I can't for the life of my wrap my head around this seemingly easy problem.
I am trying to create a sine wave with upper and lower bounds for the amplitude (ie. highest point is 3 and lowest point is 0.4)
Using regular math I am able to get a sine wave in an array from 1 to -1 but I don't know how to change those bounds.
static int MAX_POINTS = 100;
static int CYCLES = 1;
static double[] list = new double[100];
public static void SineCurve()
{
double phaseMultiplier = 2 * Math.PI * CYCLES / MAX_POINTS;
for (int i = 0; i < MAX_POINTS; i++)
{
double cycleX = i * phaseMultiplier;
double sineResult = Math.sin(cycleX);
list[i]= sineResult;
}
for(int i=0;i<list.length;i++){
System.out.println(list[i]);
}
}
Any tips would be greatly appreciated.
The amplitude (multiplier of sin(x) value) is half the difference between the highest and lowest values you want. In your case
amplitude = (3 - 0.4)/2
which is 1.3. Then zero offset is the lowest value plus the amplitude, which makes it 1.7 in your case.
The equation you want to graph is then
1.3 * sin(x) + 1.7
Related
I got my wave file creator working and I split it into three classes, I also made a sinewave generator that inherits from an abstract class called waveform and I can export 8 and 16 bit mono or sterio sine waves. I am trying to make a class called TriangleWave Generator to output a triangle wave tone, but I can't get the algebra from https://en.wikipedia.org/wiki/Triangle_wave#, the first formula, to work. It will only export the highest harmonic stated and not blend them together with the fundamental
Sample length: length in seconds
point: individual sample
amp limit: the highest position possible
harmonics: the number of harmonics to use to make the waveform 1 = fundamental, 2 = 1st overtone, 3 = 2nd overtone.......
frequency: fundamental frequency (Middle C = 261.63)
sample rate = 44100; (CD quality)
triangle Samples array: sample data
This is my code
public class TriangleGenerator extends Waveform {
// constants
public static final int HARMONIC_COUNT = 16;
// instance variabls
int harmonics;
int[] triangleSample;
int addCount;
// constructor
public TriangleGenerator(double amplitude, double frequency, int bitRate, double duration, int harmonics) {
super(amplitude, frequency, bitRate, duration);
// sample data
triangleSample = new int[sampleLength];
calculateAmpLimit();
this.harmonics = harmonics;
}
// one arg cunstructor
public TriangleGenerator(double frequency) {
this(AMPLITUDE, frequency, BIT_RATE, DURATION, HARMONIC_COUNT);
}
// no args constructor
public TriangleGenerator() {
this(AMPLITUDE, FREQUENCY, BIT_RATE, DURATION, HARMONIC_COUNT);
}
#Override
public int[] generateWaveForm() {
// generate the actual waveform
for (int i = 0; i < sampleLength; i++) {
point = (int)(ampLimit * ((8 / Math.pow(Math.PI, 2)) * sumnate(harmonics - 1, Math.pow(-1, addCount))
* Math.pow(harmonics, -2) * Math.sin(2 * Math.PI * frequency * harmonics * i / SAMPLE_RATE)));
triangleSample[i] = point;
}
// return the sample data
return triangleSample;
}
public double sumnate(int n, double adder) {
double sum = 0;
for (addCount = 0; addCount <= n; addCount++) {
sum += adder;
}
return sum;
}
}
In the formula for the triangle wave:
the mode number n is dependent on the harmonic label i:
This means that it must also be summed over the components
which doesn't happen in the current implementation. One possible implementation is:
public int[] generateWaveForm() {
for (int t = 0; t < sampleLength; t++) {
triangleSample[t] = (int)(ampLimit * 8.0 / Math.pow(Math.PI, 2.0) * getDataPoint(t, N));
}
return triangleSample;
}
private double getDataPoint(int t, int N) {
double sum = 0;
for (int i = 0; i <= N - 1; i++) {
sum += getHarmonicShare(t, i);
}
return sum;
}
private double getHarmonicShare(int t, int i) {
double n = 2.0 * i + 1.0;
return Math.pow(-1.0, i) * Math.pow(n, -2.0) * Math.sin(2.0 * Math.PI * frequency * (t / SAMPLE_RATE) * n);
}
Here t, i, n and N correspond to the values from the formula. frequency denotes the frequency. The remaining values correspond to the parameters of the posted code.
The curve reaches up to the value sampleLength / SAMPLE_RATE. The period is 1 / frequency and there are (sampleLength / SAMPLE_RATE) * frequency periods in the displayed frame.
Example:
sampleLength: 500
ampLimit: 100.00
SAMPLE_RATE: 44100.00
frequency: 261.63
sampleLength / SAMPLE_RATE: 0.0113378685
1 / frequency: 0.0038221916
(sampleLength / SAMPLE_RATE) * frequency: 2.9663265306
In the following the corresponding curve is shown for different N using JFreeChart:
Is there a reason you want to use sin to do this rather than produce the straight lines directly by a linear formula? There is an advantage in using sin in that you don't get harmonic distortion from aliasing, but if that's an issue then you can oversample. The issue is that sin is much slower than basic arithmetic.
I make a simple sound equalizer that operates in frequency domain and lets user to adjust frequencies in sound by using 4 sliders. The first one responsible for 0 - 5kHz, the fourth one for 15-20kHz.
Steps are as follows:
I read wav file and store it in float array
I perform complex fft on that array (separately for left and right channel)
I multiply real and imaginary parts of bins representing 0-5kHz frequencies (both positive and negative) by 1.1 3.981 to increase these low frequencies by 10% 12dB in the final sound.
I perform ifft on array
I alternate real parts of left and right channels (returned by ifft) to create the final audio
The problem is that after this process the sound is distorted. It sounds like the speakers were not plugged in correctly. I found that if I divide values returned by ifft by arbitrary constant then the final sound is right, but is much quieter. I make the division in time domain, on the results from ifft.
The problem doesn't occur if I multiply frequencies by a number less than 1. So if frequencies are attenuated no further division in time domain is needed.
I suppose there is a mistake in the whole process. But if all steps are fine, how should I deal with distorted sound? Is dividing in time domain a proper solution? What number should I use to divide the results then so the sound is not distorted?
EDIT
This is the code I use to perform presented steps. I use Apache Commons math implementation of FFT and SimpleAudioConversion class taken from there http://stackoverflow.com/a/26824664/2891664
// read file and store playable content in byte array
File file = new File("/home/kamil/Downloads/Glory.wav");
AudioInputStream in = AudioSystem.getAudioInputStream(file);
AudioFormat fmt = in.getFormat();
byte[] bytes = new byte[in.available()];
int result = in.read(bytes);
// convert bytes to float array
float[] samples = new float[bytes.length * 8 / fmt.getSampleSizeInBits()];
int validSamples = SimpleAudioConversion.decode(bytes, samples, result, fmt);
// find nearest power of 2 to zero-pad array in order to use fft
int power = 0;
while (Math.pow(2, power) < samples.length / 2)
power++;
// divide data into left and right channels
double[][] left = new double[2][(int) Math.pow(2, power)];
double[][] right = new double[2][(int) Math.pow(2, power)];
for (int i = 0; i < samples.length / 2; i++) {
left[0][i] = samples[2 * i];
right[0][i] = samples[2 * i + 1];
}
//fft
FastFourierTransformer.transformInPlace(left, DftNormalization.STANDARD, TransformType.FORWARD);
FastFourierTransformer.transformInPlace(right, DftNormalization.STANDARD, TransformType.FORWARD);
// here I amplify the 0-4kHz frequencies by 12dB
// 0-4kHz is 1/5 of whole spectrum, and since there are negative frequencies in the array
// I iterate over 1/10 and multiply frequencies on both sides of the array
for (int i = 1; i < left[0].length / 10; i++) {
double factor = 3.981d; // ratio = 10^(12dB/20)
//positive frequencies 0-4kHz
left[0][i] *= factor;
right[0][i] *= factor;
left[1][i] *= factor;
right[1][i] *= factor;
// negative frequencies 0-4kHz
left[0][left[0].length - i] *= factor;
right[0][left[0].length - i] *= factor;
left[1][left[0].length - i] *= factor;
right[1][left[0].length - i] *= factor;
}
//ifft
FastFourierTransformer.transformInPlace(left, DftNormalization.STANDARD, TransformType.INVERSE);
FastFourierTransformer.transformInPlace(right, DftNormalization.STANDARD, TransformType.INVERSE);
// put left and right channel into array
float[] samples2 = new float[(left[0].length) * 2];
for (int i = 0; i < samples2.length / 2; i++) {
samples2[2 * i] = (float) left[0][i];
samples2[2 * i + 1] = (float) right[0][i];
}
// convert back to byte array which can be played
byte[] bytes2 = new byte[bytes.length];
int validBytes = SimpleAudioConversion.encode(samples2, bytes2, validSamples, fmt);
You may listen to the sound here
https://vocaroo.com/i/s095uOJZiewf
If you amplify in either domain, you can potentially end up clipping the signal (which can sound horrible).
So you might need to check your ifft results to see if any sample values exceed the allowed range (usually -32768 to 32768, or -1.0 to 1.0), that your audio system allows. The way to avoid any found clipping is to either reduce the gain applied to the fft bins, or reduce the amplitude of the original input signal or the total ifft result.
The search term for a dynamic gain control process is AGC (Automatic Gain Control), which is non-trivial to do well.
e.g. if the volume for any particular frequency bin is already at "10", your computer's knob doesn't have an "11".
I have a program that checks distance and whether or not the player has collided with a barrier. I now am trying to calculate which barrier in the array of barriers is the closest to the moving player, then returning the index of that barrier.
Here is what I have so far:
public static int closestBarrier(GameObject object, GameObject[] barriers)
// TODO stub
{
int closest = 0;
for (int i = 0; i < barriers.length - 1; i++) {
if (Math.sqrt((object.getX() - barriers[i].getX())
* (object.getX() - barriers[i].getX()))
+ ((object.getY() - barriers[i].getY()) * (object.getY() - barriers[i]
.getY())) <= Math
.sqrt((object.getX() - barriers[i + 1].getX())
* (object.getX() - barriers[i + 1].getX()))
+ ((object.getY() - barriers[i + 1].getY()) * (object
.getY() - barriers[i + 1].getY()))) {
closest = i;
} else
closest = i + 1;
}
return closest;
}
I am still new to java so I understand what I already have probably isn't very efficient or the best method of doing it (or even right at all!?).
I'd refactor it a wee bit simpler like so:
public static int closestBarrier(GameObject object, GameObject[] barriers)
{
int closest = -1;
float minDistSq = Float.MAX_VALUE;//ridiculously large value to start
for (int i = 0; i < barriers.length - 1; i++) {
GameObject curr = barriers[i];//current
float dx = (object.getX()-curr.getX());
float dy = (object.getY()-curr.getY());
float distSq = dx*dx+dy*dy;//use the squared distance
if(distSq < minDistSq) {//find the smallest and remember the id
minDistSq = distSq;
closest = i;
}
}
return closest;
}
This way you're doing less distance checks (your version does two distance checks per iteration) and also you only need the id, not the actual distance, so you can gain a bit of speed by not using Math.sqrt() and simply using the squared distance instead.
Another idea I can think of depends on the layout. Say you have a top down vertical scroller, you would start by checking the y property of your obstacle. If you have a hash of them or a sorted list, for an object at the bottom of the screen you would start loop from the largest y barrier to the smallest. Once you found the closest barriers on the Y axis, if there are more than 1 you can check for the closest on the x axis. You wouldn't need to use square or square root as you're basically splitting the checks from 1 in 2D per barrier to 2 checks in 1D, narrowing down your barrier and discarding far away barriers instead of checking against every single object all the time.
An even more advanced version would be using space partitioning but hopefully you won't need it for a simple game while learning.
I've modulated a carrier frequency signal with my data using FSK like this:
double SAMPLING_TIME = 1.0 / 441000 // 44khz
int SAMPLES_PER_BIT = 136;
int ENCODING_SAMPLES_PER_BIT = SAMPLES_PER_BIT / 2;
int duration = ENCODING_SAMPLES_PER_BIT * SAMPLING_TIME;
public double[] encode(int[] bits) {
for (int i = 0; i < bits.length; i++) {
int freq = FREQUENCY_LOW;
if (bits[i] > 1)
freq = FREQUENCY_HIGH;
bitArray = generateTone(freq, duration);
message = bitArray;
}
return message;
}
private double[] generateTone(int frequency, double duration) {
int samplingRate = 1/SAMPLING_TIME; // Hz
int numberOfSamples = (int) (duration * samplingRate);
samplingTime = 2 * SAMPLING_TIME;
double[] tone = new double[numberOfSamples];
for (int i = 0; i < numberOfSamples; i++) {
double y = Math.sin(2 * Math.PI * frequency * i * SAMPLING_TIME);
tone[i] = y * CARRIER_AMPLITUDE;
}
return tone;
}
Clearly, I'm sending FREQUENCY_LOW for ZERO and FREQUENCY_HIGH for 1.
Now how do I demodulate it using FFT? I'm interested in sampling magnitudes (presence and absence) of FREQUENCY_LOW, FREQUENCY_HIGH throughout the time.
I only know basics of FFT, I was starting to write this but it doesn't make sense:
private void decode(byte[] tone, int length) {
float[] input = new float[FFT_SIZE*2]; // not sure what size? shouldn't this be buffer?
for(int i=0;i<length;i++){
input[i]=tone[i];
}
FloatFFT_1D fft = new FloatFFT_1D(FFT_SIZE);
fft.realForward(input);
}
Can someone help with code?
You can use overlapping sliding windows for your FFTs, with the window and FFT the same length as that of your data bits. Then look for magnitude peaks for your 1's and 0's in the appropriate FFT result bins across these windows. You will also need some synchronization logic for runs of 1's and 0's.
Another DSP techniques that may be less compute intensive is to do quadrature demodulation for your two frequencies and low-pass filter the result before feeding it to the synchronization logic and bit detector. Yet another possibility is two sliding Goertzel filters.
I'm trying to calculate the Mean Difference average of a set of data. I have two (supposedly equivalent) formulas which calculate this, with one being more efficient (O^n) than the other (O^n2).
The problem is that while the inefficient formula gives correct output, the efficient one does not. Just by looking at both formulas I had a hunch that they weren't equivalent, but wrote it off because the derivation was made by a statician in a scientific journal. So i'm assuming the problem is my translation. Can anyone help me translate the efficient function properly?
Inefficient formula:
Inefficient formula translation (Java):
public static double calculateMeanDifference(ArrayList<Integer> valuesArrayList)
{
int valuesArrayListSize = valuesArrayList.size();
int sum = 0;
for(int i = 0; i < valuesArrayListSize; i++)
{
for(int j = 0; j < valuesArrayListSize; j++)
sum += (i != j ? Math.abs(valuesArrayList.get(i) - valuesArrayList.get(j)) : 0);
}
return new Double( (sum * 1.0)/ (valuesArrayListSize * (valuesArrayListSize - 1)));
}
Efficient derived formula:
where (sorry, don't know how to use MathML on here):
x(subscript i) = the ith order statistic of the data set
x(bar) = the mean of the data set
Efficient derived formula translation (Java):
public static double calculateMean(ArrayList<Integer> valuesArrayList)
{
double sum = 0;
int valuesArrayListSize = valuesArrayList.size();
for(int i = 0; i < valuesArrayListSize; i++)
sum += valuesArrayList.get(i);
return sum / (valuesArrayListSize * 1.0);
}
public static double calculateMeanDifference(ArrayList<Integer> valuesArrayList)
{
double sum = 0;
double mean = calculateMean(valuesArrayList);
int size = valuesArrayList.size();
double rightHandTerm = mean * size * (size + 1);
double denominator = (size * (size - 1)) / 2.0;
Collections.sort(valuesArrayList);
for(int i = 0; i < size; i++)
sum += (i * valuesArrayList.get(i) - rightHandTerm);
double meanDifference = (2 * sum) / denominator;
return meanDifference;
}
My data set consists of a collection of integers each having a value bounded by the set [0,5].
Randomly generating such sets and using the two functions on them gives different results. The inefficient one seems to be the one producing results in line with what is being measured: the absolute average difference between any two values in the set.
Can anyone tell me what's wrong with my translation?
EDIT: I created a simpler implementation that is O(N) provided the all your data has values limited to a relatively small set.The formula sticks to the methodology of the first method and thus, gives identical results to it (unlike the derived formula). If it fits your use case, I suggest people use this instead of the derived efficient formula, especially since the latter seems to give negative values when N is small).
Efficient, non-derived translation (Java):
public static double calculateMeanDifference3(ArrayList<Integer> valuesArrayList)
{
HashMap<Integer, Double> valueCountsHashMap = new HashMap<Integer, Double>();
double size = valuesArrayList.size();
for(int i = 0; i < size; i++)
{
int currentValue = valuesArrayList.get(i);
if(!valueCountsHashMap.containsKey(currentValue))
valueCountsHashMap.put(currentValue, new Double(1));
else
valueCountsHashMap.put(currentValue, valueCountsHashMap.get(currentValue)+ 1);
}
double sum = 0;
for(Map.Entry<Integer, Double> valueCountKeyValuePair : valueCountsHashMap.entrySet())
{
int currentValue = valueCountKeyValuePair.getKey();
Double currentCount = valueCountKeyValuePair.getValue();
for(Map.Entry<Integer, Double> valueCountKeyValuePair1 : valueCountsHashMap.entrySet())
{
int loopValue = valueCountKeyValuePair1.getKey();
Double loopCount = valueCountKeyValuePair1.getValue();
sum += (currentValue != loopValue ? Math.abs(currentValue - loopValue) * loopCount * currentCount : 0);
}
}
return new Double( sum/ (size * (size - 1)));
}
Your interpretation of sum += (i * valuesArrayList.get(i) - rightHandTerm); is wrong, it should be sum += i * valuesArrayList.get(i);, then after your for, double meanDifference = ((2 * sum) - rightHandTerm) / denominator;
Both equations yields about the same value, but they are not equal. Still, this should help you a little.
You subtract rightHandTerm on each iteration, so it gets [over]multiplied to N.
The big Sigma in the nominator touches only (i x_i), not the right hand term.
One more note: mean * size == sum. You don't have to divide sum by N and then remultiply it back.