I have a textbox that gives out suggestions based on user input and one of my textboxes is location based.
The problem is, if a user types in Chicago,IL, everything works, but if they type in Chicago, IL, the suggestions stop. The only difference between the two is the space after the comma.
How can I fix this, so that even if a user puts in 2 or 4 spaces after the comma it still shows the same results as the first case?
This is my code:
if (location.contains(",")) {
// the city works correctly
String city = location.substring(0, location.indexOf(","));
// state is the problem if the user puts any space after the comma
// it throws everything off
String state = location.substring(location.indexOf(",") + 1);
String myquery = "select * from zips where city ilike ? and state ilike ?";
}
I have also tried this:
String state = location.substring(location.indexOf(",".trim()) + 1);
The string variables are used to make calls to the database; that is why I have to eliminate any spaces.
How can I fix this, so that even if a user puts in 2 or 4 spaces after
the comma it still shows the same results as the first case?
you can use location.replaceAll(" ", "")
for extracting the location into city,state
you can use split() method as
String location[]=location.split(",");
Now
String city=location[0];
String state=location[1];
EDIT:(for Whome)
String location="New York, NY";
String loc[]=location.split(",");
String city=loc[0].trim();
String state=loc[1].trim();
System.out.println("City->"+city+"\nState->"+state);
you were in the right direction by using trim(). However, you put it in the wrong place.
",".trim() will always yield ",". you want to trim the result of the substring operation:
String state = location.substring(location.indexOf(",") + 1).trim();
Trim the entire result. For example:
String city = (location.substring(0, location.indexOf(","))).trim();
String state = (location.substring(location.indexOf(",") + 1)).trim();
try using java.lang.String trim() function in the correct place.
trim on ",".trim() will produce ",".
Need to trim() the final result.
if (location.contains(",")) {
String city = location.substring(0, location.indexOf(",")).trim();
String state = location.substring(location.indexOf(",")).trim();
}
Use
String state = location.substring(location.indexOf(",") + 1).trim();
Instead of
String state = location.substring(location.indexOf(",".trim()) + 1);
That should work.
Related
Need help with getting rid of half of a string in android studio. The string is:
final String strOrigin = String.valueOf(origin).trim();
The value that is returned is;
"Point{type=Point, bbox=null, coordinates=[27.993726079654873,-26.14686805145815]}"
I want to be left with only the numbers of that, in the String. I have tried;
strOrigin.replace("Point{type=Point, bbox=null, coordinates=", "");
But it isn't working. Any help would be appreciated.
In Java strings are immutable. You must assign the result to a new string:
String strResult = strOrigin.replace("Point{type=Point, bbox=null, coordinates=", "");
Make your life simpler by just getting the coordinates:
final String strOigin = origin.coordinates().stream()
.map(String::valueOf)
.collect(Collectors.joining(",","{","}"));
Or, if you're stuck on java 7:
final String strOigin = String.format(
"{%s,%s}",
String.valueOf(origin.latitude()),
String.valueOf(origin.longitude())
);
Maybe you forgot that replace() returns the result and you must assign it to a string:
String strOrigin = "Point{type=Point, bbox=null, coordinates=[27.993726079654873,-26.14686805145815]}";
String str = strOrigin
.replace("Point{type=Point, bbox=null, coordinates=", "")
.replace("}","");
System.out.println(str);
will print:
[27.993726079654873,-26.14686805145815]
This should do the trick
String s="blabla coordinates=[27.993726079654873,-26.14686805145815] ";
String requiredString = s.substring(s.indexOf("[") + 1, s.indexOf("]"));
will print:
27.993726079654873,-26.14686805145815
Than you can cast it to double or latlong format
Have a look at regular expressions, they allow you to define more flexible search patterns. In your example you only find the coordinates if the rest of the string matches the pattern exactly, but if you happen to get some other value of bbox, or even extra space it will not work. This will always match everything between a pair of square brackets:
String c = origin.replaceAll(".+?(\\[.+?\\]).+?", "$1");
http://www.vogella.com/tutorials/JavaRegularExpressions/article.html
https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html
Can someone help me here? I dont understand where's the problem...
I need check if a String have more than 1 char like 'a', if so i need replace all 'a' for a empty space, but i still want only one 'a'.
String text = "aaaasomethingsomethingaaaa";
for (char c: text.toCharArray()) {
if (c == 'a') {
count_A++;//8
if (count_A > 1) {//yes
//app crash at this point
do {
text.replace("a", "");
} while (count_A != 1);
}
}
}
the application stops working when it enters the while loop. Any suggestion? Thank you very much!
If you want to replace every a in the string except for the last one then you may try the following regex option:
String text = "aaaasomethingsomethingaaaa";
text = text.replaceAll("a(?=.*a)", " ");
somethingsomething a
Demo
Edit:
If you really want to remove every a except for the last one, then use this:
String text = "aaaasomethingsomethingaaaa";
text = text.replaceAll("a(?=.*a)", "");
You can also do it like
String str = new String ("asomethingsomethingaaaa");
int firstIndex = str.indexOf("a");
firstIndex++;
String firstPart = str.substring(0, firstIndex);
String secondPart = str.substring(firstIndex);
System.out.println(firstPart + secondPart.replace("a", ""));
Maybe I'm wrong here but I have a feeling your talking about runs of any single character within a string. If this is the case then you can just use a little method like this:
public String removeCharacterRuns(String inputString) {
return inputString.replaceAll("([a-zA-Z])\\1{2,}", "$1");
}
To use this method:
String text = "aaaasomethingsomethingaaaa";
System.out.println(removeCharacterRuns(text));
The console output is:
asomethingsomethinga
Or perhaps even:
String text = "FFFFFFFourrrrrrrrrrrty TTTTTwwwwwwooo --> is the answer to: "
+ "The Meeeeeaniiiing of liiiiife, The UUUniveeeerse and "
+ "Evvvvverything.";
System.out.println(removeCharacterRuns(text));
The console output is........
Fourty Two --> is the answer to: The Meaning of life, The Universe and Everything.
The Regular Expression used within the provided removeCharacterRuns() method was actually borrowed from the answers provided within this SO Post.
Regular Expression Explanation:
I'm retrieving Strings from the database and storing in into a String variable which is inside the for loop. Few Strings i'm retrieving are in the form of:
https://www.ppltalent.com/test/en/soln-computers-ltd
and few are in the form of
https://www.ppltalent.com/test/ja/aman-computers-ltd
I want split string into two substrings i.e
https://www.ppltalent.com/test/en/soln-computers-ltd as https://www.ppltalent.com/test/en and /soln-computers-ltd.
It can easily be separated if i would have only /en.
String[] parts = stringPart.split("/en");
System.out.println("Divided String : "+ parts[1]);
But in many of the strings it has /jr , /ch etc.
So how can I split them in two sub-strings?
You could perhaps use the fact that /en and /ja are both preceeded by /test/. So, something like indexOf("/test/") and then substring.
In your examples, it seems like you're interested in the very last part, which could be retrieved by lastIndexOf('/') for instance.
Or, using look-arounds you could do
String s1 = "https://www.ppltalent.com/test/en/soln-computers-ltd";
String[] parts = s1.split("(?<=/test/../)");
System.out.println(parts[0]); // https://www.ppltalent.com/test/er/
System.out.println(parts[1]); // soln-computers-ltd
Split on the last /
String fullUrl = "https:////www.ppltalent.com//test//en//soln-computers-ltd";
String baseUrl = fullUrl.substring(0, fullUrl.lastIndexOf("//"));
String manufacturer = fullUrl.subString(fullUrl.lastIndexOf("//"));
I have a string :
"id=40114662&mode=Edit&reminderId=44195234"
All i want from this string is the final number 44195234. I can't use :
String reminderIdFin = reminderId.substring(reminderId.lastIndexOf("reminderId=")+1);
as i cant have the = sign as the point it splits the string. Is there any other way ?
Try String.split(),
reminderIdFin.split("=")[3];
You can use indexOf() method to get where this part starts:
int index = reminderIdFin.indexOf("Id=") + 3;
the plus 3 will make it so that it jumps over these characters. Then you can use substring to pull out your wanted string:
String newString = reminderIdFin.substring(index);
Remove everything else and you'll be left with your target content:
String reminderIdFin = reminderId.replaceAll(".*=", "");
The regex matches everything up to the last = (the .* is "greedy").
This may sound a bit strange but I'm trying to only show part of a string that is retrieved. The string that is retrieved contains something only the lines of NAME:myname and I'm trying to only show the "myname" part is there a way to 'disect' a string considering I know what the prefix "NAME:" is all ways going to be?
There are plenty of ways:
Replace "NAME:" by nothing.
String cleaned = myString.replace("NAME:", "");
Split the string (as shown in the other answer).
Cut the string (if it always starts with NAME: which length is 5):
String cleaned = myString.subString(5);
Use a regular expression
Probably 200 other ways.
Yes. Use something like:
String arr[] = myString.Split(":");
String name = arr[1];
arr[] will contain 2 elements (0 and 1).
arr[0] will contain "Name"
and
arr[1] will contain the second part (the name itself)
Another version of the same (1 line only):
String name = myString.Split(":")[1];
Use split method :
String name = tmpStr.split(":")[tmpStr.split(":").length-1] ;