I have used the following
SimpleDateFormat df = new SimpleDateFormat("dd-mm-yyyy hh:mm:ss zzz");
Date date = new Date();
String formattedDate= df.format(date);
Date dateWithTime = df.parse(formattedDate);
i got the formatted date as string when i conver this into date i got error like
java.text.ParseException: Unparseable date: "Tue Feb 26 11:45:43 IST 2013"
How would convert to date or how i format a current date and get as date?
I think your code wouldn't throw ParseException. But it sure would definitely yield wrong output. your format should be:
"dd-MM-yyyy hh:mm:ss zzz"
Note that
MM---> Months
mm---> Minutes
Test with your code with out correcting the format:
Sat Jan 26 06:24:07 GMT 2013
Test with your code with correcting the format:
Tue Feb 26 06:20:51 GMT 2013
The date format should be as follows as shown in the exception. Change it to -
EEE MMM d hh:mm:ss z yyyy
The correct simpledateformat will be
SimpleDateFormat df = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
Please refer the link for proper date formatting and parsing
SimpleDateFormat
Related
I've got a problem with the following date format: "Jan 15 2020 11:11:50.000 +0000". I need to parse the date into ms.
The odd behavior is that i can't use date.parse(). The function is always failing with "java.text.ParseException: Unparseable date: "Jan 15 2020 11:11:50.000 +0000";".
Someone got an idea how to manually parse the date or to change the date format within date.parse()?
Thanks all
With a ZonedDateTime and this pattern LLL d yyyy HH:mm:ss.SSS Z (DateTimeFormatter) you'll be able to handle it
String value = "Jan 15 2020 11:11:50.000 +0000";
DateTimeFormatter dt = DateTimeFormatter.ofPattern("LLL d yyyy HH:mm:ss.SSS Z", Locale.ENGLISH);
ZonedDateTime l = ZonedDateTime.parse(value, dt);
System.out.println(l.format(dt)); // Jan 15 2020 11:11:50.000 +0000
This question already has answers here:
Change date format in a Java string
(22 answers)
how to parse output of new Date().toString()
(4 answers)
Closed 3 years ago.
I'm having the date in this pattern EEEEE MMMMM yyyy HH:mm:ss.SSSZ, I would like to convert this to yyyy-MM-dd format in java, I tried below approach but I'm getting this exception java.text.ParseException: Unparseable date:
SimpleDateFormat formatter = new SimpleDateFormat("dd-MMM-yyyy");
String dateInString = "Sun Oct 01 00:00:00 EDT 2017";
try {
Date date = formatter.parse(dateInString);
System.out.println(date);
System.out.println(formatter.format(date));
} catch (ParseException e) {
e.printStackTrace();
}
Can someone please help me to resolve this?
Thanks.
From java-8 you can use the ZonedDateTime with pattern of your input date which is EEE MMM dd HH:mm:ss zzz yyyy
String dateInString = "Sun Oct 01 00:00:00 EDT 2017";
ZonedDateTime time = ZonedDateTime.parse(dateInString,DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss zzz yyyy"));
System.out.println(time.toLocalDate()); //2017-10-01
By default LocalDate is without a time-zone in the ISO-8601 calendar system, such as 2007-12-03.
You've defined your formatter as the concept 'date, month, year', and then you try to ask it to parse a string that isn't in this format at all. You need to make a formatter that can format Sun Oct 01 00:00:00 EDT 2017, and dd-MMM-yyyy obviously isn't it. The javadoc of SimpleDateFormat will tell you what combination of letters you need to use.
Once you've got that, it's easy: parse with this new formatter, then call .format with your old one (the dd-MMM-yyyy one).
You can't use the same formatter for both parsing and formatting. See this answer: https://stackoverflow.com/a/999191
You double-create the DateFormat one parse and once to format
DateFormat dfParse = new SimpleDateFormat("EEEEE MMMMM yyyy HH:mm:ss.SSSZ");
DateFormat dfFormat = new SimpleDateFormat("yyyy-MM-dd");
dfFormat.format(dfParse.parse("Sun Oct 01 00:00:00 EDT 2017"))
I want to convert : Thu Feb 02 00:00:00 WET 2012 to 02/02/2012 (with date type not string) using JAVA.
I did
String date = "Thu Feb 02 00:00:00 WET 2012";
SimpleDateFormat formatnow = new SimpleDateFormat("EEE MMM dd HH:mm:ss ZZZ yyyy", Locale.ENGLISH);
SimpleDateFormat formatneeded=new SimpleDateFormat("YYYY-MM-dd");
Date date1 = formatnow.parse(date);
String date2 = formatneeded.format(date1);
Date date3= formatneeded.parse(date2);
System.out.println(date3);
And I'm having : Thu Feb 02 00:00:00 WET 2012.
Can anyone tell me where is the problem ??
The Date object does not hold any information about the display format you want. So parsing a date from a formatted date string is not going to 'remember' any formatting.
System.out.println(date3) will print value of date3 using java's toString method.
You have the formatted date string in date2. So System.out.println(date2) should give you the right value.
I want to convert a string to date before storing it and I used
SimpleDateFormat format = new SimpleDateFormat("yyyy-mm-dd");
Date returnDate = format.parse(date);
When I ran this with sample date:
the input string for date conversion is 2014-05-06
the parsed date is Mon Jan 06 00:05:00 IST 2014
now when I store the returnDate in MySql the value is 2014-01-06 00:05:00
Why is the date changed ? Want to know if I am missing something. I went through the posts related to date string conversion : How to convert a date from a Datepicker to Mysql DATETIME format using java?
In your DateFormat use MM for month instead of mm, that is for minutes
Reference: http://docs.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html
You can use like this :
Date mDate= new Date(System.currentTimeMillis());
SimpleDateFormat mDateFormat= new SimpleDateFormat("dd MMM yyyy HH:mm a");
String dateformat=mDateFormat.format(mDate);
the string ["dd MMM yyyy HH:mm a"] can be changed according to need of formate.
Like in your case : "yyyy-mm-dd
This question already has answers here:
How to convert date in to yyyy-MM-dd Format?
(6 answers)
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Java - Unparseable date
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Closed 5 years ago.
I got problem with date parse example date:
SimpleDateFormat parserSDF=new SimpleDateFormat("EEE MMM dd HH:mm:ss zzzz yyyy", Locale.getDefault());
parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
got exception
Exacly I want parse this format date to yyyy-MM-dd
I try:
SimpleDateFormat parserSDF = new SimpleDateFormat("yyyy-MM-dd", Locale.ENGLISH);
Date date = parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
take :
java.text.ParseException: Unparseable date: "Wed Oct 16 00:00:00 CEST 2013"
OK I change to and works :
SimpleDateFormat parserSDF = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzzz yyyy", Locale.ENGLISH);
Date date = parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
I'm going to assume that Locale.getDefault() for you is pl-PL since you seem to be in Poland.
English words in date strings therefore cause an unparseable date.
An appropriate Polish date String would be something like
"Wt paź 16 00:00:00 -0500 2013"
Otherwise, change your Locale to Locale.ENGLISH so that the SimpleDateFormat object can parse String dates with English words.
Instead of using Locale.default that you and others often don't know which default, you can decide by using locale.ENGLISH because I see your string date is format in English. If you are at other countries, the format will be different.
Here is my example code:
public static void main(String[] args) {
try {
SimpleDateFormat parserSDF = new SimpleDateFormat("EEE MMM dd HH:mm:ss Z yyyy", Locale.ENGLISH);
Date date = parserSDF.parse("Wed Oct 16 00:00:00 CEST 2013");
System.out.println("date: " + date.toString());
} catch (ParseException ex) {
ex.printStackTrace();
}
}
The result will be : date: Wed Oct 16 05:00:00 ICT 2013. Or you can decide which part of this date to be printed, by using its fields.
Hope this help :)
I think the original Exception is due to Z in your format.
Per documentation:
Z Time zone RFC 822 time zone -0800
most likely you meant to use lower case z