I have a homework that the teacher test if it's corrects by checking it's output using this website moodle.caseine.org, so to test my code the program execute these lines and compare the output with the expected one, this is the test :
Tas t = new Tas();
Random r = new Random(123);
for(int i =0; i<10000;i++)t.inser(r.nextInt());
for(int i =0;i<10000;i++)System.out.println(t.supprMax());
System.out.println(t);
And my Heap (Tas) class:
package td1;
import java.util.ArrayList;
import java.util.List;
public class Tas {
private List<Integer> t;
public Tas() {
t = new ArrayList<>();
}
public Tas(ArrayList<Integer> tab) {
t = new ArrayList<Integer>(tab);
}
public static int getFilsGauche(int i) {
return 2 * i + 1;
}
public static int getFilsDroit(int i) {
return 2 * i + 2;
}
public static int getParent(int i) {
return (i - 1) / 2;
}
public boolean estVide() {
return t.isEmpty();
}
#Override
public String toString() {
String str = "";
int size = t.size();
if (size > 0) {
str += "[" + t.get(0);
str += toString(0);
str += "]";
}
return str;
}
public boolean testTas() {
int size = t.size();
int check = 0;
if (size > 0) {
for (int i = 0; i < t.size(); i++) {
if (getFilsGauche(i) < size) {
if (t.get(i) < t.get(getFilsGauche(i))) {
check++;
}
}
if (getFilsDroit(i) < size) {
if (t.get(i) < t.get(getFilsDroit(i))) {
check++;
}
}
}
}
return check == 0;
}
public String toString(int i) {
String str = "";
int size = t.size();
if (getFilsGauche(i) < size) {
str += "[";
str += t.get(getFilsGauche(i));
str += toString(getFilsGauche(i));
str += "]";
}
if (getFilsDroit(i) < size) {
str += "[";
str += t.get(getFilsDroit(i));
str += toString(getFilsDroit(i));
str += "]";
}
return str;
}
//insert value and sort
public void inser(int value) {
t.add(value);
int index = t.size() - 1;
if (index > 0) {
inserCheck(index); // O(log n)
}
}
public void inserCheck(int i) {
int temp = 0;
int parent = getParent(i);
if (parent >= 0 && t.get(i) > t.get(parent)) {
temp = t.get(parent);
t.set(parent, t.get(i));
t.set(i, temp);
inserCheck(parent);
}
}
//switch position of last element is list with first (deletes first and return it)
public int supprMax() {
int size = t.size();
int max = 0;
if (size > 0) {
max = t.get(0);
t.set(0, t.get(size - 1));
t.remove(size - 1);
supprMax(0);
}
else {
throw new IllegalStateException();
}
return max;
}
public void supprMax(int i) {
int size = t.size();
int temp = 0;
int index = i;
if (getFilsGauche(i) < size && t.get(getFilsGauche(i)) > t.get(index)) {
index = getFilsGauche(i);
}
if (getFilsDroit(i) < size && t.get(getFilsDroit(i)) > t.get(index)) {
index = getFilsDroit(i);
}
if (index != i) {
temp = t.get(index);
t.set(index, t.get(i));
t.set(i, temp);
supprMax(index);
}
}
public static void tri(int[] tab) {
Tas tas = new Tas();
for (int i = 0; i < tab.length; i++) {
tas.inser(tab[i]);
}
for (int i = 0; i < tab.length; i++) {
tab[i] = tas.supprMax();
}
}
}
The last 3 lines of the test are :
-2145024521
-2147061786
-2145666206
But the last 3 of my code are :
-2145024521
-2145666206
-2147061786
The problem are probably with the inser and supprMax methods.
I hate to get a bad grade just because of 3 lines placement, because it is a program that verify the code, it dosn't care the the solution was close, it's still says it's wrong.
I have a String Unitedin.
Here the char "n" is occurred at index 1 and index 6 ; The Difference between index number is 5
Similarly for "i" which occurs at index 2 and index 5. The Difference is 3.
I need to Print the chars according to ascending order of there Difference at the OutPut.
Challenge is I cannot use any type of array list or List or hashMap or set or linked hash etc
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
StringBuilder temp = new StringBuilder();
StringBuilder output = new StringBuilder();
System.out.println("Enter a string : ");
String instring = in.next();
for (int i = 0; i < instring.length(); i++) {
for (int j = i + 1; j < instring.length(); j++) {
if (instring.charAt(i) == instring.charAt(j)) {
temp.append(instring.charAt(i));
}
}
}
for (int m = 0; m < temp.length(); m++) {
for (int p = m + 1; p < temp.length(); p++) {
if (m == temp.length() - 1) {
output.append(temp.charAt(m));
} else if (instring.lastIndexOf(temp.charAt(m), 0) >= instring.lastIndexOf(temp.charAt(p), 0)) {
output.append(temp.charAt(p));
} else {
output.append(temp.charAt(m));
}
}
}
System.out.println(output);
}
I am Getting output as i. Can anyone help me? Expected output = in
Smth. like that. This is not the best performance, but it does not use Collections:
public static String foo(String str) {
str = str.toLowerCase();
int[] letters = new int[26];
Arrays.fill(letters, Integer.MIN_VALUE);
for (int i = 0; i < str.length(); i++)
if (letters[str.charAt(i) - 'a'] == Integer.MIN_VALUE)
letters[str.charAt(i) - 'a'] = -i;
for (int i = str.length() - 1; i >= 0; i--)
if (letters[str.charAt(i) - 'a'] != Integer.MIN_VALUE)
letters[str.charAt(i) - 'a'] += i;
return IntStream.range(0, letters.length)
.filter(i -> letters[i] > 0)
.boxed()
.sorted(Comparator.comparingInt(i -> letters[i]))
.map(i -> String.valueOf((char)('a' + i)))
.collect(Collectors.joining());
}
In case you do not want to use Streams, then the second part it:
int cur = 1;
boolean checkNext;
StringBuilder buf = new StringBuilder();
do {
checkNext = false;
for (int i = 0; i < letters.length; i++) {
if (letters[i] < cur)
continue;
checkNext = true;
if (letters[i] == cur)
buf.append((char)('a' + i));
}
cur++;
} while (checkNext);
return buf.toString();
import java.util.TreeMap;
import java.util.Scanner;
public class SameCharOccurenceDiff {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int firstIndex = 0;
int lastIndex = 0;
TreeMap<Integer,Character> outputMap = new TreeMap<Integer,Character>();
String stringInput = sc.next();
StringBuilder strBuilder = new StringBuilder();
sc.close();
for (int i = 0; i < stringInput.length(); i++) {
char chr = stringInput.charAt(i);
firstIndex = stringInput.indexOf(chr);
lastIndex = stringInput.lastIndexOf(chr);
int diff = lastIndex-firstIndex;
if( diff > 0) {
outputMap.put(diff,chr);
}
}
for (char c : outputMap.values()) {
strBuilder.append(c);
}
System.out.println(strBuilder);
}
}
Edit : ( Without using TreeMap )
import java.util.Arrays;
import java.util.Comparator;
import java.util.Scanner;
public class SameCharOccurenceDiff {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int firstIndex = 0;
int lastIndex = 0;
int count = 0;
String stringInput = sc.next().toLowerCase();
String[] stringInputArr = new String[stringInput.length()];
StringBuilder strBuilder = new StringBuilder();
sc.close();
for (int i = 0; i < stringInput.length(); i++) {
char chr = stringInput.charAt(i);
firstIndex = stringInput.indexOf(chr);
lastIndex = stringInput.lastIndexOf(chr);
int diff = lastIndex - firstIndex;
if( diff > 0 && !inArray(stringInputArr,diff+""+chr)) {
stringInputArr[count] = diff+""+chr;
count++;
}
}
//System.out.println(Arrays.toString(stringInputArr));
Arrays.sort(stringInputArr,0,count,new Comparator<String>() {
public int compare(String s1, String s2) {
int num1 = Integer.parseInt(s1.replaceAll("[^\\d]", ""));
int num2 = Integer.parseInt(s2.replaceAll("[^\\d]", ""));
return num1 - num2;
}
});
//System.out.println(Arrays.toString(stringInputArr));
for (String str : stringInputArr) {
if(str == null)break;
strBuilder.append(str.replaceAll("\\d", ""));
}
System.out.println(strBuilder);
}
public static boolean inArray(String[] arr,String chr) {
boolean isPresent = false;
for (int i = 0; i < arr.length; i++) {
if(arr[i] == null)break;
if(arr[i].equalsIgnoreCase(chr)) {
isPresent = true;
break;
}
}
return isPresent;
}
}
I have opened an account for Ridit, one of 7-years-old students learning Java at SPOJ. The first task i gave to him was PALIN -The Next Palindrome. Here is the link to this problem- PALIN- The next Palindrome- SPOJAfter i explained it to him, he was able to solve it mostly except removing the leading zeros, which i did. Following is his solution of the problem -
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
// TODO Auto-generated method stub
try {
Scanner in = new Scanner(System.in);
int t = Integer.parseInt(in.nextLine());
String[] numbersInString = new String[t];
for (int i = 0; i <t; i++) {
String str = in.nextLine();
numbersInString[i] = removeLeadingZeros(str);
}
for (int i = 0 ; i<t; i++) {
int K = Integer.parseInt(numbersInString[i]);
int answer = findTheNextPalindrome(K);
System.out.println(answer);
}
}catch(Exception e) {
return;
}
}
static boolean isPalindrome(int x) {
String str = Integer.toString(x);
int length = str.length();
StringBuffer strBuff = new StringBuffer();
for(int i = length - 1;i>=0;i--) {
char ch = str.charAt(i);
strBuff.append(ch);
}
String str1 = strBuff.toString();
if(str.equals(str1)) {
return true;
}
return false;
}
static int findTheNextPalindrome(int K) {
for(int i = K+1;i<9999999; i++) {
if(isPalindrome(i) == true) {
return i;
}
}
return -1;
}
static String removeLeadingZeros(String str) {
String retString = str;
if(str.charAt(0) != '0') {
return retString;
}
return removeLeadingZeros(str.substring(1));
}
}
It is giving correct answer in Eclipse on his computer, but it is failing in SPOJ. If someone helps this little boy in his first submission, it will definitely make him very happy. I couldn't find any problem with this solution... Thank you in advance...
This might be helpful
import java.io.IOException;
import java.util.Scanner;
public class ThenNextPallindrom2 {
public static void main(String[] args) throws IOException {
// TODO Auto-generated method stub
int t = 0;
Scanner sc = new Scanner(System.in);
if(sc.hasNextInt()) {
t = sc.nextInt();
}
sc.nextLine();
int[] arr, arr2;
while(t > 0) {
t--;
String s = sc.nextLine();
arr = getStringToNumArray(s);
if(all9(arr)) {
arr2 = new int[arr.length + 1];
arr2[0] = 1;
for(int i=0;i<arr.length;i++) {
arr2[i+1] = 0;
}
arr2[arr2.length -1] = 1;
arr = arr2;
} else{
int mid = arr.length/ 2;
int left = mid-1;
int right = arr.length % 2 == 1 ? mid + 1 : mid;
boolean left_small = false;
while(left >= 0 && arr[left] == arr[right]) {
left--;
right++;
}
if(left < 0 || arr[left] < arr[right]) left_small = true;
if(!left_small) {
while(left >= 0) {
arr[right++] = arr[left--];
}
} else {
mid = arr.length/ 2;
left = mid-1;
int carry = 1;
if(arr.length % 2 == 0) {
right = mid;
} else {
arr[mid] += carry;
carry = arr[mid]/10;
arr[mid] %= 10;
right = mid + 1;
}
while(left >= 0) {
arr[left] += carry;
carry = arr[left] / 10;
arr[left] %= 10;
arr[right++] = arr[left--];
}
}
}
printArray(arr);
}
}
public static boolean all9(int[] arr) {
for(int i=0;i<arr.length;i++) {
if(arr[i] != 9)return false;
}
return true;
}
public static void printArray(int[] arr) {
for(int i=0;i<arr.length;i++) {
System.out.print(arr[i]);
}
System.out.println();
}
public static int[] getStringToNumArray(String s) {
int[] arr = new int[s.length()];
for(int i=0; i<s.length();i++) {
arr[i] = Integer.parseInt(String.valueOf(s.charAt(i)));
}
return arr;
}
}
import java.util.InputMismatchException;
import java.util.Scanner;
import java.util.Stack;
public class TSPNearestNeighbour {
{
private final Stack<Integer> stack;
private int numberOfNodes;
public TSPNearestNeighbour()
{
stack = new Stack<Integer>();
}
public void tsp(int adjacencyMatrix[][])
{
numberOfNodes = adjacencyMatrix[1].length - 1;
int[] visited = new int[numberOfNodes + 1];
visited[1] = 1;
stack.push(1);
int element, dst = 0, i,cost=0;
int min = Integer.MAX_VALUE;
boolean minFlag = false;
System.out.print(1 + "\t");
while (!stack.isEmpty())
{
element = stack.peek();
i = 1;
min = Integer.MAX_VALUE;
while (i <= numberOfNodes)
{
if (adjacencyMatrix[element][i] > 1 && visited[i] == 0)
{
if (min > adjacencyMatrix[element][i])
{
min = adjacencyMatrix[element][i];
cost=cost+adjacencyMatrix[element][i];
dst = i;
minFlag = true;
}
}
i++;
}
if (minFlag)
{
visited[dst] = 1;
stack.push(dst);
System.out.print( dst + "\t");
minFlag = false;
continue;
}
stack.pop();
}
System.out.println("total cost" +cost);
}
public static void main(String args[])
{
int number_of_nodes;
Scanner scanner = null;
try
{
System.out.println("Enter the number of nodes in the graph");
scanner = new Scanner(System.in);
number_of_nodes = scanner.nextInt();
int adjacency_matrix[][] = new int[number_of_nodes + 1][number_of_nodes + 1];
System.out.println("Enter the adjacency matrix");
for (int i = 1; i <= number_of_nodes; i++)
{
for (int j = 1; j <= number_of_nodes; j++)
{
adjacency_matrix[i][j] = scanner.nextInt();
}
}
for (int i = 1; i <= number_of_nodes; i++)
{
for (int j = 1; j <= number_of_nodes; j++)
{
if (adjacency_matrix[i][j] == 1 && adjacency_matrix[j][i] == 0)
{
adjacency_matrix[j][i] = 1;
}
}
}
System.out.println("the citys are visited as follows");
TSPNearestNeighbour tspNearestNeighbour = new TSPNearestNeighbour();
tspNearestNeighbour.tsp(adjacency_matrix);
} catch (InputMismatchException inputMismatch)
{
System.out.println("Wrong Input format");
}
scanner.close();
}
}
> illegal start of expression in the line:
> **private final Stack<Integer> stack;**
You have 2 open braces
public class TSPNearestNeighbour { {
remove one and may be you get your code compiled
I am struggling with a "find supersequence" algorithm.
The input is for set of strings
String A = "caagccacctacatca";
String B = "cgagccatccgtaaagttg";
String C = "agaacctgctaaatgctaga";
the result would be properly aligned set of strings (and next step should be merge)
String E = "ca ag cca cc ta cat c a";
String F = "c gag ccat ccgtaaa g tt g";
String G = " aga acc tgc taaatgc t a ga";
Thank you for any advice (I am sitting on this task for more than a day)
after merge the superstring would be
cagagaccatgccgtaaatgcattacga
The definition of supersequence in "this case" would be something like
The string R is contained in supersequence S if and only if all characters in a string R are present in supersequence S in the order in which they occur in the input sequence R.
The "solution" i tried (and again its the wrong way of doing it) is:
public class Solution4
{
static boolean[][] map = null;
static int size = 0;
public static void main(String[] args)
{
String A = "caagccacctacatca";
String B = "cgagccatccgtaaagttg";
String C = "agaacctgctaaatgctaga";
Stack data = new Stack();
data.push(A);
data.push(B);
data.push(C);
Stack clone1 = data.clone();
Stack clone2 = data.clone();
int length = 26;
size = max_size(data);
System.out.println(size+" "+length);
map = new boolean[26][size];
char[] result = new char[size];
HashSet<String> chunks = new HashSet<String>();
while(!clone1.isEmpty())
{
String a = clone1.pop();
char[] residue = make_residue(a);
System.out.println("---");
System.out.println("OLD : "+a);
System.out.println("RESIDUE : "+String.valueOf(residue));
String[] r = String.valueOf(residue).split(" ");
for(int i=0; i<r.length; i++)
{
if(r[i].equals(" ")) continue;
//chunks.add(spaces.substring(0,i)+r[i]);
chunks.add(r[i]);
}
}
for(String chunk : chunks)
{
System.out.println("CHUNK : "+chunk);
}
}
static char[] make_residue(String candidate)
{
char[] result = new char[size];
for(int i=0; i<candidate.length(); i++)
{
int pos = find_position_for(candidate.charAt(i),i);
for(int j=i; j<pos; j++) result[j]=' ';
if(pos==-1) result[candidate.length()-1] = candidate.charAt(i);
else result[pos] = candidate.charAt(i);
}
return result;
}
static int find_position_for(char character, int offset)
{
character-=((int)'a');
for(int i=offset; i<size; i++)
{
// System.out.println("checking "+String.valueOf((char)(character+((int)'a')))+" at "+i);
if(!map[character][i])
{
map[character][i]=true;
return i;
}
}
return -1;
}
static String move_right(String a, int from)
{
return a.substring(0, from)+" "+a.substring(from);
}
static boolean taken(int character, int position)
{ return map[character][position]; }
static void take(char character, int position)
{
//System.out.println("taking "+String.valueOf(character)+" at "+position+" (char_index-"+(character-((int)'a'))+")");
map[character-((int)'a')][position]=true;
}
static int max_size(Stack stack)
{
int max=0;
while(!stack.isEmpty())
{
String s = stack.pop();
if(s.length()>max) max=s.length();
}
return max;
}
}
Finding any common supersequence is not a difficult task:
In your example possible solution would be something like:
public class SuperSequenceTest {
public static void main(String[] args) {
String A = "caagccacctacatca";
String B = "cgagccatccgtaaagttg";
String C = "agaacctgctaaatgctaga";
int iA = 0;
int iB = 0;
int iC = 0;
char[] a = A.toCharArray();
char[] b = B.toCharArray();
char[] c = C.toCharArray();
StringBuilder sb = new StringBuilder();
while (iA < a.length || iB < b.length || iC < c.length) {
if (iA < a.length && iB < b.length && iC < c.length && (a[iA] == b[iB]) && (a[iA] == c[iC])) {
sb.append(a[iA]);
iA++;
iB++;
iC++;
}
else if (iA < a.length && iB < b.length && a[iA] == b[iB]) {
sb.append(a[iA]);
iA++;
iB++;
}
else if (iA < a.length && iC < c.length && a[iA] == c[iC]) {
sb.append(a[iA]);
iA++;
iC++;
}
else if (iB < b.length && iC < c.length && b[iB] == c[iC]) {
sb.append(b[iB]);
iB++;
iC++;
} else {
if (iC < c.length) {
sb.append(c[iC]);
iC++;
}
else if (iB < b.length) {
sb.append(b[iB]);
iB++;
} else if (iA < a.length) {
sb.append(a[iA]);
iA++;
}
}
}
System.out.println("SUPERSEQUENCE " + sb.toString());
}
}
However the real problem to solve is to find the solution for the known problem of Shortest Common Supersequence http://en.wikipedia.org/wiki/Shortest_common_supersequence,
which is not that easy.
There is a lot of researches which concern the topic.
See for instance:
http://www.csd.uwo.ca/~lila/pdfs/Towards%20a%20DNA%20solution%20to%20the%20Shortest%20Common%20Superstring%20Problem.pdf
http://www.ncbi.nlm.nih.gov/pubmed/14534185
You can try finding the shortest combination like this
static final char[] CHARS = "acgt".toCharArray();
public static void main(String[] ignored) {
String A = "caagccacctacatca";
String B = "cgagccatccgtaaagttg";
String C = "agaacctgctaaatgctaga";
String expected = "cagagaccatgccgtaaatgcattacga";
List<String> ABC = new Combination(A, B, C).findShortest();
System.out.println("expected: " + expected.length());
System.out.println("Merged: " + ABC.get(0).length() + " " + ABC);
}
static class Combination {
int shortest = Integer.MAX_VALUE;
List<String> shortestStr = new ArrayList<>();
char[][] chars;
int[] pos;
int count = 0;
Combination(String... strs) {
chars = new char[strs.length][];
pos = new int[strs.length];
for (int i = 0; i < strs.length; i++) {
chars[i] = strs[i].toCharArray();
}
}
public List<String> findShortest() {
findShortest0(new StringBuilder(), pos);
return shortestStr;
}
private void findShortest0(StringBuilder sb, int[] pos) {
if (allDone(pos)) {
if (sb.length() < shortest) {
shortestStr.clear();
shortest = sb.length();
}
if (sb.length() <= shortest)
shortestStr.add(sb.toString());
count++;
if (++count % 100 == 1)
System.out.println("Searched " + count + " shortest " + shortest);
return;
}
if (sb.length() + maxLeft(pos) > shortest)
return;
int[] pos2 = new int[pos.length];
int i = sb.length();
sb.append(' ');
for (char c : CHARS) {
if (!tryChar(pos, pos2, c)) continue;
sb.setCharAt(i, c);
findShortest0(sb, pos2);
}
sb.setLength(i);
}
private int maxLeft(int[] pos) {
int maxLeft = 0;
for (int i = 0; i < pos.length; i++) {
int left = chars[i].length - pos[i];
if (left > maxLeft)
maxLeft = left;
}
return maxLeft;
}
private boolean allDone(int[] pos) {
for (int i = 0; i < chars.length; i++)
if (pos[i] < chars[i].length)
return false;
return true;
}
private boolean tryChar(int[] pos, int[] pos2, char c) {
boolean matched = false;
for (int i = 0; i < chars.length; i++) {
pos2[i] = pos[i];
if (pos[i] >= chars[i].length) continue;
if (chars[i][pos[i]] == c) {
pos2[i]++;
matched = true;
}
}
return matched;
}
}
prints many solutions which are shorter than the one suggested.
expected: 28
Merged: 27 [acgaagccatccgctaaatgctatcga, acgaagccatccgctaaatgctatgca, acgaagccatccgctaacagtgctaga, acgaagccatccgctaacatgctatga, acgaagccatccgctaacatgcttaga, acgaagccatccgctaacatgtctaga, acgaagccatccgctacaagtgctaga, acgaagccatccgctacaatgctatga, acgaagccatccgctacaatgcttaga, acgaagccatccgctacaatgtctaga, acgaagccatcgcgtaaatgctatcga, acgaagccatcgcgtaaatgctatgca, acgaagccatcgcgtaacagtgctaga, acgaagccatcgcgtaacatgctatga, acgaagccatcgcgtaacatgcttaga, acgaagccatcgcgtaacatgtctaga, acgaagccatcgcgtacaagtgctaga, acgaagccatcgcgtacaatgctatga, acgaagccatcgcgtacaatgcttaga, acgaagccatcgcgtacaatgtctaga, acgaagccatgccgtaaatgctatcga, acgaagccatgccgtaaatgctatgca, acgaagccatgccgtaacagtgctaga, acgaagccatgccgtaacatgctatga, acgaagccatgccgtaacatgcttaga, acgaagccatgccgtaacatgtctaga, acgaagccatgccgtacaagtgctaga, acgaagccatgccgtacaatgctatga, acgaagccatgccgtacaatgcttaga, acgaagccatgccgtacaatgtctaga, cagaagccatccgctaaatgctatcga, cagaagccatccgctaaatgctatgca, cagaagccatccgctaacagtgctaga, cagaagccatccgctaacatgctatga, cagaagccatccgctaacatgcttaga, cagaagccatccgctaacatgtctaga, cagaagccatccgctacaagtgctaga, cagaagccatccgctacaatgctatga, cagaagccatccgctacaatgcttaga, cagaagccatccgctacaatgtctaga, cagaagccatcgcgtaaatgctatcga, cagaagccatcgcgtaaatgctatgca, cagaagccatcgcgtaacagtgctaga, cagaagccatcgcgtaacatgctatga, cagaagccatcgcgtaacatgcttaga, cagaagccatcgcgtaacatgtctaga, cagaagccatcgcgtacaagtgctaga, cagaagccatcgcgtacaatgctatga, cagaagccatcgcgtacaatgcttaga, cagaagccatcgcgtacaatgtctaga, cagaagccatgccgtaaatgctatcga, cagaagccatgccgtaaatgctatgca, cagaagccatgccgtaacagtgctaga, cagaagccatgccgtaacatgctatga, cagaagccatgccgtaacatgcttaga, cagaagccatgccgtaacatgtctaga, cagaagccatgccgtacaagtgctaga, cagaagccatgccgtacaatgctatga, cagaagccatgccgtacaatgcttaga, cagaagccatgccgtacaatgtctaga, cagagaccatccgctaaatgctatcga, cagagaccatccgctaaatgctatgca, cagagaccatccgctaacagtgctaga, cagagaccatccgctaacatgctatga, cagagaccatccgctaacatgcttaga, cagagaccatccgctaacatgtctaga, cagagaccatccgctacaagtgctaga, cagagaccatccgctacaatgctatga, cagagaccatccgctacaatgcttaga, cagagaccatccgctacaatgtctaga, cagagaccatcgcgtaaatgctatcga, cagagaccatcgcgtaaatgctatgca, cagagaccatcgcgtaacagtgctaga, cagagaccatcgcgtaacatgctatga, cagagaccatcgcgtaacatgcttaga, cagagaccatcgcgtaacatgtctaga, cagagaccatcgcgtacaagtgctaga, cagagaccatcgcgtacaatgctatga, cagagaccatcgcgtacaatgcttaga, cagagaccatcgcgtacaatgtctaga, cagagaccatgccgtaaatgctatcga, cagagaccatgccgtaaatgctatgca, cagagaccatgccgtaacagtgctaga, cagagaccatgccgtaacatgctatga, cagagaccatgccgtaacatgcttaga, cagagaccatgccgtaacatgtctaga, cagagaccatgccgtacaagtgctaga, cagagaccatgccgtacaatgctatga, cagagaccatgccgtacaatgcttaga, cagagaccatgccgtacaatgtctaga, cagagccatcctagctaaagtgctaga, cagagccatcctagctaaatgctatga, cagagccatcctagctaaatgcttaga, cagagccatcctagctaaatgtctaga, cagagccatcctgactaaagtgctaga, cagagccatcctgactaaatgctatga, cagagccatcctgactaaatgcttaga, cagagccatcctgactaaatgtctaga, cagagccatcctgctaaatgctatcga, cagagccatcctgctaaatgctatgca, cagagccatcctgctaacagtgctaga, cagagccatcctgctaacatgctatga, cagagccatcctgctaacatgcttaga, cagagccatcctgctaacatgtctaga, cagagccatcctgctacaagtgctaga, cagagccatcctgctacaatgctatga, cagagccatcctgctacaatgcttaga, cagagccatcctgctacaatgtctaga]