I've never really used http requests in Java, I'm trying to make a request that would basically recreate this http://supersecretserver.net:8080/http://whateverwebsite.com
This server takes whatever website and returns only the text of the page in the body of the response.
The code is as follows:
public String getText(String webPage) throws ParseException, IOException{
HttpResponse response = null;
try {
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet();
request.setURI(new URI("http://supersecretserver.net:8080/" + "http://www.androidhive.info/2012/01/android-text-to-speech-tutorial/"));
response = client.execute(request);
} catch (URISyntaxException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
String responseBody = "No text found on webpage.";
int responseCode = response.getStatusLine().getStatusCode();
switch(responseCode) {
case 200:
HttpEntity entity = response.getEntity();
if(entity != null) {
responseBody = EntityUtils.toString(entity);
}
}
System.out.println("Returning Response..");
System.out.println(responseBody);
return responseBody;
}
It seems to get stuck on
response = client.execute(request);
I'm not sure what the problems is, any insight would be helpful.
Seems likely that your HttpClient is not timing out, you can set a timeout value by following this example (from http://www.jayway.com/2009/03/17/configuring-timeout-with-apache-httpclient-40/)
You just to have to consider a timeout value that makes sense for you.
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpParams params = httpClient.getParams();
HttpConnectionParams.setConnectionTimeout(httpParams, connectionTimeoutMillis);
HttpConnectionParams.setSoTimeout(httpParams, socketTimeoutMillis);
Also as your HttpClient is not connecting (since it's getting stuck) you should also take into consideration why is that happening (maybe you need to configure a proxy?)
Related
I have a lot of requests. How can I set default headers for all requests? Please, give me examples
Now My code look like this:
HttpPost request = new HttpPost(url);
StringEntity params = null;
try {
params = new StringEntity(o.writeValueAsString(auth));
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
request.addHeader("content-type", "application/json");
request.setEntity(params);
try {
client = HttpClientBuilder.create().build();
HttpResponse response = client.execute(request);
} catch (IOException e) {
e.printStackTrace();
}
So I have many requests like this
Since you're using the HttpClientBuilder, why not try using its setDefaultHeaders() method?
HttpClientBuilder client = HttpClientBuilder.create();
Header header = new BasicHeader(HttpHeaders.CONTENT_TYPE, "application/json");
client.setDefaultHeaders(header);
HttpPost request = new HttpPost(url);
StringEntity params = null;
try {
params = new StringEntity(o.writeValueAsString(auth));
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
request.setEntity(params);
try {
client.build();
HttpResponse response = client.execute(request);
} catch (IOException e) {
e.printStackTrace();
}
Hope that helps!
The most awkward are the try-catches. Best would be to throw them to the caller, and rely on the logging there.
However a single try-catch is possible too. There the style declaration of var + try{ assigning to var } processing var should better be try { declaration + assigning + processing }
Then one already gets shorter, more readable code.
HttpPost request = new HttpPost(url);
request.addHeader("content-type", "application/json");
try {
request.setEntity(new StringEntity(o.writeValueAsString(auth)));
HttpClient client = HttpClientBuilder.create().build();
HttpResponse response = client.execute(request);
} catch (IOException e) {
Logger.log(Level.SEVERE, e);
}
The HttpClient part is still a bit dubious, and could be reduced without declaration.
Alternatives exist like using annotations, Spring and some more declarative techniques. But this is short enough.
I developed an ODataClient in Java in order to create new entities. I am encountering difficulties to create new entities. I took the initiative to see all messages sent by my client with Fiddler.
ODataEntityCreateRequest<ClientEntity> request=
client.getCUDRequestFactory()
.getEntityCreateRequest(new URI("http://localhost:8888/"), clientEntity);
request.addCustomHeader("Content-Type", "application/json;odata.metadata=minimal");
request.setAccept("application/json;odata=minimalmetadata");
ODataEntityCreateResponse<ClientEntity> response = request.execute();
below the first line of the body I obtained with Fiddler:
17b
{"#odata.type":"#ODataDemo.Product", ....}
I tested manually with Fiddler to create a new entity and the first line of message body should be:
{"odata.type":"ODataDemo.Product", ....}
I would like to know if it possible to set the body of the request with Odata in order to delete "#" and "#".
Thanks,
I found an alternative solution to this problem. I do not use entirely OData libraries. I created methods to to the post Request.
public void insertData(String entityName, Entity entity)
{
try {
ResWrap<Entity> resW = new ResWrap<Entity>(new URI(this.baseURI.concat("/").concat(entityName)), "full", entity);
ClientEntity clientEntity = this.client.getBinder().getODataEntity(resW);
//String message = getMessageRebuild(client.getWriter().writeEntity(clientEntity, ContentType.APPLICATION_JSON));
InputStream is = client.getWriter().writeEntity(clientEntity, ContentType.APPLICATION_JSON);
if(is != null)
{
System.out.println("POST: "+post(this.baseURI.concat("/").concat(entityName), is));
//System.out.println("POST:"+post("http://localhost:8888/"+entityName, is));
}
} catch (URISyntaxException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (ODataSerializerException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public String post(String url,InputStream message) throws Exception{
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost(url);
//post.addHeader("Content-Type", "application/json;odata.metadata=minimal");
//post.addHeader("Accept", "application/json;odata=verbose");
post.addHeader("Content-Type", "application/json");
post.addHeader("Accept", "application/json");
HttpEntity entity = new ByteArrayEntity(IOUtils.toByteArray(message));
post.setEntity(entity);
HttpResponse response = client.execute(post);
String result = EntityUtils.toString(response.getEntity());
return result;
}
insertData take two parameters : entityName + Entity I generated.
I use the librairie org.apache.http to send the http message to the OData Server.
public class CacheDemo {
public static void main(String[] args) {
CacheConfig cacheConfig = new CacheConfig();
cacheConfig.setMaxCacheEntries(1000);
cacheConfig.setMaxObjectSizeBytes(1024 * 1024);
HttpClient cachingClient = new CachingHttpClient(new DefaultHttpClient(), cacheConfig);
HttpContext localContext = new BasicHttpContext();
sendRequest(cachingClient, localContext);
CacheResponseStatus responseStatus = (CacheResponseStatus) localContext.getAttribute(
CachingHttpClient.CACHE_RESPONSE_STATUS);
checkResponse(responseStatus);
sendRequest(cachingClient, localContext);
responseStatus = (CacheResponseStatus) localContext.getAttribute(
CachingHttpClient.CACHE_RESPONSE_STATUS);
checkResponse(responseStatus);
}
static void sendRequest(HttpClient cachingClient, HttpContext localContext) {
HttpGet httpget = new HttpGet("http://www.mydomain.com/content/");
HttpResponse response = null;
try {
response = cachingClient.execute(httpget, localContext);
} catch (ClientProtocolException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
HttpEntity entity = response.getEntity();
try {
EntityUtils.consume(entity);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
static void checkResponse(CacheResponseStatus responseStatus) {
switch (responseStatus) {
case CACHE_HIT:
System.out.println("A response was generated from the cache with no requests "
+ "sent upstream");
break;
case CACHE_MODULE_RESPONSE:
System.out.println("The response was generated directly by the caching module");
break;
case CACHE_MISS:
System.out.println("The response came from an upstream server");
break;
case VALIDATED:
System.out.println("The response was generated from the cache after validating "
+ "the entry with the origin server");
break;
}
}
}
It is not worked for me.
Every time it get the data from the server.not from the cache.
I m using jar "httpclient-cache-4.1-beta1".
You haven't showed us what's going on with your HTTP server. Is the service at mydomain.com/content setting the correct Cache-Control headers on the HTTP response? For caching to work, you need to have your HTTP server or web application indicate if the data can be cached and the length that the data can be cached using the appropriate headers.
Also, check the API documented on CachingHttpClient to see what headers it expects from the web server.
I'm trying to perform a GET request to the server that returns me a JSON file. But I am getting an error in the HTTP statusLine / 422. Anyone know why. Below I show how I'm doing
public void testConverteArquivoJsonEmObjetoJava() {
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet get = new HttpGet(
"http://safe-sea-4024.ppooiheroku4554566adffasdfasdfalaqwerpcp.com/crimes/mobilelist");
get.setHeader("Accept", "application/json");
get.setHeader("Content-type", "application/json");
get.getParams()
.setParameter("token",
"0V1AYFK12SeCZHYgXbNMew==$tRqPNplipDwtbD0vxWv6GPJIT6Yk5abwca3IJ88888a6JhMs=");
HttpResponse httpResponse;
try {
httpResponse = httpClient.execute(get);
String jsonDeResposta = EntityUtils.toString(httpResponse
.getEntity());
System.out.println();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
Usually you do not specify a Content-Type header with a GET request. This header tells the server how to interpret the entity includes in the message. It is possible that the server side is expecting a JSON entity even though GET cannot include a body. Try removing the Content-Type header.
I tried the URL that you cleverly changed and got it to work fine. However, I did get a 422 when I specified a different token query parameter. Being that the status line is missing a phrase, I would assume that the Ruby application is generating it.
I managed to solve the problem. I was passing the parameter so wrong. According to this post [blog]:How to add parameters to a HTTP GET request in Android? "link". This method is used to that I kind of POST request
this method is correct
public void testConverteArquivoJsonEmObjetoJava() {
List<NameValuePair> params = new LinkedList<NameValuePair>();
params.add(new BasicNameValuePair("token","0V1AYFK12SeCZHYgXbNMew==$="));
String paramString = URLEncodedUtils.format(params, "utf-8");
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet get = new HttpGet(
"http://safep.com/crimes/mobilelist" + "?"
+ paramString);
HttpResponse httpResponse;
try {
httpResponse = httpClient.execute(get);
String jsonDeResposta = EntityUtils.toString(httpResponse
.getEntity());
System.out.println();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}`
I need a simple code example of sending http post request with post parameters that I get from form inputs.
I have found Apache HTTPClient, it has very reach API and lots of sophisticated examples, but I couldn't find a simple example of sending http post request with input parameters and getting text response.
Update: I'm interested in Apache HTTPClient v.4.x, as 3.x is deprecated.
Here's the sample code for Http POST, using Apache HTTPClient API.
import java.io.InputStream;
import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.methods.PostMethod;
public class PostExample {
public static void main(String[] args){
String url = "http://www.google.com";
InputStream in = null;
try {
HttpClient client = new HttpClient();
PostMethod method = new PostMethod(url);
//Add any parameter if u want to send it with Post req.
method.addParameter("p", "apple");
int statusCode = client.executeMethod(method);
if (statusCode != -1) {
in = method.getResponseBodyAsStream();
}
System.out.println(in);
} catch (Exception e) {
e.printStackTrace();
}
}
}
I pulled this code from an Android project by Andrew Gertig that I have used in my application. It allows you to do an HTTPost. If I had time, I would create an POJO example, but hopefully, you can dissect the code and find what you need.
Arshak
https://github.com/AndrewGertig/RubyDroid/blob/master/src/com/gertig/rubydroid/AddEventView.java
private void postEvents()
{
DefaultHttpClient client = new DefaultHttpClient();
/** FOR LOCAL DEV HttpPost post = new HttpPost("http://192.168.0.186:3000/events"); //works with and without "/create" on the end */
HttpPost post = new HttpPost("http://cold-leaf-59.heroku.com/myevents");
JSONObject holder = new JSONObject();
JSONObject eventObj = new JSONObject();
Double budgetVal = 99.9;
budgetVal = Double.parseDouble(eventBudgetView.getText().toString());
try {
eventObj.put("budget", budgetVal);
eventObj.put("name", eventNameView.getText().toString());
holder.put("myevent", eventObj);
Log.e("Event JSON", "Event JSON = "+ holder.toString());
StringEntity se = new StringEntity(holder.toString());
post.setEntity(se);
post.setHeader("Content-Type","application/json");
} catch (UnsupportedEncodingException e) {
Log.e("Error",""+e);
e.printStackTrace();
} catch (JSONException js) {
js.printStackTrace();
}
HttpResponse response = null;
try {
response = client.execute(post);
} catch (ClientProtocolException e) {
e.printStackTrace();
Log.e("ClientProtocol",""+e);
} catch (IOException e) {
e.printStackTrace();
Log.e("IO",""+e);
}
HttpEntity entity = response.getEntity();
if (entity != null) {
try {
entity.consumeContent();
} catch (IOException e) {
Log.e("IO E",""+e);
e.printStackTrace();
}
}
Toast.makeText(this, "Your post was successfully uploaded", Toast.LENGTH_LONG).show();
}
HTTP POST request example using Apache HttpClient v.4.x
HttpClient httpClient = HttpClients.createDefault();
HttpPost httpPost = new HttpPost(url);
MultipartEntityBuilder builder = MultipartEntityBuilder.create();
builder.addTextBody("param1", param1Value, ContentType.TEXT_PLAIN);
builder.addTextBody("param2", param2Value, ContentType.TEXT_PLAIN);
HttpEntity multipart = builder.build();
httpPost.setEntity(multipart);
HttpResponse response = httpClient.execute(httpMethod);
http://httpunit.sourceforge.net/doc/cookbook.html
use PostMethodWebRequest and setParameter method
shows a very simple exapmle where you do post from Html page, servlet processes it and sends a text response..
http://java.sun.com/developer/onlineTraining/Programming/BasicJava1/servlet.html