I want to execute a command in the cmd from java. I want to execute link41b.exe in cmd from java. Normally it work like that :
I write the path of the link41b.exe
I execute link41b.exe
I wait until she excute this application and it give me a result .
I write the sentence that I want to link it
For example: linkparser>""the sentence""
So to execute this command I have written this code.
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintStream;
public class tistlink {
public static void main(String[] args) {
Process child;
String line;
try {
String command="cmd /c link41b.exe";
child = Runtime.getRuntime().exec(command);
child.waitFor();
OutputStream out = child.getOutputStream();
PrintStream printStream = new PrintStream(out);
printStream.println(" the girl is beautifull");
System.out.println(child.exitValue());
BufferedReader input =new BufferedReader(new
InputStreamReader(child.getInputStream()));
while((line = input.readLine()) != null)
{System.out.println(line); }
} catch (IOException e) {
e.printStackTrace();
} catch (InterruptedException e) {
e.printStackTrace();
}}
}
The method exitvalue() returns 1. But it didn't return the result.
What it is the problem of this code because it gave me any error?
Related
Let's say I have theese words in a text file
Dictionary.txt
artificial
intelligence
abbreviation
hybrid
hysteresis
illuminance
identity
inaccuracy
impedance
impenetrable
imperfection
impossible
independent
How can I make each word a different object and print them on the console?
You can simple use Scanner.nextLine(); function.
Here is the following code which can help
also import the libraries
import java.util.Scanner;
import java.io.File;
import java.util.Arrays;
Use following code:-
String []words = new String[1];
try{
File file = new File("/path/to/Dictionary.txt");
Scanner scan = new Scanner(file);
int i=0;
while(scan.hasNextLine()){
words[i]=scan.nextLine();
i++;
words = Arrays.copyOf(words,words.legnth+1); // Increasing legnth of array with 1
}
}
catch(Exception e){
System.out.println(e);
}
You must go and research on Scanner class
This is a very simple solution using Files:
package org.kodejava.io;
import java.net.URI;
import java.nio.charset.Charset;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.List;
import java.util.Objects;
public class ReadFileAsListDemo {
public static void main(String[] args) {
ReadFileAsListDemo demo = new ReadFileAsListDemo();
demo.readFileAsList();
}
private void readFileAsList() {
String fileName = "Dictionary.txt";
try {
URI uri = Objects.requireNonNull(this.getClass().getResource(fileName)).toURI();
List<String> lines = Files.readAllLines(Paths.get(uri),
Charset.defaultCharset());
for (String line : lines) {
System.out.println(line);
}
} catch (Exception e) {
e.printStackTrace();
}
}
}
Source: https://kodejava.org/how-do-i-read-all-lines-from-a-file/
This is another neat solution using buffered reader:
import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.logging.Level;
import java.util.logging.Logger;
/**
* BufferedReader and Scanner can be used to read
line by line from any File or
* console in Java.
* This Java program
demonstrate line by line reading using BufferedReader in Java
*
* #author Javin Paul
*/
public class BufferedReaderExample {
public static void main(String args[]) {
//reading file line by line in Java using BufferedReader
FileInputStream fis = null;
BufferedReader reader = null;
try {
fis = new FileInputStream("C:/sample.txt");
reader = new BufferedReader(new InputStreamReader(fis));
System.out.println("Reading
File line by line using BufferedReader");
String line = reader.readLine();
while(line != null){
System.out.println(line);
line = reader.readLine();
}
} catch (FileNotFoundException ex) {
Logger.getLogger(BufferedReaderExample.class.getName()).log(Level.SEVERE, null, ex);
} catch (IOException ex) {
Logger.getLogger(BufferedReaderExample.class.getName()).log(Level.SEVERE, null, ex);
} finally {
try {
reader.close();
fis.close();
} catch (IOException ex) {
Logger.getLogger(BufferedReaderExample.class.getName()).log(Level.SEVERE, null, ex);
}
}
}
Source: https://javarevisited.blogspot.com/2012/07/read-file-line-by-line-java-example-scanner.html#axzz7lrQcYlyy
These are all good answers. The OP didn't state what release of Java they require, but in modern Java I'd just use:
import java.nio.file.*;
public class x {
public static void main(String[] args) throws java.io.IOException {
Files.lines(Path.of("/path/to/Dictionary.txt")).forEach(System.out::println);
}
}
I have to run a run a python script from a maven project. I created a temporary class with main method to check if it works as expected, used the process builder and it works if I specify the absolute path of the python script and then run the java class from eclipse using RUN as Java application.
If I change it getClass().getResourceAsStream("/scripts/script.py"), it throws an exception as it cannot locate the python script.
What would be the best place to place the python script and how can I access it in the Java class without specifying the complete path. Since I am new to maven, it could be due to the method used to execute the Java program.
package discourse.apps.features;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;
public class Test {
protected String scriptPath = "/Users/user1/project1/scripts/script.py";
protected String python3Path = "/Users/user1/.virtualenvs/python3/bin/python3";
public static void main(String[] args) throws IOException {
new Test().score();
}
public JSONObject score() {
String text1="a";
String text2="b";
JSONObject rmap =null;
try
{
String line= null;
String writedir=System.getProperty("user.dir")+ "/Tmp";
String pbCommand[] = { python3Path, scriptPath,"--stringa", text1, "--stringb",text2,"--writedir", writedir };
ProcessBuilder pb = new ProcessBuilder(pbCommand);
Process p = pb.start();
InputStream is = p.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);
while ((line = br.readLine()) != null) {
JSONParser parser = new JSONParser();
rmap= (JSONObject) parser.parse(line);
}
} catch (IOException | ParseException ioe) {
System.err.println("Error running script");
ioe.printStackTrace();
System.exit(0);
}
return rmap;
}
}
Here is the output from pb command
pbCommand[0]:/Users/user1/.virtualenvs/python3/bin/python3
pbCommand[1]:displays the complete python script
import os,sys
from pyrouge import Rouge155
import json
from optparse import OptionParser
def get_opts():
parser = OptionParser()
parser.add_option("--stringa", dest="str_a",help="First string")
parser.add_option("--stringb", dest= "str_b",help="second string")
parser.add_option("--writedir", dest="write_dir", help="Tmp write directory for rouge")
(options, args) = parser.parse_args()
if options.str_a is None:
print("Error: requires string")
parser.print_help()
sys.exit(-1)
if options.str_b is None:
print("Error:requires string")
parser.print_help()
sys.exit(-1)
if options.write_dir is None:
print("Error:requires write directory for rouge")
parser.print_help()
sys.exit(-1)
return (options, args)
def readTextFile(Filename):
f = open(Filename, "r", encoding='utf-8')
TextLines=f.readlines()
f.close()
return TextLines
def writeTextFile(Filename,Lines):
f = open(Filename, "w",encoding='utf-8')
f.writelines(Lines)
f.close()
def rougue(stringa, stringb, writedirRouge):
newrow={}
r = Rouge155()
count=0
dirname_sys= writedirRouge +"rougue/System/"
dirname_mod=writedirRouge +"rougue/Model/"
if not os.path.exists(dirname_sys):
os.makedirs(dirname_sys)
if not os.path.exists(dirname_mod):
os.makedirs(dirname_mod)
Filename=dirname_sys +"string_."+str(count)+".txt"
LinesA=list()
LinesA.append(stringa)
writeTextFile(Filename, LinesA)
LinesB=list()
LinesB.append(stringb)
Filename=dirname_mod+"string_.A."+str(count)+ ".txt"
writeTextFile(Filename, LinesB)
r.system_dir = dirname_sys
r.model_dir = dirname_mod
r.system_filename_pattern = 'string_.(\d+).txt'
r.model_filename_pattern = 'string_.[A-Z].#ID#.txt'
output = r.convert_and_evaluate()
output_dict = r.output_to_dict(output)
newrow["rouge_1_f_score"]=output_dict["rouge_1_f_score"]
newrow["rouge_2_f_score"]=output_dict["rouge_2_f_score"]
newrow["rouge_3_f_score"]=output_dict["rouge_3_f_score"]
newrow["rouge_4_f_score"]=output_dict["rouge_4_f_score"]
newrow["rouge_l_f_score"]=output_dict["rouge_l_f_score"]
newrow["rouge_s*_f_score"]=output_dict["rouge_s*_f_score"]
newrow["rouge_su*_f_score"]=output_dict["rouge_su*_f_score"]
newrow["rouge_w_1.2_f_score"]=output_dict["rouge_w_1.2_f_score"]
rouge_dict=json.dumps(newrow)
print (rouge_dict)
def run():
(options, args) = get_opts()
stringa=options.str_a
stringb=options.str_b
writedir=options.write_dir
rougue(stringa, stringb, writedir)
if __name__ == '__main__':
run()
pbCommand[2]:--stringa
pbCommand[3]:a
pbCommand[4]:--stringb
pbCommand[5]:b
pbCommand[6]:--writedir
pbCommand[7]:/users/user1/project1/Tmp
Put the script in the main/resources folder it will then be copied to the target folder.
Then make sure you use something like the com.google.common.io.Resources class, which you can add with
<dependency>
<groupId>com.google.guava</groupId>
<artifactId>guava-io</artifactId>
<version>r03</version>
</dependency>
I then have a class like this which helps to convert resource files to Strings:
import java.net.MalformedURLException;
import java.net.URI;
import java.net.URL;
import com.google.common.base.Charsets;
import com.google.common.io.Resources;
public class FileUtil
{
public static String convertResourceToString(URL url)
{
try
{
return Resources.toString(url, Charsets.UTF_8);
}
catch (Exception e)
{
return null;
}
}
public static String convertResourceToString(String path)
{
return convertResourceToString(Resources.getResource(path));
}
public static String convertResourceToString(URI url)
{
try
{
return convertResourceToString(url.toURL());
}
catch (MalformedURLException e)
{
return null;
}
}
}
Some advice if you are learning maven try using it instead of the IDE to run and package your application, that is what it is suppose to do. Then once you are confident that the application will function as a packaged jar then just use the IDE to run it.
i try to convert video using ffmpeg in ubuntu.
ffmpeg -i inputfile.flv -sameq outputfile.mpeg
this works if change directory to inputfile directory.
is that posible to use this command ?
ffmpeg -i "home/Documents/inputfile.flv" -sameq "home/Documents/outputfile.mpeg"
i don't want to change directory when i use that command, because that command is using for my java code.
so my input file and output file is variable in my code .
here's my full code
package Converter;
import Controller.ConvertedButtonListener;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.URL;
import java.util.Arrays;
/**
*
* #author roylisto
*/
public class VideoConverter {
private String defaultFile;
private String convertedFile;
private ConverterThread myThread;
private ConvertedButtonListener butListener;
public VideoConverter(String fileDir,String convertOutput,ConvertedButtonListener buttonListener){
this.defaultFile=fileDir;
this.convertedFile=convertOutput;
this.butListener=buttonListener;
}
public void convertToMjpeg(){
String[] listCommands={"ffmpeg","-i","\""+defaultFile+"\"","-qscale","0","\""+convertedFile+"\""};
myThread=new ConverterThread(listCommands,this);
myThread.start();
}
public void setCommandStream(String stream){
butListener.setCommandOutput(stream);
}
class ConverterThread extends Thread{
VideoConverter vc;
String[] command;
ConverterThread(String[] command,VideoConverter vc){
this.command=command;
this.vc=vc;
}
public void run(){
synchronized(vc){
try{
String s = null;
Process process = new ProcessBuilder(command).start();
BufferedReader stdInput = new BufferedReader(new InputStreamReader(process.getInputStream()));
BufferedReader stdError = new BufferedReader(new InputStreamReader(process.getErrorStream()));
StringBuffer start= new StringBuffer();
// read the output from the command
while ((s = stdInput.readLine()) != null)
{
start.append(s);
vc.setCommandStream(s);
}
stdInput.close();
// read any errors from the attempted command
while ((s = stdError.readLine()) != null)
{
start.append(s);
vc.setCommandStream(s);
}
}catch(Exception ex){
System.out.println(ex.toString());
}
}
}
}
}
until now my code works well in windows with some modification like change ffmpeg to ffmpeg.exe because ffmpeg isn't native in my windows. but when i use my code in ubuntu
it show this error
"/home/roylisto/Documents/Tugas Akhir/Video Master/3a.avi": No such file or directory
UPDATE
solve problem, here's my code :)
package Converter;
import Controller.ConvertedButtonListener;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.URL;
import java.util.Arrays;
/**
*
* #author roylisto
*/
public class VideoConverter {
private String defaultFile;
private String convertedFile;
private ConverterThread myThread;
private ConvertedButtonListener butListener;
public VideoConverter(String fileDir,String convertOutput,ConvertedButtonListener buttonListener){
this.defaultFile=fileDir;
this.convertedFile=convertOutput;
this.butListener=buttonListener;
}
public void convertToMjpeg(){
String[] listCommands={"ffmpeg","-i",defaultFile,"-qscale","0",convertedFile};
myThread=new ConverterThread(listCommands,this);
myThread.start();
}
public void setCommandStream(String stream){
butListener.setCommandOutput(stream);
}
class ConverterThread extends Thread{
VideoConverter vc;
String[] command;
ConverterThread(String[] command,VideoConverter vc){
this.command=command;
this.vc=vc;
}
public void run(){
synchronized(vc){
try{
String s = null;
Process process = new ProcessBuilder(command).start();
BufferedReader stdInput = new BufferedReader(new InputStreamReader(process.getInputStream()));
BufferedReader stdError = new BufferedReader(new InputStreamReader(process.getErrorStream()));
StringBuffer start= new StringBuffer();
// read the output from the command
while ((s = stdInput.readLine()) != null)
{
start.append(s);
vc.setCommandStream(s);
}
stdInput.close();
// read any errors from the attempted command
while ((s = stdError.readLine()) != null)
{
start.append(s);
vc.setCommandStream(s);
}
}catch(Exception ex){
System.out.println(ex.toString());
}
}
}
}
}
is that posible to use this command ?
Yes, it is possible, as long as you specify a valid absolute or a relative path:
"home/Documents/inputfile.flv"
Should be:
"/home/Documents/inputfile.flv"
Otherwise it'd look for a home directory inside the current working directory. Notice the / at the beginning.
And as for this:
"/home/roylisto/Documents/Tugas Akhir/Video Master/3a.avi": No such file or directory
Are you really shure the file is there and you have r/w access to that directory?
This there anything wrong with my code? I'm new to Java and i'm trying to import a file into MongoDB. However there is a error that i have no idea what is it. I am using Eclipse.
import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStreamReader;
import com.mongodb.DB;
import com.mongodb.DBCollection;
import com.mongodb.DBCursor;
import com.mongodb.DBObject;
import com.mongodb.Mongo;
import com.mongodb.util.JSON;
import com.mongodb.util.JSONParseException;
public class readwrite {
public static void main(String[] args) throws FileNotFoundException,IOException,JSONParseException{
Mongo mongo = new Mongo("localhost", 27017);
DB db = mongo.getDB("actualdata");
DBCollection collection = db.getCollection("metadata");
String line = null;
StringBuilder sb = new StringBuilder();
try {
FileInputStream fstream = null;
try {
fstream = new FileInputStream("/home/Output/json1-100000-all");
} catch (FileNotFoundException e) {
e.printStackTrace();
System.out.println("File does not exist, exiting");
return;
}
BufferedReader bufferedReader =
new BufferedReader(new InputStreamReader(fstream));
while((line = bufferedReader.readLine()) != null) {
System.out.println(line);
DBObject dbObject;
sb.append(dbObject = (DBObject) JSON.parse(bufferedReader.readLine()));
collection.insert(dbObject);
DBCursor cursorDoc = collection.find();
while (cursorDoc.hasNext()) {
System.out.println(cursorDoc.next());
}
}
bufferedReader.close();
}
catch(FileNotFoundException ex) {
System.out.println("Unable to open file");
}
catch(IOException ex) {
System.out.println(
"Error reading file");
}
}
}
This is the error that is displayed
[
Exception in thread "main" com.mongodb.util.JSONParseException:
{
^
at com.mongodb.util.JSONParser.read(JSON.java:272)
at com.mongodb.util.JSONParser.parseObject(JSON.java:230)
at com.mongodb.util.JSONParser.parse(JSON.java:195)
at com.mongodb.util.JSONParser.parse(JSON.java:145)
at com.mongodb.util.JSON.parse(JSON.java:81)
at com.mongodb.util.JSON.parse(JSON.java:66)
at readwrite.main(readwrite.java:45)
It show me this error when i clicked on at com.mongodb.util.JSONParser.read(JSON.java:272) where it says that the Source is not found. The source attachment does not contain the source for the file JSON.class.
I can print the output of BufferedReader if i did not included the conversion of DBObject. Thanks in advance!
1) Didn't you mean to write JSON.parse(line)
instead of JSON.parse(bufferedReader.readLine())) ?
This might cause it to try and parse 'null' at the last iteration
2) If that doesn't help, could you get the exact string value of 'line' on the failed iteration? (this should be easy using debugger or simple printing to system out)
Regards
I would like to run a Dos program from a web server. The Dos program has to be run interactively as the user interface is via a series of questions and answers. The answer to one question will determine the next question. I will have to use ajax on the web server, but I think I can do that.
I found one java program on Stackoverflow which seems to do something similar to what I want. However when I compile the program I get an error ie.
javac PipeRedirection.java
PipeRedirection.java:43: package InputProcess does not exist
InputProcess.Gobbler outGobbler = new InputProcess.Gobbler(p.getInputStream());
The stack overflow question url was
How can I write large output to Process getOutputStream?
The Java file was
/*
####### PipeRedirection.java
*/
import java.io.BufferedOutputStream;
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.List;
public class PipeRedirection {
public static void main(String[] args) throws FileNotFoundException {
if(args.length < 2) {
System.err.println("Need at least two arguments");
System.exit(1);
}
try {
String input = null;
for(int i = 0; i < args.length; i++) {
String[] commandList = args[i].split(" ");
ProcessBuilder pb = new ProcessBuilder(commandList);
//pb.redirectErrorStream(true);
Process p = pb.start();
if(input != null) {
PrintWriter writer = new PrintWriter(new OutputStreamWriter(new BufferedOutputStream(p.getOutputStream())), true);
writer.println(input);
writer.flush();
writer.close();
}
InputProcess.Gobbler outGobbler = new InputProcess.Gobbler(p.getInputStream());
InputProcess.Gobbler errGobbler = new InputProcess.Gobbler(p.getErrorStream());
Thread outThread = new Thread(outGobbler);
Thread errThread = new Thread(errGobbler);
outThread.start();
errThread.start();
outThread.join();
errThread.join();
int exitVal = p.waitFor();
System.out.println("\n****************************");
System.out.println("Command: " + args[i]);
System.out.println("Exit Value = " + exitVal);
List<String> output = outGobbler.getOuput();
input = "";
for(String o: output) {
input += o;
}
}
System.out.println("Final Output:");
System.out.println(input);
} catch (IOException ioe) {
// TODO Auto-generated catch block
System.err.println(ioe.getLocalizedMessage());
ioe.printStackTrace();
} catch (InterruptedException ie) {
// TODO Auto-generated catch block
System.err.println(ie.getLocalizedMessage());
ie.printStackTrace();
}
}
public static class Gobbler implements Runnable {
private BufferedReader reader;
private List<String> output;
public Gobbler(InputStream inputStream) {
this.reader = new BufferedReader(new InputStreamReader(inputStream));
}
public void run() {
String line;
this.output = new ArrayList<String>();
try {
while((line = this.reader.readLine()) != null) {
this.output.add(line + "\n");
}
this.reader.close();
}
catch (IOException e) {
// TODO
System.err.println("ERROR: " + e.getMessage());
}
}
public List<String> getOuput() {
return this.output;
}
}
}
Does anyone know why I get the compile error? Can I substitute some other code for InputProcess?
Thanks for any help
Peter
I think it's pretty obvious that you're missing parts to this code. A package named InputProcess which has a class called Gobbler was not included in the OP's post. Probably because it was not relevant to their question.
The error message essentially says that it can not find this package/code that it is looking for.
What this class does exactly, only the OP can tell you. At its most basic, though, it appears to read from an InputStream and convert it to a List<String>. I would read up on Java IO and try to replicate similar functionality.
Edit:
Looks like the Gobbler class is indeed included in the example above. Remove the InputProcess package name from your code (or put the Gobbler class in an InputProcess package) and you should be good to go.