This question already has answers here:
want current date and time in "dd/MM/yyyy HH:mm:ss.SS" format
(11 answers)
Change the format of Date Java [closed]
(2 answers)
Closed 4 years ago.
I have the following piece of code:
System.out.println(array[9]);
Date d = df.parse(array[9]);
System.out.println(d.toString());
and the result of this looks like the following:
01.01.2017
Sun Jan 01 00:00:00 CET 2017
My DateFormatter:
DateFormat df = new SimpleDateFormat("dd.MM.yyyy",Locale.GERMANY);
So my question is now why I get the wrong format.
First result is a string, which I must convert to date.
But I got the wrong format, not the German one (dd.MM.yyyy).
What's wrong?
In your example you should use df.format(d) if you plan to convert Date to String. The default Date.toString() method will use the predefined format which you can't control.
Related
This question already has answers here:
Convert String to Date format in andorid
(2 answers)
Closed 1 year ago.
I'm trying to convert timestamps to date, I got this exception:
java.text.ParseException: Unparseable date: "1604328483716"
at java.base/java.text.DateFormat.parse(DateFormat.java:395)
All the timestamps values that I have, having a format like this 1604328483716
Your formatter is set up to handle the format "EEE, d MMM yyyy HH:mm:ss Z". "1604328483716" isn't remotely in that format.
The value "1604328483716" looks like the string version of a milliseconds-since-The-Epoch value. If so, convert it to a long (Long.parseLong) and use new Date(theLongValue), which will give you a Date instance for Monday November 2nd 2020 14:48:03 GMT (or whatever that is in your local timezone).
You might also consider using the newer date/time API in the java.time package, rather than java.util.Date.
1604328483716
It is timestamp: https://www.unixtimestamp.com/?ref=dtf.ru
So, simply do:
long modificationTime = rec.getJsonNumber("modificationTime").lngValue();
Date date = new Date(modificationTime);
This question already has answers here:
How can I convert a date in YYYYMMDDHHMMSS format to epoch or unix time?
(2 answers)
Changing String date format
(4 answers)
Change date format in a Java string
(22 answers)
Closed 3 years ago.
I am currently facing a problem when it comes to some Java methods that weren't explained to me in lectures very well. I need to write a program that accepts user-inputted strings (particularly a date) in yyyymmddhhss format, which should then convert to hh:mm Month day, year.
E.g. 201901151500 outputs: "03:00 PM January 15, 2019".
Currently, in my program, I have accepted the user's input and implemented a method that returns an error message if the inputted format is invalid.
Any tips on where to go from here? Advice is greatly appreciated-- thank you!
If you are using Java 8 you can use java.time API like so :
String input = "201901151500";
LocalDateTime dt = LocalDateTime.parse(input, DateTimeFormatter.ofPattern("uuuuMMddHHmm"));
String output = dt.format(DateTimeFormatter.ofPattern("hh:mm a MMMM dd, uuuu"));
>> output = 03:00 PM janvier 15, 2019
Use the DateTimeFormatter as defined here: https://docs.oracle.com/javase/8/docs/api/java/time/format/DateTimeFormatter.html
Pay attention to the parse method. You can define a formatter that takes in a string and then returns it in a certain way, almost any way you choose.
Here is the LocalDataTime class:
https://docs.oracle.com/javase/8/docs/api/java/time/LocalDateTime.html
Example code:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy MM dd");
LocalDateTime local = LocalDateTime.parse("2004 12 25", formatter);
This question already has answers here:
java date format yyyy-mm-dd.hh.MM.ss.ms
(3 answers)
Closed 5 years ago.
I am trying to parse the date from a given String. My input string is 2017-08-11, which represents Aug 11th 2017 (Basically yyyy-mm-dd format)
However if I run
new SimpleDateFormat("yyyy-mm-dd").parse("2017-08-11")
I get Wed Jan 11 00:08:00 GMT 2017
Why is this? I have created a test program at: http://ideone.com/dHe0ZA
M (capital M) represents month and m (small m) represents minute in java.
So the format you have specified is wrong.
Try
new SimpleDateFormat("yyyy-MM-dd").parse("2017-08-11")
You can see more details about the formats here.
This question already has answers here:
Convert String to java.util.Date
(4 answers)
Closed 7 years ago.
I read more questions on the web but I dont' find a solution yet.
I have a String like "14/05/1994", exactly in this format.
I need to covert it into java.util.Date in the same format.
I tried:
DateFormat df = new SimpleDateFormat("dd/MM/yyyy");
Date dataFrom = new Date();
dataFrom = df.format("14/05/1994");
But the result is: Sat May 14 00:00:00 CET 1994
It's possibile have as a result: 14/05/1994 not as a String, but as java.util.Date?
A java.util.Date doesn't have a format. It's just a date.
When you print it out, e.g. using toString(), it uses a default format, which is what you're seeing. But you have that date.
Date dataFrom = new Date();
dataFrom = df.format("14/05/1994");
I don't think that can be your code because DateFormat.format accepts a Date and returns a String, not the other way around. You might mean df.parse, which would get you the results you describe. But if you take your SimpleDateFormat and use its format method on the Date, then you should get back out 14/05/1994 as you want. A java.util.Date doesn't have a format, though.
This question already has answers here:
want current date and time in "dd/MM/yyyy HH:mm:ss.SS" format
(11 answers)
Closed 9 years ago.
I need to java.util.Calendar object with dd/mm/yyyy HH:ss:MM format. Please help me. I am getting always below format.
Thu Nov 21 14:12:57 EST 2013.
I have need the dd/mm/yyyy HH:ss:MM format in calendar object while fetch the getTime() method.
Refer below tutorial about Java Date, Calendar and Time API - Tutorial.
http://www.vogella.com/articles/JavaDateTimeAPI/article.html