Hibernate Unidirectional OneToMany with composite key - java

I wanted to frame Hibernate OneToMany relationship where
Parent has a composite primary key and Child has a primary key (hibernate-auto generated). Below is my working sample code :
class Parent{
#EmbeddedId
private ParentPk parentPk;
#OneToMany( mappedBy="parent")
private List<ChildType1>;
#OneToMany( mappedBy="parent")
private List<ChildType2>;
#OneToMany( mappedBy="parent")
private List<ChildType3>;
//--setters and getters
}
#Embeddable
public class ParentPk {
private Long parentId;
private BigDecimal version;
//..setters and getters
}
class ChildType1{
#Id
private Long childId;
#ManyToOne(cascade = CascadeType.ALL)
#JoinColumns({ #JoinColumn(name = "parentId"),
#JoinColumn(name = "version") })
private Parent parent;
//..other fields and setters and getters
}
//--ChildType2 and ChildType3 like above
But now I wanted to model above as OneToMany unidirectional relationship, i.e., a child should not reference the parent (want to omit Parent instance in the child class). Is it possible?

An example approach:
#Entity
class Parent {
#EmbeddedId
private ParentPk parentPk;
#OneToMany
#JoinColumns({
#JoinColumn(name = "parentId", referencedColumnName = "parentId"),
#JoinColumn(name = "version", referencedColumnName = "version")
})
private List<ChildType1> children1;
// exactly the same annotations as for children1
private List<ChildType2> children2;
// exactly the same annotations as for children1
private List<ChildType3> children3;
//..other fields and setters and getters
}
#Entity
class ChildType1 {
#Id
private Long childId;
//..other fields and setters and getters
}
//--ChildType2 and ChildType3 like above

Related

How to map OneToOne recursion entities?

I'm looking for how to solve a recursion and bidiretional onetoone relationship in my Branch object:
#Entity
#Table("BRANCH")
public class Branch {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(name = "name")
private String name;
#OneToOne
#JoinColumn(name = "id")
private Branch parent;
#OneToOne(mappedBy = "parent")
#JoinColumn(name = "parent_id")
private Branch child;
//Getters and Setters
}
Is it an accepted pattern?
Right way of bidirectional #OneToOne mapping with self reference:
#Entity
#Table("BRANCH")
public class Branch {
#OneToOne
#JoinColumn(name = "parent_id")
private Branch parent;
#OneToOne(mappedBy = "parent")
private Branch child;
this is ancestor for object in child field
this is descendant for object in parent field
Hierarchy is: parent > this > child
You do not require two foreign keys, single
foreign key in the owning side of the relationship is sufficient. In
JPA the inverse OneToOne must use the mappedBy attribute.
https://en.wikibooks.org/wiki/Java_Persistence/OneToOne#Inverse_Relationships,_Target_Foreign_Keys_and_Mapped_By

Mapping a composite foreign key to a composite primary key

I'm having problems mapping composite keys in jpa / hibernate. The parent entity and the child entity both have composite primary keys.
I have been able to use #mapsId when the parent entity has a simple key and the child has a composite key.
In the hibernate documentation they use #JoinCoumns in the mapping to demonstrate mapping two composite keys. But in their example its not clear where those column references are defined.
I have the following:
#Embeddable
public class PriceRequestLegKey implements Serializable {
#Column(name = "leg_request_id")
private String requestId;
#Column(name = "display_index")
private int displayIndex;
...
}
#Embeddable
public class AllocationKey implements Serializable {
#Column(name = "leg_request_id")
private String requestId;
#Column(name = "display_index")
private int displayIndex;
#Column(name = "allocation_index")
private int allocationIndex;
...
}
#Entity(name = "PriceRequestLeg")
public class PriceRequestLegModel {
#EmbeddedId
private PriceRequestLegKey legKey;
#OneToMany(cascade = CascadeType.ALL)
#JoinColumns({
#JoinColumn(name = "leg_request_id", referencedColumnName = "leg_request_id"),
#JoinColumn(name = "display_index", referencedColumnName = "display_index")
})
private List<AllocationModel> allocations;
...
}
#Entity(name = "Allocation")
public class AllocationModel {
#EmbeddedId
private AllocationKey allocationKey;
#ManyToOne
#MapsId
#JoinColumns({
#JoinColumn(name = "leg_request_id", referencedColumnName = "leg_request_id"),
#JoinColumn(name = "display_index", referencedColumnName = "display_index")
})
private PriceRequestLegModel leg;
...
}
At runtime when saving it gives the follow exception:
org.springframework.orm.jpa.JpaSystemException: could not get a field value by reflection getter of com.lbg.legato.rfq.data.entity.AllocationKey.displayIndex; nested exception is org.hibernate.PropertyAccessException: could not get a field value by reflection getter of com.lbg.legato.rfq.data.entity.AllocationKey.displayIndex
Which I assume is spurious as there are getters and setters. I also get the same error if I use mappedBy="leg" on the priceRequestLegModel and #MapsId on the AllocationModel. Could anyone point out what I'm doing wrong here?
You should restore the mappedBy="leg" to the PriceRequestLegModel #OneToMany annotation:
#Entity(name = "PriceRequestLeg")
public class PriceRequestLegModel {
#EmbeddedId
private PriceRequestLegKey legKey;
#OneToMany(mappedBy="leg", cascade = CascadeType.ALL)
private List<AllocationModel> allocations;
...
}
Then you should change AllocationKey to reference PriceRequestLegKey:
#Embeddable
public class AllocationKey implements Serializable {
PriceRequestLegKey legKey; // corresponds to PK type of PriceRequestLegModel
#Column(name = "allocation_index")
private int allocationIndex;
...
}
And then set the value of the Allocation.leg #MapsId annotation appropriately:
#Entity(name = "Allocation")
public class AllocationModel {
#EmbeddedId
private AllocationKey allocationKey;
#ManyToOne
#MapsId("legKey")
#JoinColumns({
#JoinColumn(name = "leg_request_id", referencedColumnName = "leg_request_id"),
#JoinColumn(name = "display_index", referencedColumnName = "display_index")
})
private PriceRequestLegModel leg;
...
}
Some examples like this are in the JPA 2.2 spec section 2.4.1.

Hibernate #ManyToOne cascade children constraint exception

Im facing a little problem here.
I have two entities: Parent and Child, Parent has a List annotated #OneToMany.
The problem is when I try to insert a new Parent, it crashes when persisting the children, because the Parent Id was not generated yet.
Is that a fix for it?
#Entity
#Table(name = "PRODUTO")
public class Parent extends BaseEntity
{
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "ID_PRODUTO")
private Integer produtoId;
#OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER, mappedBy = "produtoId", orphanRemoval = true)
// #JoinTable(name = "PRODUTO_TAMANHO", joinColumns = #JoinColumn(name = "ID_PRODUTO"))
#OrderBy("preco ASC")
private List<Child> children;
}
#Entity
#IdClass(Child.PrimaryKey.class)
#Table(name = "PRODUTO_TAMANHO")
public class Child extends BaseEntity
{
public static class PrimaryKey extends BaseEntity
{
private static final long serialVersionUID = -2697749220510151526L;
private Integer parentId;
private String tamanho;
//rest of implementation
}
#Id
#Column(name = "ID_PRODUTO")
private Integer parentId;
#Id
#Column(name = "TAMANHO")
private String tamanho;
#ManyToOne
#JoinColumn(name = "ID_PRODUTO", insertable = false, updatable = false)
private Parent parent;
}
I think if I persist firstly the parent, than persist the children would be a bad approach.
Is that a way to persist the children, when persisting Parent?
Thanks!
Guys, the exception that occurs when persisting Parent is:
com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException: Column 'ID_PRODUTO' cannot be null
I found a guy facing the same problem: #OneToMany and composite primary keys? (maybe it's better explained)
Here is my insertion code
Parent parent = new Parent();
Child child1 = new Child();
child1.setTamanho("Tamanho 1");
child1.setParent(parent);
Child child2 = new Child();
child2.setTamanho("Tamanho 1");
child2.setParent(parent);
List<Child> children = parent.getChildren();
children.add(child1);
children.add(child2);
save(parent);
//all of this instances, is coming from a view.jsp binded by spring, I can confirm it is exactly like this, with parentId as null
//when updating, it goes perfectly
There are few problems with your entity class.
mappedBy attribute in Parent entity should be set to parent: mappedBy="parent".
In child entity, below field is not required.
#Id
#Column(name = "ID_PRODUTO", nullable = true)
private Integer parentId;
Updated entity is like this.
#Entity
#Table(name = "PRODUTO")
public class Parent extends BaseEntity
{
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "ID_PRODUTO")
private Integer produtoId;
#OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER, mappedBy = "parent", orphanRemoval = true)
// #JoinTable(name = "PRODUTO_TAMANHO", joinColumns = #JoinColumn(name = "ID_PRODUTO"))
#OrderBy("preco ASC")
private List<Child> children;
}
#Entity
#IdClass(Child.PrimaryKey.class)
#Table(name = "PRODUTO_TAMANHO")
public class Child extends BaseEntity
{
public static class PrimaryKey extends BaseEntity
{
private static final long serialVersionUID = -2697749220510151526L;
private Integer parentId;
private String tamanho;
//rest of implementation
}
/* #Id
#Column(name = "ID_PRODUTO", nullable = true)
private Integer parentId; */ // Not required.
#Id
#Column(name = "TAMANHO")
private String tamanho;
#ManyToOne
#JoinColumn(name = "ID_PRODUTO", insertable = false, updatable = false)
private Parent parent;
}
Also I do not understand child inner class for primary key. Use proper primary as you have used parent.
And while inserting set both parent to child and child to parent. See my blog for more details.Here

#OneToOne relationship with additional constraint

Suppose, we have two entities, first one:
#Entity
#Table(name = "entitya")
public class EntityA {
#Id
#Column(name = "id")
private Long id;
#Column(name = "name")
private Long name;
#OneToMany(mappedBy = "parent", fetch = FetchType.LAZY)
private Set<EntityB> childEntities;
}
and the second:
#Entity
#Table(name = "entityb")
public class EntityB {
#Id
#Column(name = "id")
private Long id;
#Column(name = "name")
private String name;
#Column(name = "master")
private Boolean master;
#ManyToOne
#JoinColumn(name = "parent")
private EntityA parent;
}
So far, so good. However underlying database tables and constrains enforce that for any entityA there can be only one EntityB with boolean field master set to true. I can extract it by adding following method to entityA:
public entityB getMasterChild() {
for(entityB ent : childEntities) {
if(ent.isMaster()) {
return ent;
}
}
}
The question is, can I create #OneToOne relationship in EntityA that can express that rule, so that entityA can have additional masterChild member of type entityB?
If I understood you correctly you want to create/define a relationship between two entities based on a value of some entity's property. The think is that relationship between entities is defined on entities count (how many entities can has the other entity) and not on some entity's property value.
However
If you really want to use #OneToOne mapping for masterChild I would recommend creating a separate table/entity for it. Once this is done, you can include this new MasterChild entity into EntityA and annotate it with #OneToOne.
Here is new MasterChild entity
#Entity
public class MasterChild extends EntityB{
#Id
#Column(name = "id")
private Long id;
}
Note that I have removed 'master' from EntityB as it is no longer needed
#Entity
#Table(name = "entityb")
public class EntityB {
#Id
#Column(name = "id")
private Long id;
#Column(name = "name")
private String name;
#ManyToOne
#JoinColumn(name = "parent")
private EntityA parent;
}
And here is modified EntityA
#Entity
#Table(name = "entitya")
public class EntityA {
#Id
#Column(name = "id")
private Long id;
#Column(name = "name")
private Long name;
#OneToOne
private MasterChild master;
#OneToMany(mappedBy = "parent", fetch = FetchType.LAZY)
private Set<EntityB> childEntities;
}

Hibernate creating relation on #JoinTable

I have two tables which have Many-to-Many relations which have a JoinTable USER_SERVICES as below.
#Entity
public class User implements Serializable {
#NotNull
#Column(unique=true)
private String username;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
#ManyToMany(fetch = FetchType.EAGER)
#JoinTable(
name = "USER_SERVICES",
joinColumns = {#JoinColumn(name = "id", referencedColumnName = "id")},
inverseJoinColumns = {#JoinColumn(name = "", referencedColumnName = "name")})
private Set<Services> services;
// Getters and Setters
}
#Entity
public class Services implements Serializable {
#NotNull
#GeneratedValue(strategy = GenerationType.AUTO)
#Id
private Long serviceId;
#NotNull
#Column(unique=true)
private String name;
//Getters and Setters
}
The above code creates a table USER_SERVICES, but I also want to have a Many-to-Many relation on the table USER_SERVICES with another table RATINGS which would result in another table USER_SERVICES_RATINGS. how can I define this relation with Hibernate/JPA annotations?
Bi-Directional Many to Many using user managed join table object (Relatively common)
Commonly used when you want to store extra information on the join object such as the date the relationship was created.
public class Foo{
private UUID fooId;
#OneToMany(mappedBy = "bar", cascade=CascadeType.ALL)
private List<FooBar> bars;
}
public class Bar{
private UUID barId;
#OneToMany(mappedBy = "foo", cascade=CascadeType.ALL)
private List<FooBar> foos;
}
#Entity
#Table(name="FOO_BAR")
public class FooBar{
private UUID fooBarId;
#ManyToOne
#JoinColumn(name = "fooId")
private Foo foo;
#ManyToOne
#JoinColumn(name = "barId")
private Bar bar;
//You can store other objects/fields on this table here.
}
You need to create an explicit UserServices entity and setup the relationship to the Ratings entity per your needs.
Remember that in hibernate you model relationships between entities (i.e. your java objects), not db tables.

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