I have two tables which have Many-to-Many relations which have a JoinTable USER_SERVICES as below.
#Entity
public class User implements Serializable {
#NotNull
#Column(unique=true)
private String username;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
#ManyToMany(fetch = FetchType.EAGER)
#JoinTable(
name = "USER_SERVICES",
joinColumns = {#JoinColumn(name = "id", referencedColumnName = "id")},
inverseJoinColumns = {#JoinColumn(name = "", referencedColumnName = "name")})
private Set<Services> services;
// Getters and Setters
}
#Entity
public class Services implements Serializable {
#NotNull
#GeneratedValue(strategy = GenerationType.AUTO)
#Id
private Long serviceId;
#NotNull
#Column(unique=true)
private String name;
//Getters and Setters
}
The above code creates a table USER_SERVICES, but I also want to have a Many-to-Many relation on the table USER_SERVICES with another table RATINGS which would result in another table USER_SERVICES_RATINGS. how can I define this relation with Hibernate/JPA annotations?
Bi-Directional Many to Many using user managed join table object (Relatively common)
Commonly used when you want to store extra information on the join object such as the date the relationship was created.
public class Foo{
private UUID fooId;
#OneToMany(mappedBy = "bar", cascade=CascadeType.ALL)
private List<FooBar> bars;
}
public class Bar{
private UUID barId;
#OneToMany(mappedBy = "foo", cascade=CascadeType.ALL)
private List<FooBar> foos;
}
#Entity
#Table(name="FOO_BAR")
public class FooBar{
private UUID fooBarId;
#ManyToOne
#JoinColumn(name = "fooId")
private Foo foo;
#ManyToOne
#JoinColumn(name = "barId")
private Bar bar;
//You can store other objects/fields on this table here.
}
You need to create an explicit UserServices entity and setup the relationship to the Ratings entity per your needs.
Remember that in hibernate you model relationships between entities (i.e. your java objects), not db tables.
Related
I can not change the db schema and this is what I got so far:
public class User{
#Id
private String userId;
#OneToMany
#JoinTable(
name = "user_invoice",
joinColumns = #JoinColumn(name="user_id"),
inverseJoinColumns = #JoinColumn(name = "invoice_id")
)
private List<InvoiceItem> invoiceItems;
}
public class InvoiceItem{
#Id
private String invoiceId;
private String invoiceItemId;
}
This configuration does not allow invoice_id to be duplicated on invoice_item table(it should since I can have multiple items on a given invoice)
If I make invoice_item_id composite pk I would need to add an extra column on user_invoice table which I can not.
How can I map this?
You could split up the many-to-many association into two one-to-many associations and an entity for the join table. You can map it like this:
public class User{
#Id
private String userId;
#OneToMany(mappedBy = "user")
private List<Invoice> invoices;
}
#Table(name = "user_invoice")
public class Invoice{
#Id
#ManyToOne(fetch = LAZY)
#JoinColumn(name="user_id")
private User user;
#Id
private String invoiceId;
#OneToMany(mappedBy = "invoice")
private List<InvoiceItem> invoiceItems;
}
public class InvoiceItem{
#Id
#ManyToOne(fetch = LAZY)
private Invoice invoice;
#Id
private String invoiceItemId;
}
I am new in Hibernate and just look at several examples and started to make some practice.
Here in the example, there are 3 entities which have relations e.g. #ManyToMany, #OneToMany and #ManyToOne.
Student:
#Entity
#Data
public class Student {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
Long id;
private String name;
#JsonIgnore
#ManyToMany(mappedBy = "students")
private Set<Subject> subjects = new HashSet<>();
}
Subject:
#Entity
#Data
public class Subject {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
Long id;
private String name;
#ManyToMany
#JoinTable(
name = "subject_student",
joinColumns = #JoinColumn(name = "subject_id"),
inverseJoinColumns = #JoinColumn(name = "student_id")
)
Set<Student> students = new HashSet<>();
#ManyToOne(cascade = CascadeType.ALL)
#JoinColumn(name = "teacher_id", referencedColumnName = "id")
private Teacher teacher;
}
Teacher:
#Entity
#Data
public class Teacher {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String name;
#JsonIgnore
#OneToMany(mappedBy = "teacher")
private Set<Subject> subjects;
}
My questions are:
1. In the subject entity, I tried to remove #JoinColumn and the related entities are connected as the example above:
#ManyToMany
#JoinTable(name="subject_student")
public Set<Student> students = new HashSet<>();
#ManyToOne(cascade = CascadeType.ALL)
private Teacher teacher;
So, if we want to use subject_id - student_id pair in subject_student table and use teacher_id in subject table as it is created in the example, can I use my simplified notation by removing #JoinColumn? Because, if there is not a special case, I think it is redundant to verbose notation of relations.
2. When I use the second approach, the columns are created as plural e.g. subjects_id - students_id in subject_student. So, can I prevent this and create them as in the previous example by using my approach?
I'm working on a Spring-Boot project with a H2 database. I have two entities Portfolio and Report, and there is a many-to-many association between the two.
I want those entities to be audited, so I followed this tutorial to audit through an AuditorAware interface with custom fields.
The two entities are well audited, the columns are created in the database. However, the join table portfolio_reports is not audited. How can I audit the join table as well ?
Portfolio.java
#Entity
#Table(name = "portfolio")
public class Portfolio extends Auditable<String> implements Serializable {
#Id
#Column(name = "id")
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(name = "name")
#Unique
private String name;
#ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
#JoinTable(name = "portfolio_report", joinColumns = #JoinColumn(name = "portfolio_id"), inverseJoinColumns = #JoinColumn(name = "report_id"))
private List<Report> reports;
// Getters and setters
}
Report.java
#Entity
#Table(name = "report")
public class Report extends Auditable<String> implements Serializable {
#Id
#Column(name = "id")
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(name = "axioma_id")
private Long axiomaId;
#Column(name = "name")
private String name;
#AuditJoinTable
#ManyToMany(mappedBy = "reports", cascade = CascadeType.PERSIST, fetch = FetchType.LAZY)
private List<Portfolio> portfolios;
// Getters and setters
}
Auditable.java
#MappedSuperclass
#EntityListeners(AuditingEntityListener.class)
public abstract class Auditable<U> {
#Version
#Column(name = "version_no")
protected Long versionNo;
#CreatedDate
#Temporal(TemporalType.TIMESTAMP)
#Column(name = "created_date")
protected Date createdDate;
#LastModifiedDate
#Temporal(TemporalType.TIMESTAMP)
#Column(name = "modified_date")
protected Date modifiedDate;
}
AuditorAwareImpl.java
public class AuditorAwareImpl implements AuditorAware<String> {
#Override
public Optional<String> getCurrentAuditor() {
return Optional.of("Admin");
}
}
PersistenceConfiguration.java
#Configuration
#EnableJpaAuditing(auditorAwareRef = "auditorAware")
public class PersistenceConfiguration {
#Bean
public AuditorAware<String> auditorAware() {
return new AuditorAwareImpl();
}
}
Problem:
Clearly here Auditable should add some column to your intermediate table that maintains relation between Portfolio and Report and that table is created behind the scene and you don't have access to that table in your program. Only hibernate can use that table to maintain relation between your entities and do join operation.
Solution:
Here you should make Join table that maintain Many to Many relation between Portfolio and Report explicit so that you can have entity like PortfolioReport in your program that can extends from Auditable. Please read the following post to see how to do that: The best way to map a many-to-many association with extra columns when using JPA and Hibernate
I work with an embedded H2 database in which I use the #OneToMany relationship to relate an entity instance (product) to multiple instances of the other entities (suppliers); it's useful when I have specific suppliers for a particular product.
However now, I want to associate all the suppliers with every single product; I don't want to generate in my supplier table different supplier records for each product, instead I want to have only 5 records (5 suppliers) in my supplier table which are associated to every single product, it few words I want to achieve something like "one to all", is it possible to do it using JPA annotations?
Product entity
#Entity
public class Product {
#Id
private String productCode;
#OneToMany
#JoinColumn(name = "supplier_id", referencedColumnName = "productCode")
private List<Supplier> suppliers;
}
Supplier entity
#Entity
public class Supplier {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
private String name;
}
Unidirectional #OneToMany association:
#Entity
public class Product {
#Id
// #Column(name = "id") maybe
// #GeneratedValue maybe
private String productCode;
#OneToMany(cascade = CascadeType.ALL, orphanRemoval = true) // according to your need
private List<Supplier> suppliers;
...
}
And,
#Entity
public class Supplier {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private String name;
...
}
#ManyToOne association:
#Entity
public class Product {
#Id
// #Column(name = "id") maybe
// #GeneratedValue maybe
private String productCode;
...
}
And,
#Entity
public class Supplier {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#ManyToOne
#JoinColumn(name = "product_id", foreignKey = #ForeignKey(name = "PRODUCT_ID_FK"))
private Product product;
private String name;
...
}
Have a problem persisting a ManyToMany relationship mapped like that
Document.java
public class Document {
.......
#ManyToMany(targetEntity = Category.class, cascade = CascadeType.ALL, fetch = FetchType.LAZY)
#JoinTable(name = "fideuram_gup_documents_in_categories",
joinColumns = #JoinColumn(name="fk_document"),
inverseJoinColumns = #JoinColumn(name = "fk_category"))
private Set<Category> categories = new HashSet<Category>();
.......
}
where Category is one more entity of my model which I don't paste here since it doesn't carry a reverse mapping of this relation, and has just an ID and a name.
When I try to persist Document however I get the following error:
org.hibernate.PropertyAccessException: could not get a field value by reflection getter of it.ardesia.fideuram.gup.model.Category.id
I've surfed the web about it but no page relates to ManyToMany relations. Of course all the ManyToOne relations I have on the entity Document work fine.
I'm using:
spring-data-jpa:1.2.0.RELEASE
hibernate-core:4.2.2.Final
hibernate-entitymanager:4.2.2.final
UPDATE
All entities expose a default constructor and getter/setter for every field. Or,more preciselt, I'm using Spring Roo for creating the entity and it injects getters and setters automatically upon compilation.
You can instrument Hibernate how it must access your property using #javax.persistence.Access annotation; put on your mapped class with #Access.value set to
AccessType.FIELD for direct field access
AccessType.PROPERTY for accessing properties using accessors
Maybe it can help you, I already did the same, I put my code, it creates a join table:
#Entity
#Table(name = "custom_pizza")
public class CustomPizza extends BaseEntity {
private static final long serialVersionUID = 1L;
// ManyToMany instead of oneToMany in order to don't have the unique
// constraint on each primary key of the join table
#ManyToMany(fetch = FetchType.LAZY)
#JoinTable(name = "custom_pizza_topping", joinColumns = #JoinColumn(name = "custom_pizza_id"), inverseJoinColumns = #JoinColumn(name = "topping_id"))
private Set<Topping> toppings = new HashSet<Topping>();
public void addTopping(Topping topping) {
toppings.add(topping);
}
public void removeTopping(Topping topping) {
toppings.remove(topping);
}
...
And my topping:
#Entity
#Table(name = "topping")
public class Topping extends BaseEntity {
private static final long serialVersionUID = 1L;
#Column(name = "name", nullable = false)
private String name;
#Column(name = "price", nullable = false)
private float price;
....
and the BaseEntity
#MappedSuperclass
public abstract class BaseEntity implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
...