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SimpleDateFormat is not able to parse the date with offset value like - 'GMT-0500'

I am trying to parse this (and many similar) dateString - "Wed Aug 26 2020 11:03:30 GMT-0500"
Looking at the SimpleDateFormat documentation, I was assuming that a pattern like this should work:
String dateFormat = "EEE MMM d yyyy HH:mm:ss z";
However, it doesn't. But the following format is able to parse
String dateFormat = "EEE MMM d yyyy HH:mm:ss 'GMT'z";
But when I print the parsed date, I get the time with an hour added and offset reduced by an hour - Wed Aug 26 12:03:30 GMT-04:00 2020
What can I do to prevent this offset change?
Here is the sample code:
String dateStr = "Wed Aug 26 2020 11:03:30 GMT-0500";
String dateFormat = "EEE MMM d yyyy HH:mm:ss 'GMT'z";
Date date = new SimpleDateFormat(dateFormat).parse(dateStr);
System.out.println("Original Date String : "+dateStr);
System.out.println("Original Date Object : "+date);
Output:
Original Date String : Wed Aug 26 2020 11:03:30 GMT-0500
Original Date Object : Wed Aug 26 12:03:30 GMT-04:00 2020

Use java.time.OffsetDateTime here because there is no zone in that String, just an offset and the classes you are using are outdated for good reasons... Get rid of java.util.Date and java.text.SimpleDateFormat.
See this example:
public static void main(String[] args) {
// provide the String to be parsed
String dateStr = "Wed Aug 26 2020 11:03:30 GMT-0500";
// provide a matching pattern
String dateFormat = "EEE MMM d yyyy HH:mm:ss 'GMT'Z";
// create a formatter with this pattern and a suitable locale for unit names
DateTimeFormatter dtf = DateTimeFormatter.ofPattern(dateFormat, Locale.ENGLISH);
// parse the String to an OffsetDateTime using the formatter
OffsetDateTime odt = OffsetDateTime.parse(dateStr, dtf);
// print the result in the default format
System.out.println("Default/ISO format:\t" + odt);
// and print it in your custom format
System.out.println("Custom format:\t\t" + odt.format(dtf));
}
Output:
Default/ISO format: 2020-08-26T11:03:30-05:00
Custom format: Wed Aug 26 2020 11:03:30 GMT-0500

Convert EEE MMM dd HH:mm:ss ZZZ yyyy to YYYY-MM-dd JAVA

I want to convert : Thu Feb 02 00:00:00 WET 2012 to 02/02/2012 (with date type not string) using JAVA.
I did
String date = "Thu Feb 02 00:00:00 WET 2012";
SimpleDateFormat formatnow = new SimpleDateFormat("EEE MMM dd HH:mm:ss ZZZ yyyy", Locale.ENGLISH);
SimpleDateFormat formatneeded=new SimpleDateFormat("YYYY-MM-dd");
Date date1 = formatnow.parse(date);
String date2 = formatneeded.format(date1);
Date date3= formatneeded.parse(date2);
System.out.println(date3);
And I'm having : Thu Feb 02 00:00:00 WET 2012.
Can anyone tell me where is the problem ??

The Date object does not hold any information about the display format you want. So parsing a date from a formatted date string is not going to 'remember' any formatting.
System.out.println(date3) will print value of date3 using java's toString method.
You have the formatted date string in date2. So System.out.println(date2) should give you the right value.

Error by converting date: Unparseable date in JAVA

I can't find the problem. I'm trying to convert the date:
"Thu, 10 Jul 2014 13:33:26 +0200"
from string to Date with this code:
String formatType = "EEE, dd MMM yyyy HH:mm:ss Z";
Date startzeit = new SimpleDateFormat(formatType).parse(einsatz.getString("startzeit"));
but I'm getting this exceptoin:
java.text.ParseException: Unparseable date: "Thu, 10 Jul 2014 13:33:26 +0200"

You're creating a SimpleDateFormat without specifying a locale, so it'll use the default locale. By the looks of your variable names, that may not be English - so it'll have a hard time parsing "Thu" and "Jul".
Try:
String formatType = "EEE, dd MMM yyyy HH:mm:ss Z";
Date startzeit = new SimpleDateFormat(formatType, Locale.US)
.parse(einsatz.getString("startzeit");
(That works for me, with your sample value.)

Date format parse exception - "EEE MMM dd HH:mm:ss Z yyyy" [duplicate]

This question already has answers here:
How to convert date in to yyyy-MM-dd Format?
(6 answers)
How can I convert Date.toString back to Date?
(5 answers)
Java - Unparseable date
(3 answers)
Closed 5 years ago.
I got problem with date parse example date:
SimpleDateFormat parserSDF=new SimpleDateFormat("EEE MMM dd HH:mm:ss zzzz yyyy", Locale.getDefault());
parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
got exception
Exacly I want parse this format date to yyyy-MM-dd
I try:
SimpleDateFormat parserSDF = new SimpleDateFormat("yyyy-MM-dd", Locale.ENGLISH);
Date date = parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
take :
java.text.ParseException: Unparseable date: "Wed Oct 16 00:00:00 CEST 2013"
OK I change to and works :
SimpleDateFormat parserSDF = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzzz yyyy", Locale.ENGLISH);
Date date = parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");

I'm going to assume that Locale.getDefault() for you is pl-PL since you seem to be in Poland.
English words in date strings therefore cause an unparseable date.
An appropriate Polish date String would be something like
"Wt paź 16 00:00:00 -0500 2013"
Otherwise, change your Locale to Locale.ENGLISH so that the SimpleDateFormat object can parse String dates with English words.

Instead of using Locale.default that you and others often don't know which default, you can decide by using locale.ENGLISH because I see your string date is format in English. If you are at other countries, the format will be different.
Here is my example code:
public static void main(String[] args) {
try {
SimpleDateFormat parserSDF = new SimpleDateFormat("EEE MMM dd HH:mm:ss Z yyyy", Locale.ENGLISH);
Date date = parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
System.out.println("date: " + date.toString());
} catch (ParseException ex) {
ex.printStackTrace();
}
}
The result will be : date: Wed Oct 16 05:00:00 ICT 2013. Or you can decide which part of this date to be printed, by using its fields.
Hope this help :)

I think the original Exception is due to Z in your format.
Per documentation:
Z Time zone RFC 822 time zone -0800
most likely you meant to use lower case z

Java new Date with time stamp in date format

I have used the following
SimpleDateFormat df = new SimpleDateFormat("dd-mm-yyyy hh:mm:ss zzz");
Date date = new Date();
String formattedDate= df.format(date);
Date dateWithTime = df.parse(formattedDate);
i got the formatted date as string when i conver this into date i got error like
java.text.ParseException: Unparseable date: "Tue Feb 26 11:45:43 IST 2013"
How would convert to date or how i format a current date and get as date?

I think your code wouldn't throw ParseException. But it sure would definitely yield wrong output. your format should be:
"dd-MM-yyyy hh:mm:ss zzz"
Note that
MM---> Months
mm---> Minutes
Test with your code with out correcting the format:
Sat Jan 26 06:24:07 GMT 2013
Test with your code with correcting the format:
Tue Feb 26 06:20:51 GMT 2013

The date format should be as follows as shown in the exception. Change it to -
EEE MMM d hh:mm:ss z yyyy

The correct simpledateformat will be
SimpleDateFormat df = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");

Please refer the link for proper date formatting and parsing
SimpleDateFormat