Develop Reference

JAVA - How to get text after a particular character?

I have a String Chocolate:30:2 in a variable and I want to extract the number after the second colon i.e. 2. So, How can I extract that number?

For example:
String s = "Chocolate:30:2";
String number = s.split(":")[2];

If the second colon is actually the last colon, you can use:
String after = str.substring(1 + str.lastIndexOf(':'));

You can use String lastIndexOf method.
String result = str.substring(str.lastIndexOf(':') + 1);

Java - Split string with multiple dash

I want to get an output first-second from the string below:
first-second-third
So basically what i want is to get the string before the last dash (-).
Can anyone give me a best solution for this?

Well, many down votes but I'll add a solution
the most efficient way to do that is using java.lang.String#lastIndexOf, which returns the index within this string of the last occurrence of the specified character, searching backwards
lastIndexOf will return -1 if dash does not exist
String str = "first-second-third";
int lastIndexOf = str.lastIndexOf('-');
System.out.println(lastIndexOf);
System.out.println(str.substring(0, lastIndexOf)); // 0 represent to cut from the beginning of the string
output:
12
first-second

String s = "first-second-third";
String newString = s.substring(0,s.lastIndexOf("-"));

Just an another way other than lastIndex method, using regex too can be done, try below code:
Pattern p = Pattern.compile("\\s*(.*)-.*");
Matcher m = p.matcher("first-second-third");
if (m.find())
System.out.println(m.group(1));

Substring between first instance of two different symbols

I want to parse the following and store it as a new string, with the condition that mawi is stored and everything else is removed.
<ns0:Assignee>mawi - Manfred Wilson</ns0:Assignee>
One solution I suppose could be a substring starting with the first character after the first > and ending two characters before the first -. All the data is identical. The result is a String with value mawi.
String initial = "<ns0:Assignee>mawi - Manfred Wilson</ns0:Assignee>";
String substring = initial.substring(example.indexOf(">"));
Not sure where to go from here... Any thoughts?

Although the below code do the trick, I suggest you to use Jsoup or XML Parse if you are processing multiple strings like this
Pattern pattern = Pattern.compile("<ns0:Assignee>(.+?)</ns0:Assignee>");
Matcher matcher = pattern.matcher("<ns0:Assignee>mawi - Manfred Wilson</ns0:Assignee>");
matcher.find();
String result = matcher.group(1);
String finalString = result.split(" - ")[0];
System.out.println(finalString); // mawi

If all the strings are built like your example string, you could go with this:
initial.substring(initial.indexOf('>') + 1, initial.indexOf(' '));
Note the + 1 at the start index.
When your Strings are more complicated, I would recommend either using a library for working with XML or using Regular Expressions.

So now you got substring which is equal to: >mawi - Manfred Wilson</ns0:Assignee>.
Now, you can substring your substring again to find only mawi, like this;
String initial = "<ns0:Assignee>mawi - Manfred Wilson</ns0:Assignee>";
String midSub = initial.substring(initial.indexOf('>'));
String finalSub = midSub.substring(1, midSub.indexOf(' ')); // 1 because we still have `>`
System.out.println(finalSub);
Or, one liner:
String finalSub = initial.substring(initial.indexOf('>')+1, initial.indexOf(' '));

show this:
String s = "<ns0:Assignee>mawi - Manfred Wilson</ns0:Assignee>";
s = s.substring(s.indexOf("<ns0:Assignee>")+"<ns0:Assignee>".length(), s.indexOf("</ns0:Assignee>"));

public class string {
public static void main(String[] args) {
String s = "<ns0:Assignee>mawi - Manfred Wilson</ns0:Assignee>";
s = s.substring(14, 18);
System.out.println(s);
}
}

How to Remove string after second last occurrence of special character?

In my application I am trying to make breadcrumbs using StringBuilder
Suppose this is the string :
String1>String2>String3>String4>String5>
Now I want to remove String5> and I want string like this:
String1>String2>String3>String4>
How can I do this?
Please help!!

you can use regex \\w+>$
\\w+ mean match [a-zA-Z0-9_]
>$ match > character where $ mean at the end
Regex Demo Link
String s = "String1>String2>String3>String4>String5>";
String s2 = s.replaceAll("\\w+>$","");
System.out.println(s2);
Output :
String1>String2>String3>String4>
Note : To avoid _ use
String s2 = s.replaceAll("[a-zA-Z\\d]+>$","");
Just in case if you have data with some special characters like
String s = "String1>Stri$#$ng2>String3>Stri#$$#ng4>St$#:/|ring5>";
then above solution won't work so you can use
String s2 = s.replaceAll("[^>]+>$","");
// s2 will be = String1>Stri$#$ng2>String3>Stri#$$#ng4>
Regex Demo Link
[^>]+ : ^ inside [] works as negation mean match everything except > character

Split string by > and then apply for loop on the array. match string by position. if match then delete otherwise add to new stringBuilder.

You can use combination of lastIndexOf and substring().
Example:
String oldValue = "String1>String2>String3>String4>String5>";
int lastIndex = oldValue.lastIndexOf('>', oldValue.length() - 2);
String newValue = oldValue.substring(0, lastIndex + 1);

Unable to replace String containing special characters

I want to replace all special characters with whitespace but I am unable to replace x :
String search = "640×20141007151608##$%$20141008104817.jpeg";
String newSearch = search.replaceAll("[\\p{Punct}&&[^_]]", "");
System.out.println(newSearch);
output : 640×2014100715160820141008104817jpeg

I use the logic below:
String newSearch = search.replaceAll("[^A-Za-z0-9 ]","");
That is, remove anything that is not a number or a digit. Is this what you wanted ?

[^0-9a-zA-Z\.]
Try this.Repalce by ``.See demo.
http://regex101.com/r/hQ1rP0/51