Develop Reference

Split a date into equal intervals based on a given frequency

I'm trying to break a range of dates into equal intervals. Here is the code that I'm using. (Dates are in YYYY-MM-dd format)
Integer frequency= 4;
Date startDate = '2020-02-27';
Date endDate = '2022-02-26';
String[] startD = string.valueOf(behadelPlan.Start_datum__c).split('-');
String[] endD = string.valueOf(behadelPlan.Einddatum__c).split('-');
//String[] dates;
Integer x = 0;
Integer startYear = Integer.valueof(startD[0]);
Integer endYear = Integer.valueof(endD[0]);
//while (x < 4) {
for (Integer i = startYear; i <= endYear; i++) {
Integer endMonth = i != endYear ? 11 : Integer.valueof(endD[1]) - 1;
Integer startMon = i == startYear ? Integer.valueof(startD[1]) - 1 : 0;
for (Integer j = startMon; j <= endMonth && x < frequency; j = j + 1) {
Integer month = j + 1;
String displayMonth;
if (month < 10) {
displayMonth = '0' + month;
} else {
displayMonth = String.valueOf(month);
}
List<string> slist = new string[]{string.valueOf(i), displayMonth, '01'};
string allstring = string.join(sList,'-');
System.debug(slist);
x+=1;
}
}
when I run this I get the output as
2020-02-01
2020-03-01
2020-04-01
2020-05-01
Here In my case, I want to generate the dates at equal(monthly with the day being start dates day) intervals. In the above example, I should be getting the resultant dates as 4 equal intervals (as I've given my frequency in a number of months).
Please let me know on how can I achieve this.
Here is a simple example.
startdate = '2020-01-01'
endDate = '2020-12-01'
frequency = 4
output should be
2020-01-01
2020-03-01
2020-06-01
2020-09-01

Here is how I would do it. I will us class Calendar for this.
public class FrequencyTransform {
public static void main (String[] args) {
System.out.println("Split a date into equal intervals based on a given frequency");
Integer frequency= 4;
try {
Date startDate = new SimpleDateFormat("yyyy-mm-dd").parse("2020-02-27");
Date endDate = new SimpleDateFormat("yyyy-mm-dd").parse("2021-02-26");
Calendar startCalendar = Calendar.getInstance();
startCalendar.clear();
startCalendar.setTime(startDate);
Calendar endCalendar = Calendar.getInstance();
endCalendar.clear();
endCalendar.setTime(endDate);
// id you want the interval to be months
int monthsElapsed = elapsed(startCalendar, endCalendar, Calendar.MONTH);
System.out.println("Number of months between dates:" + monthsElapsed);
int interval = monthsElapsed % frequency;
System.out.println("For the frequency 4 the interval is: " + interval);
while (!startCalendar.after(endCalendar)){
startCalendar.add(Calendar.MONTH,interval);
Date auxDate= startCalendar.getTime();
System.out.println(auxDate);
}
}
catch (ParseException ex) {
ex.printStackTrace();
}
}
private static int elapsed(Calendar before, Calendar after, int field) {
Calendar clone = (Calendar) before.clone(); // Otherwise changes are been reflected.
int elapsed = -1;
while (!clone.after(after)) {
clone.add(field, 1);
elapsed++;
}
return elapsed;
}
}
This is just a quick example. You can take it from here. The thing is Calendar allow you to use different time units. Instead of Calendar.MONTH you can use Calendar.DATE for days, Calendar.YEAR for year. Wasn't very sure how you wanted to do the split.

Sample code ,
import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
public class SOTest {
static DateFormat dateFormat = new SimpleDateFormat("yyy-MM-dd");
public static void main(String[] args) {
try {
String startDateString = "2020-01-01";
String endDateString = "2020-12-01";
int frequency = 4;
Date startDate = (Date)dateFormat.parse(startDateString);
Date endDate = (Date)dateFormat.parse(endDateString);
Long intervalSize = (endDate.getTime()-startDate.getTime())/frequency;
for(int i=0; i<= frequency && intervalSize > 0; i++) {
Date date = new Date(startDate.getTime()+intervalSize*i);
System.out.println("Date :: "+dateFormat.format(date));
}
} catch (ParseException e) {
e.printStackTrace();
}
}
}
output for above ::
Date :: 2020-01-01
Date :: 2020-03-24
Date :: 2020-06-16
Date :: 2020-09-08
Date :: 2020-12-01
For input :: startDate = '2020-02-27' , endDate = '2022-02-26', interval = 4
Date :: 2020-02-27
Date :: 2020-08-27
Date :: 2021-02-26
Date :: 2021-08-27
Date :: 2022-02-26

how to get near time for the present time [Android Studio]

i have 5 times
example:
4:21 AM
12:1 PM
3:32 PM
6:30 PM
8:4 PM
and the current time is
10:4 AM
I want to do a comparison
What is the next time closest to the current time
the result will be:
NEXT TIME : 12:1 PM

You can turn a time to a date object and then into a long (milliseconds since Jan 1, 1970), and calculate the difference in milliseconds
long diffInMs = currentDate.getTime() - anotherDate.getTime();
And then check which has the smallest difference, but being also equal to or greater than zero. Negative difference means old date and you want the next closest date
To convert the times to dates check this: https://stackoverflow.com/a/8826392/2597775
Basically, it says:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");
sdf.setTimeZone(TimeZone.getTimeZone("UTC"));
String inputString = "00:01:30.500";
Date date = sdf.parse("1970-01-01 " + inputString);

Update: Added logic to rollover at midnight, and added alternative using binary search.
First parse the inputs to a time in milliseconds of the day, by parsing the time string as if it's in UTC time zone.
Then find the smallest value on or after the "current" value, or just smallest value if no value is on or after the "current" value (rollover).
Example:
public static String findNext(String current, String... times) throws ParseException {
SimpleDateFormat fmt = new SimpleDateFormat("hh:mm a");
fmt.setTimeZone(TimeZone.getTimeZone("UTC"));
long currentMillis = fmt.parse(current).getTime();
long bestMillis = 0, minMillis = 0;
String bestTime = null, minTime = null;
for (String time : times) {
long millis = fmt.parse(time).getTime();
if (millis >= currentMillis && (bestTime == null || millis < bestMillis)) {
bestMillis = millis;
bestTime = time;
}
if (minTime == null || millis < minMillis) {
minMillis = millis;
minTime = time;
}
}
return (bestTime != null ? bestTime : minTime);
}
Test
System.out.println(findNext("10:4 AM",
"4:21 AM", "12:1 PM", "3:32 PM", "6:30 PM", "8:4 PM"));
System.out.println(findNext("10:4 PM",
"4:21 AM", "12:1 PM", "3:32 PM", "6:30 PM", "8:4 PM"));
Output
12:1 PM
4:21 AM
If the given times are guaranteed to already be sorted, then it can be done with a binary search:
public static String findNext(String current, String... times) {
SimpleDateFormat fmt = new SimpleDateFormat("hh:mm a");
fmt.setTimeZone(TimeZone.getTimeZone("UTC"));
int idx = Arrays.binarySearch(times, current, new Comparator<String>() {
#Override
public int compare(String s1, String s2) {
try {
return fmt.parse(s1).compareTo(fmt.parse(s2));
} catch (ParseException e) {
throw new RuntimeException(e);
}
}
});
if (idx < 0)
idx = -idx - 1;
return times[idx < times.length ? idx : 0];
}

i specially design a function to solve your problem , use function as you needed.
it will works for you surely.
/**
*
* #author Niravdas
*/
public class TimeDiff {
String[] times = { "04:21 AM", "12:01 PM", "03:32 PM", "06:30 PM", "08:04 PM"};
String findingafter="10:04 AM";
public TimeDiff()
{
int time=nextTimeArrayIndex(findingafter,times);
if(time>=0)
System.out.println("NEXT TIME: "+times[time]);
}
public static void main(String argv[])
{
new TimeDiff();
}
int nextTimeArrayIndex(String Finding,String[] fromArray)
{
int shortest=-1,shortestsec=-1;
long minsecdif=(24*60*60+1),minsec=(24*60*60+1);
int hr=Integer.parseInt(Finding.substring(0, 2));
int min=Integer.parseInt(Finding.substring(3, 5));
long seconds = convertToSec(hr, min, 0, Finding.substring(Finding.length()-2));
System.out.println("seconds :" + seconds);
for(int i=0;i<fromArray.length;i++)
{
int temphr=Integer.parseInt(fromArray[i].substring(0, 2));
int tempmin = Integer.parseInt(fromArray[i].substring(3,5));
long tempsec = convertToSec(temphr, tempmin, 0, fromArray[i].substring(Finding.length()-2));
System.out.println("Compared to :" + tempsec);
if((tempsec - seconds) > 0 && minsecdif > (tempsec - seconds))
{
minsecdif = (tempsec - seconds);
shortest = i;
}
if(minsec > tempsec)
{
minsec = tempsec;
shortestsec=i;
}
}
if(shortest >=0)
{
return shortest;
}
else
{
return shortestsec;
}
}
long convertToSec(int hr,int min,int sec,String AMorPM)
{
if(hr==12)
{
hr=0;
}
long secs = (hr*60*60) + (min*60) + (sec*60);
if(AMorPM.equalsIgnoreCase("PM"))
{
secs += (12*60*60);
}
return secs;
}
}
i hope it will solve your problem.

How to get saturday and sunday between two date in java [duplicate]

This question already has answers here:
Calculate number of weekdays between two dates in Java
(20 answers)
Closed 6 years ago.
StartDate: 2016-05-8 20:16:00;
EndDate: 2016-05-30 20:16:00;
public int saturdaysundaycount(Date d1, Date d2) {
Calendar c1 = Calendar.getInstance();
c1.setTime(d1);
Calendar c2 = Calendar.getInstance();
c2.setTime(d2);
int sundays = 0;
int saturday = 0;
while (c1.after(c2)) {
if (c2.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY || c2.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY)
sundays++;
saturday++;
c2.add(Calendar.DATE, 1);
c2.add(Calendar.DATE, 1);
}
System.out.println(sundays);
return saturday + sundays;
}
In this function I am trying to get total count of Saturdays and Sundays between two dates. But when I pass the date I get zero as a result. Please point out the mistake and suggest corrections.

It is not advisable to write full program but since you put effort, here is what seems to be working on my system and returning a value of 7.
public class CountWeekends {
public static void main(String[] args){
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
int count = 0;
try {
Date d1 = formatter.parse("2016-05-8 20:16:00");
Date d2 = formatter.parse("2016-05-30 20:16:00");
count = saturdaysundaycount(d1,d2);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("Count of Sats & Sundays = "+count);
}
public static int saturdaysundaycount(Date d1, Date d2) {
Calendar c1 = Calendar.getInstance();
c1.setTime(d1);
Calendar c2 = Calendar.getInstance();
c2.setTime(d2);
int sundays = 0;
int saturday = 0;
while (! c1.after(c2)) {
if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SATURDAY ){
saturday++;
}
if(c1.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY){
sundays++;
}
c1.add(Calendar.DATE, 1);
}
System.out.println("Saturday Count = "+saturday);
System.out.println("Sunday Count = "+sundays);
return saturday + sundays;
}
Logic: You need to keep increment start date by one day till it
surpasses end date and keep checking day on start date.

The problem is in your while, with this piece of code is working fine for me.
Check the endDate and startDate because I guess that you are sending it in the wrong order.
while (endDate.after(startDate)) {
if (endDate.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY ){
sundays++;
}else if (endDate.get(Calendar.DAY_OF_WEEK) == Calendar.SATURDAY){
saturday++;
}
endDate.add(Calendar.DATE, -1);
}

Your code does not loop through the days. Please try the following code. In the while loop it loops through all the days between the given fist date and last date. It does this by adding a day to c1 in every iteration until c1 is after c2. This gives number of Saturdays and Sundays between given dates including those two days.
public static int saturdaysundaycount(Date d1, Date d2) {
Calendar c1 = Calendar.getInstance();
c1.setTime(d1);
Calendar c2 = Calendar.getInstance();
c2.setTime(d2);
int sundays = 0;
int saturdays = 0;
while (!c1.after(c2)) {
SimpleDateFormat format1 = new SimpleDateFormat("yyyy-MM-dd-E");
String formatted = format1.format(c1.getTime());
System.out.println("Current Date C1 : " + formatted);
if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY) {
sundays++;
} else if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SATURDAY) {
saturdays++;
}
c1.add(Calendar.DATE, 1);
}
System.out.println("Sundays : " + sundays);
System.out.println("Saturdays : " + saturdays);
return saturdays + sundays;
}

public static int getNumberofSundays(String d1,String d2) throws Exception{ //object in Date form
Date date1=getDate(d1);
Date date2=getDate(d2);
Calendar c1=Calendar.getInstance();
c1.setTime(date1);
Calendar c2=Calendar.getInstance();
c2.setTime(date2);
int sundays=0;
while(c1.after(c2)){
if(c2.get(Calendar.DAY_OF_WEEK)==Calendar.SUNDAY){
sundays++;
c2.add(Calendar.DATE,1);
}
}
System.out.println("number of days between 2 dates"+sundays);
return sundays;
}

How to calculate a full days difference between two dates considering daylight savings in java

I need to get the full days between two dates in java (the dates are given in Date type) .
For example:
01/01/2015/12:00:00 - 01/02/2015/11:59:00 isn't a full day
and i need to consider daylight savings.
I know that jodatime lib does that but i reached the 65k method limit and i cant use jodatime lib.
i tried the millisecond diff way and the while loop that uses the "before" method:
Android/Java - Date Difference in days

I manage to figure it out:
i used some of this code - https://stackoverflow.com/a/28865648/3873513
and added some of mine:
public static int calcDaysDiff(Date day1, Date day2) {
Date d1 = new Date(day1.getTime());
Date d2 = new Date(day2.getTime());
Calendar date1 = Calendar.getInstance();
date1.setTime(d1);
Calendar date2 = Calendar.getInstance();
date2.setTime(d2);
//checks if the start date is later then the end date - gives 0 if it is
if (date1.get(Calendar.YEAR) >= date2.get(Calendar.YEAR)) {
if (date1.get(Calendar.DAY_OF_YEAR) >= date2.get(Calendar.DAY_OF_YEAR)) {
return 0;
}
}
//checks if there is a daylight saving change between the two dates
int offset = calcOffset(d1, d2);
if (date1.get(Calendar.YEAR) > date2.get(Calendar.YEAR)) {
//swap them
Calendar temp = date1;
date1 = date2;
date2 = temp;
}
return calcDaysDiffAux(date1, date2) + checkFullDay(date1, date2, offset);
}
// check if there is a 24 hour diff between the 2 dates including the daylight saving offset
public static int checkFullDay(Calendar day1, Calendar day2, int offset) {
if (day1.get(Calendar.HOUR_OF_DAY) <= day2.get(Calendar.HOUR_OF_DAY) + offset) {
return 0;
}
return -1;
}
// find the number of days between the 2 dates. check only the dates and not the hours
public static int calcDaysDiffAux(final Calendar day1, final Calendar day2) {
Calendar dayOne = (Calendar) day1.clone(),
dayTwo = (Calendar) day2.clone();
if (dayOne.get(Calendar.YEAR) == dayTwo.get(Calendar.YEAR)) {
return Math.abs(dayOne.get(Calendar.DAY_OF_YEAR) - dayTwo.get(Calendar.DAY_OF_YEAR));
} else {
int extraDays = 0;
while (dayTwo.get(Calendar.YEAR) > dayOne.get(Calendar.YEAR)) {
dayTwo.add(Calendar.YEAR, -1);
// getActualMaximum() important for leap years
extraDays += dayTwo.getActualMaximum(Calendar.DAY_OF_YEAR);
}
return extraDays - day1.get(Calendar.DAY_OF_YEAR) + day2.get(Calendar.DAY_OF_YEAR);
}
}

public class DateDiff {
public static void main(String[] av) {
SimpleDateFormat myFormat = new SimpleDateFormat("MM/dd/yyyy/HH:mm:ss");
String inputString1 = "01/01/2015/12:00:00";
String inputString2 = "01/02/2015/11:59:00";
try {
Date date1 = myFormat.parse(inputString1);
Date date2 = myFormat.parse(inputString2);
long diff = date2.getTime() - date1.getTime(); // Calculate the different
int days = (int) (diff / (1000*60*60*24)); // This convert milliseconds to days
System.out.println ("Days differ: " + days);
} catch (Exception e) {
e.printStackTrace();
}
}
}
The following code will calculate the two dates given, the result print is:
Days differ: 0

How can I calculate a time difference in Java?

I want to subtract two time periods say 16:00:00 from 19:00:00. Is there any Java function for this? The results can be in milliseconds, seconds, or minutes.

Java 8 has a cleaner solution - Instant and Duration
Example:
import java.time.Duration;
import java.time.Instant;
...
Instant start = Instant.now();
//your code
Instant end = Instant.now();
Duration timeElapsed = Duration.between(start, end);
System.out.println("Time taken: "+ timeElapsed.toMillis() +" milliseconds");

String time1 = "16:00:00";
String time2 = "19:00:00";
SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
Date date1 = format.parse(time1);
Date date2 = format.parse(time2);
long difference = date2.getTime() - date1.getTime();
Difference is in milliseconds.
I modified sfaizs post.

To get pretty timing differences, then
// d1, d2 are dates
long diff = d2.getTime() - d1.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000) % 24;
long diffDays = diff / (24 * 60 * 60 * 1000);
System.out.print(diffDays + " days, ");
System.out.print(diffHours + " hours, ");
System.out.print(diffMinutes + " minutes, ");
System.out.print(diffSeconds + " seconds.");

Java 8
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss");
LocalDateTime dateTime1= LocalDateTime.parse("2014-11-25 19:00:00", formatter);
LocalDateTime dateTime2= LocalDateTime.parse("2014-11-25 16:00:00", formatter);
long diffInMilli = java.time.Duration.between(dateTime1, dateTime2).toMillis();
long diffInSeconds = java.time.Duration.between(dateTime1, dateTime2).getSeconds();
long diffInMinutes = java.time.Duration.between(dateTime1, dateTime2).toMinutes();

Just like any other language; convert your time periods to a unix timestamp (ie, seconds since the Unix epoch) and then simply subtract.
Then, the resulting seconds should be used as a new unix timestamp and read formatted in whatever format you want.
Ah, give the above poster (genesiss) his due credit, code's always handy ;)
Though, you now have an explanation as well :)

import java.util.Date;
...
Date d1 = new Date();
...
...
Date d2 = new Date();
System.out.println(d2.getTime()-d1.getTime()); //gives the time difference in milliseconds.
System.out.println((d2.getTime()-d1.getTime())/1000); //gives the time difference in seconds.
and, to show in a nicer format, you can use:
DecimalFormat myDecimalFormatter = new DecimalFormat("###,###.###");
System.out.println(myDecimalFormatter.format(((double)d2.getTime()-d1.getTime())/1000));

Besides the most common approach with Period and Duration objects you can widen your knowledge with another way for dealing with time in Java.
Advanced Java 8 libraries.
ChronoUnit for Differences.
ChronoUnit is a great way to determine how far apart two Temporal values are. Temporal includes LocalDate, LocalTime and so on.
LocalTime one = LocalTime.of(5,15);
LocalTime two = LocalTime.of(6,30);
LocalDate date = LocalDate.of(2019, 1, 29);
System.out.println(ChronoUnit.HOURS.between(one, two)); //1
System.out.println(ChronoUnit.MINUTES.between(one, two)); //75
System.out.println(ChronoUnit.MINUTES.between(one, date)); //DateTimeException
First example shows that between truncates rather than rounds.
The second shows how easy it is to count different units.
And the last example reminds us that we should not mess up with dates and times in Java :)

public class timeDifference {
public static void main(String[] args) {
try {
Date startTime = Calendar.getInstance().getTime();
Thread.sleep(10000);
Date endTime = Calendar.getInstance().getTime();
long difference = endTime.getTime() - startTime.getTime();
long differenceSeconds = difference / 1000 % 60;
long differenceMinutes = difference / (60 * 1000) % 60;
long differenceHours = difference / (60 * 60 * 1000) % 24;
long differenceDays = difference / (24 * 60 * 60 * 1000);
System.out.println(differenceDays + " days, ");
System.out.println(differenceHours + " hours, ");
System.out.println(differenceMinutes + " minutes, ");
System.out.println(differenceSeconds + " seconds.");
}
catch (Exception e) {
e.printStackTrace();
}
}
}

I found this cleaner.
Date start = new Date();
//Waiting for 10 seconds
Thread.sleep(10000);
Date end = new Date();
long diff = end.getTime() - start.getTime();
String TimeTaken = String.format("[%s] hours : [%s] mins : [%s] secs",
Long.toString(TimeUnit.MILLISECONDS.toHours(diff)),
TimeUnit.MILLISECONDS.toMinutes(diff),
TimeUnit.MILLISECONDS.toSeconds(diff));
System.out.println(String.format("Time taken %s", TimeTaken));
Output
Time taken [0] hours : [0] mins : [10] secs

The painful way is to convert to millis and do the subtraction and then back to whatever seconds or so you want. The better way is to use JodaTime.

String start = "12:00:00";
String end = "02:05:00";
SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
Date date1 = format.parse(start);
Date date2 = format.parse(end);
long difference = date2.getTime() - date1.getTime();
int minutes = (int) TimeUnit.MILLISECONDS.toMinutes(difference);
if(minutes<0)minutes += 1440;
Now minutes will be the correct duration between two time (in minute).

import java.text.SimpleDateFormat;
import java.util.Date;
public class Main {
public static void main(String[] args) throws Exception {
String time1 = "12:00:00";
String time2 = "12:01:00";
SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
Date date1 = format.parse(time1);
Date date2 = format.parse(time2);
long difference = date2.getTime() - date1.getTime();
System.out.println(difference/1000);
}
}
It throws exception handles parsing exceptions.

This can be easily done using Java 8 LocalTime;
String time1 = "16:00:00";
String time2 = "19:00:00";
long seconds = Duration.between(LocalTime.parse(time1), LocalTime.parse(time2)).getSeconds()
Duration also supports toMillis(), toMinutes() which can be used in place of getSeconds() to get milliseconds or minutes

Аlternative option if time from different days is taken, for example: 22:00 and 01:55.
public static long getDiffTime(Date date1, Date date2){
if (date2.getTime() - date1.getTime() < 0) {// if for example date1 = 22:00, date2 = 01:55.
Calendar c = Calendar.getInstance();
c.setTime(date2);
c.add(Calendar.DATE, 1);
date2 = c.getTime();
} //else for example date1 = 01:55, date2 = 03:55.
long ms = date2.getTime() - date1.getTime();
//235 minutes ~ 4 hours for (22:00 -- 01:55).
//120 minutes ~ 2 hours for (01:55 -- 03:55).
return TimeUnit.MINUTES.convert(ms, TimeUnit.MILLISECONDS);
}

Try this:
public String timeDifference8(String startTime, String endTime) {
LocalTime initialTime = LocalTime.parse(startTime);
LocalTime finalTime =LocalTime.parse(endTime);
StringJoiner joiner = new StringJoiner(":");
long hours = initialTime.until( finalTime, ChronoUnit.HOURS);
initialTime = initialTime.plusHours( hours );
long minutes = initialTime.until(finalTime, ChronoUnit.MINUTES);
initialTime = initialTime.plusMinutes( minutes );
long seconds = initialTime.until( finalTime, ChronoUnit.SECONDS);
joiner.add(String.valueOf(hours));
joiner.add(String.valueOf(minutes));
joiner.add(String.valueOf(seconds));
return joiner.toString();
}

import java.sql.*;
class Time3 {
public static void main(String args[]){
String time1 = "01:03:23";
String time2 = "02:32:00";
long difference ;
Time t1 = Time.valueOf(time1);
Time t2 = Time.valueOf(time2);
if(t2.getTime() >= t1.getTime()){
difference = t2.getTime() - t1.getTime() -19800000;
}
else{
difference = t1.getTime() - t2.getTime() -19800000;
}
java.sql.Time time = new java.sql.Time(difference);
System.out.println(time);
}
}

/*
* Total time calculation.
*/
private void getTotalHours() {
try {
// TODO Auto-generated method stub
if (tfTimeIn.getValue() != null && tfTimeOut.getValue() != null) {
Long min1 = tfTimeOut.getMinutesValue();
Long min2 = tfTimeIn.getMinutesValue();
Long hr1 = tfTimeOut.getHoursValue();
Long hr2 = tfTimeIn.getHoursValue();
Long hrsTotal = new Long("0");
Long minTotal = new Long("0");
if ((hr2 - hr1) == 1) {
hrsTotal = (long) 1;
if (min1 != 0 && min2 == 0) {
minTotal = (long) 60 - min1;
} else if (min1 == 0 && min2 != 0) {
minTotal = min2;
} else if (min1 != 0 && min2 != 0) {
minTotal = min2;
Long minOne = (long) 60 - min1;
Long minTwo = min2;
minTotal = minOne + minTwo;
}
if (minTotal >= 60) {
hrsTotal++;
minTotal = minTotal % 60;
}
} else if ((hr2 - hr1) > 0) {
hrsTotal = (hr2 - hr1);
if (min1 != 0 && min2 == 0) {
minTotal = (long) 60 - min1;
} else if (min1 == 0 && min2 != 0) {
minTotal = min2;
} else if (min1 != 0 && min2 != 0) {
minTotal = min2;
Long minOne = (long) 60 - min1;
Long minTwo = min2;
minTotal = minOne + minTwo;
}
if (minTotal >= 60) {
minTotal = minTotal % 60;
}
} else if ((hr2 - hr1) == 0) {
if (min1 != 0 || min2 != 0) {
if (min2 > min1) {
hrsTotal = (long) 0;
minTotal = min2 - min1;
} else {
Notification.show("Enter A Valid Time");
tfTotalTime.setValue("00.00");
}
}
} else {
Notification.show("Enter A Valid Time");
tfTotalTime.setValue("00.00");
}
String hrsTotalString = hrsTotal.toString();
String minTotalString = minTotal.toString();
if (hrsTotalString.trim().length() == 1) {
hrsTotalString = "0" + hrsTotalString;
}
if (minTotalString.trim().length() == 1) {
minTotalString = "0" + minTotalString;
}
tfTotalTime.setValue(hrsTotalString + ":" + minTotalString);
} else {
tfTotalTime.setValue("00.00");
}
}
catch (Exception e) {
e.printStackTrace();
}
}

class TimeCalculator
{
String updateTime;
public TimeCalculator(String time)
{
// Time should be in 24 hours format like 15/06/2016 17:39:20
this.updateTime = time;
}
public String getTimeDifference()
{
String td = null;
// Get Current Time
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss");
Date currentDate = new Date();
Calendar calendar = new GregorianCalendar();
calendar.setTime(currentDate);
int c_year = calendar.get(Calendar.YEAR);
int c_month = calendar.get(Calendar.MONTH) + 1;
int c_day = calendar.get(Calendar.DAY_OF_MONTH);
// Get Editing Time
Date edit_date = sdf.parse(updateTime);
Calendar edit_calendar = new GregorianCalendar();
edit_calendar.setTime(edit_date);
int e_year = edit_calendar.get(Calendar.YEAR);
int e_month = edit_calendar.get(Calendar.MONTH) + 1;
int e_day = edit_calendar.get(Calendar.DAY_OF_MONTH);
if(e_year == c_year && e_month == c_month && e_day == c_day)
{
int c_hours = calendar.get(Calendar.HOUR_OF_DAY);
int c_minutes = calendar.get(Calendar.MINUTE);
int c_seconds = calendar.get(Calendar.SECOND);
int e_hours = edit_calendar.get(Calendar.HOUR_OF_DAY);
int e_minutes = edit_calendar.get(Calendar.MINUTE);
int e_seconds = edit_calendar.get(Calendar.SECOND);
if(c_hours == e_hours && c_minutes == e_minutes && c_seconds == e_seconds)
{
td = "just now";
return td;
}
else if(c_hours == e_hours && c_minutes == e_minutes)
{
int d_seconds = c_seconds-e_seconds;
td = String.valueOf(d_seconds);
td = td + " seconds ago";
return td;
}
else if(c_hours == e_hours && c_minutes != e_minutes)
{
int d_minutes = c_minutes-e_minutes;
int d_seconds;
if(c_seconds>e_seconds)
{
d_seconds = c_seconds-e_seconds;
}
else
{
d_seconds = e_seconds-c_seconds;
}
td = "00:" + String.valueOf(d_minutes) + ":" + String.valueOf(d_seconds) + " ago";
return td;
}
else
{
int d_minutes, d_seconds, d_hours;
d_hours = c_hours-e_hours;
if(c_minutes>e_minutes)
{
d_minutes = c_minutes - e_minutes;
}
else
{
d_minutes = e_minutes - c_minutes;
}
if(c_seconds>e_seconds)
{
d_seconds = c_seconds - e_seconds;
}
else
{
d_seconds = e_seconds - c_seconds;
}
td = String.valueOf(d_hours) + ":" + String.valueOf(d_minutes) + ":" + String.valueOf(d_seconds) + " ago";
return td;
}
}
else if(e_year == c_year && e_month == c_month && c_day == e_day+1)
{
td = "yesterday";
return td;
}
else
{
td = updateTime;
return td;
}
}
}

using Instant
Instant start = Instant.parse("2017-10-03T10:15:30.00Z");
Instant end = Instant.parse("2017-10-04T11:35:31.00Z");
long duration = Duration.between(start, end).toMillis();
long minutes = TimeUnit.MILLISECONDS.toMinutes(duration)*60;
String time = String.format("%02d hours, %02d min, %02d sec",
TimeUnit.MILLISECONDS.toHours(duration),
TimeUnit.MILLISECONDS.toMinutes(duration) - TimeUnit.MILLISECONDS.toHours(duration) * 60,
TimeUnit.MILLISECONDS.toSeconds(duration) - minutes);
;
System.out.println("time = " + time);