Running a .bat inside Java Swing GUI Not Working - java

Using the following code, I can get the .bat file to execute (no GUI, just the following lines). However, when I add it in as a method of the ActionListener for the button (its a Java Swing app), the .bat file never executes. Any ideas?
Runtime runtime = Runtime.getRuntime();
try {
Process proc = runtime.exec("cmd /c start C:\\Users\\someName\\Desktop\\test.bat");
} catch (IOException e1) {
e1.printStackTrace();
}


Me too getting the same errors.
You can use like this
public void actionPerformed(java.awt.event.ActionEvent evt)
{
File file = new File("filename.bat");
try {
Desktop.getDesktop().open(file);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
jButton1ActionPerformed(evt);
}

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Have you signed the dll? Please sign the dll and then check.

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If I make a simple program that browses to google.com, the program doesn't exit automatically when reaching the end of the main method. I would rather not call System.exit(0), so I was wondering if there was a way to "close" the desktop thread so it can exit automagically.
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Running command with resource as argument

I am running a jar file on a different path on the system programmatically. One of the arguments needed is the path to a file, and the file is in my jar file. How can I pass the file (script.ospt) as an argument for another java application?
Current code:
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EDIT: More explanation:
I have a command I would like to run from java, using Runtime.getRuntime().exec().
The command I am running requires one argument: the path to a file. If the file is in the same package as my main class, how can I use the file in my program as an argument for the command?

How to open an exe file in java

I am trying to use java to open an exe file. I'm not sure which program I want to open so I am using Skype as an example. When I try to do it, it gives me errors.
try {
Process p = Runtime.getRuntime().exec("C:\\Program Files (x86)\\Skype\\Phone\\Skype");
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
error:
Cannot run program "C:\Program": CreateProcess error=2, The system cannot find the file specified

Try this:
String path = "/path/to/my_app.exe";
File file = new File(path);
if (! file.exists()) {
throw new IllegalArgumentException("The file " + path + " does not exist");
}
Process p = Runtime.getRuntime().exec(file.getAbsolutePath());

You have to use a string array, change to
try {
Process p = Runtime.getRuntime().exec(new String[] {"C:\\Program Files (x86)\\Notepad++\\notepad++.exe"});
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}

You are on windows so you have to include the extension .exe
try {
Process p = Runtime.getRuntime().exec("C:/Program Files (x86)/Skype/Phone/Skype.exe");
} catch (IOException e) {
// TODO Auto-generated catch block
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Maybe use File.separator instead of '\'

I tried this and it works fine, it's taken from your example. Pay attention to the double \\
public static void main(String[] args) {
try {
Process p;
p = Runtime.getRuntime().exec("C:\\Program Files\\Java\\jdk1.8.0_05\\bin\\Jconsole.exe");
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}

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public Server() throws InterruptedException
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//this.es = e;
try {
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myModule mod= new myModule();
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#Override
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My Question :
How to display log info of eclipse in the Cmd ? and how to see if the server launched the module or not ??
Thank You :)

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