Develop Reference

Getting a null pointer exception from my JSON parser

Error converting result java.lang.NullPointerException: lock == null
Error parsing data org.json.JSONException: End of input at character 0
of
can anyone tell me if whether this work?? I have connected my laptop with my wifi and mobile also with that. both having the same ipv4 address, and in the android code i have mentioned that address. How will my mobile know to contact the laptop where the database is stored?
This is my Android code JSON parser
public JSONObject makeHttpRequest(String url, String method,List<NameValuePair> params) {
try {
if(method.equals("POST"))
{
DefaultHttpClient httpClient = new DefaultHttpClient();
Log.e("herehai"," "+is);
HttpPost httpPost = new HttpPost(url);
Log.e("hereiam"," "+httpPost);
httpPost.setEntity(new UrlEncodedFormEntity(params));
HttpResponse httpResponse = httpClient.execute(httpPost);//<-----Error is here
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
Log.e("here"," "+is);
}
else if(method.equals("GET"))
{
DefaultHttpClient httpClient = new DefaultHttpClient();
String paramString = URLEncodedUtils.format(params, "utf-8");
url += "?" + paramString;
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
Log.e("here1"," "+is);
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine())!=null)
{
sb.append(line + "\n");
}
is.close();
json = sb.toString();
Log.e("errors",json);
}
catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
//return json string
return jObj;
}
Can someone tell me why is the null pointer exception is throwing up?

Try this
<?php
$con=mysqli_connect("localhost","root","") or die(mysql_error());
mysqli_select_db($con,"something")or die("Unable to connect 1");
$response = array();
$response["success"] = 0;
$email = $_POST['email'];
$passwd = $_POST['pass'];
$query1 = mysqli_query($con,"SELECT pass FROM userinfo where email='$email'");
$res= mysqli_fetch_assoc($query1);
if($res)
{
if($passwd!=$res['pass'])
{
$response["success"]=1;
print(json_encode($response));
}
else
{
$response["success"]=0;
print(json_encode($response));
}
}
else
{
$response["success"]=0;
print(json_encode($res));
}
?>

Getting partial Json response

I am getting a server side json response to load my menu, I tried twice and it gave this error message (the Error parsing data org.json.JSONException).
the reason for that is I'm getting the response partially, in both attempts i got different responses as shown in the images. i think I'm not getting the complete json response, getting only partial response. what should I do to get the complete response.
this is my code
#Override
protected JSONObject doInBackground(String... params) {
String path = null;
String response = null;
HashMap<String, String> request = null;
JSONObject requestJson = null;
DefaultHttpClient httpClient = null;
HttpPost httpPost = null;
StringEntity requestString = null;
ResponseHandler<String> responseHandler = null;
// get the email and password
try {
path = "http://xxxxxxxxxxxxxxxxxxx";
new URL(path);
} catch (MalformedURLException e) {
e.printStackTrace();
}
try {
// set the API request
request = new HashMap<String, String>();
request.put(new String("CetegoryCode"), "P");
request.entrySet().iterator();
// Store locations in JSON
requestJson = new JSONObject(request);
httpClient = new DefaultHttpClient();
httpPost = new HttpPost(path);
requestString = new StringEntity(requestJson.toString());
// sets the post request as the resulting string
httpPost.setEntity(requestString);
httpPost.setHeader("Content-type", "application/json");
// Handles the response
responseHandler = new BasicResponseHandler();
response = httpClient.execute(httpPost, responseHandler);
responseJson = new JSONObject(response);
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
try {
responseJson = new JSONObject(response);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
return responseJson;
}
this is the image

If your response is returning JsonArray thn need to set tht response string jsonarray. create instance of jsonarray and fill it up with the response.
if its normal get ws thn you can append parameters in url like query string
protected Void doInBackground(String... urls) {
/************ Make Post Call To Web Server ***********/
BufferedReader reader = null;
try {
// Append parameters with values eg ?CetegoryCode=p
String path = "http://xxxxxxxxxxxxxxxxxxx?CetegoryCode=p";
URL url = new URL(path);
URLConnection conn = url.openConnection();
conn.setDoOutput(true);
OutputStreamWriter wr = new OutputStreamWriter(
conn.getOutputStream());
wr.write(data);
wr.flush();
// Get the server response
reader = new BufferedReader(new InputStreamReader(
conn.getInputStream()));
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "");
}
Content = sb.toString();
JSONArray jArray = new JSONArray(Content);
if (jArray != null)
Log.e("Data", "" + jArray.length());
} catch (Exception ex) {
Error = ex.getMessage();
} finally {
try {
reader.close();
}
catch (Exception ex) {
}
}
/*****************************************************/
return null;
}

Try out below code to parse and get JSON response:
public static JSONObject getJSONFromUrl(String url) {
// Making HTTP request
try {
URL url1 = new URL(url);
HttpURLConnection conn = (HttpURLConnection) url1.openConnection();
conn.setReadTimeout(10000 /* milliseconds */);
conn.setConnectTimeout(15000 /* milliseconds */);
conn.setRequestMethod("POST");
conn.setDoInput(true);
// Starts the query
conn.connect();
InputStream stream = conn.getInputStream();
json = convertStreamToString(stream);
stream.close();
} catch (Exception e) {
e.printStackTrace();
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
static String convertStreamToString(java.io.InputStream is) {
java.util.Scanner s = new java.util.Scanner(is).useDelimiter("\\A");
return s.hasNext() ? s.next() : "";
}
Use getJSONFromUrl method as below in your code:
#Override
protected JSONObject doInBackground(String... params) {
String path = null;
String response = null;
HashMap<String, String> request = null;
try {
responseJson = new JSONObject(response);
responseJson =getJSONFromUrl("http://xxxxxxxxxxxxxxxxxxx?CetegoryCode=p");
}catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
return responseJson;
}

pass parameters via http post method

I have two text boxes, 1 for username and the other for password.
I wanted to pass what the user enters into the edit texts with the post method
String request = "https://beta135.hamarisuraksha.com/web/webservice/HamariSurakshaMobile.asmx/getIMSafeAccountInfoOnLogon";
URL url;
try {
url = new URL(request);
HttpURLConnection connection = (HttpURLConnection) url
.openConnection();
connection.setDoOutput(true);
connection.setDoInput(true);
connection.setInstanceFollowRedirects(false);
connection.setRequestMethod("POST");
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded;");// boundary="+CommonFunctions.boundary
connection.setUseCaches(false);
DataOutputStream wr = new DataOutputStream(
connection.getOutputStream());
wr.writeBytes(urlParameters);
wr.flush();
wr.close();
int responseCode = connection.getResponseCode();
/*
* System.out.println("\nSending 'POST' request to URL : " +
* url); System.out.println("Post parameters : " +
* urlParameters);
*/
System.out.println("Response Code : " + responseCode);
InputStream errorstream = connection.getErrorStream();
BufferedReader br = null;
if (errorstream == null) {
InputStream inputstream = connection.getInputStream();
br = new BufferedReader(new InputStreamReader(inputstream));
} else {
br = new BufferedReader(new InputStreamReader(errorstream));
}
String response = "";
String nachricht;
while ((nachricht = br.readLine()) != null) {
response += nachricht;
}
// print result
// System.out.println(response.toString());
return response.toString();
} catch (MalformedURLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
return null;
} catch (ProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
return null;
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
return null;
}
}

if i am getting your question correctly , you need to pass your parameters to a web service. in my case i have implemented a method to get the web service response by giving the url and the values as parameters. i think this will help you.
public JSONObject getJSONFromUrl(JSONObject parm,String url) throws JSONException {
InputStream is = null;
JSONObject jObj = null;
String json = "";
// Making HTTP request
try {
// defaultHttpClient
/*JSONObject parm = new JSONObject();
parm.put("agencyId", 27);
parm.put("caregiverPersonId", 47);*/
/* if(!(jObj.isNull("d"))){
jObj=null;
}
*/
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.addHeader("Content-Type", "application/json; charset=utf-8");
HttpEntity body = new StringEntity(parm.toString(), "utf8");
httpPost.setEntity(body);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
/* String response = EntityUtils.toString(httpEntity);
Log.w("myApp", response);*/
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// JSONObject jObj2 = new JSONObject(json);
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
this method take two parameters. one is the url, other one is the values that we should send to the web service. and simply returns the json object. hope this will help you
EDIT
to pass your username and password just use below code
JsonParser jp = new JsonParser(); // create instance for the jsonparse class
String caregiverID = MainActivity.confirm.toString();
JSONObject param = new JSONObject();
JSONObject job = new JSONObject();
try {
param.put("username", yourUserNAme);
job = jp.getJSONFromUrl(param, yourURL);

How can i multiple picture send with android

hello i need when i click to button "send" i send all selected picture ( i have all this picture in table picture[]
in PHP i do this
<input id="uploadImageAct" type="file" name="uploadImageAct[]" data-max-size="2048" accept="image/x-png, image/gif, image/jpeg" style="visibility: hidden" multiple="multiple">
and in android for just one picture i do this but i don't know how i do for multi picture (I put all my picture in table picture[] )
this solution is for one image for FileBody and me i need multi image in one FileBody
public JSONObject post(String url, ArrayList<NameValuePair> nameValuePairs) {
HttpClient httpClient = new DefaultHttpClient();
HttpContext localContext = new BasicHttpContext();
HttpPost httpPost = new HttpPost(url);
try {
MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
for(int index=0; index < nameValuePairs.size(); index++) {
if(nameValuePairs.get(index).getName().equalsIgnoreCase("uploadFile")) {
// If the key equals to "image", we use FileBody to transfer the data
entity.addPart(nameValuePairs.get(index).getName(), new FileBody(new File (nameValuePairs.get(index).getValue())));
} else {
// Normal string data
Charset chars = Charset.forName("UTF-8");
entity.addPart(nameValuePairs.get(index).getName(), new StringBody(nameValuePairs.get(index).getValue(),chars));
}
}
httpPost.setEntity(entity);
HttpResponse response = httpClient.execute(httpPost, localContext);
HttpEntity httpEntity = response.getEntity();
is = httpEntity.getContent();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
How can I change this function so that I can do this
thanks :)

You can upload multiple files in one request along with other string parameters in Android.
For that, you have to include 2 libraries into your project build path, apache-mime4j-0.6.jar and httpmime-4.0.1.jar.
private void doFileUpload(){
File file1 = new File(selectedPath1);
File file2 = new File(selectedPath2);
String urlString = "Your server location";
try
{
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost(urlString);
FileBody bin1 = new FileBody(file1);
FileBody bin2 = new FileBody(file2);
MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("uploadedfile1", bin1);
reqEntity.addPart("uploadedfile2", bin2);
reqEntity.addPart("user", new StringBody("User"));
post.setEntity(reqEntity);
HttpResponse response = client.execute(post);
resEntity = response.getEntity();
final String response_str = EntityUtils.toString(resEntity);
if (resEntity != null) {
Log.i("RESPONSE",response_str);
runOnUiThread(new Runnable(){
public void run() {
try {
res.setTextColor(Color.GREEN);
res.setText("n Response from server : n " + response_str);
Toast.makeText(getApplicationContext(),"Upload Complete. Check the server uploads directory.", Toast.LENGTH_LONG).show();
} catch (Exception e) {
e.printStackTrace();
}
}
});
}
}
Or simply visit CoderzHeaven, it may help you.

Android : JSON Parser with async task (GET and POST methods)

Just want to check whether this JSON Parser with async task is it correctly done? When I put this code into my Eclipse, this (method.equals("POST") was underline red. And it state that the 'method' cannot be solved. Any suggestion or help in this? Thank you.
public class JSONParser {
static InputStream is = null;
static JSONObject jObj = null;
static String json = "";
String url=null;
List<NameValuePair> nvp=null;
// constructor
public JSONParser() {
}
// function get json from url
// by making HTTP POST or GET method
public JSONObject makeHttpRequest(String url, String method,
List<NameValuePair> params) {
BackGroundTask Task= new BackGroundTask(url, method, params);
try {
return Task.execute().get();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
return null;
} catch (ExecutionException e) {
// TODO Auto-generated catch block
e.printStackTrace();
return null;
}
}
public class BackGroundTask extends AsyncTask<String, String, JSONObject>{
List<NameValuePair> postparams= new ArrayList<NameValuePair>();
String URL=null;
public BackGroundTask(String url, String method, List<NameValuePair> params) {
URL=url;
postparams=params;
}
#Override
protected JSONObject doInBackground(String... params) {
// TODO Auto-generated method stub
// Making HTTP request
try {
// Making HTTP request
// check for request method
if(method.equals("POST")){
// request method is POST
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(postparams));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}else if(method == "GET"){
// request method is GET
DefaultHttpClient httpClient = new DefaultHttpClient();
String paramString = URLEncodedUtils.format(postparams, "utf-8");
url += "?" + paramString;
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
}
}

You forgot to declare method property in your BackGroundTask class.
EDIT Like this:
public class BackGroundTask extends AsyncTask<String, String, JSONObject>{
List<NameValuePair> postparams= new ArrayList<NameValuePair>();
String URL=null;
String method = null;
public BackGroundTask(String url, String method, List<NameValuePair> params) {
URL=url;
postparams=params;
this.method = method;
}
#Override
protected JSONObject doInBackground(String... params) {
// TODO Auto-generated method stub
// Making HTTP request
try {
// Making HTTP request
// check for request method
if(method.equals("POST")){
// request method is POST
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(postparams));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}else if(method == "GET"){
// request method is GET
DefaultHttpClient httpClient = new DefaultHttpClient();
String paramString = URLEncodedUtils.format(postparams, "utf-8");
url += "?" + paramString;
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
}
}

You need to set method as a class variable within BackGroundTask. You are passing it into the constructor but not going anything with it. Set it the same way you have done with url and postparams.