.closeEntry();
return FileVisitResult.CONTINUE;
}
public FileVisitResult preVisitDirectory(Path dir, BasicFileAttributes attrs) throws IOException {
zos.putNextEntry(new ZipEntry(folder.relativize(dir).toString() + "/"));
zos.closeEntry();
return FileVisitResult.CONTINUE;
}
});
}
}
It copies all files in folder, including empty directories, and creates a zip archive at zipFilePath.

Java 7+, commons.io
public final class ZipUtils {
public static void zipFolder(final File folder, final File zipFile) throws IOException {
zipFolder(folder, new FileOutputStream(zipFile));
}
public static void zipFolder(final File folder, final OutputStream outputStream) throws IOException {
try (ZipOutputStream zipOutputStream = new ZipOutputStream(outputStream)) {
processFolder(folder, zipOutputStream, folder.getPath().length() + 1);
}
}
private static void processFolder(final File folder, final ZipOutputStream zipOutputStream, final int prefixLength)
throws IOException {
for (final File file : folder.listFiles()) {
if (file.isFile()) {
final ZipEntry zipEntry = new ZipEntry(file.getPath().substring(prefixLength));
zipOutputStream.putNextEntry(zipEntry);
try (FileInputStream inputStream = new FileInputStream(file)) {
IOUtils.copy(inputStream, zipOutputStream);
}
zipOutputStream.closeEntry();
} else if (file.isDirectory()) {
processFolder(file, zipOutputStream, prefixLength);
}
}
}
}

I usually use a helper class I once wrote for this task:
import java.util.zip.*;
import java.io.*;
public class ZipExample {
public static void main(String[] args){
ZipHelper zippy = new ZipHelper();
try {
zippy.zipDir("folderName","test.zip");
} catch(IOException e2) {
System.err.println(e2);
}
}
}
class ZipHelper
{
public void zipDir(String dirName, String nameZipFile) throws IOException {
ZipOutputStream zip = null;
FileOutputStream fW = null;
fW = new FileOutputStream(nameZipFile);
zip = new ZipOutputStream(fW);
addFolderToZip("", dirName, zip);
zip.close();
fW.close();
}
private void addFolderToZip(String path, String srcFolder, ZipOutputStream zip) throws IOException {
File folder = new File(srcFolder);
if (folder.list().length == 0) {
addFileToZip(path , srcFolder, zip, true);
}
else {
for (String fileName : folder.list()) {
if (path.equals("")) {
addFileToZip(folder.getName(), srcFolder + "/" + fileName, zip, false);
}
else {
addFileToZip(path + "/" + folder.getName(), srcFolder + "/" + fileName, zip, false);
}
}
}
}
private void addFileToZip(String path, String srcFile, ZipOutputStream zip, boolean flag) throws IOException {
File folder = new File(srcFile);
if (flag) {
zip.putNextEntry(new ZipEntry(path + "/" +folder.getName() + "/"));
}
else {
if (folder.isDirectory()) {
addFolderToZip(path, srcFile, zip);
}
else {
byte[] buf = new byte[1024];
int len;
FileInputStream in = new FileInputStream(srcFile);
zip.putNextEntry(new ZipEntry(path + "/" + folder.getName()));
while ((len = in.read(buf)) > 0) {
zip.write(buf, 0, len);
}
}
}
}
}

Enhanced Java 8+ example (Forked from Nikita Koksharov's answer)
public static void pack(String sourceDirPath, String zipFilePath) throws IOException {
Path p = Files.createFile(Paths.get(zipFilePath));
Path pp = Paths.get(sourceDirPath);
try (ZipOutputStream zs = new ZipOutputStream(Files.newOutputStream(p));
Stream<Path> paths = Files.walk(pp)) {
paths
.filter(path -> !Files.isDirectory(path))
.forEach(path -> {
ZipEntry zipEntry = new ZipEntry(pp.relativize(path).toString());
try {
zs.putNextEntry(zipEntry);
Files.copy(path, zs);
zs.closeEntry();
} catch (IOException e) {
System.err.println(e);
}
});
}
}
Files.walk has been wrapped in try with resources block so that stream can be closed. This resolves blocker issue identified by SonarQube.
Thanks #Matt Harrison for pointing this.

I would use Apache Ant, which has an API to call tasks from Java code rather than from an XML build file.
Project p = new Project();
p.init();
Zip zip = new Zip();
zip.setProject(p);
zip.setDestFile(zipFile); // a java.io.File for the zip you want to create
zip.setBasedir(new File("D:\\reports"));
zip.setIncludes("january/**");
zip.perform();
Here I'm telling it to start from the base directory D:\reports and zip up the january folder and everything inside it. The paths in the resulting zip file will be the same as the original paths relative to D:\reports, so they will include the january prefix.

Using zip4j you can simply do this
ZipFile zipfile = new ZipFile(new File("D:\\reports\\january\\filename.zip"));
zipfile.addFolder(new File("D:\\reports\\january\\"));
It will archive your folder and everything in it.
Use the .extractAll method to get it all out:
zipfile.extractAll("D:\\destination_directory");

Try this:
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class Zip {
public static void main(String[] a) throws Exception {
zipFolder("D:\\reports\\january", "D:\\reports\\january.zip");
}
static public void zipFolder(String srcFolder, String destZipFile) throws Exception {
ZipOutputStream zip = null;
FileOutputStream fileWriter = null;
fileWriter = new FileOutputStream(destZipFile);
zip = new ZipOutputStream(fileWriter);
addFolderToZip("", srcFolder, zip);
zip.flush();
zip.close();
}
static private void addFileToZip(String path, String srcFile, ZipOutputStream zip)
throws Exception {
File folder = new File(srcFile);
if (folder.isDirectory()) {
addFolderToZip(path, srcFile, zip);
} else {
byte[] buf = new byte[1024];
int len;
FileInputStream in = new FileInputStream(srcFile);
zip.putNextEntry(new ZipEntry(path + "/" + folder.getName()));
while ((len = in.read(buf)) > 0) {
zip.write(buf, 0, len);
}
}
}
static private void addFolderToZip(String path, String srcFolder, ZipOutputStream zip)
throws Exception {
File folder = new File(srcFolder);
for (String fileName : folder.list()) {
if (path.equals("")) {
addFileToZip(folder.getName(), srcFolder + "/" + fileName, zip);
} else {
addFileToZip(path + "/" + folder.getName(), srcFolder + "/" + fileName, zip);
}
}
}
}

Java 6 +
import java.io.*;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class Zip {
private static final FileFilter FOLDER_FILTER = new FileFilter() {
#Override
public boolean accept(File pathname) {
return pathname.isDirectory();
}
};
private static final FileFilter FILE_FILTER = new FileFilter() {
#Override
public boolean accept(File pathname) {
return pathname.isFile();
}
};
private static void compress(File file, ZipOutputStream outputStream, String path) throws IOException {
if (file.isDirectory()) {
File[] subFiles = file.listFiles(FILE_FILTER);
if (subFiles != null) {
for (File subFile : subFiles) {
compress(subFile, outputStream, new File(path, subFile.getName()).getAbsolutePath());
}
}
File[] subDirs = file.listFiles(FOLDER_FILTER);
if (subDirs != null) {
for (File subDir : subDirs) {
compress(subDir, outputStream, new File(path, subDir.getName()).getAbsolutePath());
}
}
} else if (file.exists()) {
outputStream.putNextEntry(new ZipEntry(path));
FileInputStream inputStream = new FileInputStream(file);
byte[] buffer = new byte[1024];
int len;
while ((len = inputStream.read(buffer)) >= 0) {
outputStream.write(buffer, 0, len);
}
outputStream.closeEntry();
}
}
public static void compress(String dirPath, String zipFilePath) throws IOException {
File file = new File(dirPath);
final ZipOutputStream outputStream = new ZipOutputStream(new FileOutputStream(zipFilePath));
compress(file, outputStream, "/");
outputStream.close();
}
}

I found this solution worked perfectly fine for me. Doesn't require any third party apis
'test' is actually a folder will lots of file inside.
String folderPath= "C:\Users\Desktop\test";
String zipPath = "C:\Users\Desktop\test1.zip";
private boolean zipDirectory(String folderPath, String zipPath) throws IOException{
byte[] buffer = new byte[1024];
FileInputStream fis = null;
ZipOutputStream zos = null;
try{
zos = new ZipOutputStream(new FileOutputStream(zipPath));
updateSourceFolder(new File(folderPath));
if (sourceFolder == null) {
zos.close();
return false;
}
generateFileAndFolderList(new File(folderPath));
for (String unzippedFile: fileList) {
System.out.println(sourceFolder + unzippedFile);
ZipEntry entry = new ZipEntry(unzippedFile);
zos.putNextEntry(entry);
if ((unzippedFile.substring(unzippedFile.length()-1)).equals(File.separator))
continue;
try{
fis = new FileInputStream(sourceFolder + unzippedFile);
int len=0;
while ((len = fis.read(buffer))>0) {
zos.write(buffer,0,len);
}
} catch(IOException e) {
return false;
} finally {
if (fis != null)
fis.close();
}
}
zos.closeEntry();
} catch(IOException e) {
return false;
} finally {
zos.close();
fileList = null;
sourceFolder = null;
}
return true;
}
private void generateFileAndFolderList(File node) {
if (node.isFile()) {
fileList.add(generateZipEntry(node.getAbsoluteFile().toString()));
}
if (node.isDirectory()) {
String dir = node.getAbsoluteFile().toString();
fileList.add(dir.substring(sourceFolder.length(), dir.length()) + File.separator);
String[] subNode = node.list();
for (String fileOrFolderName : subNode) {
generateFileAndFolderList(new File(node, fileOrFolderName));
}
}
}
private void updateSourceFolder(File node) {
if (node.isFile() || node.isDirectory()) {
String sf = node.getAbsoluteFile().toString();
sourceFolder = sf.substring(0, (sf.lastIndexOf("/") > 0 ? sf.lastIndexOf("/") : sf.lastIndexOf("\\")));
sourceFolder += File.separator;
} else
sourceFolder = null;
}
private String generateZipEntry(String file) {
return file.substring(sourceFolder.length(), file.length());
}

This method zips a folder and adds all of the child files & folders (including empty folders) into the zip file.
void zipFolder(Path sourceDir, Path targetFile) throws IOException {
ZipDirectoryVisitor zipVisitor = new ZipDirectoryVisitor(sourceDir);
Files.walkFileTree(sourceDir, zipVisitor);
FileOutputStream fos = new FileOutputStream(targetFile.toString());
ZipOutputStream zos = new ZipOutputStream(fos);
byte[] buffer = new byte[1024];
for (ZipEntry entry : zipVisitor.getZipEntries()) {
zos.putNextEntry(entry);
Path curFile = Paths.get(sourceDir.getParent().toString(), entry.toString());
if (!curFile.toFile().isDirectory()) {
FileInputStream in = new FileInputStream(Paths.get(sourceDir.getParent().toString(), entry.toString()).toString());
int len;
while ((len = in.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
in.close();
}
zos.closeEntry();
}
zos.close();
}
And here is the ZipDirectoryVisitor implementation:
class ZipDirectoryVisitor extends SimpleFileVisitor<Path> {
private Path dirToZip;
private List<ZipEntry> zipEntries; // files and folders inside source folder as zip entries
public ZipDirectoryVisitor(Path dirToZip) throws IOException {
this.dirToZip = dirToZip;
zipEntries = new ArrayList<>();
}
#Override
public FileVisitResult visitFile(Path path, BasicFileAttributes basicFileAttributes) throws IOException {
// According to zip standard backslashes
// should not be used in zip entries
String zipFile = dirToZip.getParent().relativize(path).toString().replace("\\", "/");
ZipEntry entry = new ZipEntry(zipFile);
zipEntries.add(entry);
return FileVisitResult.CONTINUE;
}
#Override
public FileVisitResult preVisitDirectory(Path path, BasicFileAttributes basicFileAttributes) throws IOException {
String zipDir = dirToZip.getParent().relativize(path).toString().replace("\\", "/");
// Zip directory entries should end with a forward slash
ZipEntry entry = new ZipEntry(zipDir + "/");
zipEntries.add(entry);
return FileVisitResult.CONTINUE;
}
#Override
public FileVisitResult visitFileFailed(Path path, IOException e) throws IOException {
System.err.format("Could not visit file %s while creating a file list from file tree", path);
return FileVisitResult.TERMINATE;
}
public List<ZipEntry> getZipEntries() {
return zipEntries;
}
}

I have modified the above solutions and replaced Files.walk with Files.list. This also assumes the directory you are zipping only contains file and not any sub directories.
private void zipDirectory(Path dirPath) throws IOException {
String zipFilePathStr = dirPath.toString() + ".zip";
Path zipFilePath = Files.createFile(Paths.get(zipFilePathStr));
try (ZipOutputStream zs = new ZipOutputStream(Files.newOutputStream(zipFilePath))) {
Files.list(dirPath)
.filter(filePath-> !Files.isDirectory(filePath))
.forEach(filePath-> {
ZipEntry zipEntry = new ZipEntry(dirPath.relativize(filePath).toString());
try {
zs.putNextEntry(zipEntry);
Files.copy(filePath, zs);
zs.closeEntry();
}
catch (IOException e) {
System.err.println(e);
}
});
}
}

Improving #Nikita Koksharov's code had problems packing empty directories.
private void zipDirectory(OutputStream outputStream, Path directoryPath) throws IOException {
try (ZipOutputStream zs = new ZipOutputStream(outputStream)) {
Path pp = directoryPath;
Files.walk(pp)
.forEach(path -> {
try {
if (Files.isDirectory(path)) {
zs.putNextEntry(new ZipEntry(pp.relativize(path).toString() + "/"));
} else {
ZipEntry zipEntry = new ZipEntry(pp.relativize(path).toString());
zs.putNextEntry(zipEntry);
Files.copy(path, zs);
zs.closeEntry();
}
} catch (IOException e) {
System.err.println(e);
}
});
}
}
Test usage
FileOutputStream zipOutput = new FileOutputStream("path_to_file.zip");
Path pathOutput = Path.of("path_directory_fid");
zipDirectory(outputStream, pathOutput);

try this zip("C:\testFolder", "D:\testZip.zip")
public void zip( String sourcDirPath, String zipPath) throws IOException {
Path zipFile = Files.createFile(Paths.get(zipPath));
Path sourceDirPath = Paths.get(sourcDirPath);
try (ZipOutputStream zipOutputStream = new ZipOutputStream(Files.newOutputStream(zipFile));
Stream<Path> paths = Files.walk(sourceDirPath)) {
paths
.filter(path -> !Files.isDirectory(path))
.forEach(path -> {
ZipEntry zipEntry = new ZipEntry(sourceDirPath.relativize(path).toString());
try {
zipOutputStream.putNextEntry(zipEntry);
Files.copy(path, zipOutputStream);
zipOutputStream.closeEntry();
} catch (IOException e) {
System.err.println(e);
}
});
}
System.out.println("Zip is created at : "+zipFile);
}

Copying children files of a source to a destination in Java

I'm trying to make a program that copies a directory's children, and I can't label all the specific names because they vary throughout each folder. Here's the code I have, but if the source is "C:\src" and the output is "C:\dst" it'll create the folder "C:\dst\src(children files)", but I want to make "C:\dst(children files)". Can anyone help?
public static void copy(File source, File destination) throws IOException {
if (source == null) {
throw new NullPointerException("Null Source");
}
if (destination == null) {
throw new NullPointerException("Null Destination");
}
if (source.isDirectory()) {
copyDirectory(source, destination);
} else {
copyFile(source, destination);
}
}
//converts to location
public static void copyDirectory(File source, File destination) throws IOException {
copyDirectory(source, destination, null);
}
public static void copyDirectory(File source, File destination, FileFilter filter) throws IOException {
File nextDirectory = new File(destination, source.getName());
if (!nextDirectory.exists() && !nextDirectory.mkdirs()) {// create the directory if necessary...
Object[] filler = {nextDirectory.getAbsolutePath()};
String message = "Dir Copy Failed";
throw new IOException(message);
}
File[] files = source.listFiles();
for (int n = 0; n < files.length; ++n) {// and then all the items below the directory...
if (filter == null || filter.accept(files[n])) {
if (files[n].isDirectory()) {
copyDirectory(files[n], nextDirectory, filter);
} else {
copyFile(files[n], nextDirectory);
}
}
}
}
public static void copyFile(File source, File destination) throws IOException {
// what we really want to do is create a file with the same name in that dir
if (destination.isDirectory()) {
destination = new File(destination, source.getName());
}
FileInputStream input = new FileInputStream(source);
copyFile(input, destination);
}
public static void copyFile(InputStream input, File destination) throws IOException {
OutputStream output = null;
try {
output = new FileOutputStream(destination);
byte[] buffer = new byte[1024];
int bytesRead = input.read(buffer);
while (bytesRead >= 0) {
output.write(buffer, 0, bytesRead);
bytesRead = input.read(buffer);
}
} catch (Exception e) {
//
} finally {
input.close();
output.close();
}
input = null;
output = null;
}

Replace
if (source.isDirectory()) {
copyDirectory(source, destination);
} else {
copyFile(source, destination);
}
By
if (source.isDirectory()) {
for (File child : source.listFiles()) {
if (child.isDirectory()) {
copyDirectory(child, destination);
} else {
copyFile(child, destination);
}
}
} else {
copyFile(source, destination);
}

use getParentFile() to get the parent directory:
if (source.isDirectory()) {
copyDirectory(source, destination.getParentFile());
} else {
copyFile(source, destination.getParentFile());
}

You can do everything here in one line using commons-io library :
FileUtils.copyDirectory(src, dest);
see :
http://commons.apache.org/io/api-1.4/org/apache/commons/io/FileUtils.html#copyDirectory%28java.io.File,%20java.io.File%29
jar file : http://mvnrepository.com/artifact/commons-io/commons-io/2.4

Try this one. copying whole files in a folder from source to destination.
import java.io.*;
public class copydir
{
public static void main(String args[])
{
File srcFolder = new File("E://Paresh/programs/test");
File destFolder = new File("D://paresh");
if(!srcFolder.exists())
{
System.out.println("Directory does not exist.");
//just exit
System.exit(0);
}
else{
try{
copyDirectory(srcFolder,destFolder);
}
catch(IOException e)
{
e.printStackTrace();
//error, just exit
System.exit(0);
}
}
System.out.println("Done");
}
public static void copyDirectory(File src , File target) throws IOException
{
if (src.isDirectory())
{
if (!target.exists())
{
target.mkdir();
}
String[] children = src.list();
for (int i=0; i<children.length; i++)
{
copyDirectory(new File(src, children[i]),new File(target, children[i]));
}
}
// if Directory exists then only files copy
else
{
InputStream in = new FileInputStream(src);
OutputStream out = new FileOutputStream(target);
// Copy the bits from instream to outstream
byte[] buf = new byte[1024];
int len;
while ((len = in.read(buf)) > 0)
{
out.write(buf, 0, len);
}
in.close();
out.close();
}
}
}

zip4j zipping for files and folders in java

I wish to create a zip program in Java, which zip files and folders let say structure like this -
folder-one/
folder-one/one.txt
folder-one/two.mp3
folder-one/three.jpg
folder-two/
folder-two/four.doc
folder-two/five.rtf
folder-two/folder-three/
folder-two/folder-three/six.txt
I used zip4j open source, I have collected all the files (with absolute path) in one list then given it to zip but it is zipping files only as in my.zip -
one.txt
two.mp3
three.jpg
four.doc
five.rtf
six.txt
How can I preserve same structure on zipping and unzipping as it was on local earlier. Please suggest if any other open source can help me to zip/unzip in same structure files and folders like other windows zip programs.
Code is below --
public class CreateZipWithOutputStreams {
ArrayList filesToAdd = new ArrayList();
public void CreateZipWithOutputStreams(String sAbsolutePath) {
ZipOutputStream outputStream = null;
InputStream inputStream = null;
try {
ArrayList arrLocal = exploredFolder(sAbsolutePath);
outputStream = new ZipOutputStream(new FileOutputStream(new File("c:\\ZipTest\\CreateZipFileWithOutputStreams.zip")));
ZipParameters parameters = new ZipParameters();
parameters.setCompressionMethod(Zip4jConstants.COMP_DEFLATE);
parameters.setCompressionLevel(Zip4jConstants.DEFLATE_LEVEL_NORMAL);
parameters.setEncryptFiles(true);
parameters.setEncryptionMethod(Zip4jConstants.ENC_METHOD_AES);
parameters.setAesKeyStrength(Zip4jConstants.AES_STRENGTH_256);
parameters.setPassword("neelam");
for (int i = 0; i < arrLocal.size(); i++) {
File file = (File) arrLocal.get(i);
outputStream.putNextEntry(file, parameters);
if (file.isDirectory()) {
outputStream.closeEntry();
continue;
}
inputStream = new FileInputStream(file);
byte[] readBuff = new byte[4096];
int readLen = -1;
while ((readLen = inputStream.read(readBuff)) != -1) {
outputStream.write(readBuff, 0, readLen);
}
outputStream.closeEntry();
inputStream.close();
}
outputStream.finish();
} catch (Exception e) {
e.printStackTrace();
} finally {
if (outputStream != null) {
try {
outputStream.close();
} catch (IOException e) {
e.printStackTrace();
}
}
if (inputStream != null) {
try {
inputStream.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
public ArrayList exploredFolder(String sAbsolutePath) {
File[] sfiles;
File fsSelectedPath = new File(sAbsolutePath);
sfiles = fsSelectedPath.listFiles();
if (sfiles == null) {
return null;
}
for (int j = 0; j < sfiles.length; j++) {
File f = sfiles[j];
if (f.isDirectory() == true) {
exploredFolder(f.getAbsolutePath());
} else {
filesToAdd.add(f);
}
}
return filesToAdd;
}
public static void main(String[] args) {
new CreateZipWithOutputStreams().CreateZipWithOutputStreams("c:\\ZipTest");
}
}
Thanks!

Okay so first the code that is attached is supposed to work the way it is because the exploredFolder(String absolutePath) method is returning the "files to add" which in turn is being used by the CreateZipWithOutputStreams() method to create a single layered(flat) zip file.
What needs to be done is looping over the individual folders and keep adding them to the ZipOutputStream.
Please go through the link below and you will find the code snippet and detailed explaination.
Let me know if that helps!
http://www.java-forums.org/blogs/java-io/973-how-work-zip-files-java.html

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