I am making project with GUI. The thing is, that I have a button and what I need to do is that after clicking this button I need to change Frame layout. For example, like when you are installing some program and you click "next" button, the Frame layout changes and you can see some different content. Basicly, dynamic wizard.
I have tried use another Frame, but it opens in another window and that is not what I want. I want to open it in the same window.
Another thing I have tried is set visibility of these components I don't want to be displayed to false, but I find it unprofessional and it is overlook in making a desing, when I have components over themselfs.
So do you guys have any idea? Thank you.
Most of the times for a wizard like GUI, you should have JFrame and a set of JPanels. In each step you can pass the shared data as constructor arguments to each panel, and when you are making one of them invisible and make another one visible, you can get some date from the previous step panel and pass it to the next step panel(if needed).
It is very common that your panels extend the JPanel and have some argument in their constructor(s). You use these data for initializing your panel and managing the state of the overall progress.
There is no a total plan for all situations. So you should decide what to do which is best fit for your case.
Try not to have multiple JFrames.
Hope this would be helpful.
Related
So I have this project to make and I'm somehow stuck. I have an encyclopedia to make and I do not know how to make the pages.
For example, I have a JFrame with two buttons, called Back and Next. When I press that button, I want my program to switch to the next page, same as an e-book.
I thought of creating a new JPanel, get the X and the Y of the first frame and close the first frame when this one opens, reopen it only when I press back. How can I do that?
You have several options:
Create new JPanels for each "page" and swap them via a CardLayout.
Create a single JPanel for displaying page information, and then swap content on pressing the button. I favor this solution if at all possible as the simplest and the one best suited to a good MVC solution.
As an aside, if you're new to the Swing GUI library, then I suggest that you put the GUI-builder to the side for a bit til you learn the underpinnings of the library. This will help prevent you from painting yourself in a corner should you use the GUI builder later.
I am creating a GUI for my project. I am completely stuck at one point. I was able to create a GUI which will make some simple queries like the release number, command name, and few other boolean questions.
Now I want the user to press CONTINUE button to move to the next page of the GUI form. I have created the continue button, but now I need to register an event to it. This is where I am stuck. I have no idea what event can I register to it which will move the GUI to next page. (By moving to the next page I mean, the different GUI pages we see when we are installing a software for our computer.)
For instance, if I am installing iTunes, I'd first select the radio button for "I accept the terms and conditions" and then I'd press the CONTINUE or the NEXT button to move ahead. If I need to come back, I'd press the BACK button.
One logical answer would be to create another GUI form and then link it to the one I created first.
EDIT:: this is the first time I am working in Java, so I might have ignored some obvious facts.
Look into using a CardLayout, adding several JPanels to the CardLayout-using container, and then to swap to the next view (the next JPanel), call the layout's next(...) method in the JButton's ActionListener. You could also randomly access components held by the CardLayout using its show(...) method.
To learn more about this including sample code, please have a look at the CardLayout Tutorial, and the API.
Well, register an ActionListener or an Action with the button. To do that wizard style, have a look at the CardLayout layout manager to switch cards or use a tabbed pane, hide the tabs and switch them inside the action or action listener.
if i understood, i think you should use the CardLayout
If you are using Swing, you can using several instances of JPanel over a one instance of JFrame.
You can have something like that structure:
JFrame
+------JPanel:root
|
+---JPanel:current // This panel change by other instance
|
+---JPanel:controlPanel // This panel contains you button
In you button need add a ActionListener with the method addActionListener
The panel control may need changes your elements, may the text of button or remove the listener and change by other.
I hope that can help
I have developed my Java code in Netbeans, and now I want to develop the GUI for my application.
The application communicates with a server, so it's going to have a login frame for sure. After that there will be a main frame. From the main frame the user can choose where to go and as you can understand there will be a lot of frames.
I have already developed a version of the application where there are a lot of frames and using the "setVisible()", but I want something better looking. I want a stable frame and inside it, changing the panels or something similar.
How would I do this?
You might use JInternalFrames if you like them, or simply use a main panel with a CardLayout, and display the appropriate card depending on the clicked menu item, or the selected JTree node (as it's done in Windows Explorer and similar applications).
Use the Swing tutorial to get you started.
You can, at any time, make any Container object a JFrame's ContentPane. You can also add and remove Containers from any other Container. If you want a user to be able to jump to any of a dozen panels at any time, CardLayout, as suggested in another answer, is easily the best route. If, however, you intend to lead the user along a somewhat controlled path, you can start with a login JPanel. When that's done, you can create the next panel (a JPanel or something else), add it, and dispose of the first one. And so on until the user exits.
If the transition from one panel to another affects nothing else in the program besides the two panels and the parent Container (JFrame or descendant), this is probably the way to go. If a bunch of other places in the program need to know about the change, you'll want a more centralized mechanism, maybe using CardLayout.
In my program I have two JFrame instances. When I click next button I want to show next frame and hide current frame. So I use this.setVisible(false) and new Next().setVisible(true). But in Next window if I click back button I want to set previous frame to be visible again and next frame must be ended (which means it must be exited).
Is there any special method(s) to do this? How can I do it?
Consider using CardLayout instead of hunting for how many JFrames there are. Then..
only one JFrame would be needed
any of Next/Back Actions will be only switching between cards
There are lots of examples in this forum - e.g. as shown here.
That is an odd & quirky GUI. I suggest instead to run a JFrame for the main GUI, and when the user wants to search, pop a JOptionPane (or modal JDialog) to accept the details to search for. This will not have the effect described above, but will follow the 'path of least surprise' for the end user.
If you want to destroy a JFrame releasing all associated resources you shold call dispose() method on it.
You may place your JFrames on a list data structure and keep a reference to current position according to the window you are displaying. In that way it will be easy to move to next and previous. But note that each frame added to the list will use memory and will have its state as you placed it in to the list.
If you are trying to create a wizard like UI, you should look up Sun(oracle)tutorial here.
create the instance of your main window in next() window.. and use same method which you chosed befoe to hide your main window, for example if your main window is named as gui then what we have to do is.
gui obj = new gui();
and if you click on back button now than do these also
this.setVisibility(false);
obj.setVisibility(true);
that's all you need.
good luck.
I am developing a desktop Java application with GUI implemented through Swing. I have made a JFrame and have added three buttons on it - Add, Edit, Delete.
Now I want that whenever a user clicks on any of the button, the content specific to that button appears besides those three buttons.
So how to implement this? Should I need to add a JPanel besides those three buttons and then add the content specific to the button to that JPanel?
So far, I have taken a JFrame and have added 3 buttons on it. That's it.
For the Add button, I want to add some buttons and textfields to add information to the database.
For the Delete button, I want to add some buttons to find records in the database based on the information entered through the user in the textfield that appears when the user clicks on the Delete button.
Similar type of content for Edit button.
So how to implement this. Should I need to add a JPanel besides those three buttons and then add the content specific to the button to that JPane
That would be fine. When you push the button, you can call JPanel.removeAll() to remove all the controls currently in the control, and then just do the layout again, specific to whatever button you pushed.
If you have custom swing controls, just add your custom control the JPanel using a BorderLayout and putting in the center.
Another option would be to use a CardLayout, and flipping between the cards when a user presses one of the buttons. If the layouts for the buttons never change, that would probably be a better way to do it. Obviously if the content changes between button presses, you'll need to redo the layout each time.
Either of Chad's or Alex's answers would be fine. You will probably need to call a combination of revalidate() and repaint() on the panel that you've changed, as in the past I've noticed Swing doesn't always like panels being swapped out.
Also, have you considered using a JTabbedPane instead of manually coding the interaction with the add/edit/delete buttons?
I haven't done a lot of Java programming, but I think using 2-3 different JPanel, and make visible the one you need depending on the button that was clicked would do the trick.
I'm not sure if this is the right approach though.
I was using a JFrame to add all buttons and make a new JFrame for a new window and hide a previous one.
gven way are better. I will do that now.