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insert json data into postgres database using java program

I'm looking for help to insert json data into postgres table using java program. I have tried with following code but cannot find any data is inserted in to the table. I have very little experience in programming. Can some one help me to modify my program to make it work?
here is my code.
enter code here stmt = c.createStatement();
String sql = "CREATE TABLE jason " +
"(ID INT NOT NULL," +
" NAME json NOT NULL)";
stmt.executeUpdate(sql); //updates the table
//json data----------------
String[] MESSAGE = {"{\"customer_name\": \"John\", \"items\": { \"description\": \"milk\", \"quantity\": 4 } }"};
sql = "INSERT INTO jason (ID,NAME) "
+ "VALUES (1,::MESSAGE );";
stmt.executeUpdate(sql);

You have problem with syntax here, please read this instruction: https://docs.oracle.com/javase/7/docs/api/java/sql/PreparedStatement.html
It's should be:
PreparedStatement pstmt = con.prepareStatement("INSERT INTO jason (ID,NAME) VALUES (1, ?1);");
pstmt.setString(1, yourJsonString)

To use parameters in a statement, you need to use a prepared statement:
java.sql.PreparedStatement stmt = conn.prepareStatement("INSERT INTO jason (ID,NAME) VALUES (1,?)" );
stmt.setString(1, "{\"customer_name\": \"John\", \"items\": { \"description\": \"milk\", \"quantity\": 4 } }");
stmt.executeUpdate();

Can't find an Error in SQL update statement

I'm working in one quiz game. There is question maker window. Which works good for saving question. But when want update one of text Field and press save, than error is happening. something is wrong with syntax?!
void insertCell(String tableNamer, String column, String value, int id) throws ClassNotFoundException, SQLException{
Class.forName("org.h2.Driver");
Connection conn = DriverManager.getConnection("jdbc:h2:file:C:/Users/Juris Puneiko/IdeaProjects/for_my_testings/src/sample/DB/Questions/For_Private/Easy", "Juris", "1");
PreparedStatement ps = conn.prepareStatement("UPDATE ? SET ? = ? where ID = ?");
ps.setString(1, tableNamer);
ps.setString(2, column);
ps.setString(3, value);
ps.setInt(4, id);
ps.executeUpdate();
ps.close();
conn.close();
}
org.h2.jdbc.JdbcSQLException: Syntax error in SQL statement "UPDATE ?[*] SET ? = ? WHERE ID = ? "; expected "identifier"; SQL statement:
UPDATE ? SET ? = ? where ID = ? [42001-196]
What is this >>> [*]?
What does it mean?

String sql = "UPDATE " + tableNamer + " SET " + column + " = ? where ID = ?";
PreparedStatement ps = conn.prepareStatement(sql);
ps.setString(1, value);
ps.setInt(2, id);
ps.executeUpdate();
ps.close();
conn.close();

The placeholders can only be used for values in most SQL databases, not for identifiers like table or column names:
"UPDATE myTable SET myCol = ? where ID = ?" -- OK
"UPDATE ? SET ? = ? where ID = ?" -- not OK
The reason is that those parameters are also used for prepared statements, where you send the query to the database once, the database "prepares" the statement, and then you can use this prepared statement many times with different value parameters. this can improve DB performance because DB can compile and optimize the query and then use this processed form repeatedly - but to be able to do this, it needs to know names of the tables and columns involved.
To fix this, you only leave the ?s in for the values, and you concatenate the tableNamer and column manually:
"UPDATE " + tableNamer + " SET " + column + " = ? where ID = ?"
Keep in mind though that by doing this, tableNamer and column are now potentially vulnerable to SQL injection. Make sure that you don't allow user to provide or affect them, or else sanitize the user input.

Insert int value of Resultset in SQL-Database

I'm working with a MySQL-Server and I'm trying to select an ID from another table and insert that ID in a table but it doesn't work all the time.
Code:
public void submit() throws Exception {
Connection connection = getConnection();
Statement stmt = connection.createStatement();
Statement stmt1 = connection.createStatement();
ResultSet asset_id = stmt.executeQuery("SELECT id FROM cars.asset_type WHERE asset_type.name =" + "'" + sellables.getValue()+ "'");
while (asset_id.next()) {
System.out.println(asset_id.getInt("id"));
}
double value = parseDouble(purchased.getText());
System.out.println(value);
LocalDate localDate = purchased_at.getValue();
String insert = "INSERT INTO asset (type_id, purchase_price, purchased_at) VALUES ('"+ asset_id + "','" + value +"','" + localDate +"')";
stmt1.executeUpdate(insert);
}
I keep getting the same error message.
Caused by: java.sql.SQLException: Incorrect integer value: 'com.mysql.cj.jdbc.result.ResultSetImpl#1779d92' for column 'type_id' at row 1

There's no value in doing two client/server roundtrips in your case, so use a single statement instead:
INSERT INTO asset (type_id, purchase_price, purchased_at)
SELECT id, ?, ?
FROM cars.asset_type
WHERE asset_type.name = ?
If you really want to insert only the last ID from your SELECT query (as you were iterating the SELECT result and throwing away all the other IDs), then use this query instead:
INSERT INTO asset (type_id, purchase_price, purchased_at)
SELECT id, ?, ?
FROM cars.asset_type
WHERE asset_type.name = ?
ORDER BY id DESC -- I guess? Specify your preferred ordering here
LIMIT 1
Or with the JDBC code around it:
try (PreparedStatement s = connection.prepareStatement(
"INSERT INTO asset (type_id, purchase_price, purchased_at) " +
"SELECT id, ?, ? " +
"FROM cars.asset_type " +
"WHERE asset_type.name = ?")) {
s.setDouble(1, parseDouble(purchased.getText()));
s.setDate(2, Date.valueOf(purchased_at.getValue()));
s.setString(3, sellables.getValue());
}
This is using a PreparedStatement, which will prevent SQL injection and syntax errors like the one you're getting. At this point, I really really recommend you read about these topics!

How to insert and select from mysql simultaneously

I have a requirement where I need to insert mobile number in mysql if and only if the number is is not present.So for this I am first checking if a number is present in mysql using select query .If number is not present then insert.Following is my code
PreparedStatement pt1=con.prepareStatement("select * from registerSmsUsers where mobile='"+mobile+"'");
PreparedStatement pt=con.prepareStatement("insert into registerSmsUsers values(?,?,?)");
pt.setString(1, name);
pt.setString(2, email);
pt.setString(3, mobile);
ResultSet rs1=pt1.executeQuery();
if(rs1.next())
{pt.executeUpdate();}
i dont know whether this is a efficient way or not.Please suggest me a better way then this

Probably the easiest way in mysql is:
insert ignore into registerSmsUsers values(?,?,?)
When assuming you have unique key on mobile
You may check it here: How to 'insert if not exists' in MySQL?
Or here: http://dev.mysql.com/doc/refman/5.6/en/insert.html

Many of the proposed solutions (including yours) have a race condition that can cause a primary key or unique constraint violation. You code also have a possible SQL injection attack by concatenating SQL rather than using prepared statement parameters. Use SELECT...FOR UPDATE.
PreparedStatement ps = con.prepareStatement("SELECT name, email, mobile FROM registerSmsUsers WHERE mobile=? FOR UPDATE",
ResultSet.TYPE_FORWARD_ONLY,
ResultSet.CONCUR_UPDATABLE);
ps.setString(1, mobile);
ResultSet rs = ps.executeQuery();
if (rs.next()) { // it exists already
rs.moveToCurrentRow();
rs.updateString(3, mobile);
rs.updateRow();
} else { // it does NOT exist
rs.moveToInsertRow();
rs.updateString(1, name);
rs.updateString(2, email);
rs.updateString(3, mobile);
rs.insertRow();
}
rs.close();
ps.close();
EDIT: Just make sure you have an index on registerSmsUsers.
CREATE INDEX registerSmsUsers_mobile_ndx ON registerSmsUsers(mobile)
or a unique contraint (which implicitly creates an index):
ALTER TABLE registerSmsUsers ADD CONSTRAINT registerSmsUsers_mobile_unq UNIQUE (mobile)
With an index, even with millions of records the update/insert will basically be instant.
EDIT2: Added cursor/result set options.

I think it would be better to create a stored procedure and then in that stored procedure you can first use the IF NOT EXISTS clause to check if the user exists using the select statement. If the user is not present you can insert the user in database.
Something like this:
IF NOT EXISTS(SELECT 1 FROM `registerSmsUsers` WHERE mobile= #mobile) THEN
BEGIN
INSERT INTO
`registerSmsUsers`
(
//column names
)
VALUES
(
//values
);
END;
END IF;
Also there is a INSERT IGNORE statement which you can use like this:
insert ignore into registerSmsUsers values(?,?,?)

if not exists(select * from registerSmsUsers where mobile='232323') <-- will check your mobile no
begin
insert into registerSmsUsers values(?,?,?)
end
This one is also an efficient way to check your method is also working fine but this also can be done
See difference is you will have only one query here
i hope this will help you thanks
[Edit]
Your questions answer
Ya there is a execution time diff between yours and mine query its depends upon a database size what you are using if you are using small size database (probably 1000 people) then you will not see any diff between your query and mine query but if your are using lakhs of users then your will have a performace issues check include execution plan in mysql you will get realtime difference between two

As requested, here is my tweaked version of brettw's answer:
import java.sql.*;
public class MySQLtest {
public static void main(String[] args) {
Connection con;
try {
con = DriverManager.getConnection(
"jdbc:mysql://192.168.1.3/zzzTest?" +
"useUnicode=yes&characterEncoding=UTF-8" +
"&user=root&password=whatever");
String newName = "Gord";
String newEmail = "gord#example.com";
String newMobile = "416-555-1212";
String sql =
"SELECT " +
"id, " +
"name, " +
"email, " +
"mobile " +
"FROM registerSmsUsers " +
"WHERE mobile = ? " +
"FOR UPDATE";
PreparedStatement pst = con.prepareStatement(
sql,
ResultSet.TYPE_FORWARD_ONLY,
ResultSet.CONCUR_UPDATABLE);
pst.setString(1, newMobile);
ResultSet rs = pst.executeQuery();
if (rs.next()) {
rs.moveToCurrentRow();
rs.updateString("name", newName);
rs.updateString("email", newEmail);
rs.updateRow();
System.out.println("Existing row updated.");
}
else {
rs.moveToInsertRow();
rs.updateString("name", newName);
rs.updateString("email", newEmail);
rs.updateString("mobile", newMobile);
rs.insertRow();
System.out.println("New row inserted.");
}
} catch (SQLException ex) {
ex.printStackTrace();
}
}
}
Note that id is the Primary Key for the table: int(11) NOT NULL AUTO_INCREMENT

Inserting values in specific row sql java

"SELECT * FROM PlayerClass WHERE Username = '" + p.getName() + "'"
So I have selected the specific row and how would I go about inserting a value in column ExColumn in the same exact row?

If you're allowed to use JDBC and PreparedStatement, I would suggest you do this:
String sql = "UPDATE PlayerClass SET ExColumn = ? WHERE Username = ?";
PreparedStatement ps = connection.prepareStatement(sql);
ps.setObject(1, exColumnValue); // exColumnValue is the data you're trying to insert
ps.setString(2, p.getName());
ps.executeUpdate();
This way you'll be avoiding SQL injection attacks.

You have to use UPDATE
"Update PlayerClass set Username = '" +someValue + "'"
That will update all rows
To update secific rows with some condition ,add where clause.
"Update PlayerClass set Username = '" +someValue + "'
WHERE Username = '" + p.getName() + "'"

May be your are trying to update specific row. then this will help you
UPDATE PlayerClass SET ExColumn='YOUR_INSERTION_DATA_IN_THIS'
WHERE Username = 'XYZ'