How to get saturday and sunday between two date in java [duplicate] - java

This question already has answers here:
Calculate number of weekdays between two dates in Java
(20 answers)
Closed 6 years ago.
StartDate: 2016-05-8 20:16:00;
EndDate: 2016-05-30 20:16:00;
public int saturdaysundaycount(Date d1, Date d2) {
Calendar c1 = Calendar.getInstance();
c1.setTime(d1);
Calendar c2 = Calendar.getInstance();
c2.setTime(d2);
int sundays = 0;
int saturday = 0;
while (c1.after(c2)) {
if (c2.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY || c2.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY)
sundays++;
saturday++;
c2.add(Calendar.DATE, 1);
c2.add(Calendar.DATE, 1);
}
System.out.println(sundays);
return saturday + sundays;
}
In this function I am trying to get total count of Saturdays and Sundays between two dates. But when I pass the date I get zero as a result. Please point out the mistake and suggest corrections.

It is not advisable to write full program but since you put effort, here is what seems to be working on my system and returning a value of 7.
public class CountWeekends {
public static void main(String[] args){
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
int count = 0;
try {
Date d1 = formatter.parse("2016-05-8 20:16:00");
Date d2 = formatter.parse("2016-05-30 20:16:00");
count = saturdaysundaycount(d1,d2);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("Count of Sats & Sundays = "+count);
}
public static int saturdaysundaycount(Date d1, Date d2) {
Calendar c1 = Calendar.getInstance();
c1.setTime(d1);
Calendar c2 = Calendar.getInstance();
c2.setTime(d2);
int sundays = 0;
int saturday = 0;
while (! c1.after(c2)) {
if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SATURDAY ){
saturday++;
}
if(c1.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY){
sundays++;
}
c1.add(Calendar.DATE, 1);
}
System.out.println("Saturday Count = "+saturday);
System.out.println("Sunday Count = "+sundays);
return saturday + sundays;
}
Logic: You need to keep increment start date by one day till it
surpasses end date and keep checking day on start date.

The problem is in your while, with this piece of code is working fine for me.
Check the endDate and startDate because I guess that you are sending it in the wrong order.
while (endDate.after(startDate)) {
if (endDate.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY ){
sundays++;
}else if (endDate.get(Calendar.DAY_OF_WEEK) == Calendar.SATURDAY){
saturday++;
}
endDate.add(Calendar.DATE, -1);
}

Your code does not loop through the days. Please try the following code. In the while loop it loops through all the days between the given fist date and last date. It does this by adding a day to c1 in every iteration until c1 is after c2. This gives number of Saturdays and Sundays between given dates including those two days.
public static int saturdaysundaycount(Date d1, Date d2) {
Calendar c1 = Calendar.getInstance();
c1.setTime(d1);
Calendar c2 = Calendar.getInstance();
c2.setTime(d2);
int sundays = 0;
int saturdays = 0;
while (!c1.after(c2)) {
SimpleDateFormat format1 = new SimpleDateFormat("yyyy-MM-dd-E");
String formatted = format1.format(c1.getTime());
System.out.println("Current Date C1 : " + formatted);
if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SUNDAY) {
sundays++;
} else if (c1.get(Calendar.DAY_OF_WEEK) == Calendar.SATURDAY) {
saturdays++;
}
c1.add(Calendar.DATE, 1);
}
System.out.println("Sundays : " + sundays);
System.out.println("Saturdays : " + saturdays);
return saturdays + sundays;
}

public static int getNumberofSundays(String d1,String d2) throws Exception{ //object in Date form
Date date1=getDate(d1);
Date date2=getDate(d2);
Calendar c1=Calendar.getInstance();
c1.setTime(date1);
Calendar c2=Calendar.getInstance();
c2.setTime(date2);
int sundays=0;
while(c1.after(c2)){
if(c2.get(Calendar.DAY_OF_WEEK)==Calendar.SUNDAY){
sundays++;
c2.add(Calendar.DATE,1);
}
}
System.out.println("number of days between 2 dates"+sundays);
return sundays;
}

Related

Java - Count Number of days except Holidays(Saturday and Sunday) [duplicate]

This question already has an answer here:
Calculate business days in java without saturdays, sunday and public holiday
(1 answer)
Closed 4 years ago.
I need to count for number of days except holidays(Saturday and sunday). For example my start date is 07/02/2018 and end date is 15/02/2018 (in dd/MM/yyyy format). I need to count number of working days between them. Can some please help me out? This is my code:
SimpleDateFormat dateformat3 = new SimpleDateFormat("dd/MM/yyyy");
//Date date12 = dateformat3.parse("17/07/1989");
String date1 = "11/07/2018";
String date2 = "20/07/2018";
// Date date2 = dateformat3.parse("15/10/2007");
Calendar startdate = Calendar.getInstance();
startdate.setTime(dateformat3.parse(date1));
Calendar enddate = Calendar.getInstance();
enddate.setTime(dateformat3.parse(date2));
while (!startdate.after(enddate)) {
int day = startdate.get(Calendar.DAY_OF_WEEK);
if ((day != Calendar.SATURDAY) && (day != Calendar.SUNDAY)) {
workingDays++;
}
}
I've tried with this code but is not showing any result.
You were close, just need to increment start date inside while loop.
public static void main(String[] args) throws Exception {
System.out.println(countDays("07/02/2018", "15/02/2018"));
}
public static int countDays(String startDate, String endDate) throws Exception {
int workingDays = 0;
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
Calendar startdate = Calendar.getInstance();
startdate.setTime(sdf.parse(startDate));
Calendar enddate = Calendar.getInstance();
enddate.setTime(sdf.parse(endDate));
while (!startdate.after(enddate)) {
int day = startdate.get(Calendar.DAY_OF_WEEK);
System.out.println(day);
if ((day != Calendar.SATURDAY) && (day != Calendar.SUNDAY)) {
workingDays++;
}
// increment start date, otherwise while will give infinite loop
startdate.add(Calendar.DATE, 1);
}
return workingDays;
}
As you can see, the only difference with the code I provided from yours (besides removing hard-coded values) is startdate.add(Calendar.DATE, 1);
I think you are doing wrong with your while condition.
Try this
while (ChronoUnit.DAYS.between(startdate.toInstant(), enddate.toInstant()) > 0) {
startdate.add(Calendar.DAY_OF_MONTH, 1);
if (startdate.get(Calendar.DAY_OF_WEEK) != Calendar.SATURDAY && startdate.get(Calendar.DAY_OF_WEEK) != Calendar.SUNDAY) {
workingDays++;
}
}
If you are using Java 8 you can use :
//Here I change the format of date to make it parsable
String date1 = "2018-07-11";
String date2 = "2018-07-20";
//Parse the date to LocalDate
LocalDate start = LocalDate.parse(date1);
LocalDate end = LocalDate.parse(date2);
//iterate over the list of dates between start and end date,
//then filter only those who are not equal SATURDAY or SUNDAY, then count the result
long result = Stream.iterate(start, date -> date.plusDays(1))
.limit(ChronoUnit.DAYS.between(start, end))
.filter(date -> date.getDayOfWeek() != DayOfWeek.SATURDAY
&& date.getDayOfWeek() != DayOfWeek.SUNDAY
).count();
In your case it will return 7 days

how to find next and previous date from date variable

Trying to solve a problem puzzle but not having much luck.
I have a list of dates and a Date object that get passed through to a function:
function void dateSorting(List<Date> dateList, Date newDate);
Based on the newDate i need to find out between which 2 indexes of list would this newDate fit into.
so e.g.
if date is 1/3/2015 and list contains:
INDEX, VALUE
0 , 5/1/2015
1 , 20/2/2015
2 , 15/3/2015
3 , 11/4/2015
Then function would print out/return 1 and 2 and the corresponding dates 20/2/2015 & 15/3/2015.
I have been scouring the net for pseudocode and examples but no luck. Closest i came to is closest date to newDate which doesn't help me.
Any help is appreciated.
Here, I got one for you.
void dateSorting(List<Date> dateList, Date newDate) {
for (int i = 0; i < dateList.size(); i++) {
if (newDate.before(dateList.get(i))) {
if (i != 0)
System.out.println("Previous index:" + (i - 1));
System.out.println("Next index:" + i);
break;
} else if (i == dateList.size() - 1) {
System.out.println("Previous index:" + i);
}
}
}
And I tested my code like this:
public static void main(String[] args) throws ParseException {
List<Date> dateList = new ArrayList<Date>();
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
dateList.add(sdf.parse("5/1/2015"));
dateList.add(sdf.parse("20/2/2015"));
dateList.add(sdf.parse("15/3/2015"));
dateList.add(sdf.parse("11/4/2015"));
System.out.println("Testing with 1/3/2015.");
dateSorting(dateList, sdf.parse("1/3/2015"));
System.out.println("Testing with 1/1/2015.");
dateSorting(dateList, sdf.parse("1/1/2015"));
System.out.println("Testing with 12/4/2015.");
dateSorting(dateList, sdf.parse("12/4/2015"));
}
And I got the following result:
Testing with 1/3/2015.
Previous index:1
Next index:2
Testing with 1/1/2015.
Next index:0
Testing with 12/4/2015.
Previous index:3
I believe this will be helpful for you.
Replace 17/11/2015 with Date.toString() (date iterator)
public static void main(String []args){
Date date = new Date();
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
try {
date = sdf.parse("17/11/2015");
Calendar cal = Calendar.getInstance();
cal.setTime(date);
System.out.println(cal.getTime());
cal.add(Calendar.DAY_OF_MONTH, 1);
System.out.println(cal.getTime());
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
These References will help you
Ref 1
Ref 2
try something like below code:
long current = newDate.getTime();
boolean flag = false;
for (int i =1; i < dateList.size(); i++){
long a = dateList.get(i-1).getTime(); long b = dateList.get(i).getTime();
if ( (a > current && b < current) || (a < current && b > current){
//newDate is in between index i-1 and i, set flag to true and do your stuff.
}
if(!flag) { //newDate did not fit between any indexes.
}
}
You should understand Calendar and Date APIs. It is preferable to use Calender API as most methods in Date are deprecated.
I think this is what you really expected:
First you have to crate a class implementing Comparator to sort your Date list :
public class DateSort implements Comparator<Date> {
#Override
public int compare(Date d1, Date d2) {
return (d1.getTime() > d2.getTime() ? 1 : -1);
}
}
Then you can get implement an algorithm to get closet max date and closest min date like below:
public class CompareDate {
public void compare(String oparation, List<Date> dateList, SimpleDateFormat sdf, Comparator<Date> comparator)
throws ParseException {
Collections.sort(dateList, comparator);
//using joda time api
DateTime givenDate = new DateTime(sdf.parse("01/03/2015"));
Days diff = Days.days(0);
OUTER:
for (Date date : dateList) {
Days newDiff = Days.daysBetween(new DateTime(date), givenDate);
switch (oparation) {
case "max-closet":
if (newDiff.getDays() < diff.getDays()) {
diff = newDiff;
System.out.println(oparation + " - " + sdf.format(date));
break OUTER;
}
break;
case "min-closet":
if (newDiff.getDays() > diff.getDays()) {
diff = newDiff;
System.out.println(oparation + " - " + sdf.format(date));
break OUTER;
}
break;
}
}
}
public static void main(String[] args) throws ParseException {
List<Date> dateList = new ArrayList<>();
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
dateList.add(sdf.parse("05/01/2015"));
dateList.add(sdf.parse("20/02/2015"));
dateList.add(sdf.parse("15/03/2015"));
dateList.add(sdf.parse("11/04/2015"));
new CompareDate().compare("max-closet", dateList, sdf, new DateSort());
new CompareDate().compare("min-closet", dateList, sdf, new DateSort().reversed());
//I m reversing the date list so I can sort dates to descending order.
}
}
Here I have used joda time api to get the different between two dates.

How to calculate a full days difference between two dates considering daylight savings in java

I need to get the full days between two dates in java (the dates are given in Date type) .
For example:
01/01/2015/12:00:00 - 01/02/2015/11:59:00 isn't a full day
and i need to consider daylight savings.
I know that jodatime lib does that but i reached the 65k method limit and i cant use jodatime lib.
i tried the millisecond diff way and the while loop that uses the "before" method:
Android/Java - Date Difference in days
I manage to figure it out:
i used some of this code - https://stackoverflow.com/a/28865648/3873513
and added some of mine:
public static int calcDaysDiff(Date day1, Date day2) {
Date d1 = new Date(day1.getTime());
Date d2 = new Date(day2.getTime());
Calendar date1 = Calendar.getInstance();
date1.setTime(d1);
Calendar date2 = Calendar.getInstance();
date2.setTime(d2);
//checks if the start date is later then the end date - gives 0 if it is
if (date1.get(Calendar.YEAR) >= date2.get(Calendar.YEAR)) {
if (date1.get(Calendar.DAY_OF_YEAR) >= date2.get(Calendar.DAY_OF_YEAR)) {
return 0;
}
}
//checks if there is a daylight saving change between the two dates
int offset = calcOffset(d1, d2);
if (date1.get(Calendar.YEAR) > date2.get(Calendar.YEAR)) {
//swap them
Calendar temp = date1;
date1 = date2;
date2 = temp;
}
return calcDaysDiffAux(date1, date2) + checkFullDay(date1, date2, offset);
}
// check if there is a 24 hour diff between the 2 dates including the daylight saving offset
public static int checkFullDay(Calendar day1, Calendar day2, int offset) {
if (day1.get(Calendar.HOUR_OF_DAY) <= day2.get(Calendar.HOUR_OF_DAY) + offset) {
return 0;
}
return -1;
}
// find the number of days between the 2 dates. check only the dates and not the hours
public static int calcDaysDiffAux(final Calendar day1, final Calendar day2) {
Calendar dayOne = (Calendar) day1.clone(),
dayTwo = (Calendar) day2.clone();
if (dayOne.get(Calendar.YEAR) == dayTwo.get(Calendar.YEAR)) {
return Math.abs(dayOne.get(Calendar.DAY_OF_YEAR) - dayTwo.get(Calendar.DAY_OF_YEAR));
} else {
int extraDays = 0;
while (dayTwo.get(Calendar.YEAR) > dayOne.get(Calendar.YEAR)) {
dayTwo.add(Calendar.YEAR, -1);
// getActualMaximum() important for leap years
extraDays += dayTwo.getActualMaximum(Calendar.DAY_OF_YEAR);
}
return extraDays - day1.get(Calendar.DAY_OF_YEAR) + day2.get(Calendar.DAY_OF_YEAR);
}
}
public class DateDiff {
public static void main(String[] av) {
SimpleDateFormat myFormat = new SimpleDateFormat("MM/dd/yyyy/HH:mm:ss");
String inputString1 = "01/01/2015/12:00:00";
String inputString2 = "01/02/2015/11:59:00";
try {
Date date1 = myFormat.parse(inputString1);
Date date2 = myFormat.parse(inputString2);
long diff = date2.getTime() - date1.getTime(); // Calculate the different
int days = (int) (diff / (1000*60*60*24)); // This convert milliseconds to days
System.out.println ("Days differ: " + days);
} catch (Exception e) {
e.printStackTrace();
}
}
}
The following code will calculate the two dates given, the result print is:
Days differ: 0

I need to store the all Saturdays and Sundays in one array and Reaming as another string Array

public class Sample {
public static void main(String[] args) {
int year = 2012;
// put the month you want
int month = Calendar.MARCH;
Calendar cal = new GregorianCalendar(year, month, 1);
do {
int day = cal.get(Calendar.DAY_OF_WEEK);
if (day == Calendar.SATURDAY || day == Calendar.SUNDAY) {
System.out.println(cal.get(Calendar.DAY_OF_MONTH));
}
cal.add(Calendar.DAY_OF_YEAR, 1);
} while (cal.get(Calendar.MONTH) == month);
}
By the above code i am getting all saturdays and sundays in a given month .I want store all these days in an array and the other days in another String array.
Not sure what you mean by reaming days, but if I understand the first part of your question correctly, this should work:
public static void main(String[] args) {
int year = 2012;
// put the month you want
int month = Calendar.MARCH;
Calendar cal = new GregorianCalendar(year, month, 1);
List<String> saturdaysAndSundays = new ArrayList<String>();
List<String> otherDays = new ArrayList<String>();
do {
int day = cal.get(Calendar.DAY_OF_WEEK);
String dayInMonth = Integer.toString(cal.get(Calendar.DAY_OF_MONTH));
if (day == Calendar.SATURDAY || day == Calendar.SUNDAY) {
saturdaysAndSundays.add(dayInMonth);
} else {
otherDays.add(dayInMonth);
}
cal.add(Calendar.DAY_OF_YEAR, 1);
} while (cal.get(Calendar.MONTH) == month);
//In case you really want an array:
String[] array = saturdaysAndSundays.toArray(new String[0]);
}

How do I calculate someone's age in Java?

I want to return an age in years as an int in a Java method.
What I have now is the following where getBirthDate() returns a Date object (with the birth date ;-)):
public int getAge() {
long ageInMillis = new Date().getTime() - getBirthDate().getTime();
Date age = new Date(ageInMillis);
return age.getYear();
}
But since getYear() is deprecated I'm wondering if there is a better way to do this? I'm not even sure this works correctly, since I have no unit tests in place (yet).
JDK 8 makes this easy and elegant:
public class AgeCalculator {
public static int calculateAge(LocalDate birthDate, LocalDate currentDate) {
if ((birthDate != null) && (currentDate != null)) {
return Period.between(birthDate, currentDate).getYears();
} else {
return 0;
}
}
}
A JUnit test to demonstrate its use:
public class AgeCalculatorTest {
#Test
public void testCalculateAge_Success() {
// setup
LocalDate birthDate = LocalDate.of(1961, 5, 17);
// exercise
int actual = AgeCalculator.calculateAge(birthDate, LocalDate.of(2016, 7, 12));
// assert
Assert.assertEquals(55, actual);
}
}
Everyone should be using JDK 8 by now. All earlier versions have passed the end of their support lives.
Check out Joda, which simplifies date/time calculations (Joda is also the basis of the new standard Java date/time apis, so you'll be learning a soon-to-be-standard API).
e.g.
LocalDate birthdate = new LocalDate (1970, 1, 20);
LocalDate now = new LocalDate();
Years age = Years.yearsBetween(birthdate, now);
which is as simple as you could want. The pre-Java 8 stuff is (as you've identified) somewhat unintuitive.
EDIT: Java 8 has something very similar and is worth checking out.
EDIT: This answer pre-dates the Java 8 date/time classes and is not current any more.
Modern answer and overview
a) Java-8 (java.time-package)
LocalDate start = LocalDate.of(1996, 2, 29);
LocalDate end = LocalDate.of(2014, 2, 28); // use for age-calculation: LocalDate.now()
long years = ChronoUnit.YEARS.between(start, end);
System.out.println(years); // 17
Note that the expression LocalDate.now() is implicitly related to the system timezone (which is often overlooked by users). For clarity it is generally better to use the overloaded method now(ZoneId.of("Europe/Paris")) specifying an explicit timezone (here "Europe/Paris" as example). If the system timezone is requested then my personal preference is to write LocalDate.now(ZoneId.systemDefault()) to make the relation to the system timezone clearer. This is more writing effort but makes reading easier.
b) Joda-Time
Please note that the proposed and accepted Joda-Time-solution yields a different computation result for the dates shown above (a rare case), namely:
LocalDate birthdate = new LocalDate(1996, 2, 29);
LocalDate now = new LocalDate(2014, 2, 28); // test, in real world without args
Years age = Years.yearsBetween(birthdate, now);
System.out.println(age.getYears()); // 18
I consider this as a small bug but the Joda-team has a different view on this weird behaviour and does not want to fix it (weird because the day-of-month of end date is smaller than of start date so the year should be one less). See also this closed issue.
c) java.util.Calendar etc.
For comparison see the various other answers. I would not recommend using these outdated classes at all because the resulting code is still errorprone in some exotic cases and/or way too complex considering the fact that the original question sounds so simple. In year 2015 we have really better libraries.
d) About Date4J:
The proposed solution is simple but will sometimes fail in case of leap years. Just evaluating the day of year is not reliable.
e) My own library Time4J:
This works similar to Java-8-solution. Just replace LocalDate by PlainDate and ChronoUnit.YEARS by CalendarUnit.YEARS. However, getting "today" requires an explicit timezone reference.
PlainDate start = PlainDate.of(1996, 2, 29);
PlainDate end = PlainDate.of(2014, 2, 28);
// use for age-calculation (today):
// => end = SystemClock.inZonalView(EUROPE.PARIS).today();
// or in system timezone: end = SystemClock.inLocalView().today();
long years = CalendarUnit.YEARS.between(start, end);
System.out.println(years); // 17
Calendar now = Calendar.getInstance();
Calendar dob = Calendar.getInstance();
dob.setTime(...);
if (dob.after(now)) {
throw new IllegalArgumentException("Can't be born in the future");
}
int year1 = now.get(Calendar.YEAR);
int year2 = dob.get(Calendar.YEAR);
int age = year1 - year2;
int month1 = now.get(Calendar.MONTH);
int month2 = dob.get(Calendar.MONTH);
if (month2 > month1) {
age--;
} else if (month1 == month2) {
int day1 = now.get(Calendar.DAY_OF_MONTH);
int day2 = dob.get(Calendar.DAY_OF_MONTH);
if (day2 > day1) {
age--;
}
}
// age is now correct
/**
* This Method is unit tested properly for very different cases ,
* taking care of Leap Year days difference in a year,
* and date cases month and Year boundary cases (12/31/1980, 01/01/1980 etc)
**/
public static int getAge(Date dateOfBirth) {
Calendar today = Calendar.getInstance();
Calendar birthDate = Calendar.getInstance();
int age = 0;
birthDate.setTime(dateOfBirth);
if (birthDate.after(today)) {
throw new IllegalArgumentException("Can't be born in the future");
}
age = today.get(Calendar.YEAR) - birthDate.get(Calendar.YEAR);
// If birth date is greater than todays date (after 2 days adjustment of leap year) then decrement age one year
if ( (birthDate.get(Calendar.DAY_OF_YEAR) - today.get(Calendar.DAY_OF_YEAR) > 3) ||
(birthDate.get(Calendar.MONTH) > today.get(Calendar.MONTH ))){
age--;
// If birth date and todays date are of same month and birth day of month is greater than todays day of month then decrement age
}else if ((birthDate.get(Calendar.MONTH) == today.get(Calendar.MONTH )) &&
(birthDate.get(Calendar.DAY_OF_MONTH) > today.get(Calendar.DAY_OF_MONTH ))){
age--;
}
return age;
}
I simply use the milliseconds in a year constant value to my advantage:
Date now = new Date();
long timeBetween = now.getTime() - age.getTime();
double yearsBetween = timeBetween / 3.15576e+10;
int age = (int) Math.floor(yearsBetween);
If you are using GWT you will be limited to using java.util.Date, here is a method that takes the date as integers, but still uses java.util.Date:
public int getAge(int year, int month, int day) {
Date now = new Date();
int nowMonth = now.getMonth()+1;
int nowYear = now.getYear()+1900;
int result = nowYear - year;
if (month > nowMonth) {
result--;
}
else if (month == nowMonth) {
int nowDay = now.getDate();
if (day > nowDay) {
result--;
}
}
return result;
}
It's perhaps surprising to note that you don't need to know how many days or months there are in a year or how many days are in those months, likewise, you don't need to know about leap years, leap seconds, or any of that stuff using this simple, 100% accurate method:
public static int age(Date birthday, Date date) {
DateFormat formatter = new SimpleDateFormat("yyyyMMdd");
int d1 = Integer.parseInt(formatter.format(birthday));
int d2 = Integer.parseInt(formatter.format(date));
int age = (d2-d1)/10000;
return age;
}
With the date4j library :
int age = today.getYear() - birthdate.getYear();
if(today.getDayOfYear() < birthdate.getDayOfYear()){
age = age - 1;
}
This is an improved version of the one above... considering that you want age to be an 'int'. because sometimes you don't want to fill your program with a bunch of libraries.
public int getAge(Date dateOfBirth) {
int age = 0;
Calendar born = Calendar.getInstance();
Calendar now = Calendar.getInstance();
if(dateOfBirth!= null) {
now.setTime(new Date());
born.setTime(dateOfBirth);
if(born.after(now)) {
throw new IllegalArgumentException("Can't be born in the future");
}
age = now.get(Calendar.YEAR) - born.get(Calendar.YEAR);
if(now.get(Calendar.DAY_OF_YEAR) < born.get(Calendar.DAY_OF_YEAR)) {
age-=1;
}
}
return age;
}
The correct answer using JodaTime is:
public int getAge() {
Years years = Years.yearsBetween(new LocalDate(getBirthDate()), new LocalDate());
return years.getYears();
}
You could even shorten it into one line if you like. I copied the idea from BrianAgnew's answer, but I believe this is more correct as you see from the comments there (and it answers the question exactly).
Try to copy this one in your code, then use the method to get the age.
public static int getAge(Date birthday)
{
GregorianCalendar today = new GregorianCalendar();
GregorianCalendar bday = new GregorianCalendar();
GregorianCalendar bdayThisYear = new GregorianCalendar();
bday.setTime(birthday);
bdayThisYear.setTime(birthday);
bdayThisYear.set(Calendar.YEAR, today.get(Calendar.YEAR));
int age = today.get(Calendar.YEAR) - bday.get(Calendar.YEAR);
if(today.getTimeInMillis() < bdayThisYear.getTimeInMillis())
age--;
return age;
}
I use this piece of code for age calculation ,Hope this helps ..no libraries used
private static DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd", Locale.getDefault());
public static int calculateAge(String date) {
int age = 0;
try {
Date date1 = dateFormat.parse(date);
Calendar now = Calendar.getInstance();
Calendar dob = Calendar.getInstance();
dob.setTime(date1);
if (dob.after(now)) {
throw new IllegalArgumentException("Can't be born in the future");
}
int year1 = now.get(Calendar.YEAR);
int year2 = dob.get(Calendar.YEAR);
age = year1 - year2;
int month1 = now.get(Calendar.MONTH);
int month2 = dob.get(Calendar.MONTH);
if (month2 > month1) {
age--;
} else if (month1 == month2) {
int day1 = now.get(Calendar.DAY_OF_MONTH);
int day2 = dob.get(Calendar.DAY_OF_MONTH);
if (day2 > day1) {
age--;
}
}
} catch (ParseException e) {
e.printStackTrace();
}
return age ;
}
The fields birth and effect are both date fields:
Calendar bir = Calendar.getInstance();
bir.setTime(birth);
int birthNm = bir.get(Calendar.DAY_OF_YEAR);
int birthYear = bir.get(Calendar.YEAR);
Calendar eff = Calendar.getInstance();
eff.setTime(effect);
This basically a modification of John O's solution without using depreciated methods. I spent a fair amount of time trying to get his code to work in in my code. Maybe this will save others that time.
What about this one?
public Integer calculateAge(Date date) {
if (date == null) {
return null;
}
Calendar cal1 = Calendar.getInstance();
cal1.setTime(date);
Calendar cal2 = Calendar.getInstance();
int i = 0;
while (cal1.before(cal2)) {
cal1.add(Calendar.YEAR, 1);
i += 1;
}
return i;
}
String dateofbirth has the date of birth. and format is whatever (defined in the following line):
org.joda.time.format.DateTimeFormatter formatter = org.joda.time.format.DateTimeFormat.forPattern("mm/dd/yyyy");
Here is how to format:
org.joda.time.DateTime birthdateDate = formatter.parseDateTime(dateofbirth );
org.joda.time.DateMidnight birthdate = new org.joda.time.DateMidnight(birthdateDate.getYear(), birthdateDate.getMonthOfYear(), birthdateDate.getDayOfMonth() );
org.joda.time.DateTime now = new org.joda.time.DateTime();
org.joda.time.Years age = org.joda.time.Years.yearsBetween(birthdate, now);
java.lang.String ageStr = java.lang.String.valueOf (age.getYears());
Variable ageStr will have the years.
Elegant, seemingly correct, timestamp difference based variant of Yaron Ronen solution.
I am including a unit test to prove when and why it is not correct. It is impossible due (to possibly) different number of leap days (and seconds) in any timestamp difference. The discrepancy should be max +-1 day (and one second) for this algorithm, see test2(), whereas Yaron Ronen solution based on completely constant assumption of timeDiff / MILLI_SECONDS_YEAR can differ 10 days for a 40ty year old, nevertheless this variant is incorrect too.
It is tricky, because this improved variant, using formula diffAsCalendar.get(Calendar.YEAR) - 1970, returns correct results most of the time, as number of leap years in on average same between two dates.
/**
* Compute person's age based on timestamp difference between birth date and given date
* and prove it is INCORRECT approach.
*/
public class AgeUsingTimestamps {
public int getAge(Date today, Date dateOfBirth) {
long diffAsLong = today.getTime() - dateOfBirth.getTime();
Calendar diffAsCalendar = Calendar.getInstance();
diffAsCalendar.setTimeInMillis(diffAsLong);
return diffAsCalendar.get(Calendar.YEAR) - 1970; // base time where timestamp=0, precisely 1/1/1970 00:00:00
}
final static DateFormat df = new SimpleDateFormat("dd.MM.yyy HH:mm:ss");
#Test
public void test1() throws Exception {
Date dateOfBirth = df.parse("10.1.2000 00:00:00");
assertEquals(87, getAge(df.parse("08.1.2088 23:59:59"), dateOfBirth));
assertEquals(87, getAge(df.parse("09.1.2088 23:59:59"), dateOfBirth));
assertEquals(88, getAge(df.parse("10.1.2088 00:00:01"), dateOfBirth));
}
#Test
public void test2() throws Exception {
// between 2000 and 2021 was 6 leap days
// but between 1970 (base time) and 1991 there was only 5 leap days
// therefore age is switched one day earlier
// See http://www.onlineconversion.com/leapyear.htm
Date dateOfBirth = df.parse("10.1.2000 00:00:00");
assertEquals(20, getAge(df.parse("08.1.2021 23:59:59"), dateOfBirth));
assertEquals(20, getAge(df.parse("09.1.2021 23:59:59"), dateOfBirth)); // ERROR! returns incorrect age=21 here
assertEquals(21, getAge(df.parse("10.1.2021 00:00:01"), dateOfBirth));
}
}
public class CalculateAge {
private int age;
private void setAge(int age){
this.age=age;
}
public void calculateAge(Date date){
Calendar calendar=Calendar.getInstance();
Calendar calendarnow=Calendar.getInstance();
calendarnow.getTimeZone();
calendar.setTime(date);
int getmonth= calendar.get(calendar.MONTH);
int getyears= calendar.get(calendar.YEAR);
int currentmonth= calendarnow.get(calendarnow.MONTH);
int currentyear= calendarnow.get(calendarnow.YEAR);
int age = ((currentyear*12+currentmonth)-(getyears*12+getmonth))/12;
setAge(age);
}
public int getAge(){
return this.age;
}
/**
* Compute from string date in the format of yyyy-MM-dd HH:mm:ss the age of a person.
* #author Yaron Ronen
* #date 04/06/2012
*/
private int computeAge(String sDate)
{
// Initial variables.
Date dbDate = null;
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
// Parse sDate.
try
{
dbDate = (Date)dateFormat.parse(sDate);
}
catch(ParseException e)
{
Log.e("MyApplication","Can not compute age from date:"+sDate,e);
return ILLEGAL_DATE; // Const = -2
}
// Compute age.
long timeDiff = System.currentTimeMillis() - dbDate.getTime();
int age = (int)(timeDiff / MILLI_SECONDS_YEAR); // MILLI_SECONDS_YEAR = 31558464000L;
return age;
}
Here is the java code to calculate age in year, month and days.
public static AgeModel calculateAge(long birthDate) {
int years = 0;
int months = 0;
int days = 0;
if (birthDate != 0) {
//create calendar object for birth day
Calendar birthDay = Calendar.getInstance();
birthDay.setTimeInMillis(birthDate);
//create calendar object for current day
Calendar now = Calendar.getInstance();
Calendar current = Calendar.getInstance();
//Get difference between years
years = now.get(Calendar.YEAR) - birthDay.get(Calendar.YEAR);
//get months
int currMonth = now.get(Calendar.MONTH) + 1;
int birthMonth = birthDay.get(Calendar.MONTH) + 1;
//Get difference between months
months = currMonth - birthMonth;
//if month difference is in negative then reduce years by one and calculate the number of months.
if (months < 0) {
years--;
months = 12 - birthMonth + currMonth;
} else if (months == 0 && now.get(Calendar.DATE) < birthDay.get(Calendar.DATE)) {
years--;
months = 11;
}
//Calculate the days
if (now.get(Calendar.DATE) > birthDay.get(Calendar.DATE))
days = now.get(Calendar.DATE) - birthDay.get(Calendar.DATE);
else if (now.get(Calendar.DATE) < birthDay.get(Calendar.DATE)) {
int today = now.get(Calendar.DAY_OF_MONTH);
now.add(Calendar.MONTH, -1);
days = now.getActualMaximum(Calendar.DAY_OF_MONTH) - birthDay.get(Calendar.DAY_OF_MONTH) + today;
} else {
days = 0;
if (months == 12) {
years++;
months = 0;
}
}
}
//Create new Age object
return new AgeModel(days, months, years);
}
Easiest way without any libraries:
long today = new Date().getTime();
long diff = today - birth;
long age = diff / DateUtils.YEAR_IN_MILLIS;
With Java 8, we can calculate a person age with one line of code:
public int calCAge(int year, int month,int days){
return LocalDate.now().minus(Period.of(year, month, days)).getYear();
}
Simple solution in kotlin.
fun getAgeOfUser(date: String?) : Int {
if(date.isNullOrEmpty()) return 0
val calendar = Calendar.getInstance()
val cYear = calendar.get(Calendar.YEAR)
val cDay = calendar.get(Calendar.DAY_OF_YEAR)
val dob = Calendar.getInstance()
dob.timeInMillis = date.toLong()
val bYear = dob.get(Calendar.YEAR)
val bDay = dob.get(Calendar.DAY_OF_YEAR)
var age = cYear - bYear
if(cDay < bDay) age--
return age
}
public int getAge(Date dateOfBirth)
{
Calendar now = Calendar.getInstance();
Calendar dob = Calendar.getInstance();
dob.setTime(dateOfBirth);
if (dob.after(now))
{
throw new IllegalArgumentException("Can't be born in the future");
}
int age = now.get(Calendar.YEAR) - dob.get(Calendar.YEAR);
if (now.get(Calendar.DAY_OF_YEAR) < dob.get(Calendar.DAY_OF_YEAR))
{
age--;
}
return age;
}
import java.io.*;
class AgeCalculator
{
public static void main(String args[])
{
InputStreamReader ins=new InputStreamReader(System.in);
BufferedReader hey=new BufferedReader(ins);
try
{
System.out.println("Please enter your name: ");
String name=hey.readLine();
System.out.println("Please enter your birth date: ");
String date=hey.readLine();
System.out.println("please enter your birth month:");
String month=hey.readLine();
System.out.println("please enter your birth year:");
String year=hey.readLine();
System.out.println("please enter current year:");
String cYear=hey.readLine();
int bDate = Integer.parseInt(date);
int bMonth = Integer.parseInt(month);
int bYear = Integer.parseInt(year);
int ccYear=Integer.parseInt(cYear);
int age;
age = ccYear-bYear;
int totalMonth=12;
int yourMonth=totalMonth-bMonth;
System.out.println(" Hi " + name + " your are " + age + " years " + yourMonth + " months old ");
}
catch(IOException err)
{
System.out.println("");
}
}
}
public int getAge(String birthdate, String today){
// birthdate = "1986-02-22"
// today = "2014-09-16"
// String class has a split method for splitting a string
// split(<delimiter>)
// birth[0] = 1986 as string
// birth[1] = 02 as string
// birth[2] = 22 as string
// now[0] = 2014 as string
// now[1] = 09 as string
// now[2] = 16 as string
// **birth** and **now** arrays are automatically contains 3 elements
// split method here returns 3 elements because of yyyy-MM-dd value
String birth[] = birthdate.split("-");
String now[] = today.split("-");
int age = 0;
// let us convert string values into integer values
// with the use of Integer.parseInt(<string>)
int ybirth = Integer.parseInt(birth[0]);
int mbirth = Integer.parseInt(birth[1]);
int dbirth = Integer.parseInt(birth[2]);
int ynow = Integer.parseInt(now[0]);
int mnow = Integer.parseInt(now[1]);
int dnow = Integer.parseInt(now[2]);
if(ybirth < ynow){ // has age if birth year is lesser than current year
age = ynow - ybirth; // let us get the interval of birth year and current year
if(mbirth == mnow){ // when birth month comes, it's ok to have age = ynow - ybirth if
if(dbirth > dnow) // birth day is coming. need to subtract 1 from age. not yet a bday
age--;
}else if(mbirth > mnow){ age--; } // birth month is comming. need to subtract 1 from age
}
return age;
}
import java.time.LocalDate;
import java.time.ZoneId;
import java.time.Period;
public class AgeCalculator1 {
public static void main(String args[]) {
LocalDate start = LocalDate.of(1970, 2, 23);
LocalDate end = LocalDate.now(ZoneId.systemDefault());
Period p = Period.between(start, end);
//The output of the program is :
//45 years 6 months and 6 days.
System.out.print(p.getYears() + " year" + (p.getYears() > 1 ? "s " : " ") );
System.out.print(p.getMonths() + " month" + (p.getMonths() > 1 ? "s and " : " and ") );
System.out.print(p.getDays() + " day" + (p.getDays() > 1 ? "s.\n" : ".\n") );
}//method main ends here.
}
I appreciate all correct answers but this is the kotlin answer for the same question
I hope would be helpful to kotlin developers
fun calculateAge(birthDate: Date): Int {
val now = Date()
val timeBetween = now.getTime() - birthDate.getTime();
val yearsBetween = timeBetween / 3.15576e+10;
return Math.floor(yearsBetween).toInt()
}

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