This question already has answers here:
Date and time conversion to some other Timezone in java
(11 answers)
Closed 8 years ago.
I need Date strings sent to sencha frontend of the form:
'Wed Jan 10 2007 15:05:01 GMT-0600 (Central Standard Time)'
I'm unable to get the right text formatter string to output in this form.
Has anyone converted a Java Date object to this format ?
PS: not a duplicate of time lag while converting between timezones,
Its a query to get Dates in a specific format required for frontends using sencha which isn't answered by the "dd-MM-yyyy HH:mm:ss" format used in this post
This is the format pattern you need:
"EEE MMM dd yyyy HH:mm:ss zZ (zzzzzzz)"
Related
This question already has answers here:
Convert String to Date format in andorid
(2 answers)
Closed 1 year ago.
I'm trying to convert timestamps to date, I got this exception:
java.text.ParseException: Unparseable date: "1604328483716"
at java.base/java.text.DateFormat.parse(DateFormat.java:395)
All the timestamps values that I have, having a format like this 1604328483716
Your formatter is set up to handle the format "EEE, d MMM yyyy HH:mm:ss Z". "1604328483716" isn't remotely in that format.
The value "1604328483716" looks like the string version of a milliseconds-since-The-Epoch value. If so, convert it to a long (Long.parseLong) and use new Date(theLongValue), which will give you a Date instance for Monday November 2nd 2020 14:48:03 GMT (or whatever that is in your local timezone).
You might also consider using the newer date/time API in the java.time package, rather than java.util.Date.
1604328483716
It is timestamp: https://www.unixtimestamp.com/?ref=dtf.ru
So, simply do:
long modificationTime = rec.getJsonNumber("modificationTime").lngValue();
Date date = new Date(modificationTime);
This question already has answers here:
How can I convert a date in YYYYMMDDHHMMSS format to epoch or unix time?
(2 answers)
Changing String date format
(4 answers)
Change date format in a Java string
(22 answers)
Closed 3 years ago.
I am currently facing a problem when it comes to some Java methods that weren't explained to me in lectures very well. I need to write a program that accepts user-inputted strings (particularly a date) in yyyymmddhhss format, which should then convert to hh:mm Month day, year.
E.g. 201901151500 outputs: "03:00 PM January 15, 2019".
Currently, in my program, I have accepted the user's input and implemented a method that returns an error message if the inputted format is invalid.
Any tips on where to go from here? Advice is greatly appreciated-- thank you!
If you are using Java 8 you can use java.time API like so :
String input = "201901151500";
LocalDateTime dt = LocalDateTime.parse(input, DateTimeFormatter.ofPattern("uuuuMMddHHmm"));
String output = dt.format(DateTimeFormatter.ofPattern("hh:mm a MMMM dd, uuuu"));
>> output = 03:00 PM janvier 15, 2019
Use the DateTimeFormatter as defined here: https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatter.html
Pay attention to the parse method. You can define a formatter that takes in a string and then returns it in a certain way, almost any way you choose.
Here is the LocalDataTime class:
https://docs.oracle.com/javase/8/docs/api/java/time/LocalDateTime.html
Example code:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy MM dd");
LocalDateTime local = LocalDateTime.parse("2004 12 25", formatter);
This question already has answers here:
want current date and time in "dd/MM/yyyy HH:mm:ss.SS" format
(11 answers)
Change the format of Date Java [closed]
(2 answers)
Closed 4 years ago.
I have the following piece of code:
System.out.println(array[9]);
Date d = df.parse(array[9]);
System.out.println(d.toString());
and the result of this looks like the following:
01.01.2017
Sun Jan 01 00:00:00 CET 2017
My DateFormatter:
DateFormat df = new SimpleDateFormat("dd.MM.yyyy",Locale.GERMANY);
So my question is now why I get the wrong format.
First result is a string, which I must convert to date.
But I got the wrong format, not the German one (dd.MM.yyyy).
What's wrong?
In your example you should use df.format(d) if you plan to convert Date to String. The default Date.toString() method will use the predefined format which you can't control.
This question already has answers here:
Java string to date conversion
(17 answers)
Calendar date to yyyy-MM-dd format in java
(11 answers)
java.util.Date format conversion yyyy-mm-dd to mm-dd-yyyy
(8 answers)
Closed 4 years ago.
I have a string e.g. Thu May 10 15:48:23 IST 2018. How to convert this string in the form of Calendar object with format 2018-05-10 15:48:23.84.
Start by using having a look at DateTimeFormatter and Parsing and Formatting for more details about how to parse and format date/time values in Java 8+
Based on your examples, something like...
String inValue = "Thu May 10 15:48:23 IST 2018";
DateTimeFormatter inFormatter = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss z yyyy", Locale.ENGLISH);
LocalDateTime ldt = LocalDateTime.parse(inValue, inFormatter);
DateTimeFormatter outFormatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SS", Locale.ENGLISH);
String outValue = outFormatter.format(ldt);
System.out.println(outValue);
Will print 2018-05-10 15:48:23.00
Thank you for your response. I actually want the end result as Calendar Object with required format, not a string.
Calendar is effectively deprecated, you shouldn't be using it anymore. Even if you're not using Java 8+, you should be using the ThreeTen Backport API
Calendar (and Date and all other "date/time" class) are just containers of a value representing some point in time, they do not have any kind of "formatting" capabilities of their own. This is why the API has formatting classes. Keep you date/time values represented as appropriate classes until you need to display them, at that point, you should format the value to a String
This question already has answers here:
Java SimpleDateFormat Pattern for JavaScript Date
(4 answers)
Closed 5 years ago.
I'm trying to parse a date string with a GMT+100
new SimpleDateFormat("EEE MMM dd yyyy HH:mm:ss").parse("Thu Apr 23 2015 11:30:49 GMT+0100")
Comes out as
Thu Apr 23 11:30:49 UTC 2015
If I add z or Z or X to the format, it's unparseable. If I don't add it, it's off by the offset, one hour.
What is the right way to parse this date?
--
Update: this differs from Java SimpleDateFormat Pattern for JavaScript Date in two ways: 1) this question is pure java and would have accepted answers other than those using SimpleDateFormat (i.e. new Java 8 features), and 2) the solution here is different to the other question.
Your expresssion should be EEE MMM dd yyyy HH:mm:ss 'GMT'Z(including the quotes), so your code is as follows:
new SimpleDateFormat("EEE MMM dd yyyy HH:mm:ss 'GMT'Z").parse("Thu Apr 23 2015 11:30:49 GMT+0100")
HOW THIS WORKS
According to the docs, anything passed in between single quotes(') in SimpleDateFormat pattern is not interpolated, but is assumed be just a part of the date format to be ignored while parsing.
And the equivalent of +0100 in SimpleDateFormat pattern terms is Z