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I have this code in Python:
if word[x:x+2] in twowords:
(twowords is a list). I can't figure out how to write in twowords in Java.
It looks like Python uses [x:y] to create a substring. You can use the substring method for that purpose, with the same parameters.
There is no in syntax in Java, but all Lists in Java support the contains method.
Try
if (twowords.contains(word.substring(x, x+2)))
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I am writing a program with IPOPT in Java and due to the nature of the problem, it is rather difficult to provide a Jacobian matrix.
The question is basically the title:
Is it possible to use IPOPT without Jacobian matrix and if so how?
i couldn't find anything in the documentation, but maybe i am just blind.
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I am writing a simple OpcUa client using milo and want to use multi-dimensional arrays as values.
Do I have to create an ExtensionObject to decode my matrix or is there an attribute to store the dimensions in? And if there is such an attribute, how can I access it?
Thanks
Chris
I oversaw the VariableNode.getArrayDimensions() and VariableNode.setArrayDimensions() methods.
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I have been working on a java algorithm and I want to improve it by allowing it to accept and process very large String values.
Could you suggest me any good ways of storing the input/output results. I've been thinking of writing it on a file with the readLine(), writeLine() methods? Is this a good technique ???
I recommend you to store all your string in a text file (if possible) and use BufferedReader utilities ...
here is the a link to how its done :
https://www.tutorialspoint.com/java/io/bufferedreader_readline.htm
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So the question is basically if to have
getDriver().findElement(by).clear();
or to have
String text = getDriver().findElement(by).getText();
if (!text.equals(""))
getDriver().findElement(by).clear();
and after that a sendKeys.
Note: Most of the times, the field is empty.
This is simple math
getDriver().findElement(by).clear();
Costs as
getDriver().findElement(by).getText();
To the second line you add an if check and maybe getDriver().findElement(by).clear(); anyway.
So just call clear() without a check.
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I'm thinking on possibility of making a Huffman code without "node".
It's based on the nodes then my question seems a bit ambiguous.
I know,maybe we have to use string's abilites ...
Is it possible ? and if "YES" how Is it possible in java?
Thanks.
You can use indices instead of nodes but you need somewhere nodes and/or vertices.