Error HTTP 422 GET in Android - java

I'm trying to perform a GET request to the server that returns me a JSON file. But I am getting an error in the HTTP statusLine / 422. Anyone know why. Below I show how I'm doing
public void testConverteArquivoJsonEmObjetoJava() {
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet get = new HttpGet(
"http://safe-sea-4024.ppooiheroku4554566adffasdfasdfalaqwerpcp.com/crimes/mobilelist");
get.setHeader("Accept", "application/json");
get.setHeader("Content-type", "application/json");
get.getParams()
.setParameter("token",
"0V1AYFK12SeCZHYgXbNMew==$tRqPNplipDwtbD0vxWv6GPJIT6Yk5abwca3IJ88888a6JhMs=");
HttpResponse httpResponse;
try {
httpResponse = httpClient.execute(get);
String jsonDeResposta = EntityUtils.toString(httpResponse
.getEntity());
System.out.println();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}

Usually you do not specify a Content-Type header with a GET request. This header tells the server how to interpret the entity includes in the message. It is possible that the server side is expecting a JSON entity even though GET cannot include a body. Try removing the Content-Type header.
I tried the URL that you cleverly changed and got it to work fine. However, I did get a 422 when I specified a different token query parameter. Being that the status line is missing a phrase, I would assume that the Ruby application is generating it.

I managed to solve the problem. I was passing the parameter so wrong. According to this post [blog]:How to add parameters to a HTTP GET request in Android? "link". This method is used to that I kind of POST request
this method is correct
public void testConverteArquivoJsonEmObjetoJava() {
List<NameValuePair> params = new LinkedList<NameValuePair>();
params.add(new BasicNameValuePair("token","0V1AYFK12SeCZHYgXbNMew==$="));
String paramString = URLEncodedUtils.format(params, "utf-8");
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet get = new HttpGet(
"http://safep.com/crimes/mobilelist" + "?"
+ paramString);
HttpResponse httpResponse;
try {
httpResponse = httpClient.execute(get);
String jsonDeResposta = EntityUtils.toString(httpResponse
.getEntity());
System.out.println();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}`

Related

Odata V4 Client: getEntityCreate method

I developed an ODataClient in Java in order to create new entities. I am encountering difficulties to create new entities. I took the initiative to see all messages sent by my client with Fiddler.
ODataEntityCreateRequest<ClientEntity> request=
client.getCUDRequestFactory()
.getEntityCreateRequest(new URI("http://localhost:8888/"), clientEntity);
request.addCustomHeader("Content-Type", "application/json;odata.metadata=minimal");
request.setAccept("application/json;odata=minimalmetadata");
ODataEntityCreateResponse<ClientEntity> response = request.execute();
below the first line of the body I obtained with Fiddler:
17b
{"#odata.type":"#ODataDemo.Product", ....}
I tested manually with Fiddler to create a new entity and the first line of message body should be:
{"odata.type":"ODataDemo.Product", ....}
I would like to know if it possible to set the body of the request with Odata in order to delete "#" and "#".
Thanks,
I found an alternative solution to this problem. I do not use entirely OData libraries. I created methods to to the post Request.
public void insertData(String entityName, Entity entity)
{
try {
ResWrap<Entity> resW = new ResWrap<Entity>(new URI(this.baseURI.concat("/").concat(entityName)), "full", entity);
ClientEntity clientEntity = this.client.getBinder().getODataEntity(resW);
//String message = getMessageRebuild(client.getWriter().writeEntity(clientEntity, ContentType.APPLICATION_JSON));
InputStream is = client.getWriter().writeEntity(clientEntity, ContentType.APPLICATION_JSON);
if(is != null)
{
System.out.println("POST: "+post(this.baseURI.concat("/").concat(entityName), is));
//System.out.println("POST:"+post("http://localhost:8888/"+entityName, is));
}
} catch (URISyntaxException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (ODataSerializerException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public String post(String url,InputStream message) throws Exception{
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost(url);
//post.addHeader("Content-Type", "application/json;odata.metadata=minimal");
//post.addHeader("Accept", "application/json;odata=verbose");
post.addHeader("Content-Type", "application/json");
post.addHeader("Accept", "application/json");
HttpEntity entity = new ByteArrayEntity(IOUtils.toByteArray(message));
post.setEntity(entity);
HttpResponse response = client.execute(post);
String result = EntityUtils.toString(response.getEntity());
return result;
}
insertData take two parameters : entityName + Entity I generated.
I use the librairie org.apache.http to send the http message to the OData Server.

How to get info from HttpResponse java?

First of all please look at my code below:
List<BasicNameValuePair> qsList = new ArrayList<BasicNameValuePair>();
qsList.add(new BasicNameValuePair("oauth_token", accessToken));
String queryString = URLEncodedUtils.format(qsList, HTTP.UTF_8);
HttpGet userInfoRequest = new HttpGet(id + "?" + queryString);
DefaultHttpClient defaultHttpClientclient = new DefaultHttpClient();
HttpResponse userInfoResponse;
try {
userInfoResponse = defaultHttpClientclient.execute(userInfoRequest);
String responseBody = EntityUtils.toString(userInfoResponse.getEntity());
System.out.println("User info response: " + responseBody);
System.out.println("");
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
I got an access token from Salesforce. Now I request user's information via that token. In the responseBody I got all infomation of that user like username, id, language,... Now I need to take only username from the response. What should I do to take it?
The response is likely in JSON. If so you can parse the data you need. I won't repost the code, instead please see: How to parse JSON in Java
JSONObject responseJSON = new JSONObject(EntityUtils.toString(userInfoResponse.getEntity());
String username = responseJSON.getString("username");

Java HTTP Request Stuck

I've never really used http requests in Java, I'm trying to make a request that would basically recreate this http://supersecretserver.net:8080/http://whateverwebsite.com
This server takes whatever website and returns only the text of the page in the body of the response.
The code is as follows:
public String getText(String webPage) throws ParseException, IOException{
HttpResponse response = null;
try {
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet();
request.setURI(new URI("http://supersecretserver.net:8080/" + "http://www.androidhive.info/2012/01/android-text-to-speech-tutorial/"));
response = client.execute(request);
} catch (URISyntaxException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
String responseBody = "No text found on webpage.";
int responseCode = response.getStatusLine().getStatusCode();
switch(responseCode) {
case 200:
HttpEntity entity = response.getEntity();
if(entity != null) {
responseBody = EntityUtils.toString(entity);
}
}
System.out.println("Returning Response..");
System.out.println(responseBody);
return responseBody;
}
It seems to get stuck on
response = client.execute(request);
I'm not sure what the problems is, any insight would be helpful.
Seems likely that your HttpClient is not timing out, you can set a timeout value by following this example (from http://www.jayway.com/2009/03/17/configuring-timeout-with-apache-httpclient-40/)
You just to have to consider a timeout value that makes sense for you.
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpParams params = httpClient.getParams();
HttpConnectionParams.setConnectionTimeout(httpParams, connectionTimeoutMillis);
HttpConnectionParams.setSoTimeout(httpParams, socketTimeoutMillis);
Also as your HttpClient is not connecting (since it's getting stuck) you should also take into consideration why is that happening (maybe you need to configure a proxy?)

curl equivalent in Java using commons HttpClient

I am using Commons HttpClient to send a post request along with some string content as parameter. Following is my code:
// obtain the default httpclient
client = new DefaultHttpClient();
// obtain a http post request object
postRequest = new HttpPost(stanbolInstance);
postRequest.setHeader("Accept", "application/json");
// create an http param containing summary of article
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
nameValuePairs.add(new BasicNameValuePair("data", content));
try {
// add the param to postRequest
postRequest.setEntity(new UrlEncodedFormEntity(nameValuePairs));
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
try {
// obtain the response
response = client.execute(postRequest);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Here, stanbolInstance is: http://dev.iks-project.eu:8081/enhancer
It does not work. Following is the exception:
Problem accessing /enhancer. Reason:
<pre> The parsed byte array MUST NOT be NULL!</pre></p><h3>Caused by:</h3><pre>java.lang.IllegalArgumentException: The parsed byte array MUST NOT be NULL!
Following is the cURL equivalent which works:
curl -X POST -H "Accept: text/turtle" -H "Content-type: text/plain" --data "The Stanbol enhancer can detect famous cities such as Paris and people such as Bob Marley." http://dev.iks-project.eu:8081/enhancer
Help!
I think you're putting the content in the wrong way.
Replace:
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
nameValuePairs.add(new BasicNameValuePair("data", content));
try {
// add the param to postRequest
postRequest.setEntity(new UrlEncodedFormEntity(nameValuePairs));
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
with
postRequest.setEntity(new StringEntity(content));

POST XML on Android by using HTTP

I am trying to post xml on android. Same xml and server works on iphone perfectly, but on android i am getting invalid xml error message.
public void postData() {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://stage.isadiasjd.com.tr/asdasdad-web/getProductDeviceService.do");
try {
StringEntity se = new StringEntity("<customer><districtId>2541</districtId><barcode>45464654654917</barcode><udid>dade51ce2c127310d1df5ee25e876e46feae470b</udid><email>Xzcxzcxzczxc#zxczxcxczxc.com</email><hashCode>2500a7005c01903093fa268984zczczczaeawdwa2w1d3w6dec9b61afbe28f37baad819ba3e0d</hashCode></customer>", "UTF-8");
// se.setContentType("text/xml");
se.setContentType("application/atom+xml");
httppost.setEntity(se);
HttpResponse httpresponse = httpclient.execute(httppost);
HttpEntity resEntity = httpresponse.getEntity();
String ss = EntityUtils.toString(resEntity);
Log.v("http req", ss);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
Log.v("ex","1");
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
Log.v("ex","2");
e.printStackTrace();
}
}
Try application/json. On Android 2 something wrong with xml responses on some models

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