I'm working in one quiz game. There is question maker window. Which works good for saving question. But when want update one of text Field and press save, than error is happening. something is wrong with syntax?!
void insertCell(String tableNamer, String column, String value, int id) throws ClassNotFoundException, SQLException{
Class.forName("org.h2.Driver");
Connection conn = DriverManager.getConnection("jdbc:h2:file:C:/Users/Juris Puneiko/IdeaProjects/for_my_testings/src/sample/DB/Questions/For_Private/Easy", "Juris", "1");
PreparedStatement ps = conn.prepareStatement("UPDATE ? SET ? = ? where ID = ?");
ps.setString(1, tableNamer);
ps.setString(2, column);
ps.setString(3, value);
ps.setInt(4, id);
ps.executeUpdate();
ps.close();
conn.close();
}
org.h2.jdbc.JdbcSQLException: Syntax error in SQL statement "UPDATE ?[*] SET ? = ? WHERE ID = ? "; expected "identifier"; SQL statement:
UPDATE ? SET ? = ? where ID = ? [42001-196]
What is this >>> [*]?
What does it mean?
String sql = "UPDATE " + tableNamer + " SET " + column + " = ? where ID = ?";
PreparedStatement ps = conn.prepareStatement(sql);
ps.setString(1, value);
ps.setInt(2, id);
ps.executeUpdate();
ps.close();
conn.close();
The placeholders can only be used for values in most SQL databases, not for identifiers like table or column names:
"UPDATE myTable SET myCol = ? where ID = ?" -- OK
"UPDATE ? SET ? = ? where ID = ?" -- not OK
The reason is that those parameters are also used for prepared statements, where you send the query to the database once, the database "prepares" the statement, and then you can use this prepared statement many times with different value parameters. this can improve DB performance because DB can compile and optimize the query and then use this processed form repeatedly - but to be able to do this, it needs to know names of the tables and columns involved.
To fix this, you only leave the ?s in for the values, and you concatenate the tableNamer and column manually:
"UPDATE " + tableNamer + " SET " + column + " = ? where ID = ?"
Keep in mind though that by doing this, tableNamer and column are now potentially vulnerable to SQL injection. Make sure that you don't allow user to provide or affect them, or else sanitize the user input.
Related
I'm working with a MySQL-Server and I'm trying to select an ID from another table and insert that ID in a table but it doesn't work all the time.
Code:
public void submit() throws Exception {
Connection connection = getConnection();
Statement stmt = connection.createStatement();
Statement stmt1 = connection.createStatement();
ResultSet asset_id = stmt.executeQuery("SELECT id FROM cars.asset_type WHERE asset_type.name =" + "'" + sellables.getValue()+ "'");
while (asset_id.next()) {
System.out.println(asset_id.getInt("id"));
}
double value = parseDouble(purchased.getText());
System.out.println(value);
LocalDate localDate = purchased_at.getValue();
String insert = "INSERT INTO asset (type_id, purchase_price, purchased_at) VALUES ('"+ asset_id + "','" + value +"','" + localDate +"')";
stmt1.executeUpdate(insert);
}
I keep getting the same error message.
Caused by: java.sql.SQLException: Incorrect integer value: 'com.mysql.cj.jdbc.result.ResultSetImpl#1779d92' for column 'type_id' at row 1
There's no value in doing two client/server roundtrips in your case, so use a single statement instead:
INSERT INTO asset (type_id, purchase_price, purchased_at)
SELECT id, ?, ?
FROM cars.asset_type
WHERE asset_type.name = ?
If you really want to insert only the last ID from your SELECT query (as you were iterating the SELECT result and throwing away all the other IDs), then use this query instead:
INSERT INTO asset (type_id, purchase_price, purchased_at)
SELECT id, ?, ?
FROM cars.asset_type
WHERE asset_type.name = ?
ORDER BY id DESC -- I guess? Specify your preferred ordering here
LIMIT 1
Or with the JDBC code around it:
try (PreparedStatement s = connection.prepareStatement(
"INSERT INTO asset (type_id, purchase_price, purchased_at) " +
"SELECT id, ?, ? " +
"FROM cars.asset_type " +
"WHERE asset_type.name = ?")) {
s.setDouble(1, parseDouble(purchased.getText()));
s.setDate(2, Date.valueOf(purchased_at.getValue()));
s.setString(3, sellables.getValue());
}
This is using a PreparedStatement, which will prevent SQL injection and syntax errors like the one you're getting. At this point, I really really recommend you read about these topics!
I would like to leverage a prepared statement in order to insert/update postgres db.
The thing is that the table contains nullable columns I might or might not have a value for in runtime.
In case I do not have anything to insert/update , I need the old value to remain.
Is there a syntax I can use for that case?
What are the best practices in cases like that, it seems like a very common problem?
P.S
I use java/scala with plain jdbc.
You could, of course, just construct a statement without the columns you don't want to update.
If this isn't an option in your usecase, you could construct a case expression with a "flag" to indicate if the column should be bound or not.
E.g.:
String sql = "UPDATE mytable " +
"SET " +
"col1 = CASE(? WHEN 1 THEN ? ELSE col1 END), " +
"col2 = CASE(? WHEN 1 THEN ? ELSE col2 END) " +
"WHERE id = ?";
PreparedStatement ps = con.prepareStatement(sql);
// col1 should be updated
ps.setInt(1, 1);
ps.setString(2, newValueCol1);
// col2 should not be updated
ps.setInt(3, 0);
ps.setString(4, null); // or any other value...
// bind the where clause
ps.setInt(5, someId);
ps.executeUpdate();
// close resources and clean up, omitted for brevity's sake
When I view the database and run this query I get results as expected.
SELECT * FROM users WHERE options LIKE '%[-15,-3]%';
However when I use a prepared statement as seen below, the uuid is null.
String opt = "[-15,-3]"; //example
PreparedStatement ps = SQLite.connection.prepareStatement(
"SELECT * FROM users WHERE options LIKE '%" + opt + "%'"
);
ResultSet rs = ps.executeQuery();
String uuid = null;
while (rs.next()){
uuid = rs.getString("member");
}
rs.close();
ps.close();
if(uuid != null){
System.out.println("not null: " + uuid);
return Database.getUser(UUID.fromString(uuid);
}
For the code above, nothing is returned in the result set. Which is very strange because I used the same query with an SQLite viewer and it returned the proper rows. How can I solve this? I don't see an issue.
UPDATE
When I directly use "SELECT * FROM factions WHERE claims LIKE '%[-15,-3]%'" in the prepared statement instead of the variable, it works fine. Why can't I use a string variable? I've checked the variable and it prints to console fine.
I solved it after a lot of trial and error, turns out I should've been using a ? and set the string.
PreparedStatement ps = SQLite.connection.prepareStatement(
"SELECT * FROM users WHERE options LIKE ?"
);
ps.setString(1, "%" + opt + "%");
Im trying to add the number 1 to a certain field. How could i manage to do that? Ive tried it but i can never get it to add 1. My ms access table column is set to Number not text.
if (s2.equals(box1Text)) {
if (s3.equals(box2Text)) {
if (s5.equals(currentWinner)) {
String sql = "UPDATE Table2 "+ "SET Score = ? " + "WHERE Better = '" + s1+"'";
PreparedStatement stmt = con.prepareStatement(sql);
//points made here
if (s4.equals(betScore)) {
stmt.setString(1, "+1");//how could i add 1 to the field?
stmt.executeUpdate();
} else {
}
First you do something that is regarded as bad practice : you construct your query by adding the value of a parameter in the string.
String sql = "UPDATE... >+ s1 +<..."
Please nether do that (what is between > and <) when programming seriouly, but allways use ? to pass values.
Second, SQL can do the job for you :
String sql = "UPDATE Table2 SET Score = Score + 1 WHERE Better = ?";
PreparedStatement stmt = con.prepareStatement(sql);
stmt.setString(1, s1);
stmt.executeUpdate();
(try, catch, tests and other details omitted for brevity)
I have a requirement where I need to insert mobile number in mysql if and only if the number is is not present.So for this I am first checking if a number is present in mysql using select query .If number is not present then insert.Following is my code
PreparedStatement pt1=con.prepareStatement("select * from registerSmsUsers where mobile='"+mobile+"'");
PreparedStatement pt=con.prepareStatement("insert into registerSmsUsers values(?,?,?)");
pt.setString(1, name);
pt.setString(2, email);
pt.setString(3, mobile);
ResultSet rs1=pt1.executeQuery();
if(rs1.next())
{pt.executeUpdate();}
i dont know whether this is a efficient way or not.Please suggest me a better way then this
Probably the easiest way in mysql is:
insert ignore into registerSmsUsers values(?,?,?)
When assuming you have unique key on mobile
You may check it here: How to 'insert if not exists' in MySQL?
Or here: http://dev.mysql.com/doc/refman/5.6/en/insert.html
Many of the proposed solutions (including yours) have a race condition that can cause a primary key or unique constraint violation. You code also have a possible SQL injection attack by concatenating SQL rather than using prepared statement parameters. Use SELECT...FOR UPDATE.
PreparedStatement ps = con.prepareStatement("SELECT name, email, mobile FROM registerSmsUsers WHERE mobile=? FOR UPDATE",
ResultSet.TYPE_FORWARD_ONLY,
ResultSet.CONCUR_UPDATABLE);
ps.setString(1, mobile);
ResultSet rs = ps.executeQuery();
if (rs.next()) { // it exists already
rs.moveToCurrentRow();
rs.updateString(3, mobile);
rs.updateRow();
} else { // it does NOT exist
rs.moveToInsertRow();
rs.updateString(1, name);
rs.updateString(2, email);
rs.updateString(3, mobile);
rs.insertRow();
}
rs.close();
ps.close();
EDIT: Just make sure you have an index on registerSmsUsers.
CREATE INDEX registerSmsUsers_mobile_ndx ON registerSmsUsers(mobile)
or a unique contraint (which implicitly creates an index):
ALTER TABLE registerSmsUsers ADD CONSTRAINT registerSmsUsers_mobile_unq UNIQUE (mobile)
With an index, even with millions of records the update/insert will basically be instant.
EDIT2: Added cursor/result set options.
I think it would be better to create a stored procedure and then in that stored procedure you can first use the IF NOT EXISTS clause to check if the user exists using the select statement. If the user is not present you can insert the user in database.
Something like this:
IF NOT EXISTS(SELECT 1 FROM `registerSmsUsers` WHERE mobile= #mobile) THEN
BEGIN
INSERT INTO
`registerSmsUsers`
(
//column names
)
VALUES
(
//values
);
END;
END IF;
Also there is a INSERT IGNORE statement which you can use like this:
insert ignore into registerSmsUsers values(?,?,?)
if not exists(select * from registerSmsUsers where mobile='232323') <-- will check your mobile no
begin
insert into registerSmsUsers values(?,?,?)
end
This one is also an efficient way to check your method is also working fine but this also can be done
See difference is you will have only one query here
i hope this will help you thanks
[Edit]
Your questions answer
Ya there is a execution time diff between yours and mine query its depends upon a database size what you are using if you are using small size database (probably 1000 people) then you will not see any diff between your query and mine query but if your are using lakhs of users then your will have a performace issues check include execution plan in mysql you will get realtime difference between two
As requested, here is my tweaked version of brettw's answer:
import java.sql.*;
public class MySQLtest {
public static void main(String[] args) {
Connection con;
try {
con = DriverManager.getConnection(
"jdbc:mysql://192.168.1.3/zzzTest?" +
"useUnicode=yes&characterEncoding=UTF-8" +
"&user=root&password=whatever");
String newName = "Gord";
String newEmail = "gord#example.com";
String newMobile = "416-555-1212";
String sql =
"SELECT " +
"id, " +
"name, " +
"email, " +
"mobile " +
"FROM registerSmsUsers " +
"WHERE mobile = ? " +
"FOR UPDATE";
PreparedStatement pst = con.prepareStatement(
sql,
ResultSet.TYPE_FORWARD_ONLY,
ResultSet.CONCUR_UPDATABLE);
pst.setString(1, newMobile);
ResultSet rs = pst.executeQuery();
if (rs.next()) {
rs.moveToCurrentRow();
rs.updateString("name", newName);
rs.updateString("email", newEmail);
rs.updateRow();
System.out.println("Existing row updated.");
}
else {
rs.moveToInsertRow();
rs.updateString("name", newName);
rs.updateString("email", newEmail);
rs.updateString("mobile", newMobile);
rs.insertRow();
System.out.println("New row inserted.");
}
} catch (SQLException ex) {
ex.printStackTrace();
}
}
}
Note that id is the Primary Key for the table: int(11) NOT NULL AUTO_INCREMENT