Running command with resource as argument - java

I am running a jar file on a different path on the system programmatically. One of the arguments needed is the path to a file, and the file is in my jar file. How can I pass the file (script.ospt) as an argument for another java application?
Current code:
Process ps = null;
try {
ps = Runtime.getRuntime().exec(new String[]{"java","-jar",engine.getAbsolutePath(), script3.getAbsolutePath()});
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
try {
ps.waitFor();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
EDIT: More explanation:
I have a command I would like to run from java, using Runtime.getRuntime().exec().
The command I am running requires one argument: the path to a file. If the file is in the same package as my main class, how can I use the file in my program as an argument for the command?

Related

DLL Method Not Working After Creating Exe Of Project

I have calling display method from dll file This works when I run my java project . But it stop working after creating of project exe file. My Code is as follow ..
static {
try {
Bridge.setVerbose(true);
try {
Bridge.init();
} catch (IOException e) {
e.printStackTrace();
}
File dll_File = new File("helloworld.j4n.dll");
Bridge.LoadAndRegisterAssemblyFrom(dll_File);
helloworld.Hello.display(str)
} catch (Exception exception) {
exception.printStackTrace();
}
}
Have you signed the dll? Please sign the dll and then check.

How to rename the csv file in java?

I want to rename a csv file in java using following code segment, but file is not getting renamed.
public static void main(String[] args) {
File fileToBeRenamed = new File("C:/abc/a.txt");
File newFileName = new File("C:/abcd/b.txt");
try {
fileToBeRenamed.createNewFile();
newFileName.createNewFile();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
boolean isRenamed = fileToBeRenamed.renameTo(newFileName);
if(isRenamed)
System.out.println("File renamed successfully");
else
System.out.println("File could not be renamed");
}
Its not throwing any error. but file is not getting renamed.So please help me to do so.
let's suppose you have a file A(fileToBeRenamed) and you want to rename it to B(newFileName). Then , no need to create "newFileName" file. your code is fine , except the file creation part.
so comment out the lines:
try {
fileToBeRenamed.createNewFile();
newFileName.createNewFile();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
And it will work.
Note: I don't think it has anything to do with file extension(csv/text etc), when both are the same.
I think you want to rename a.txt to b.txt, So you don't need create b.txt. If you remove newFileName.createNewFile() will work

Refresh the workspace after file creation through java code

I am creating java files from json Objects using a library called jsonschema2pojo-core.jar. It successfully creates the required files for me. Now I need to access the newly(dynamically) created file and creates its instance to use it further.
But as the newly created class is still not in the classpath I am unable to do this. Tried to do my part of research and figured out that Eclipse jars allows such refresh only in plugin projects. Can anyone suggest some thing for this?
public static void main(String[] args){
String fileName = "MyJavaFile";
POJOBuilder pojo = new POJOBuilder();
pojo.buildPOJO("file:///C:/mypath/myJSON.json", fileName); //generates the java file MyJavaFile.java
Object obj = null;
try {
obj = Class.forName("com.mypackage."+fileName).newInstance(); // Java file not available yet
} catch (InstantiationException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IllegalAccessException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (ClassNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
Can this be done through threads? I mean wait until the creation of the POJO is done and then start with the rest after that?

How to open an exe file in java

I am trying to use java to open an exe file. I'm not sure which program I want to open so I am using Skype as an example. When I try to do it, it gives me errors.
try {
Process p = Runtime.getRuntime().exec("C:\\Program Files (x86)\\Skype\\Phone\\Skype");
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
error:
Cannot run program "C:\Program": CreateProcess error=2, The system cannot find the file specified
Try this:
String path = "/path/to/my_app.exe";
File file = new File(path);
if (! file.exists()) {
throw new IllegalArgumentException("The file " + path + " does not exist");
}
Process p = Runtime.getRuntime().exec(file.getAbsolutePath());
You have to use a string array, change to
try {
Process p = Runtime.getRuntime().exec(new String[] {"C:\\Program Files (x86)\\Notepad++\\notepad++.exe"});
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
You are on windows so you have to include the extension .exe
try {
Process p = Runtime.getRuntime().exec("C:/Program Files (x86)/Skype/Phone/Skype.exe");
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Maybe use File.separator instead of '\'
I tried this and it works fine, it's taken from your example. Pay attention to the double \\
public static void main(String[] args) {
try {
Process p;
p = Runtime.getRuntime().exec("C:\\Program Files\\Java\\jdk1.8.0_05\\bin\\Jconsole.exe");
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}

Running a .bat inside Java Swing GUI Not Working

Using the following code, I can get the .bat file to execute (no GUI, just the following lines). However, when I add it in as a method of the ActionListener for the button (its a Java Swing app), the .bat file never executes. Any ideas?
Runtime runtime = Runtime.getRuntime();
try {
Process proc = runtime.exec("cmd /c start C:\\Users\\someName\\Desktop\\test.bat");
} catch (IOException e1) {
e1.printStackTrace();
}
Me too getting the same errors.
You can use like this
public void actionPerformed(java.awt.event.ActionEvent evt)
{
File file = new File("filename.bat");
try {
Desktop.getDesktop().open(file);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
jButton1ActionPerformed(evt);
}

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