I'm writing a Java program to clean some data.
I'm passing it the files I need, but the first file is ignored!
Minimum code to reproduce the issue:
public class Classifier {
public static void main(String[] args) throws IOException {
System.out.println(args[0]);
for (String s : args) {
System.out.println(s);
}
}
}
I'm running it with the following Command-Line Argument:
java Classifier < March.csv February.csv
And the output I'm receiving is:
February.csv February.csv
Can someone explain why this is?
The < March.csv is being interpreted by the shell as an input redirect. The contents of March.csv are sent to your program's standard input, which you are ignoring. This happens in the shell, before your Java program is even started. So, only February.csv is being sent as a command line argument to main.
Remove that <, so that all command-line arguments you intended to send to main are sent.
< operator redirects this file to stdin to this Java process
so
if you just have
java Classifier < March.csv
and try to read arguments, you would see none and if you read stdin you would read the file content
Related
Is there a way to read data from the command prompt? I have a java program that relies on 4 input variables from an outside source. These variables are returned to the command prompt after I run a javascript program but i need a way to pass these variables from the command prompt into my java program, any help would be greatly appreciated!
While executing java program pass the parameters and all the parameters should be separated by space.
java programName parameter1 parameter2 parameter3 parameter4
This parameters would be available in your main method argument
public static void main(String[] args){
//This args array would be containing all four values, i.e. its length would be 4 and you easily iterate values.
for(int i=0; i<args.length; i++){
System.out.println("Argument " + i + " is " + args[i]);
}
Follow the link:
Command-Line Arguments - The Java™ Tutorials : https://docs.oracle.com/javase/tutorial/essential/environment/cmdLineArgs.html
shared by #BackSlash.
It has all the content which would help you to clear all your doubts.
The content from the link is quoted below:
Displaying Command-Line Arguments passed by user from command-line to a Java program
The following example displays each of its command-line arguments on a
line by itself:
public class DisplayCommandLineParameters {
public static void main (String[] args) {
for (String s: args) {
System.out.println(s);
}
}
}
To compile the program: From the Command Prompt, navigate to the directory containing your .java file, say C:\test, by typing the cd
command below.
C:\Users\username>cd c:\test
C:\test>
Assuming the file, say DisplayCommandLineParameters.java, is in the
current working directory, type the javac command below to compile it.
C:\test>javac DisplayCommandLineParameters.java
C:\test>
If everything went well, you should see no error messages.
To run the program: The following example shows how a user might run the class.
C:\test>java DisplayCommandLineParameters Hello Java World
Output:
Hello
Java
World
Note that the application displays each word — Hello, Java and World —
on a line by itself. This is because the space character separates
command-line arguments.
To have Hello, Java and World interpreted as a single argument, the
user would join them by enclosing them within quotation marks.
C:\test>java DisplayCommandLineParameters "Hello Java World"
Output: Hello Java World
Here is a strange problem I ran into:
I create a single program to print all the received args, Here is the code:
public class Test {
public static void main(String[] args) {
for (int i = 0; i < args.length; i ++) {
System.out.println(args[i]);
}
}
}
Then I built a jar file of it and ran the following command:
java -jar test.jar test&1
However, it didn't print "test&1" as expected. The result of it is:
test
'1'is not recognized as an internal or external command,operable program or batch file.
So my question is: what is the seperation of args? If I really need to receive "test&1", what should I do?
Thanks!
It's nothing to do with Java. The & character is special to the Windows shell (I can tell it's Windows from the error message): It separates two commands on one line, so what you're doing is telling the shell to run java -jar test.jar test and then run 1. If you want to pass test&1 to Java, you'll have to put it in quotes:
java -jar test.jar "test&1"
The & is also special on *nix shells (but in a different way, it runs the command in a sub-shell). There, you could use quotes as above, or put an \ before the & instead. But not on Windows.
I do have some serious troubles understanding the console in java. I am running Eclipse, and I wanted to write a small program which prompts a few text messages to the console and receives a few strings as input arguments from it. Problem is: When I run my program, it opens the command line window properly, but my outputs are only printed on the Eclipse-Console.
In some way, I do understand why this is the case. The Command Line Windows expects commands, and not just some kind of a string or something. But how do i manage to output my Strings into the Command Line Window and read Strings from it, and not just commands.
Or am I doing it the wrong way? Do I have to open another "Console" where all my messages will be prompted and from which i can read strings a user wrote?
This is the code i use to open a command line window on start:
public static void main(String args[]) throws Exception {
Process process = new ProcessBuilder(new String[] { "cmd", "/C",
"start", "cmd" }).start();
System.out.println(process.waitFor());
Edit: I did still not manage to get this to working. Somehow, when I compiled the program, and I run it, it properly opens a command window, but no messages are posted there. Seems like "System.out.println("xxx") does not have any effect on this window.
There's no "console" specified by your program, but an stdin, stdout and stderr for input, output and error output. When you run your program from windows, these streams are bound to a command window, and if you run it in eclipse, they will be associated to the eclipse console. To give a more obscure example, ff you were running it through ssh, the streams would be associated to ssh, and ssh associated to your command window, and so on.
So, you're not doing anything wrong, you just need to run the program from the command line if you want stdout and stdin to come from that command window.
How do you open a command window, by the way?
You might want to read through this page:
http://pages.cs.wisc.edu/~hasti/cs368/JavaTutorial/NOTES/JavaIO_Scanner.html
Basically what you need to is create the input stream, tell the user to input something, and then get the input. E.g.
private static Scanner newScanner = new Scanner(System.in);
public static void main(String[] args) {
System.out.println("Put your input here: ");
String inputValue = newScanner.nextLine();
System.out.println(inputValue);
}
Just remember to import the scanner library!
The static method main, which receives an array of strings. The array should have two elements: the path where the files are located (at index 0), and the name of the files to process (at index 1). For example, if the name was “Walmart” then the program should use “Walmart.cmd” (from which it will read commands) and “Walmart.pro” (from which it will read/write products).
I don't want anyone to write the code for me because this is something I need to learn. However I've been reading this through and the wording is confusing. If someone could help me understand what it wants from me through pseudo-code or an algorithm it would be greatly appreciated.
Where I'm confused is how to initialize arg[0] and arg[1] and exactly
what they are being initialized to.
The main method's String array input argument consists of whatever String arguments you pass to the program's main method when you run the program. For example, here is a simple program that loops over args and prints a nice message with each argument's index and value on a separate line:
package com.example;
public class MainExample {
public static void main(String[] args) {
for (int i = 0; i < args.length; i++) {
System.out.printf("args[%d]=%s\n", i, args[i]);
}
}
}
Once you've compiled the program, you can run it on the command-line and pass it some arguments:
java -cp . com.example.MainExample eh? be sea 1 2 3 "multiple words"
Output:
args[0]=eh?
args[1]=be
args[2]=sea
args[3]=1
args[4]=2
args[5]=3
args[6]=multiple words
So lets explain to you
Create a class Inventory : if you don't know how to create a class google it just as is
The static method main: Every executable class in java (at least from the console) has the main method you should google java main method and propably in the same place you find it you will see the default arguments that it receives
When you learn about the default arguments of method main you will undertand about the 'args' that has to be on it
You will have t study the class String google it "java String class"
You will have to study the class File google it "java File class"
At the end everything else would be just logic and I beleave you have learned some at this point.
public class Inventory { // class inventory
public static void main(String[] args) // main method
{
if(args.length==2){ // check if args contains two elements
String filePath = args[0];
String fileName = args[1];
filePath+= System.getProperty("file.separator")+fileName;
File fileCMD = new File(filePath+".cmd");
//fileCMD.createNewFile();
File filePRO =new File(filePath+".pro");
//filePRO.createNewFile();
}
else {
//write the code to print the message Usage: java Inventory Incorrect number of parameters for a while and exit the program.
}
}
This is what I've understood. Basically you have to write a program to create two files, one called fileName.cmd and the other fileName.pro. You have to construct the path of the files using the arguments (input parameters of the main method) and system's file separator. If the arguments don't have two elements you have to print the 'invalid' message. That's it.
Where I'm confused is how to initialize arg[0] and arg[1] and exactly
what they are being initialized to.
You have to use command line to pass the arguments and launch the program , something like the following code in cmd or terminal:
java inventory thePath theFileName
That's how it get initialized.
In command prompt
i usually give input to java program as follows
c:/> java Myprogram < in.txt
this in.txt have input for the Myprogram class
but i cannot do the same in eclipse
i have give the parameter in program arguments in run configuration as
< in.txt
no error is coming.
simply the program ask for the input
what should i do.
The < symbol is something understood and interpreted by the command line. You can't use that in Eclipse.
You Have a look at the answer to this question:
Eclipse reading stdin (System.in) from a file
in your main Method, you can get the parameters via the String array the main method has.
public static void main(String [] args){
for(int i = 0; i <args.length; i++)
System.out.println(args[i]);
}